Hooke's Law: Difference between revisions
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[https://www.teachengineering.org/collection/van_/lessons/van_cancer_lesson2/stress_strain_hookes_law_key.pdf] | <br>[https://www.teachengineering.org/collection/van_/lessons/van_cancer_lesson2/stress_strain_hookes_law_key.pdf] | ||
[http://hyperphysics.phy-astr.gsu.edu/hbase/permot2.html | <br>[http://hyperphysics.phy-astr.gsu.edu/hbase/permot2.html] | ||
Invention by Design: How Engineers Get from Thought to Thing. Cambridge, MA: Harvard University Press | <br>Invention by Design: How Engineers Get from Thought to Thing. Cambridge, MA: Harvard University Press | ||
[[Category:Contact Interactions]] | [[Category:Contact Interactions]] | ||
Revision as of 19:33, 27 November 2015
This resource page addresses Hooke's Law. (Claimed by brapsas3)
The Main Idea
Hooke's law is a principle that states that some force F needed to compress or extend a spring by some distance s is directly proportional to that distance.
A Mathematical Model
This system can be expressed as F = ks, where k is some constant factor that is characteristic of the spring.
A Computational Model
A vpython visualization of Hooke's Law
History
Hooke's law is named after the 17th century British physicist Robert Hooke. Hooke first publicly 'stated' the law in 1660, initially concealing it in the Latin anagram "ceiiinosssttuv," which represented the phrase Ut tensio, sic vis — "As the extension, so the force." However, this solution was not published until 1678.
Hooke's equation also applies to many other situations where some elastic body is being deformed, and the ball-spring model is often used as the basis for many contact interactions.
Problem Set
A few sample problems and their solutions.
Question 1
QUESTION:
What is the force required to stretch a spring whose constant value is 100 N/m by an amount of 0.50 m?
SOLUTION:
Using the formula F=ks solve the question
F=force(N)
k=force constant(N/m)
s=stretch or compression(m)
F=(100)(0.50) F=50 N
Question 2
QUESTION:
If 223 N stretches a spring 12.7 cm, how much stretch can we expect to result from a force of 534 N?
SOLUTION:
Set up a proportionality statement
223N/534N=12.7cm/x
Solve
x=30.4cm
Question 3
QUESITON:
When the weight hung on a spring is increased by 60 N, the new stretch is 15 cm more. If the original stretch is 5 cm, what is the original weight?
SOLUTION:
Click Here
See also
Robert Hooke
Spring Potential Energy
Tension
Young's Modulus
Further reading
Encyclopedia Brittanica: Hooke's Law
External links
Doodle Science provides a brief run through of Hooke's Law.
An alternate explanation of Hooke's Law with a sample problem set.
References
[1]
[2]
[3]
Invention by Design: How Engineers Get from Thought to Thing. Cambridge, MA: Harvard University Press