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Claimed by Deepthi Munagapati, Fall 2025 | |||
This topic covers density. | |||
==The Main Idea== | == The Main Idea == | ||
Density | Density describes how much mass is contained in a given volume. It is a measure of how “packed” matter is. Formally, density is usually written with the Greek letter <math>\rho</math> (rho), and in some engineering contexts you may also see the letter <math>D</math>. | ||
At a basic level: | |||
* If two objects have the same volume, the one with larger mass has the higher density. | |||
* If two objects have the same mass, the one that takes up less space has the higher density. | |||
: | Typical values at room temperature: | ||
* Water: <math>\rho \approx 1.0~\text{g/cm}^3 = 1000~\text{kg/m}^3</math> | |||
* Aluminum: <math>\rho \approx 2.70~\text{g/cm}^3</math> | |||
* Copper: <math>\rho \approx 8.94~\text{g/cm}^3</math> | |||
* Ice: <math>\rho \approx 0.92~\text{g/cm}^3</math> | |||
* Air: <math>\rho \approx 0.0012~\text{g/cm}^3</math> | |||
These differences in density explain everyday phenomena like floating and sinking, as well as engineering choices such as why airplanes are not built out of very dense metals. | |||
== A Mathematical Model == | |||
For a uniform material, density is defined as mass divided by volume: | |||
= | :<math>\rho = \frac{m}{V}</math> | ||
where | |||
* <math>\rho</math> is the density, | |||
* <math>m</math> is the mass, | |||
* <math>V</math> is the volume. | |||
You can rearrange this expression depending on what quantity you want: | |||
<math> \rho | * To find mass from density and volume: | ||
::<math>m = \rho V</math> | |||
* To find volume from mass and density: | |||
::<math>V = \dfrac{m}{\rho}</math> | |||
Common unit combinations: | |||
<math> \ | * SI units: <math>\text{kg/m}^3</math> | ||
* Chemistry and materials: <math>\text{g/cm}^3</math> or <math>\text{g/mL}</math> | |||
It is essential to keep units consistent. For example: | |||
* <math>1~\text{g/cm}^3 = 1000~\text{kg/m}^3</math> | |||
* <math>1~\text{mL} = 1~\text{cm}^3</math> | |||
=== | === Average vs Local Density === | ||
For extended objects that may not be uniform, you can define: | |||
<math> | * **Average density**: | ||
::<math>\rho_{\text{avg}} = \dfrac{\text{total mass}}{\text{total volume}}.</math> | |||
* **Local (or point) density**: for a nonuniform material the density can vary from point to point. In that case, density is defined in terms of differentials: | |||
<math> | ::<math>\rho = \frac{\mathrm{d}m}{\mathrm{d}V}</math> | ||
The total mass of a nonuniform object is then | |||
= | :<math>m = \int_V \rho(\vec{r})\,\mathrm{d}V,</math> | ||
where the integral is taken over the entire volume of the object and <math>\rho(\vec{r})</math> can depend on position. | |||
Later in physics this same idea is used for charge density and current density in electricity and magnetism. | |||
=== Density, Weight, and Specific Weight === | |||
Density uses **mass**, not weight. Weight is a force: | |||
* Mass is measured in kilograms. | |||
* Weight is measured in newtons and is given by <math>W = mg</math>. | |||
Sometimes in industry people informally talk about “weight per unit volume”. The correct term for that quantity is **specific weight**, which equals <math>\rho g</math>. | |||
== A Computational Model == | |||
In many physics and engineering problems you need to compute mass, volume, or density repeatedly, often for many objects or for small pieces of a larger system. This is where a computational model is useful. | |||
A basic computational idea: | |||
* Store density <math>\rho</math> and volume <math>V</math> for each object. | |||
* Compute mass with a simple relation: | |||
::<math>m = \rho V</math> | |||
For a continuously varying density <math>\rho(x)</math> along a one dimensional rod of length <math>L</math>: | |||
* Divide the rod into many small pieces of width <math>\Delta x</math>. | |||
* Approximate the mass of each piece as: | |||
::<math>\Delta m_i \approx \rho(x_i) A \Delta x</math> | |||
where <math>A</math> is the cross sectional area. | |||
* Sum over all the pieces: | |||
::<math>m \approx \sum_i \rho(x_i) A \Delta x</math> | |||
This numerical sum approximates the exact integral | |||
:<math>m = \int_0^L \rho(x) A\,\mathrm{d}x.</math> | |||
This same approach is used in GlowScript or VPython simulations where you might represent an object as many small elements and calculate total mass, center of mass, or gravitational forces by summing over these elements. | |||
== Examples == | |||
=== Simple === | |||
What is the mass of isopropyl alcohol that exactly fills a <math>200.0~\text{mL}</math> container? The density of isopropyl alcohol is <math>0.786~\text{g/mL}</math>. | |||
Start from | |||
:<math>\rho = \dfrac{m}{V} \quad \Rightarrow \quad m = \rho V.</math> | |||
Substitute: | |||
:<math>m = \left(0.786~\dfrac{\text{g}}{\text{mL}}\right) \left(200.0~\text{mL}\right) = 157.2~\text{g}.</math> | |||
So the alcohol has a mass of <math>1.572 \times 10^2~\text{g}</math>. | |||
=== Middling === | |||
A copper ingot has a mass of <math>2.15~\text{kg}</math>. If the copper is drawn into a wire whose diameter is <math>2.27~\text{mm}</math>, how many inches of copper wire can be obtained? The density of copper is <math>8.94~\text{g/cm}^3</math>. Treat the wire as a cylinder. | |||
Step (a): Find the volume of copper. | |||
Convert the mass to grams: | |||
:<math>m = 2.15~\text{kg} = 2150~\text{g}.</math> | |||
Use <math>\rho = m/V</math>: | |||
:<math>8.94~\dfrac{\text{g}}{\text{cm}^3} = \dfrac{2150~\text{g}}{V}</math> | |||
So | |||
:<math>V = \dfrac{2150~\text{g}}{8.94~\text{g/cm}^3} \approx 240.5~\text{cm}^3.</math> | |||
Step (b): Relate this volume to the volume of a cylinder. | |||
The diameter is <math>2.27~\text{mm} = 0.227~\text{cm}</math>, so the radius is <math>r = 0.1135~\text{cm}</math>. | |||
Volume of a cylinder: | |||
:<math>V = \pi r^2 h \quad \Rightarrow \quad h = \dfrac{V}{\pi r^2}.</math> | |||
Substitute: | |||
:<math>h = \dfrac{240.5~\text{cm}^3}{\pi (0.1135~\text{cm})^2} \approx 5.94 \times 10^3~\text{cm}.</math> | |||
Step (c): Convert to inches. | |||
Use <math>1~\text{in} = 2.54~\text{cm}</math>: | |||
:<math>h = \dfrac{5.94 \times 10^3~\text{cm}}{2.54~\text{cm/in}} \approx 2.34 \times 10^3~\text{in}.</math> | |||
So you can draw about <math>2.3 \times 10^3</math> inches of wire. | |||
=== Difficult === | === Difficult === | ||
Copper can be drawn into thin wires. How many meters of 34 | Copper can be drawn into thin wires. How many meters of 34 gauge wire (diameter <math>6.304 \times 10^{-3}~\text{in}</math>) can be produced from the copper that is in <math>5.88~\text{lb}</math> of covellite, an ore of copper that is <math>66\%</math> copper by mass? Treat the wire as a cylinder. The density of copper is <math>8.94~\text{g/cm}^3</math>. One kilogram weighs <math>2.2046~\text{lb}</math>. The volume of a cylinder is <math>V_{\text{cyl}} = \pi r^2 h</math>. | ||
Step (a): Find pounds of pure copper. | |||
:<math>m_{\text{Cu, lb}} = 0.66 \times 5.88~\text{lb} = 3.8808~\text{lb}.</math> | |||
Step (b): Convert to kilograms and grams. | |||
:<math>m_{\text{Cu}} = \dfrac{3.8808~\text{lb}}{2.2046~\text{lb/kg}} \approx 1.760~\text{kg} \approx 1.76 \times 10^3~\text{g}.</math> | |||
(You can keep extra digits in intermediate steps if you like.) | |||
Step (c): Use density to find the volume of copper. | |||
:<math>V = \dfrac{m}{\rho} = \dfrac{1.76 \times 10^3~\text{g}}{8.94~\text{g/cm}^3} \approx 197~\text{cm}^3.</math> | |||
Step (d): Convert the wire diameter to radius in centimeters. | |||
Diameter: <math>d = 6.304 \times 10^{-3}~\text{in}</math>. | |||
Radius: | |||
:<math>r = \frac{d}{2} = 3.152 \times 10^{-3}~\text{in}.</math> | |||
Convert to centimeters: | |||
:<math>r = (3.152 \times 10^{-3}~\text{in})(2.54~\text{cm/in}) \approx 8.00 \times 10^{-3}~\text{cm}.</math> | |||
Step (e): Use the cylinder volume to find the length. | |||
:<math>V = \pi r^2 h \quad \Rightarrow \quad h = \dfrac{V}{\pi r^2}.</math> | |||
Substitute: | |||
:<math>h = \dfrac{197~\text{cm}^3}{\pi (8.00 \times 10^{-3}~\text{cm})^2} \approx 9.80 \times 10^5~\text{cm}.</math> | |||
Convert centimeters to meters: | |||
:<math>h = 9.80 \times 10^5~\text{cm} \times \dfrac{1~\text{m}}{100~\text{cm}} \approx 9.80 \times 10^3~\text{m}.</math> | |||
So you can draw on the order of <math>10^4~\text{m}</math> of thin copper wire. | |||
== Common Mistakes == | |||
* **Mixing mass and weight** | |||
Density uses mass, not weight. If you plug weight (in newtons) into the density formula, your units will be wrong. | |||
* **Ignoring unit conversions** | |||
Be very careful with units when moving between <math>\text{g/cm}^3</math>, <math>\text{kg/m}^3</math>, and milliliters. Convert everything into one consistent system before computing. | |||
* **Using the wrong volume** | |||
For wires, rods, and spheres, you need the volume of the shape, not just its length or radius. Always write the appropriate geometric formula first. | |||
* **Assuming density never changes** | |||
For many materials density changes with temperature and phase. For example, liquid water and ice have different densities. | |||
== Connectedness == | |||
=== Importance of Density === | |||
Density is a fundamental property of matter. It connects microscopic structure to macroscopic behavior: | |||
* It helps determine whether objects float or sink in fluids. | |||
* It is used to estimate mass when you can measure volume more easily. | |||
* It appears in models of planets, stars, and galaxies where mass distribution matters. | |||
Density is also frequently used when analyzing charge and mass distributions. In electricity and magnetism, charge density plays the same role that mass density plays in mechanics: | |||
* Charge density influences electric fields and potentials. | |||
* Mass density influences gravitational fields and motion under gravity. | |||
=== How Density Changes === | |||
Density can increase in either of two ways: | |||
* Increasing mass while keeping volume fixed (for example, adding more material into the same container). | |||
* Decreasing volume while keeping mass fixed (for example, compressing a gas or squeezing foam). | |||
It can decrease by: | |||
* Removing mass from a fixed volume. | |||
* Allowing a compressed object to expand. | |||
For example: | |||
: | |||
* A bowling ball and a volleyball can have similar volumes, but the bowling ball has much greater mass, so its density is larger. | |||
* If you compress a piece of foam into a smaller volume without losing material, its density increases. | |||
=== | === Helium Balloons === | ||
Helium balloons float because the gas inside them is less dense than the surrounding air. According to Archimedes’ principle: | |||
* The buoyant force on a balloon equals the weight of the displaced air. | |||
* If the weight of the helium plus the balloon is less than the weight of the displaced air, the net force points upward. | |||
Weather balloons and blimps use the same idea, just at different scales and with different gases. | |||
:* | === Ice and Icebergs === | ||
Ice has a lower density than liquid water, which is unusual compared with many substances that get denser when they freeze. For water: | |||
* The crystalline structure of ice creates more empty space. | |||
* As a result, ice floats in liquid water. | |||
Icebergs are made of frozen freshwater that is less dense than the cold, salty seawater that surrounds them. Because of this: | |||
* Only a small fraction of an iceberg is visible above the surface. | |||
* Most of the iceberg’s volume is below the waterline, which creates navigational hazards. | |||
=== Density and Chemical Engineers === | |||
For chemical engineers and materials scientists, density is not just a number; it connects structure to function. Some uses include: | |||
* Monitoring concentration and purity of liquid mixtures by measuring density. | |||
* Designing separation processes where density differences are used to separate phases. | |||
* Modeling material behavior using density functional theory (DFT), a quantum mechanical method used to study the electronic structure of atoms, molecules, and condensed phases. | |||
DFT and related approaches have helped expand understanding of condensed fluids, polymer solutions, liquid crystals, and colloids. Many of these are important in designing and fabricating new materials. | |||
== History == | |||
A famous historical story about density involves Archimedes (around 250 BCE). The legend says that Archimedes was asked to determine whether a crown thought to be made of pure gold had been adulterated with a less valuable metal. | |||
* He realized that if the crown had the same mass as a pure gold reference piece but displaced more water, it must have a lower density, and therefore contain another metal. | |||
* By comparing water displacement, he could test the density without melting the crown. | |||
Although the details of the story are probably simplified, the underlying method is exactly what we still use today: measure mass, measure volume (often by displacement), then compare densities. | |||
== See also == | == See also == | ||
===Videos=== | === Videos === | ||
These videos give additional intuition and worked examples on density. | |||
:* https://www.youtube.com/watch?v=UggNVz87kys | :* https://www.youtube.com/watch?v=UggNVz87kys | ||
:* https://www.youtube.com/watch?v=4tYXaCADxfE | :* https://www.youtube.com/watch?v=4tYXaCADxfE | ||
| Line 136: | Line 298: | ||
:* https://www.youtube.com/watch?v=5tVNGlG1GBc | :* https://www.youtube.com/watch?v=5tVNGlG1GBc | ||
===Further reading=== | === Further reading === | ||
NOTE: This section contains interesting articles, stories, and real life applications | |||
NOTE: This section contains interesting articles, stories, and real life applications involving density. | |||
:* http://www.propertiesofmatter.si.edu/titanic.html | :* http://www.propertiesofmatter.si.edu/titanic.html | ||
| Line 143: | Line 306: | ||
:* http://www.scienceclarified.com/everyday/Real-Life-Chemistry-Vol-3-Physics-Vol-1/Density-and-Volume-Real-life applications.html | :* http://www.scienceclarified.com/everyday/Real-Life-Chemistry-Vol-3-Physics-Vol-1/Density-and-Volume-Real-life applications.html | ||
===External links=== | === External links === | ||
:* http://www.sciencedirect.com/science/article/pii/0016706189900402 | :* http://www.sciencedirect.com/science/article/pii/0016706189900402 | ||
:* http://www.ssc.education.ed.ac.uk/BSL/chemistry/densityd.html | :* http://www.ssc.education.ed.ac.uk/BSL/chemistry/densityd.html | ||
==References== | == References == | ||
:* https://en.wikipedia.org/wiki/Density | :* https://en.wikipedia.org/wiki/Density | ||
| Line 157: | Line 321: | ||
:* http://onlinelibrary.wiley.com/doi/10.1002/aic.10713/abstract | :* http://onlinelibrary.wiley.com/doi/10.1002/aic.10713/abstract | ||
:* http://archimedespalimpsest.org/about/history/archimedes.php | :* http://archimedespalimpsest.org/about/history/archimedes.php | ||
:* Chabay & Sherwood: | :* Chabay & Sherwood: ''Matter and Interactions – Modern Mechanics'', Volume 1, 4th Edition | ||
[[Category:Properties of Matter]] | [[Category:Properties of Matter]] | ||
Latest revision as of 13:54, 2 December 2025
Claimed by Deepthi Munagapati, Fall 2025
This topic covers density.
The Main Idea
Density describes how much mass is contained in a given volume. It is a measure of how “packed” matter is. Formally, density is usually written with the Greek letter [math]\displaystyle{ \rho }[/math] (rho), and in some engineering contexts you may also see the letter [math]\displaystyle{ D }[/math].
At a basic level:
- If two objects have the same volume, the one with larger mass has the higher density.
- If two objects have the same mass, the one that takes up less space has the higher density.
Typical values at room temperature:
- Water: [math]\displaystyle{ \rho \approx 1.0~\text{g/cm}^3 = 1000~\text{kg/m}^3 }[/math]
- Aluminum: [math]\displaystyle{ \rho \approx 2.70~\text{g/cm}^3 }[/math]
- Copper: [math]\displaystyle{ \rho \approx 8.94~\text{g/cm}^3 }[/math]
- Ice: [math]\displaystyle{ \rho \approx 0.92~\text{g/cm}^3 }[/math]
- Air: [math]\displaystyle{ \rho \approx 0.0012~\text{g/cm}^3 }[/math]
These differences in density explain everyday phenomena like floating and sinking, as well as engineering choices such as why airplanes are not built out of very dense metals.
A Mathematical Model
For a uniform material, density is defined as mass divided by volume:
- [math]\displaystyle{ \rho = \frac{m}{V} }[/math]
where
- [math]\displaystyle{ \rho }[/math] is the density,
- [math]\displaystyle{ m }[/math] is the mass,
- [math]\displaystyle{ V }[/math] is the volume.
You can rearrange this expression depending on what quantity you want:
- To find mass from density and volume:
- [math]\displaystyle{ m = \rho V }[/math]
- To find volume from mass and density:
- [math]\displaystyle{ V = \dfrac{m}{\rho} }[/math]
Common unit combinations:
- SI units: [math]\displaystyle{ \text{kg/m}^3 }[/math]
- Chemistry and materials: [math]\displaystyle{ \text{g/cm}^3 }[/math] or [math]\displaystyle{ \text{g/mL} }[/math]
It is essential to keep units consistent. For example:
- [math]\displaystyle{ 1~\text{g/cm}^3 = 1000~\text{kg/m}^3 }[/math]
- [math]\displaystyle{ 1~\text{mL} = 1~\text{cm}^3 }[/math]
Average vs Local Density
For extended objects that may not be uniform, you can define:
- **Average density**:
- [math]\displaystyle{ \rho_{\text{avg}} = \dfrac{\text{total mass}}{\text{total volume}}. }[/math]
- **Local (or point) density**: for a nonuniform material the density can vary from point to point. In that case, density is defined in terms of differentials:
- [math]\displaystyle{ \rho = \frac{\mathrm{d}m}{\mathrm{d}V} }[/math]
The total mass of a nonuniform object is then
- [math]\displaystyle{ m = \int_V \rho(\vec{r})\,\mathrm{d}V, }[/math]
where the integral is taken over the entire volume of the object and [math]\displaystyle{ \rho(\vec{r}) }[/math] can depend on position.
Later in physics this same idea is used for charge density and current density in electricity and magnetism.
Density, Weight, and Specific Weight
Density uses **mass**, not weight. Weight is a force:
- Mass is measured in kilograms.
- Weight is measured in newtons and is given by [math]\displaystyle{ W = mg }[/math].
Sometimes in industry people informally talk about “weight per unit volume”. The correct term for that quantity is **specific weight**, which equals [math]\displaystyle{ \rho g }[/math].
A Computational Model
In many physics and engineering problems you need to compute mass, volume, or density repeatedly, often for many objects or for small pieces of a larger system. This is where a computational model is useful.
A basic computational idea:
- Store density [math]\displaystyle{ \rho }[/math] and volume [math]\displaystyle{ V }[/math] for each object.
- Compute mass with a simple relation:
- [math]\displaystyle{ m = \rho V }[/math]
For a continuously varying density [math]\displaystyle{ \rho(x) }[/math] along a one dimensional rod of length [math]\displaystyle{ L }[/math]:
- Divide the rod into many small pieces of width [math]\displaystyle{ \Delta x }[/math].
- Approximate the mass of each piece as:
- [math]\displaystyle{ \Delta m_i \approx \rho(x_i) A \Delta x }[/math]
where [math]\displaystyle{ A }[/math] is the cross sectional area.
- Sum over all the pieces:
- [math]\displaystyle{ m \approx \sum_i \rho(x_i) A \Delta x }[/math]
This numerical sum approximates the exact integral
- [math]\displaystyle{ m = \int_0^L \rho(x) A\,\mathrm{d}x. }[/math]
This same approach is used in GlowScript or VPython simulations where you might represent an object as many small elements and calculate total mass, center of mass, or gravitational forces by summing over these elements.
Examples
Simple
What is the mass of isopropyl alcohol that exactly fills a [math]\displaystyle{ 200.0~\text{mL} }[/math] container? The density of isopropyl alcohol is [math]\displaystyle{ 0.786~\text{g/mL} }[/math].
Start from
- [math]\displaystyle{ \rho = \dfrac{m}{V} \quad \Rightarrow \quad m = \rho V. }[/math]
Substitute:
- [math]\displaystyle{ m = \left(0.786~\dfrac{\text{g}}{\text{mL}}\right) \left(200.0~\text{mL}\right) = 157.2~\text{g}. }[/math]
So the alcohol has a mass of [math]\displaystyle{ 1.572 \times 10^2~\text{g} }[/math].
Middling
A copper ingot has a mass of [math]\displaystyle{ 2.15~\text{kg} }[/math]. If the copper is drawn into a wire whose diameter is [math]\displaystyle{ 2.27~\text{mm} }[/math], how many inches of copper wire can be obtained? The density of copper is [math]\displaystyle{ 8.94~\text{g/cm}^3 }[/math]. Treat the wire as a cylinder.
Step (a): Find the volume of copper.
Convert the mass to grams:
- [math]\displaystyle{ m = 2.15~\text{kg} = 2150~\text{g}. }[/math]
Use [math]\displaystyle{ \rho = m/V }[/math]:
- [math]\displaystyle{ 8.94~\dfrac{\text{g}}{\text{cm}^3} = \dfrac{2150~\text{g}}{V} }[/math]
So
- [math]\displaystyle{ V = \dfrac{2150~\text{g}}{8.94~\text{g/cm}^3} \approx 240.5~\text{cm}^3. }[/math]
Step (b): Relate this volume to the volume of a cylinder.
The diameter is [math]\displaystyle{ 2.27~\text{mm} = 0.227~\text{cm} }[/math], so the radius is [math]\displaystyle{ r = 0.1135~\text{cm} }[/math].
Volume of a cylinder:
- [math]\displaystyle{ V = \pi r^2 h \quad \Rightarrow \quad h = \dfrac{V}{\pi r^2}. }[/math]
Substitute:
- [math]\displaystyle{ h = \dfrac{240.5~\text{cm}^3}{\pi (0.1135~\text{cm})^2} \approx 5.94 \times 10^3~\text{cm}. }[/math]
Step (c): Convert to inches.
Use [math]\displaystyle{ 1~\text{in} = 2.54~\text{cm} }[/math]:
- [math]\displaystyle{ h = \dfrac{5.94 \times 10^3~\text{cm}}{2.54~\text{cm/in}} \approx 2.34 \times 10^3~\text{in}. }[/math]
So you can draw about [math]\displaystyle{ 2.3 \times 10^3 }[/math] inches of wire.
Difficult
Copper can be drawn into thin wires. How many meters of 34 gauge wire (diameter [math]\displaystyle{ 6.304 \times 10^{-3}~\text{in} }[/math]) can be produced from the copper that is in [math]\displaystyle{ 5.88~\text{lb} }[/math] of covellite, an ore of copper that is [math]\displaystyle{ 66\% }[/math] copper by mass? Treat the wire as a cylinder. The density of copper is [math]\displaystyle{ 8.94~\text{g/cm}^3 }[/math]. One kilogram weighs [math]\displaystyle{ 2.2046~\text{lb} }[/math]. The volume of a cylinder is [math]\displaystyle{ V_{\text{cyl}} = \pi r^2 h }[/math].
Step (a): Find pounds of pure copper.
- [math]\displaystyle{ m_{\text{Cu, lb}} = 0.66 \times 5.88~\text{lb} = 3.8808~\text{lb}. }[/math]
Step (b): Convert to kilograms and grams.
- [math]\displaystyle{ m_{\text{Cu}} = \dfrac{3.8808~\text{lb}}{2.2046~\text{lb/kg}} \approx 1.760~\text{kg} \approx 1.76 \times 10^3~\text{g}. }[/math]
(You can keep extra digits in intermediate steps if you like.)
Step (c): Use density to find the volume of copper.
- [math]\displaystyle{ V = \dfrac{m}{\rho} = \dfrac{1.76 \times 10^3~\text{g}}{8.94~\text{g/cm}^3} \approx 197~\text{cm}^3. }[/math]
Step (d): Convert the wire diameter to radius in centimeters.
Diameter: [math]\displaystyle{ d = 6.304 \times 10^{-3}~\text{in} }[/math].
Radius:
- [math]\displaystyle{ r = \frac{d}{2} = 3.152 \times 10^{-3}~\text{in}. }[/math]
Convert to centimeters:
- [math]\displaystyle{ r = (3.152 \times 10^{-3}~\text{in})(2.54~\text{cm/in}) \approx 8.00 \times 10^{-3}~\text{cm}. }[/math]
Step (e): Use the cylinder volume to find the length.
- [math]\displaystyle{ V = \pi r^2 h \quad \Rightarrow \quad h = \dfrac{V}{\pi r^2}. }[/math]
Substitute:
- [math]\displaystyle{ h = \dfrac{197~\text{cm}^3}{\pi (8.00 \times 10^{-3}~\text{cm})^2} \approx 9.80 \times 10^5~\text{cm}. }[/math]
Convert centimeters to meters:
- [math]\displaystyle{ h = 9.80 \times 10^5~\text{cm} \times \dfrac{1~\text{m}}{100~\text{cm}} \approx 9.80 \times 10^3~\text{m}. }[/math]
So you can draw on the order of [math]\displaystyle{ 10^4~\text{m} }[/math] of thin copper wire.
Common Mistakes
- **Mixing mass and weight**
Density uses mass, not weight. If you plug weight (in newtons) into the density formula, your units will be wrong.
- **Ignoring unit conversions**
Be very careful with units when moving between [math]\displaystyle{ \text{g/cm}^3 }[/math], [math]\displaystyle{ \text{kg/m}^3 }[/math], and milliliters. Convert everything into one consistent system before computing.
- **Using the wrong volume**
For wires, rods, and spheres, you need the volume of the shape, not just its length or radius. Always write the appropriate geometric formula first.
- **Assuming density never changes**
For many materials density changes with temperature and phase. For example, liquid water and ice have different densities.
Connectedness
Importance of Density
Density is a fundamental property of matter. It connects microscopic structure to macroscopic behavior:
- It helps determine whether objects float or sink in fluids.
- It is used to estimate mass when you can measure volume more easily.
- It appears in models of planets, stars, and galaxies where mass distribution matters.
Density is also frequently used when analyzing charge and mass distributions. In electricity and magnetism, charge density plays the same role that mass density plays in mechanics:
- Charge density influences electric fields and potentials.
- Mass density influences gravitational fields and motion under gravity.
How Density Changes
Density can increase in either of two ways:
- Increasing mass while keeping volume fixed (for example, adding more material into the same container).
- Decreasing volume while keeping mass fixed (for example, compressing a gas or squeezing foam).
It can decrease by:
- Removing mass from a fixed volume.
- Allowing a compressed object to expand.
For example:
- A bowling ball and a volleyball can have similar volumes, but the bowling ball has much greater mass, so its density is larger.
- If you compress a piece of foam into a smaller volume without losing material, its density increases.
Helium Balloons
Helium balloons float because the gas inside them is less dense than the surrounding air. According to Archimedes’ principle:
- The buoyant force on a balloon equals the weight of the displaced air.
- If the weight of the helium plus the balloon is less than the weight of the displaced air, the net force points upward.
Weather balloons and blimps use the same idea, just at different scales and with different gases.
Ice and Icebergs
Ice has a lower density than liquid water, which is unusual compared with many substances that get denser when they freeze. For water:
- The crystalline structure of ice creates more empty space.
- As a result, ice floats in liquid water.
Icebergs are made of frozen freshwater that is less dense than the cold, salty seawater that surrounds them. Because of this:
- Only a small fraction of an iceberg is visible above the surface.
- Most of the iceberg’s volume is below the waterline, which creates navigational hazards.
Density and Chemical Engineers
For chemical engineers and materials scientists, density is not just a number; it connects structure to function. Some uses include:
- Monitoring concentration and purity of liquid mixtures by measuring density.
- Designing separation processes where density differences are used to separate phases.
- Modeling material behavior using density functional theory (DFT), a quantum mechanical method used to study the electronic structure of atoms, molecules, and condensed phases.
DFT and related approaches have helped expand understanding of condensed fluids, polymer solutions, liquid crystals, and colloids. Many of these are important in designing and fabricating new materials.
History
A famous historical story about density involves Archimedes (around 250 BCE). The legend says that Archimedes was asked to determine whether a crown thought to be made of pure gold had been adulterated with a less valuable metal.
- He realized that if the crown had the same mass as a pure gold reference piece but displaced more water, it must have a lower density, and therefore contain another metal.
- By comparing water displacement, he could test the density without melting the crown.
Although the details of the story are probably simplified, the underlying method is exactly what we still use today: measure mass, measure volume (often by displacement), then compare densities.
See also
Videos
These videos give additional intuition and worked examples on density.
Further reading
NOTE: This section contains interesting articles, stories, and real life applications involving density.
External links
References
- https://en.wikipedia.org/wiki/Density
- http://dl6.globalstf.org/index.php/joc/article/view/980
- http://www.chemteam.info/SigFigs/WS-Density-Probs1-10-Ans.html
- http://www.ssc.education.ed.ac.uk/BSL/pictures/density.jpg
- http://www.softschools.com/examples/science/density_examples/9/
- http://www.ehow.com/about_5484217_importance-density.html
- http://onlinelibrary.wiley.com/doi/10.1002/aic.10713/abstract
- http://archimedespalimpsest.org/about/history/archimedes.php
- Chabay & Sherwood: Matter and Interactions – Modern Mechanics, Volume 1, 4th Edition