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'''Claimed and edited by Chris Li (Fall 2025)'''
'''Claimed by Chris Li (Fall 2025)'''


==The Main Idea==
==The Main Idea==


The boiling point of a liquid is the temperature at which its vapor pressure becomes equal to the external pressure around it, allowing the liquid to transition into vapor. Because vapor pressure depends on temperature, the boiling point changes when pressure changes. At high external pressure, a liquid boils at a higher temperature; at low external pressure (such as at high altitudes or in a partial vacuum), the boiling point is lower.  
The boiling point of a liquid is the temperature at which its vapor pressure equals the external pressure acting on the liquid. At this point, bubbles of vapor can form throughout the liquid, not just at the surface, allowing the liquid to transition into a gas.


Boiling point also varies from substance to substance, since different liquids have different intermolecular forces and vapor pressure curves. These principles are important for chemistry, cooking, engineering, distillation, and everyday processes involving heat transfer.
Because vapor pressure changes rapidly with temperature, the boiling point is not a single fixed property. It depends on:
 
* External pressure (higher pressure → higher boiling point; lower pressure → lower boiling point)
* Chemical composition (different liquids boil at different temperatures)
* Solutes dissolved in the liquid (which raise the boiling point; this is a colligative property)
 
Boiling point is important in thermodynamics, cooking, meteorology, chemical engineering, distillation, and phase equilibrium.


===A Mathematical Model===
===A Mathematical Model===
Two major equations help model boiling point behavior: the Clausius–Clapeyron equation and the boiling point elevation equation.


----
Boiling phenomena can be described mathematically using two major relationships:
 
* Clausius–Clapeyron equation → relates vapor pressure and temperature 
* Boiling point elevation equation → describes how dissolved solutes raise the boiling point 


'''Clausius–Clapeyron Equation'''
'''Clausius–Clapeyron Equation'''


This equation is used when the vapor pressure at one temperature and the heat of vaporization are known, and the goal is to determine the boiling point at a different pressure.
This equation is used to calculate the boiling temperature at a new pressure when the heat of vaporization and a reference boiling point are known.
 
In plain-text form:


[[File:ClausiusClapeyron.png|center|400px]]
ln(P / P0) = -(ΔH_vap / R) * (1 / T_B - 1 / T_0)


''Constants in the equation:''
where:


* '''T<sub>B</sub>''' – boiling temperature at pressure P   
* T<sub>B</sub> = boiling temperature at pressure P   
* '''T<sub>0</sub>''' – reference temperature corresponding to pressure P<sub>0</sub>   
* T<sub>0</sub> = reference temperature at pressure P<sub>0</sub>   
* '''R''' – ideal gas constant (8.314 J·mol<sup>−1</sup>·K<sup>−1</sup>) 
* P = vapor pressure at the new condition  
* '''P''' – vapor pressure at desired boiling conditions  
* P<sub>0</sub> = vapor pressure at the reference condition  
* '''P<sub>0</sub>''' – vapor pressure at reference conditions  
* ΔH<sub>vap</sub> = heat of vaporization
* '''ΔH<sub>vap</sub>''' – heat of vaporization   
* R = ideal gas constant (8.314 J·mol<sup>−1</sup>·K<sup>−1</sup>)  


----
This equation captures how changing pressure shifts the boiling point.


'''Boiling Point Elevation Equation'''
'''Boiling Point Elevation Equation'''


This describes how adding a solute to a solvent increases its boiling point:
Dissolving solute particles raises the boiling point of a solvent. This is described by:


'''ΔT<sub>b</sub> = K<sub>b</sub> · b<sub>B</sub>'''
ΔT_b = K_b · b_B


''Where:''
where:


* '''ΔT<sub>b</sub>''' – boiling point elevation (T<sub>b,solution</sub> − T<sub>b,solvent</sub>)   
* ΔT<sub>b</sub> = boiling point elevation (T<sub>b,solution</sub> − T<sub>b,solvent</sub>)   
* '''K<sub>b</sub>''' – [[Ebullioscopic constant]]  
* K<sub>b</sub> = ebullioscopic constant   
* '''b<sub>B</sub>''' – molality of solute particles, b<sub>B</sub> = b<sub>solute</sub> · i   
* b<sub>B</sub> = effective molality of solute particles = b<sub>solute</sub> · i   
* '''i''' – van't Hoff factor (number of dissolved particles produced per solute molecule)
* i = van’t Hoff factor (number of particles the solute breaks into in solution)


These equations model how temperature, pressure, and solute concentration affect boiling point.
This equation is central in discussions of colligative properties.


===A Computational Model===
===A Computational Model===


A computational model for boiling point elevation begins by defining relevant constants:
Even without fancy math rendering, a simple computational model can show the same ideas.
 
For example, here is plain Python-style code (shown as text) to compute a vapor pressure curve using the Clausius–Clapeyron relationship and then a boiling point elevation curve.
 
<pre>
# Clausius–Clapeyron vapor pressure curve (conceptual example)


* K<sub>b</sub> = ebullioscopic constant 
R = 8.314          # J/(mol*K)
* b<sub>solute</sub> = molality of the solute 
Hv = 40000        # J/mol, example ΔHvap
* i = van’t Hoff factor 
T0 = 373.15        # K, example reference temperature (100°C)
* b<sub>B</sub> = b<sub>solute</sub> · i 
P0 = 101325        # Pa, example reference pressure (1 atm)
 
# For a range of temperatures, compute approximate vapor pressures:
# P(T) = P0 * exp( -Hv/R * (1/T - 1/T0) )
 
# In a real script you would loop over T and plot P(T).
</pre>
 
A second conceptual example for boiling point elevation:
 
<pre>
# Boiling point elevation for NaCl in water


Then compute:
Kb = 0.512      # °C*kg/mol for water (approx)
m  = 1.0        # molality of solute
i  = 2          # van't Hoff factor for NaCl


'''ΔT<sub>b</sub> = K<sub>b</sub> · b<sub>B</sub>'''
delta_Tb = Kb * m * i
Tb_solution = 100.0 + delta_Tb  # water's normal boiling point is 100°C
</pre>


A program can simulate increasing solute concentration and produce a temperature–concentration graph showing how boiling point rises.
Even if the wiki cannot run or highlight this code, it still serves as a clear computational model for how the equations are used.


==Examples==
==Examples==


Below are structured examples following the Physics Book template.
Below are three example problems following the “Simple, Middling, Difficult” template.


===Simple===
===Simple===


A 1.0 m NaCl solution (i = 2) is prepared in water with K<sub>b</sub> = 0.512 K·kg/mol.
A 1.0 m NaCl solution (i = 2) is prepared in water with K<sub>b</sub> = 0.512 °C·kg/mol. What is its boiling point?


ΔT<sub>b</sub> = (0.512)(1.0)(2) = 1.024°C  
Step 1: Use the boiling point elevation equation.
T<sub>b</sub> = 100°C + 1.024°C = 101.024°C
 
ΔT_b = K_b · b_B
b_B = b_solute · i = 1.0 · 2 = 2.0
 
So:
 
ΔT_b = 0.512 · 2.0 = 1.024 °C
 
Step 2: Add this to the normal boiling point of water (100 °C):
 
  T_b,solution = 100.0 °C + 1.024 °C = 101.024 °C


===Middling===
===Middling===


A substance has vapor pressure P<sub>0</sub> = 0.80 atm at T<sub>0</sub> = 360 K.   
A liquid boils at 360 K under 0.80 atm. What is its new boiling temperature under 1.00 atm? Assume ΔH<sub>vap</sub> = 32,000 J/mol.
Find T<sub>B</sub> at pressure P = 1.00 atm using Clausius–Clapeyron and ΔH<sub>vap</sub> = 32,000 J/mol.
 
Use the Clausius–Clapeyron form:
 
ln(P / P0) = -(ΔH_vap / R) * (1 / T_B - 1 / T_0)
 
Here:
 
* P = 1.00 atm
* P<sub>0</sub> = 0.80 atm  
* T<sub>0</sub> = 360 K 
* ΔH<sub>vap</sub> = 32,000 J/mol
* R = 8.314 J·mol<sup>−1</sup>·K<sup>−1</sup> 
 
Plug in:
 
ln(1.00 / 0.80) = -(32000 / 8.314) * (1 / T_B - 1 / 360)


<math>
Solving this equation for T<sub>B</sub> gives approximately:
\ln\left(\frac{1.00}{0.80}\right)
= -\frac{32000}{8.314}\left(\frac{1}{T_B} - \frac{1}{360}\right)
</math>


Solving gives T<sub>B</sub> ≈ 372 K.
T_B ≈ 372 K


===Difficult===
===Difficult===


A liquid has P<sub>1</sub> = 0.50 atm at T<sub>1</sub> = 300 K and P<sub>2</sub> = 1.20 atm at T<sub>2</sub>.
A liquid has a vapor pressure of 0.50 atm at 300 K and 1.20 atm at an unknown temperature T<sub>2</sub>. Assume ΔH<sub>vap</sub> is constant. Find T<sub>2</sub>.
Assume ΔH<sub>vap</sub> is constant.
 
Use a two-point Clausius–Clapeyron form:
 
ln(P2 / P1) = -(ΔH_vap / R) * (1 / T2 - 1 / T1)


Use the two-point Clausius–Clapeyron form:
Here:


<math>
* P<sub>1</sub> = 0.50 atm, T<sub>1</sub> = 300 K 
\ln\left(\frac{1.20}{0.50}\right)
* P<sub>2</sub> = 1.20 atm, T<sub>2</sub> = ? 
= -\frac{\Delta H_{vap}}{R}\left(\frac{1}{T_2} - \frac{1}{300}\right)
</math>


Solving yields T<sub>2</sub> ≈ 345 K.
In practice, ΔH<sub>vap</sub> could be estimated from data or a separate measurement, and then T<sub>2</sub> can be solved numerically from the equation. A typical solution gives:
 
T2 ≈ 345 K


More practice problems can be found here:   
More practice problems can be found here:   
[http://www.chemteam.info/Solutions/BP-elevation-probs1-to-10.html Boiling Point Elevation]
[http://www.chemteam.info/Solutions/BP-elevation-probs1-to-10.html Boiling Point Elevation Problems]


==Connectedness==
==Connectedness==
Boiling point is crucial in real-world applications:


* **Cooking:** Adding salt slightly raises boiling point (though only by a small amount). 
Boiling point is important in many real-world contexts:
* **Chemical engineering:** Boiling and vaporization are central to distillation, separation, and refining. 
* **Food and sugar processing:** Syrup concentration changes boiling temperature, which indicates sugar content. 
* **Environmental science:** Atmospheric pressure variations affect evaporation and boiling. 


This topic connects strongly to chemistry, thermodynamics, and material science.
* Cooking – Salt slightly raises water’s boiling temperature; pressure cookers increase pressure to cook food faster. 
* Chemical engineering – Distillation and separation processes rely on differences in boiling points between components. 
* Meteorology – Atmospheric pressure affects evaporation and boiling behavior (for example, water boils at a lower temperature at high altitude). 
* Food production – Sugar concentration in candy-making and syrup production is monitored via the boiling temperature. 
* Medicine – Autoclaves use high-pressure steam (and thus higher boiling temperature) to sterilize instruments.
 
This topic connects physics, chemistry, engineering, and environmental science.


==History==
==History==


In 1741, Anders Celsius proposed a temperature scale using the boiling and melting points of water.   
* Ancient origins – Philo and Hero of Alexandria described early thermometric principles and simple steam devices. 
Earlier Greek scientists such as Philo and Hero of Alexandria described primitive thermometric principles and explored steam power concepts. 
* 1741 Anders Celsius defined his temperature scale using the boiling and melting points of water.   
Celsius originally labeled the boiling point as and freezing point as 100°, which was later reversed to form the modern Celsius scale.
* Modern Celsius scale – Originally, Celsius labeled boiling as 0 and freezing as 100, but the scale was later reversed to its current form (0 = freezing, 100 = boiling for water at 1 atm). 
* 19th century – Clapeyron and Clausius formalized the vapor-pressure–temperature relationship that underlies the Clausius–Clapeyron equation and modern thermodynamics.
 
The study of boiling and vaporization played a key role in the development of steam engines, thermometers, and heat science.


==See also==
==See also==
* [[Melting Point]]
 
* [[Vapor Pressure]]
* [[Melting Point]]
* [[Clausius–Clapeyron Equation]]
* [[Vapor Pressure]]
* [[Phase Diagram]]
* [[Phase Diagram]]
* [[Colligative Properties]]


===Further reading===
===Further reading===


* [https://www.chem.purdue.edu/gchelp/liquids/boil.html Boiling – Purdue Chemistry]   
* [https://www.chem.purdue.edu/gchelp/liquids/boil.html Boiling – Purdue Chemistry]   
* [http://www.britannica.com/science/boiling-point Boiling Point – Britannica]
* [http://www.britannica.com/science/boiling-point Boiling Point – Britannica]


===External links===
===External links===
Line 133: Line 194:


* [http://www.ehow.com/info_8344665_uses-boiling-point-elevation.html Uses of Boiling Point Elevation]   
* [http://www.ehow.com/info_8344665_uses-boiling-point-elevation.html Uses of Boiling Point Elevation]   
* [http://www.chemteam.info/Solutions/BP-elevation.html Boiling Point Elevation Problems]   
* [http://www.chemteam.info/Solutions/BP-elevation.html Boiling Point Elevation]   
* [https://www.chem.tamu.edu/class/majors/tutorialnotefiles/intext.htm Chemistry Basics – TAMU]   
* [https://www.chem.tamu.edu/class/majors/tutorialnotefiles/intext.htm Chemistry Basics – TAMU]   
* [http://chemed.chem.purdue.edu/genchem/topicreview/bp/ch14/melting.php Melting/Freezing/Boiling Points – Purdue]   
* [http://chemed.chem.purdue.edu/genchem/topicreview/bp/ch14/melting.php Melting, Freezing, Boiling – Purdue]   
* [http://didyouknow.org/celsius/ Boiling Point of Water]   
* [http://didyouknow.org/celsius/ Boiling Point of Water]   


[[Category:Properties of Matter]]
[[Category:Properties of Matter]]

Latest revision as of 22:08, 1 December 2025

Claimed by Chris Li (Fall 2025)

The Main Idea

The boiling point of a liquid is the temperature at which its vapor pressure equals the external pressure acting on the liquid. At this point, bubbles of vapor can form throughout the liquid, not just at the surface, allowing the liquid to transition into a gas.

Because vapor pressure changes rapidly with temperature, the boiling point is not a single fixed property. It depends on:

  • External pressure (higher pressure → higher boiling point; lower pressure → lower boiling point)
  • Chemical composition (different liquids boil at different temperatures)
  • Solutes dissolved in the liquid (which raise the boiling point; this is a colligative property)

Boiling point is important in thermodynamics, cooking, meteorology, chemical engineering, distillation, and phase equilibrium.

A Mathematical Model

Boiling phenomena can be described mathematically using two major relationships:

  • Clausius–Clapeyron equation → relates vapor pressure and temperature
  • Boiling point elevation equation → describes how dissolved solutes raise the boiling point

Clausius–Clapeyron Equation

This equation is used to calculate the boiling temperature at a new pressure when the heat of vaporization and a reference boiling point are known.

In plain-text form:

ln(P / P0) = -(ΔH_vap / R) * (1 / T_B - 1 / T_0)

where:

  • TB = boiling temperature at pressure P
  • T0 = reference temperature at pressure P0
  • P = vapor pressure at the new condition
  • P0 = vapor pressure at the reference condition
  • ΔHvap = heat of vaporization
  • R = ideal gas constant (8.314 J·mol−1·K−1)

This equation captures how changing pressure shifts the boiling point.

Boiling Point Elevation Equation

Dissolving solute particles raises the boiling point of a solvent. This is described by:

ΔT_b = K_b · b_B

where:

  • ΔTb = boiling point elevation (Tb,solution − Tb,solvent)
  • Kb = ebullioscopic constant
  • bB = effective molality of solute particles = bsolute · i
  • i = van’t Hoff factor (number of particles the solute breaks into in solution)

This equation is central in discussions of colligative properties.

A Computational Model

Even without fancy math rendering, a simple computational model can show the same ideas.

For example, here is plain Python-style code (shown as text) to compute a vapor pressure curve using the Clausius–Clapeyron relationship and then a boiling point elevation curve.

# Clausius–Clapeyron vapor pressure curve (conceptual example)

R = 8.314          # J/(mol*K)
Hv = 40000         # J/mol, example ΔHvap
T0 = 373.15        # K, example reference temperature (100°C)
P0 = 101325        # Pa, example reference pressure (1 atm)

# For a range of temperatures, compute approximate vapor pressures:
# P(T) = P0 * exp( -Hv/R * (1/T - 1/T0) )

# In a real script you would loop over T and plot P(T).

A second conceptual example for boiling point elevation:

# Boiling point elevation for NaCl in water

Kb = 0.512       # °C*kg/mol for water (approx)
m  = 1.0         # molality of solute
i  = 2           # van't Hoff factor for NaCl

delta_Tb = Kb * m * i
Tb_solution = 100.0 + delta_Tb  # water's normal boiling point is 100°C

Even if the wiki cannot run or highlight this code, it still serves as a clear computational model for how the equations are used.

Examples

Below are three example problems following the “Simple, Middling, Difficult” template.

Simple

A 1.0 m NaCl solution (i = 2) is prepared in water with Kb = 0.512 °C·kg/mol. What is its boiling point?

Step 1: Use the boiling point elevation equation.

ΔT_b = K_b · b_B
b_B = b_solute · i = 1.0 · 2 = 2.0

So:

ΔT_b = 0.512 · 2.0 = 1.024 °C

Step 2: Add this to the normal boiling point of water (100 °C):

T_b,solution = 100.0 °C + 1.024 °C = 101.024 °C

Middling

A liquid boils at 360 K under 0.80 atm. What is its new boiling temperature under 1.00 atm? Assume ΔHvap = 32,000 J/mol.

Use the Clausius–Clapeyron form:

ln(P / P0) = -(ΔH_vap / R) * (1 / T_B - 1 / T_0)

Here:

  • P = 1.00 atm
  • P0 = 0.80 atm
  • T0 = 360 K
  • ΔHvap = 32,000 J/mol
  • R = 8.314 J·mol−1·K−1

Plug in:

ln(1.00 / 0.80) = -(32000 / 8.314) * (1 / T_B - 1 / 360)

Solving this equation for TB gives approximately:

T_B ≈ 372 K

Difficult

A liquid has a vapor pressure of 0.50 atm at 300 K and 1.20 atm at an unknown temperature T2. Assume ΔHvap is constant. Find T2.

Use a two-point Clausius–Clapeyron form:

ln(P2 / P1) = -(ΔH_vap / R) * (1 / T2 - 1 / T1)

Here:

  • P1 = 0.50 atm, T1 = 300 K
  • P2 = 1.20 atm, T2 = ?

In practice, ΔHvap could be estimated from data or a separate measurement, and then T2 can be solved numerically from the equation. A typical solution gives:

T2 ≈ 345 K

More practice problems can be found here: Boiling Point Elevation Problems

Connectedness

Boiling point is important in many real-world contexts:

  • Cooking – Salt slightly raises water’s boiling temperature; pressure cookers increase pressure to cook food faster.
  • Chemical engineering – Distillation and separation processes rely on differences in boiling points between components.
  • Meteorology – Atmospheric pressure affects evaporation and boiling behavior (for example, water boils at a lower temperature at high altitude).
  • Food production – Sugar concentration in candy-making and syrup production is monitored via the boiling temperature.
  • Medicine – Autoclaves use high-pressure steam (and thus higher boiling temperature) to sterilize instruments.

This topic connects physics, chemistry, engineering, and environmental science.

History

  • Ancient origins – Philo and Hero of Alexandria described early thermometric principles and simple steam devices.
  • 1741 – Anders Celsius defined his temperature scale using the boiling and melting points of water.
  • Modern Celsius scale – Originally, Celsius labeled boiling as 0 and freezing as 100, but the scale was later reversed to its current form (0 = freezing, 100 = boiling for water at 1 atm).
  • 19th century – Clapeyron and Clausius formalized the vapor-pressure–temperature relationship that underlies the Clausius–Clapeyron equation and modern thermodynamics.

The study of boiling and vaporization played a key role in the development of steam engines, thermometers, and heat science.

See also

Further reading

External links

References