Power - Revision history

Aeze3: /* External links */

2015-12-02T14:52:23Z

External links

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	Internet resources on this topic		Internet resources on this topic

			"General Mechanics/Work and Power." - Wikibooks, Open Books for an Open World. Web. [https://en.wikibooks.org/wiki/General_Mechanics/Work_and_Power General Mechanics/Work and Power]

	==References==		==References==

2015-12-02T14:37:28Z

A Mathematical Model

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	When a force is applied over a distance in a unit of time, power is calculated by		When a force is applied over a distance in a unit of time, power is calculated by

	[[File:power(1).jpg]]		[[File:power(1).jpg \|border\|right]]

	:<math>power = \frac{F \Delta r}{\Delta t} = \frac{W}{\Delta t}</math>		:<math>power = \frac{F \Delta r}{\Delta t} = \frac{W}{\Delta t}</math>

2015-12-02T14:36:49Z

The Main Idea

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	When a force is applied over a distance in a unit of time, power is calculated by		When a force is applied over a distance in a unit of time, power is calculated by

	[[File:power(1).jpg ~~\|border\|right~~]]		[[File:power(1).jpg]]

	:<math>power = \frac{F \Delta r}{\Delta t} = \frac{W}{\Delta t}</math>		:<math>power = \frac{F \Delta r}{\Delta t} = \frac{W}{\Delta t}</math>

2015-12-02T14:36:30Z

The Main Idea

← Older revision		Revision as of 10:36, 2 December 2015
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	When a force is applied over a distance in a unit of time, power is calculated by		When a force is applied over a distance in a unit of time, power is calculated by

			[[File:power(1).jpg \|border\|right]]

	:<math>power = \frac{F \Delta r}{\Delta t} = \frac{W}{\Delta t}</math>		:<math>power = \frac{F \Delta r}{\Delta t} = \frac{W}{\Delta t}</math>
	where '''F''' is force, '''Δr''' is displacement, '''Δt''' is the duration of time and '''W''' is work.		where '''F''' is force, '''Δr''' is displacement, '''Δt''' is the duration of time and '''W''' is work.

	~~[[File:power(1).jpg \|border\|right]]~~

	It then follows that instantaneous power is		It then follows that instantaneous power is

2015-12-02T14:36:06Z

The Main Idea

← Older revision		Revision as of 10:36, 2 December 2015
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	where '''F''' is force, '''Δr''' is displacement, '''Δt''' is the duration of time and '''W''' is work.		where '''F''' is force, '''Δr''' is displacement, '''Δt''' is the duration of time and '''W''' is work.

	[[File:~~http://www.differencebetween.info/sites/default/files/images/2/~~power(1).jpg \|border\|right]]		[[File:power(1).jpg \|border\|right]]

	It then follows that instantaneous power is		It then follows that instantaneous power is

2015-12-02T14:26:58Z

Simple

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	A certain motor is capable of doing 3000 J of work in 12 s		A certain motor is capable of doing 3000 J of work in 12 s
	What is the power output of this motor?		What is the power output of this motor?


	:<math>power = \frac{W}{\Delta t} = \frac{3000 J}{12 s} = 250 watts </math>		:<math>power = \frac{W}{\Delta t} = \frac{3000 J}{12 s} = 250 watts </math>

2015-12-02T14:26:45Z

Simple

← Older revision		Revision as of 10:26, 2 December 2015
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	A certain motor is capable of doing 3000 J of work in 12 s		A certain motor is capable of doing 3000 J of work in 12 s
	What is the power output of this motor?		What is the power output of this motor?


	:<math>power = \frac{W}{\Delta t} = \frac{3000 J}{12 s} = 250 watts </math>		:<math>power = \frac{W}{\Delta t} = \frac{3000 J}{12 s} = 250 watts </math>

2015-12-02T14:10:41Z

Middling

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	'''(b)''' <math> {\frac{97.2 J}{s}} \cdot \frac{3600 s}{1 h} \cdot \frac{24 h}{1 day} = 8398080 J/day </math>		'''(b)''' <math> {\frac{97.2 J}{s}} \cdot \frac{3600 s}{1 h} \cdot \frac{24 h}{1 day} = 8398080 J/day </math>


	:<math> \Delta U_g = mg\Delta y = (58 kg)(9.8 m/s^2)(8848 m - 0 m) = 5029203.2 J </math>		:<math> \Delta U_g = mg\Delta y = (58 kg)(9.8 m/s^2)(8848 m - 0 m) = 5029203.2 J </math>


	:<math> \Delta t = \frac{W}{power} = \frac{5029203.2 J}{8398080 J/day} = 0.599 days </math>		:<math> \Delta t = \frac{W}{power} = \frac{5029203.2 J}{8398080 J/day} = 0.599 days </math>

	===Difficult===		===Difficult===

2015-12-02T14:10:20Z

Middling

← Older revision		Revision as of 10:10, 2 December 2015
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	'''(b)''' <math> {\frac{97.2 J}{s}} \cdot \frac{3600 s}{1 h} \cdot \frac{24 h}{1 day} = 8398080 J/day </math>		'''(b)''' <math> {\frac{97.2 J}{s}} \cdot \frac{3600 s}{1 h} \cdot \frac{24 h}{1 day} = 8398080 J/day </math>

	<math> \Delta U_g = mg\Delta y = (58 kg)(9.8 m/s^2)(8848 m - 0 m) = 5029203.2 J <math>		:<math> \Delta U_g = mg\Delta y = (58 kg)(9.8 m/s^2)(8848 m - 0 m) = 5029203.2 J </math>
	<math> \Delta t = \frac{W}{power} = \frac{5029203.2 J}{8398080 J/day} = 0.599 days <math>		:<math> \Delta t = \frac{W}{power} = \frac{5029203.2 J}{8398080 J/day} = 0.599 days </math>

	===Difficult===		===Difficult===

2015-12-02T14:07:01Z

Middling

← Older revision		Revision as of 10:07, 2 December 2015
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	*[[Work]]		*[[Work]]
			*[[Gravitational Potential Energy]]

	Are there related topics or categories in this wiki resource for the curious reader to explore? How does this topic fit into that context?		Are there related topics or categories in this wiki resource for the curious reader to explore? How does this topic fit into that context?