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	<updated>2026-05-09T16:24:01Z</updated>
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		<id>http://www.physicsbook.gatech.edu/index.php?title=Friction&amp;diff=26965</id>
		<title>Friction</title>
		<link rel="alternate" type="text/html" href="http://www.physicsbook.gatech.edu/index.php?title=Friction&amp;diff=26965"/>
		<updated>2016-12-02T21:44:01Z</updated>

		<summary type="html">&lt;p&gt;Drao31: &lt;/p&gt;
&lt;hr /&gt;
&lt;div&gt;This page discusses the concept of friction and how it relates to both moving and static objects.&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
==The Main Idea==&lt;br /&gt;
Friction is caused by the interactions between the atoms that make up objects. When objects interact, the atoms that make up the objects also interact. Temperatures of interacting surfaces rise because of such interactions. Friction is a force that resists movement. Generally, friction makes it harder to move objects. There are two main types of friction that are covered in Physics 2211: Static Friction and Kinetic Friction. Static friction can be described as the friction acting on resting objects. Kinetic friction is the friction acting on objects in motion. &lt;br /&gt;
&lt;br /&gt;
Frictional forces depend on a few factors: the normal force and the coefficient of friction. &lt;br /&gt;
&lt;br /&gt;
In simple terms, the normal force &amp;lt;math&amp;gt; {F}_{N} &amp;lt;/math&amp;gt; or &amp;lt;math&amp;gt; {N} &amp;lt;/math&amp;gt; is the equivalent force between objects. For example, when an object of mass &#039;&#039;&#039;M&#039;&#039;&#039; is placed on a table, there is a gravitational force &#039;&#039;&#039;Mg&#039;&#039;&#039; on the table. If the table can support the object without collapsing, the table exerts an equivalent force &#039;&#039;&#039;Mg&#039;&#039;&#039; on the object. According to the momentum principle, since there is no change in momentum, the net force must be &#039;&#039;&#039;0&#039;&#039;&#039;. This is also apparent since there is no movement if the table can support the object.&lt;br /&gt;
&lt;br /&gt;
::&amp;lt;math&amp;gt; {p}_{f} - {p}_{i} = {F}_{net}{dt} = 0 &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
OR&lt;br /&gt;
&lt;br /&gt;
::&amp;lt;math&amp;gt; {F}_{g} = {M}{g} &amp;lt;/math&amp;gt;&lt;br /&gt;
::&amp;lt;math&amp;gt; {N} = {M}{g} &amp;lt;/math&amp;gt;&lt;br /&gt;
::&amp;lt;math&amp;gt; {F}_{net} = {F}_{g} - {N} = {0} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
The coefficient of friction is usually specific to each object or material. The coefficient of static friction is denoted by &amp;lt;math&amp;gt;{&amp;amp;mu;}_{s}&amp;lt;/math&amp;gt; and the coefficient of kinetic friction is denoted by &amp;lt;math&amp;gt;{&amp;amp;mu;}_{k}&amp;lt;/math&amp;gt; &lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
Static Friction:&lt;br /&gt;
&lt;br /&gt;
::&amp;lt;math&amp;gt; {F}_{s} \le {&amp;amp;mu;}_{s}{N} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
Static friction is the frictional force that must be overcome to begin moving an object at rest. The static friction can be no more than the normal force multiplied by the coefficient of static friction. Therefore, the maximum static friction an object can have is &amp;lt;math&amp;gt; {&amp;amp;mu;}_{s}{N} &amp;lt;/math&amp;gt;. &lt;br /&gt;
&lt;br /&gt;
Kinetic Friction:&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
::&amp;lt;math&amp;gt; {F}_{k} = {&amp;amp;mu;}_{k}{N} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
Kinetic friction is the frictional force that exists between objects already at motion. It acts to oppose the movement of an object. Kinetic friction can be observed, for example, when a soccer ball is kicked across a field. The friction between the ball and the field will eventually bring the ball to a stop.&lt;br /&gt;
&lt;br /&gt;
Interestingly, friction is also required for rolling motion. Without friction, objects would not be able to roll. This is true because friction results in torque acting on the object, causing the rolling motion. An example of this can be seen in cars that are stuck in a ditch or similar situations. If there is not enough friction between the car&#039;s wheels and the ground, the car&#039;s wheels will simply spin in place, and the car will not move.&lt;br /&gt;
&lt;br /&gt;
===A Mathematical Model===&lt;br /&gt;
&lt;br /&gt;
As stated above:&lt;br /&gt;
&lt;br /&gt;
Static Friction:&lt;br /&gt;
&lt;br /&gt;
::&amp;lt;math&amp;gt; {F}_{s} \le {&amp;amp;mu;}_{s}{N} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
Kinetic Friction:&lt;br /&gt;
&lt;br /&gt;
::&amp;lt;math&amp;gt; {F}_{k} = {&amp;amp;mu;}_{k}{N} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
When attempting to solve problems relating to friction, one possible method of approach is to consider the net force acting on an object. If there is a force &amp;lt;math&amp;gt; {F}&amp;lt;/math&amp;gt; pushing an object to the right, and a frictional force &amp;lt;math&amp;gt;{F}_{f}&amp;lt;/math&amp;gt; opposing the movement, then the net force is &amp;lt;math&amp;gt; {F}_{net} = {F} - {F}_{f} &amp;lt;/math&amp;gt;.&lt;br /&gt;
&lt;br /&gt;
Another possible approach is by using the momentum principle &amp;lt;math&amp;gt; {p}_{f} - {p}_{i} = {F}_{net}{dt} &amp;lt;/math&amp;gt;. The momentum principle can help solve problems where you need to account for time, net force, or change in momentum.&lt;br /&gt;
&lt;br /&gt;
===A Computational Model===&lt;br /&gt;
&lt;br /&gt;
[[File:Friction.gif]]&lt;br /&gt;
&lt;br /&gt;
Link: &lt;br /&gt;
https://trinket.io/glowscript/76028c1809&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
Code: &lt;br /&gt;
 def friction():&lt;br /&gt;
    from __future__ import division&lt;br /&gt;
    from visual import *&lt;br /&gt;
    from visual.graph import *&lt;br /&gt;
&lt;br /&gt;
    mcart = 100&lt;br /&gt;
    mew = vector(2.9,0,0)&lt;br /&gt;
&lt;br /&gt;
    track =  box(pos=vector(0,-0.05,0), size=vector(20.0,0.05,0.10), color=color.white)&lt;br /&gt;
    cart =  box(pos=vector(-10,0.25,0), size=vector(.5,0.6,0.03), color=color.blue)&lt;br /&gt;
    marker = box(pos = vector(2,0,0), size = vector(0,20,5), color = color.red)&lt;br /&gt;
&lt;br /&gt;
    cart.v=vector(2.4,0,0)&lt;br /&gt;
    cart.p = mcart*cart.v&lt;br /&gt;
    F = vector(90,0,0)&lt;br /&gt;
    F2 = vector(-200,0,0)&lt;br /&gt;
    F3 = (mcart * mew)&lt;br /&gt;
    print(F3)&lt;br /&gt;
&lt;br /&gt;
    deltat = 0.01&lt;br /&gt;
    t = 0&lt;br /&gt;
&lt;br /&gt;
    while t &amp;lt; 5.02:&lt;br /&gt;
&lt;br /&gt;
        if cart.pos.x &amp;lt; 2:&lt;br /&gt;
            cart.v = cart.p / cart.m&lt;br /&gt;
            Fnet = F&lt;br /&gt;
            cart.p = cart.p + Fnet*deltat&lt;br /&gt;
            cart.pos = cart.pos + (cart.p/mcart)*deltat&lt;br /&gt;
&lt;br /&gt;
        else:&lt;br /&gt;
            &lt;br /&gt;
            cart.v = cart.p / cart.m&lt;br /&gt;
            Fnet = F-F3&lt;br /&gt;
            cart.p = cart.p + Fnet*deltat&lt;br /&gt;
            cart.pos = cart.pos + (cart.p/mcart)*deltat&lt;br /&gt;
            &lt;br /&gt;
        t = t + deltat&lt;br /&gt;
        rate(100)&lt;br /&gt;
        &lt;br /&gt;
    print(cart.pos)&lt;br /&gt;
    &lt;br /&gt;
 friction()&lt;br /&gt;
&lt;br /&gt;
==Examples==&lt;br /&gt;
&lt;br /&gt;
Be sure to show all steps in your solution and include diagrams whenever possible&lt;br /&gt;
&lt;br /&gt;
===Simple===&lt;br /&gt;
&lt;br /&gt;
A 100Kg box is placed on a flat table. The box does not move. The coefficient of static friction &amp;lt;math&amp;gt; {&amp;amp;mu;}_{s} = {.25} &amp;lt;/math&amp;gt; and the coefficient of kinetic friction &amp;lt;math&amp;gt; {&amp;amp;mu;}_{k} = {.15} &amp;lt;/math&amp;gt;.&lt;br /&gt;
Find the force of friction &amp;lt;math&amp;gt;{F}_{s}&amp;lt;/math&amp;gt;.&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
Solution:&lt;br /&gt;
&lt;br /&gt;
Since the box does not move, there is only static friction. The normal force is equivalent to the force due to gravity: &amp;lt;math&amp;gt; {F}_{N} = {F}_{g} = {100}{g} &amp;lt;/math&amp;gt;. The static friction can be found by: &amp;lt;math&amp;gt; {F}_{s} = {&amp;amp;mu;}_{s}{F}_{N} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
&amp;lt;math&amp;gt; {F}_{s} = {.25}*{100}*{9.8} = {245.25} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
===Middling===&lt;br /&gt;
&lt;br /&gt;
A cart of mass 3Kg moves across a track pushed by a fan which exerts &amp;lt;math&amp;gt; {F} = &amp;lt;3,0,1&amp;gt; &amp;lt;/math&amp;gt;N with an initial velocity &amp;lt;math&amp;gt; {v}_{i} = &amp;lt;1,0,1&amp;gt;\frac{{m}}{{s}}&amp;lt;/math&amp;gt; . Find the required coefficient of kinetic friction &amp;lt;math&amp;gt; {&amp;amp;mu;}_{k} &amp;lt;/math&amp;gt; needed to bring the cart to a stop in 10 seconds.&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
Solution:&lt;br /&gt;
&lt;br /&gt;
Use the momentum principle: &amp;lt;math&amp;gt;{p}_{f} - {p}_{i} = {F}_{net}{dt}&amp;lt;/math&amp;gt; and &amp;lt;math&amp;gt;{F}_{f} = {&amp;amp;mu;}_{k}{N} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
The final velocity must be 0. The initial velocity, initial force, and time are given. &lt;br /&gt;
&lt;br /&gt;
&amp;lt;math&amp;gt;0- &amp;lt;3,0,3&amp;gt; = {F}_{net}*{10s}&amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
&amp;lt;math&amp;gt; {F}_{net} = &amp;lt;-0.3,0,-0.3&amp;gt; &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
&amp;lt;math&amp;gt; {F}_{net} = {F} - {F}_{f} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
&amp;lt;math&amp;gt; &amp;lt;-0.3,0,-0.3&amp;gt;  = &amp;lt;3,0,1&amp;gt; - {F}_{f}&amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
&amp;lt;math&amp;gt;{F}_{f}  = &amp;lt;3.3,0,1.3&amp;gt; &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
&amp;lt;math&amp;gt; {F}_{f} = &amp;lt;3.3,0,1.3&amp;gt; = {&amp;amp;mu;}_{k}{N} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
&amp;lt;math&amp;gt; {N} = {3Kg} * {&amp;lt;0,9.8,0&amp;gt;} = &amp;lt;0,29.43,0&amp;gt; &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
&amp;lt;math&amp;gt; {&amp;amp;mu;}_{k} = \frac{{F}_{f}}{{N}} = \frac{{&amp;lt;3.3,0,1.3&amp;gt;}}{{0,29.43,0}} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
===Difficult===&lt;br /&gt;
&lt;br /&gt;
Two blocks are stacked on top of one another on a frictionless surface. Block A is stacked on top of Block B. Block A has a mass of 2 Kg while Block B has a mass of 4 Kg. The coefficient of friction between the blocks is &amp;lt;math&amp;gt; {&amp;amp;mu;}_{s} = .35 &amp;lt;/math&amp;gt;. Find the maximum amount of force that can be applied to Block A so that the blocks stay together.&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
Solution:&lt;br /&gt;
&lt;br /&gt;
Momentum Principle:&lt;br /&gt;
&lt;br /&gt;
&amp;lt;math&amp;gt; {p}_{f} - {p}_{i} = {F}_{net}{dt} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
We need to find the force of friction at its maximum to find the maximum amount of force that can be exerted on Block A. &amp;lt;math&amp;gt; {F}_{f} = {&amp;amp;mu;}_{s}{N} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
Forces on Block A:&lt;br /&gt;
&lt;br /&gt;
&amp;lt;math&amp;gt; {F}_{A} - {F}_{f} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
Forces on Block B:&lt;br /&gt;
&lt;br /&gt;
&amp;lt;math&amp;gt; {F}_{f} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
Since we want the blocks to move together, they must therefore have the same acceleration. &lt;br /&gt;
&lt;br /&gt;
&amp;lt;math&amp;gt; {F}_{A} - {F}_{f} = {2 Kg} * {a} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
&amp;lt;math&amp;gt; {F}_{f} = {4 Kg} * {a} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
&amp;lt;math&amp;gt; {F}_{A} - {F}_{f} = {2 Kg} * {a} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
Since they have the same acceleration, we can use the acceleration to solve for the force applied.&lt;br /&gt;
&lt;br /&gt;
&amp;lt;math&amp;gt; {a} = \frac{{F}_{A} - {F}_{f}}{{2 Kg}} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
&amp;lt;math&amp;gt; {a} = \frac{{F}_{f}}{{4}}  &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
&amp;lt;math&amp;gt;\frac{{F}_{A} - {F}_{f}}{{2 Kg}}= \frac{{F}_{f}}{{4 Kg}} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
&amp;lt;math&amp;gt;{F}_{A}= \frac{{3}}{{2}}{F}_{f} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
&amp;lt;math&amp;gt;{F}_{A}= \frac{{3}}{{2}} * {.35}*{6Kg}*{9.8} = {30.87}&amp;lt;/math&amp;gt; N&lt;br /&gt;
&lt;br /&gt;
==Connectedness==&lt;br /&gt;
&lt;br /&gt;
Friction is an important topic to understand because it has many industrial implications. Since friction can cause increases in temperature when objects move, engineers who work with moving objects must understand and account for friction to ensure systems work properly. For example, car engines must have proper oil and lubricants to prevent parts from scraping together and wearing down. Mechanical engineers, aerospace engineers, and civil engineers must deal with friction and its impacts every day!&lt;br /&gt;
&lt;br /&gt;
== See also ==&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
===External links===&lt;br /&gt;
&lt;br /&gt;
Internet resources on this topic&lt;br /&gt;
&lt;br /&gt;
Hyper Physics: http://hyperphysics.phy-astr.gsu.edu/hbase/frict.html#fri&lt;br /&gt;
&lt;br /&gt;
PHET Simulation: https://phet.colorado.edu/en/simulation/friction&lt;br /&gt;
&lt;br /&gt;
==References==&lt;br /&gt;
[1] Serway, Raymond A., and John W. Jewett. Physics for Scientists and Engineers. Boston, MA: Cengage Brooks/Cole, 2014. Print.&lt;br /&gt;
&lt;br /&gt;
[2] Sherwood, Bruce A. Matter &amp;amp; Interactions. By Ruth W. Chabay. 4th ed. Vol. 1. N.p.: John Wiley &amp;amp; Sons, 2015. 45-50. Print. Modern Mechanics.&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
[[Category:Contact Forces]]&lt;/div&gt;</summary>
		<author><name>Drao31</name></author>
	</entry>
	<entry>
		<id>http://www.physicsbook.gatech.edu/index.php?title=Friction&amp;diff=25086</id>
		<title>Friction</title>
		<link rel="alternate" type="text/html" href="http://www.physicsbook.gatech.edu/index.php?title=Friction&amp;diff=25086"/>
		<updated>2016-11-27T21:17:06Z</updated>

		<summary type="html">&lt;p&gt;Drao31: /* Simple */&lt;/p&gt;
&lt;hr /&gt;
&lt;div&gt;This page discusses the concept of friction and how it relates to both moving and static objects.&lt;br /&gt;
&lt;br /&gt;
Claimed by drao31&lt;br /&gt;
&lt;br /&gt;
==The Main Idea==&lt;br /&gt;
Friction is caused by the interactions between the atoms that make up objects. When objects interact, the atoms that make up the objects also interact. Temperatures of interacting surfaces rise because of such interactions. Friction is a force that resists movement. Generally, friction makes it harder to move objects. There are two main types of friction that are covered in Physics 2211: Static Friction and Kinetic Friction. Static friction can be described as the friction acting on resting objects. Kinetic friction is the friction acting on objects in motion. &lt;br /&gt;
&lt;br /&gt;
Frictional forces depend on a few factors: the normal force and the coefficient of friction. &lt;br /&gt;
&lt;br /&gt;
In simple terms, the normal force &amp;lt;math&amp;gt; {F}_{N} &amp;lt;/math&amp;gt; or &amp;lt;math&amp;gt; {N} &amp;lt;/math&amp;gt; is the equivalent force between objects. For example, when an object of mass &#039;&#039;&#039;M&#039;&#039;&#039; is placed on a table, there is a gravitational force &#039;&#039;&#039;Mg&#039;&#039;&#039; on the table. If the table can support the object without collapsing, the table exerts an equivalent force &#039;&#039;&#039;Mg&#039;&#039;&#039; on the object. According to the momentum principle, since there is no change in momentum, the net force must be &#039;&#039;&#039;0&#039;&#039;&#039;. This is also apparent since there is no movement if the table can support the object.&lt;br /&gt;
&lt;br /&gt;
::&amp;lt;math&amp;gt; {p}_{f} - {p}_{i} = {F}_{net}{dt} = 0 &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
OR&lt;br /&gt;
&lt;br /&gt;
::&amp;lt;math&amp;gt; {F}_{g} = {M}{g} &amp;lt;/math&amp;gt;&lt;br /&gt;
::&amp;lt;math&amp;gt; {N} = {M}{g} &amp;lt;/math&amp;gt;&lt;br /&gt;
::&amp;lt;math&amp;gt; {F}_{net} = {F}_{g} - {N} = {0} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
The coefficient of friction is usually specific to each object or material. The coefficient of static friction is denoted by &amp;lt;math&amp;gt;{&amp;amp;mu;}_{s}&amp;lt;/math&amp;gt; and the coefficient of kinetic friction is denoted by &amp;lt;math&amp;gt;{&amp;amp;mu;}_{k}&amp;lt;/math&amp;gt; &lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
Static Friction:&lt;br /&gt;
&lt;br /&gt;
::&amp;lt;math&amp;gt; {F}_{s} \le {&amp;amp;mu;}_{s}{N} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
Static friction is the frictional force that must be overcome to begin moving an object at rest. The static friction can be no more than the normal force multiplied by the coefficient of static friction. Therefore, the maximum static friction an object can have is &amp;lt;math&amp;gt; {&amp;amp;mu;}_{s}{N} &amp;lt;/math&amp;gt;. &lt;br /&gt;
&lt;br /&gt;
Kinetic Friction:&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
::&amp;lt;math&amp;gt; {F}_{k} = {&amp;amp;mu;}_{k}{N} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
Kinetic friction is the frictional force that exists between objects already at motion. It acts to oppose the movement of an object. Kinetic friction can be observed, for example, when a soccer ball is kicked across a field. The friction between the ball and the field will eventually bring the ball to a stop.&lt;br /&gt;
&lt;br /&gt;
Interestingly, friction is also required for rolling motion. Without friction, objects would not be able to roll. This is true because friction results in torque acting on the object, causing the rolling motion. An example of this can be seen in cars that are stuck in a ditch or similar situations. If there is not enough friction between the car&#039;s wheels and the ground, the car&#039;s wheels will simply spin in place, and the car will not move.&lt;br /&gt;
&lt;br /&gt;
===A Mathematical Model===&lt;br /&gt;
&lt;br /&gt;
As stated above:&lt;br /&gt;
&lt;br /&gt;
Static Friction:&lt;br /&gt;
&lt;br /&gt;
::&amp;lt;math&amp;gt; {F}_{s} \le {&amp;amp;mu;}_{s}{N} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
Kinetic Friction:&lt;br /&gt;
&lt;br /&gt;
::&amp;lt;math&amp;gt; {F}_{k} = {&amp;amp;mu;}_{k}{N} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
When attempting to solve problems relating to friction, one possible method of approach is to consider the net force acting on an object. If there is a force &amp;lt;math&amp;gt; {F}&amp;lt;/math&amp;gt; pushing an object to the right, and a frictional force &amp;lt;math&amp;gt;{F}_{f}&amp;lt;/math&amp;gt; opposing the movement, then the net force is &amp;lt;math&amp;gt; {F}_{net} = {F} - {F}_{f} &amp;lt;/math&amp;gt;.&lt;br /&gt;
&lt;br /&gt;
Another possible approach is by using the momentum principle &amp;lt;math&amp;gt; {p}_{f} - {p}_{i} = {F}_{net}{dt} &amp;lt;/math&amp;gt;. The momentum principle can help solve problems where you need to account for time, net force, or change in momentum.&lt;br /&gt;
&lt;br /&gt;
===A Computational Model===&lt;br /&gt;
&lt;br /&gt;
[[File:Friction.gif]]&lt;br /&gt;
&lt;br /&gt;
Link: &lt;br /&gt;
https://trinket.io/glowscript/76028c1809&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
Code: &lt;br /&gt;
 def friction():&lt;br /&gt;
    from __future__ import division&lt;br /&gt;
    from visual import *&lt;br /&gt;
    from visual.graph import *&lt;br /&gt;
&lt;br /&gt;
    mcart = 100&lt;br /&gt;
    mew = vector(2.9,0,0)&lt;br /&gt;
&lt;br /&gt;
    track =  box(pos=vector(0,-0.05,0), size=vector(20.0,0.05,0.10), color=color.white)&lt;br /&gt;
    cart =  box(pos=vector(-10,0.25,0), size=vector(.5,0.6,0.03), color=color.blue)&lt;br /&gt;
    marker = box(pos = vector(2,0,0), size = vector(0,20,5), color = color.red)&lt;br /&gt;
&lt;br /&gt;
    cart.v=vector(2.4,0,0)&lt;br /&gt;
    cart.p = mcart*cart.v&lt;br /&gt;
    F = vector(90,0,0)&lt;br /&gt;
    F2 = vector(-200,0,0)&lt;br /&gt;
    F3 = (mcart * mew)&lt;br /&gt;
    print(F3)&lt;br /&gt;
&lt;br /&gt;
    deltat = 0.01&lt;br /&gt;
    t = 0&lt;br /&gt;
&lt;br /&gt;
    while t &amp;lt; 5.02:&lt;br /&gt;
&lt;br /&gt;
        if cart.pos.x &amp;lt; 2:&lt;br /&gt;
            cart.v = cart.p / cart.m&lt;br /&gt;
            Fnet = F&lt;br /&gt;
            cart.p = cart.p + Fnet*deltat&lt;br /&gt;
            cart.pos = cart.pos + (cart.p/mcart)*deltat&lt;br /&gt;
&lt;br /&gt;
        else:&lt;br /&gt;
            &lt;br /&gt;
            cart.v = cart.p / cart.m&lt;br /&gt;
            Fnet = F-F3&lt;br /&gt;
            cart.p = cart.p + Fnet*deltat&lt;br /&gt;
            cart.pos = cart.pos + (cart.p/mcart)*deltat&lt;br /&gt;
            &lt;br /&gt;
        t = t + deltat&lt;br /&gt;
        rate(100)&lt;br /&gt;
        &lt;br /&gt;
    print(cart.pos)&lt;br /&gt;
    &lt;br /&gt;
 friction()&lt;br /&gt;
&lt;br /&gt;
==Examples==&lt;br /&gt;
&lt;br /&gt;
Be sure to show all steps in your solution and include diagrams whenever possible&lt;br /&gt;
&lt;br /&gt;
===Simple===&lt;br /&gt;
&lt;br /&gt;
A 100Kg box is placed on a flat table. The box does not move. The coefficient of static friction &amp;lt;math&amp;gt; {&amp;amp;mu;}_{s} = {.25} &amp;lt;/math&amp;gt; and the coefficient of kinetic friction &amp;lt;math&amp;gt; {&amp;amp;mu;}_{k} = {.15} &amp;lt;/math&amp;gt;.&lt;br /&gt;
Find the force of friction &amp;lt;math&amp;gt;{F}_{s}&amp;lt;/math&amp;gt;.&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
Solution:&lt;br /&gt;
&lt;br /&gt;
Since the box does not move, there is only static friction. The normal force is equivalent to the force due to gravity: &amp;lt;math&amp;gt; {F}_{N} = {F}_{g} = {100}{g} &amp;lt;/math&amp;gt;. The static friction can be found by: &amp;lt;math&amp;gt; {F}_{s} = {&amp;amp;mu;}_{s}{F}_{N} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
&amp;lt;math&amp;gt; {F}_{s} = {.25}*{100}*{9.8} = {245.25} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
===Middling===&lt;br /&gt;
&lt;br /&gt;
A cart of mass 3Kg moves across a track pushed by a fan which exerts &amp;lt;math&amp;gt; {F} = &amp;lt;3,0,1&amp;gt; &amp;lt;/math&amp;gt;N with an initial velocity &amp;lt;math&amp;gt; {v}_{i} = &amp;lt;1,0,1&amp;gt;\frac{{m}}{{s}}&amp;lt;/math&amp;gt; . Find the required coefficient of kinetic friction &amp;lt;math&amp;gt; {&amp;amp;mu;}_{k} &amp;lt;/math&amp;gt; needed to bring the cart to a stop in 10 seconds.&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
Solution:&lt;br /&gt;
&lt;br /&gt;
Use the momentum principle: &amp;lt;math&amp;gt;{p}_{f} - {p}_{i} = {F}_{net}{dt}&amp;lt;/math&amp;gt; and &amp;lt;math&amp;gt;{F}_{f} = {&amp;amp;mu;}_{k}{N} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
The final velocity must be 0. The initial velocity, initial force, and time are given. &lt;br /&gt;
&lt;br /&gt;
&amp;lt;math&amp;gt;0- &amp;lt;3,0,3&amp;gt; = {F}_{net}*{10s}&amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
&amp;lt;math&amp;gt; {F}_{net} = &amp;lt;-0.3,0,-0.3&amp;gt; &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
&amp;lt;math&amp;gt; {F}_{net} = {F} - {F}_{f} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
&amp;lt;math&amp;gt; &amp;lt;-0.3,0,-0.3&amp;gt;  = &amp;lt;3,0,1&amp;gt; - {F}_{f}&amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
&amp;lt;math&amp;gt;{F}_{f}  = &amp;lt;3.3,0,1.3&amp;gt; &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
&amp;lt;math&amp;gt; {F}_{f} = &amp;lt;3.3,0,1.3&amp;gt; = {&amp;amp;mu;}_{k}{N} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
&amp;lt;math&amp;gt; {N} = {3Kg} * {&amp;lt;0,9.8,0&amp;gt;} = &amp;lt;0,29.43,0&amp;gt; &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
&amp;lt;math&amp;gt; {&amp;amp;mu;}_{k} = \frac{{F}_{f}}{{N}} = \frac{{&amp;lt;3.3,0,1.3&amp;gt;}}{{0,29.43,0}} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
===Difficult===&lt;br /&gt;
&lt;br /&gt;
Two blocks are stacked on top of one another on a frictionless surface. Block A is stacked on top of Block B. Block A has a mass of 2 Kg while Block B has a mass of 4 Kg. The coefficient of friction between the blocks is &amp;lt;math&amp;gt; {&amp;amp;mu;}_{s} = .35 &amp;lt;/math&amp;gt;. Find the maximum amount of force that can be applied to Block A so that the blocks stay together.&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
Solution:&lt;br /&gt;
&lt;br /&gt;
Momentum Principle:&lt;br /&gt;
&lt;br /&gt;
&amp;lt;math&amp;gt; {p}_{f} - {p}_{i} = {F}_{net}{dt} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
We need to find the force of friction at its maximum to find the maximum amount of force that can be exerted on Block A. &amp;lt;math&amp;gt; {F}_{f} = {&amp;amp;mu;}_{s}{N} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
Forces on Block A:&lt;br /&gt;
&lt;br /&gt;
&amp;lt;math&amp;gt; {F}_{A} - {F}_{f} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
Forces on Block B:&lt;br /&gt;
&lt;br /&gt;
&amp;lt;math&amp;gt; {F}_{f} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
Since we want the blocks to move together, they must therefore have the same acceleration. &lt;br /&gt;
&lt;br /&gt;
&amp;lt;math&amp;gt; {F}_{A} - {F}_{f} = {2 Kg} * {a} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
&amp;lt;math&amp;gt; {F}_{f} = {4 Kg} * {a} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
&amp;lt;math&amp;gt; {F}_{A} - {F}_{f} = {2 Kg} * {a} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
Since they have the same acceleration, we can use the acceleration to solve for the force applied.&lt;br /&gt;
&lt;br /&gt;
&amp;lt;math&amp;gt; {a} = \frac{{F}_{A} - {F}_{f}}{{2 Kg}} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
&amp;lt;math&amp;gt; {a} = \frac{{F}_{f}}{{4}}  &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
&amp;lt;math&amp;gt;\frac{{F}_{A} - {F}_{f}}{{2 Kg}}= \frac{{F}_{f}}{{4 Kg}} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
&amp;lt;math&amp;gt;{F}_{A}= \frac{{3}}{{2}}{F}_{f} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
&amp;lt;math&amp;gt;{F}_{A}= \frac{{3}}{{2}} * {.35}*{6Kg}*{9.8} = {30.87}&amp;lt;/math&amp;gt; N&lt;br /&gt;
&lt;br /&gt;
==Connectedness==&lt;br /&gt;
&lt;br /&gt;
Friction is an important topic to understand because it has many industrial implications. Since friction can cause increases in temperature when objects move, engineers who work with moving objects must understand and account for friction to ensure systems work properly. For example, car engines must have proper oil and lubricants to prevent parts from scraping together and wearing down. Mechanical engineers, aerospace engineers, and civil engineers must deal with friction and its impacts every day!&lt;br /&gt;
&lt;br /&gt;
== See also ==&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
===External links===&lt;br /&gt;
&lt;br /&gt;
Internet resources on this topic&lt;br /&gt;
&lt;br /&gt;
Hyper Physics: http://hyperphysics.phy-astr.gsu.edu/hbase/frict.html#fri&lt;br /&gt;
&lt;br /&gt;
PHET Simulation: https://phet.colorado.edu/en/simulation/friction&lt;br /&gt;
&lt;br /&gt;
==References==&lt;br /&gt;
[1] Serway, Raymond A., and John W. Jewett. Physics for Scientists and Engineers. Boston, MA: Cengage Brooks/Cole, 2014. Print.&lt;br /&gt;
&lt;br /&gt;
[2] Sherwood, Bruce A. Matter &amp;amp; Interactions. By Ruth W. Chabay. 4th ed. Vol. 1. N.p.: John Wiley &amp;amp; Sons, 2015. 45-50. Print. Modern Mechanics.&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
[[Category:Contact Forces]]&lt;/div&gt;</summary>
		<author><name>Drao31</name></author>
	</entry>
	<entry>
		<id>http://www.physicsbook.gatech.edu/index.php?title=Friction&amp;diff=25085</id>
		<title>Friction</title>
		<link rel="alternate" type="text/html" href="http://www.physicsbook.gatech.edu/index.php?title=Friction&amp;diff=25085"/>
		<updated>2016-11-27T21:16:33Z</updated>

		<summary type="html">&lt;p&gt;Drao31: /* Difficult */&lt;/p&gt;
&lt;hr /&gt;
&lt;div&gt;This page discusses the concept of friction and how it relates to both moving and static objects.&lt;br /&gt;
&lt;br /&gt;
Claimed by drao31&lt;br /&gt;
&lt;br /&gt;
==The Main Idea==&lt;br /&gt;
Friction is caused by the interactions between the atoms that make up objects. When objects interact, the atoms that make up the objects also interact. Temperatures of interacting surfaces rise because of such interactions. Friction is a force that resists movement. Generally, friction makes it harder to move objects. There are two main types of friction that are covered in Physics 2211: Static Friction and Kinetic Friction. Static friction can be described as the friction acting on resting objects. Kinetic friction is the friction acting on objects in motion. &lt;br /&gt;
&lt;br /&gt;
Frictional forces depend on a few factors: the normal force and the coefficient of friction. &lt;br /&gt;
&lt;br /&gt;
In simple terms, the normal force &amp;lt;math&amp;gt; {F}_{N} &amp;lt;/math&amp;gt; or &amp;lt;math&amp;gt; {N} &amp;lt;/math&amp;gt; is the equivalent force between objects. For example, when an object of mass &#039;&#039;&#039;M&#039;&#039;&#039; is placed on a table, there is a gravitational force &#039;&#039;&#039;Mg&#039;&#039;&#039; on the table. If the table can support the object without collapsing, the table exerts an equivalent force &#039;&#039;&#039;Mg&#039;&#039;&#039; on the object. According to the momentum principle, since there is no change in momentum, the net force must be &#039;&#039;&#039;0&#039;&#039;&#039;. This is also apparent since there is no movement if the table can support the object.&lt;br /&gt;
&lt;br /&gt;
::&amp;lt;math&amp;gt; {p}_{f} - {p}_{i} = {F}_{net}{dt} = 0 &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
OR&lt;br /&gt;
&lt;br /&gt;
::&amp;lt;math&amp;gt; {F}_{g} = {M}{g} &amp;lt;/math&amp;gt;&lt;br /&gt;
::&amp;lt;math&amp;gt; {N} = {M}{g} &amp;lt;/math&amp;gt;&lt;br /&gt;
::&amp;lt;math&amp;gt; {F}_{net} = {F}_{g} - {N} = {0} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
The coefficient of friction is usually specific to each object or material. The coefficient of static friction is denoted by &amp;lt;math&amp;gt;{&amp;amp;mu;}_{s}&amp;lt;/math&amp;gt; and the coefficient of kinetic friction is denoted by &amp;lt;math&amp;gt;{&amp;amp;mu;}_{k}&amp;lt;/math&amp;gt; &lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
Static Friction:&lt;br /&gt;
&lt;br /&gt;
::&amp;lt;math&amp;gt; {F}_{s} \le {&amp;amp;mu;}_{s}{N} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
Static friction is the frictional force that must be overcome to begin moving an object at rest. The static friction can be no more than the normal force multiplied by the coefficient of static friction. Therefore, the maximum static friction an object can have is &amp;lt;math&amp;gt; {&amp;amp;mu;}_{s}{N} &amp;lt;/math&amp;gt;. &lt;br /&gt;
&lt;br /&gt;
Kinetic Friction:&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
::&amp;lt;math&amp;gt; {F}_{k} = {&amp;amp;mu;}_{k}{N} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
Kinetic friction is the frictional force that exists between objects already at motion. It acts to oppose the movement of an object. Kinetic friction can be observed, for example, when a soccer ball is kicked across a field. The friction between the ball and the field will eventually bring the ball to a stop.&lt;br /&gt;
&lt;br /&gt;
Interestingly, friction is also required for rolling motion. Without friction, objects would not be able to roll. This is true because friction results in torque acting on the object, causing the rolling motion. An example of this can be seen in cars that are stuck in a ditch or similar situations. If there is not enough friction between the car&#039;s wheels and the ground, the car&#039;s wheels will simply spin in place, and the car will not move.&lt;br /&gt;
&lt;br /&gt;
===A Mathematical Model===&lt;br /&gt;
&lt;br /&gt;
As stated above:&lt;br /&gt;
&lt;br /&gt;
Static Friction:&lt;br /&gt;
&lt;br /&gt;
::&amp;lt;math&amp;gt; {F}_{s} \le {&amp;amp;mu;}_{s}{N} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
Kinetic Friction:&lt;br /&gt;
&lt;br /&gt;
::&amp;lt;math&amp;gt; {F}_{k} = {&amp;amp;mu;}_{k}{N} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
When attempting to solve problems relating to friction, one possible method of approach is to consider the net force acting on an object. If there is a force &amp;lt;math&amp;gt; {F}&amp;lt;/math&amp;gt; pushing an object to the right, and a frictional force &amp;lt;math&amp;gt;{F}_{f}&amp;lt;/math&amp;gt; opposing the movement, then the net force is &amp;lt;math&amp;gt; {F}_{net} = {F} - {F}_{f} &amp;lt;/math&amp;gt;.&lt;br /&gt;
&lt;br /&gt;
Another possible approach is by using the momentum principle &amp;lt;math&amp;gt; {p}_{f} - {p}_{i} = {F}_{net}{dt} &amp;lt;/math&amp;gt;. The momentum principle can help solve problems where you need to account for time, net force, or change in momentum.&lt;br /&gt;
&lt;br /&gt;
===A Computational Model===&lt;br /&gt;
&lt;br /&gt;
[[File:Friction.gif]]&lt;br /&gt;
&lt;br /&gt;
Link: &lt;br /&gt;
https://trinket.io/glowscript/76028c1809&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
Code: &lt;br /&gt;
 def friction():&lt;br /&gt;
    from __future__ import division&lt;br /&gt;
    from visual import *&lt;br /&gt;
    from visual.graph import *&lt;br /&gt;
&lt;br /&gt;
    mcart = 100&lt;br /&gt;
    mew = vector(2.9,0,0)&lt;br /&gt;
&lt;br /&gt;
    track =  box(pos=vector(0,-0.05,0), size=vector(20.0,0.05,0.10), color=color.white)&lt;br /&gt;
    cart =  box(pos=vector(-10,0.25,0), size=vector(.5,0.6,0.03), color=color.blue)&lt;br /&gt;
    marker = box(pos = vector(2,0,0), size = vector(0,20,5), color = color.red)&lt;br /&gt;
&lt;br /&gt;
    cart.v=vector(2.4,0,0)&lt;br /&gt;
    cart.p = mcart*cart.v&lt;br /&gt;
    F = vector(90,0,0)&lt;br /&gt;
    F2 = vector(-200,0,0)&lt;br /&gt;
    F3 = (mcart * mew)&lt;br /&gt;
    print(F3)&lt;br /&gt;
&lt;br /&gt;
    deltat = 0.01&lt;br /&gt;
    t = 0&lt;br /&gt;
&lt;br /&gt;
    while t &amp;lt; 5.02:&lt;br /&gt;
&lt;br /&gt;
        if cart.pos.x &amp;lt; 2:&lt;br /&gt;
            cart.v = cart.p / cart.m&lt;br /&gt;
            Fnet = F&lt;br /&gt;
            cart.p = cart.p + Fnet*deltat&lt;br /&gt;
            cart.pos = cart.pos + (cart.p/mcart)*deltat&lt;br /&gt;
&lt;br /&gt;
        else:&lt;br /&gt;
            &lt;br /&gt;
            cart.v = cart.p / cart.m&lt;br /&gt;
            Fnet = F-F3&lt;br /&gt;
            cart.p = cart.p + Fnet*deltat&lt;br /&gt;
            cart.pos = cart.pos + (cart.p/mcart)*deltat&lt;br /&gt;
            &lt;br /&gt;
        t = t + deltat&lt;br /&gt;
        rate(100)&lt;br /&gt;
        &lt;br /&gt;
    print(cart.pos)&lt;br /&gt;
    &lt;br /&gt;
 friction()&lt;br /&gt;
&lt;br /&gt;
==Examples==&lt;br /&gt;
&lt;br /&gt;
Be sure to show all steps in your solution and include diagrams whenever possible&lt;br /&gt;
&lt;br /&gt;
===Simple===&lt;br /&gt;
&lt;br /&gt;
A 100Kg box is placed on a flat table. The box does not move. The coefficient of static friction &amp;lt;math&amp;gt; {&amp;amp;mu;}_{s} = {.25} &amp;lt;/math&amp;gt; and the coefficient of kinetic friction &amp;lt;math&amp;gt; {&amp;amp;mu;}_{k} = {.15} &amp;lt;/math&amp;gt;.&lt;br /&gt;
Find the force of friction &amp;lt;math&amp;gt;{F}_{s}&amp;lt;/math&amp;gt;.&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
Solution:&lt;br /&gt;
&lt;br /&gt;
Since the box does not move, there is only static friction. The normal force is equivalent to the force due to gravity: &amp;lt;math&amp;gt; {F}_{N} = {F}_{g} = {100}{g} &amp;lt;/math&amp;gt;. The static friction can be found by: &amp;lt;math&amp;gt; {F}_{s} = {&amp;amp;mu;}_{s}{F}_{N} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
&amp;lt;math&amp;gt; {F}_{s} = {(.25)}{(100)}{(9.8)} = {245.25} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
===Middling===&lt;br /&gt;
&lt;br /&gt;
A cart of mass 3Kg moves across a track pushed by a fan which exerts &amp;lt;math&amp;gt; {F} = &amp;lt;3,0,1&amp;gt; &amp;lt;/math&amp;gt;N with an initial velocity &amp;lt;math&amp;gt; {v}_{i} = &amp;lt;1,0,1&amp;gt;\frac{{m}}{{s}}&amp;lt;/math&amp;gt; . Find the required coefficient of kinetic friction &amp;lt;math&amp;gt; {&amp;amp;mu;}_{k} &amp;lt;/math&amp;gt; needed to bring the cart to a stop in 10 seconds.&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
Solution:&lt;br /&gt;
&lt;br /&gt;
Use the momentum principle: &amp;lt;math&amp;gt;{p}_{f} - {p}_{i} = {F}_{net}{dt}&amp;lt;/math&amp;gt; and &amp;lt;math&amp;gt;{F}_{f} = {&amp;amp;mu;}_{k}{N} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
The final velocity must be 0. The initial velocity, initial force, and time are given. &lt;br /&gt;
&lt;br /&gt;
&amp;lt;math&amp;gt;0- &amp;lt;3,0,3&amp;gt; = {F}_{net}*{10s}&amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
&amp;lt;math&amp;gt; {F}_{net} = &amp;lt;-0.3,0,-0.3&amp;gt; &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
&amp;lt;math&amp;gt; {F}_{net} = {F} - {F}_{f} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
&amp;lt;math&amp;gt; &amp;lt;-0.3,0,-0.3&amp;gt;  = &amp;lt;3,0,1&amp;gt; - {F}_{f}&amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
&amp;lt;math&amp;gt;{F}_{f}  = &amp;lt;3.3,0,1.3&amp;gt; &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
&amp;lt;math&amp;gt; {F}_{f} = &amp;lt;3.3,0,1.3&amp;gt; = {&amp;amp;mu;}_{k}{N} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
&amp;lt;math&amp;gt; {N} = {3Kg} * {&amp;lt;0,9.8,0&amp;gt;} = &amp;lt;0,29.43,0&amp;gt; &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
&amp;lt;math&amp;gt; {&amp;amp;mu;}_{k} = \frac{{F}_{f}}{{N}} = \frac{{&amp;lt;3.3,0,1.3&amp;gt;}}{{0,29.43,0}} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
===Difficult===&lt;br /&gt;
&lt;br /&gt;
Two blocks are stacked on top of one another on a frictionless surface. Block A is stacked on top of Block B. Block A has a mass of 2 Kg while Block B has a mass of 4 Kg. The coefficient of friction between the blocks is &amp;lt;math&amp;gt; {&amp;amp;mu;}_{s} = .35 &amp;lt;/math&amp;gt;. Find the maximum amount of force that can be applied to Block A so that the blocks stay together.&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
Solution:&lt;br /&gt;
&lt;br /&gt;
Momentum Principle:&lt;br /&gt;
&lt;br /&gt;
&amp;lt;math&amp;gt; {p}_{f} - {p}_{i} = {F}_{net}{dt} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
We need to find the force of friction at its maximum to find the maximum amount of force that can be exerted on Block A. &amp;lt;math&amp;gt; {F}_{f} = {&amp;amp;mu;}_{s}{N} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
Forces on Block A:&lt;br /&gt;
&lt;br /&gt;
&amp;lt;math&amp;gt; {F}_{A} - {F}_{f} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
Forces on Block B:&lt;br /&gt;
&lt;br /&gt;
&amp;lt;math&amp;gt; {F}_{f} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
Since we want the blocks to move together, they must therefore have the same acceleration. &lt;br /&gt;
&lt;br /&gt;
&amp;lt;math&amp;gt; {F}_{A} - {F}_{f} = {2 Kg} * {a} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
&amp;lt;math&amp;gt; {F}_{f} = {4 Kg} * {a} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
&amp;lt;math&amp;gt; {F}_{A} - {F}_{f} = {2 Kg} * {a} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
Since they have the same acceleration, we can use the acceleration to solve for the force applied.&lt;br /&gt;
&lt;br /&gt;
&amp;lt;math&amp;gt; {a} = \frac{{F}_{A} - {F}_{f}}{{2 Kg}} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
&amp;lt;math&amp;gt; {a} = \frac{{F}_{f}}{{4}}  &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
&amp;lt;math&amp;gt;\frac{{F}_{A} - {F}_{f}}{{2 Kg}}= \frac{{F}_{f}}{{4 Kg}} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
&amp;lt;math&amp;gt;{F}_{A}= \frac{{3}}{{2}}{F}_{f} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
&amp;lt;math&amp;gt;{F}_{A}= \frac{{3}}{{2}} * {.35}*{6Kg}*{9.8} = {30.87}&amp;lt;/math&amp;gt; N&lt;br /&gt;
&lt;br /&gt;
==Connectedness==&lt;br /&gt;
&lt;br /&gt;
Friction is an important topic to understand because it has many industrial implications. Since friction can cause increases in temperature when objects move, engineers who work with moving objects must understand and account for friction to ensure systems work properly. For example, car engines must have proper oil and lubricants to prevent parts from scraping together and wearing down. Mechanical engineers, aerospace engineers, and civil engineers must deal with friction and its impacts every day!&lt;br /&gt;
&lt;br /&gt;
== See also ==&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
===External links===&lt;br /&gt;
&lt;br /&gt;
Internet resources on this topic&lt;br /&gt;
&lt;br /&gt;
Hyper Physics: http://hyperphysics.phy-astr.gsu.edu/hbase/frict.html#fri&lt;br /&gt;
&lt;br /&gt;
PHET Simulation: https://phet.colorado.edu/en/simulation/friction&lt;br /&gt;
&lt;br /&gt;
==References==&lt;br /&gt;
[1] Serway, Raymond A., and John W. Jewett. Physics for Scientists and Engineers. Boston, MA: Cengage Brooks/Cole, 2014. Print.&lt;br /&gt;
&lt;br /&gt;
[2] Sherwood, Bruce A. Matter &amp;amp; Interactions. By Ruth W. Chabay. 4th ed. Vol. 1. N.p.: John Wiley &amp;amp; Sons, 2015. 45-50. Print. Modern Mechanics.&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
[[Category:Contact Forces]]&lt;/div&gt;</summary>
		<author><name>Drao31</name></author>
	</entry>
	<entry>
		<id>http://www.physicsbook.gatech.edu/index.php?title=Friction&amp;diff=25081</id>
		<title>Friction</title>
		<link rel="alternate" type="text/html" href="http://www.physicsbook.gatech.edu/index.php?title=Friction&amp;diff=25081"/>
		<updated>2016-11-27T21:13:54Z</updated>

		<summary type="html">&lt;p&gt;Drao31: &lt;/p&gt;
&lt;hr /&gt;
&lt;div&gt;This page discusses the concept of friction and how it relates to both moving and static objects.&lt;br /&gt;
&lt;br /&gt;
Claimed by drao31&lt;br /&gt;
&lt;br /&gt;
==The Main Idea==&lt;br /&gt;
Friction is caused by the interactions between the atoms that make up objects. When objects interact, the atoms that make up the objects also interact. Temperatures of interacting surfaces rise because of such interactions. Friction is a force that resists movement. Generally, friction makes it harder to move objects. There are two main types of friction that are covered in Physics 2211: Static Friction and Kinetic Friction. Static friction can be described as the friction acting on resting objects. Kinetic friction is the friction acting on objects in motion. &lt;br /&gt;
&lt;br /&gt;
Frictional forces depend on a few factors: the normal force and the coefficient of friction. &lt;br /&gt;
&lt;br /&gt;
In simple terms, the normal force &amp;lt;math&amp;gt; {F}_{N} &amp;lt;/math&amp;gt; or &amp;lt;math&amp;gt; {N} &amp;lt;/math&amp;gt; is the equivalent force between objects. For example, when an object of mass &#039;&#039;&#039;M&#039;&#039;&#039; is placed on a table, there is a gravitational force &#039;&#039;&#039;Mg&#039;&#039;&#039; on the table. If the table can support the object without collapsing, the table exerts an equivalent force &#039;&#039;&#039;Mg&#039;&#039;&#039; on the object. According to the momentum principle, since there is no change in momentum, the net force must be &#039;&#039;&#039;0&#039;&#039;&#039;. This is also apparent since there is no movement if the table can support the object.&lt;br /&gt;
&lt;br /&gt;
::&amp;lt;math&amp;gt; {p}_{f} - {p}_{i} = {F}_{net}{dt} = 0 &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
OR&lt;br /&gt;
&lt;br /&gt;
::&amp;lt;math&amp;gt; {F}_{g} = {M}{g} &amp;lt;/math&amp;gt;&lt;br /&gt;
::&amp;lt;math&amp;gt; {N} = {M}{g} &amp;lt;/math&amp;gt;&lt;br /&gt;
::&amp;lt;math&amp;gt; {F}_{net} = {F}_{g} - {N} = {0} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
The coefficient of friction is usually specific to each object or material. The coefficient of static friction is denoted by &amp;lt;math&amp;gt;{&amp;amp;mu;}_{s}&amp;lt;/math&amp;gt; and the coefficient of kinetic friction is denoted by &amp;lt;math&amp;gt;{&amp;amp;mu;}_{k}&amp;lt;/math&amp;gt; &lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
Static Friction:&lt;br /&gt;
&lt;br /&gt;
::&amp;lt;math&amp;gt; {F}_{s} \le {&amp;amp;mu;}_{s}{N} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
Static friction is the frictional force that must be overcome to begin moving an object at rest. The static friction can be no more than the normal force multiplied by the coefficient of static friction. Therefore, the maximum static friction an object can have is &amp;lt;math&amp;gt; {&amp;amp;mu;}_{s}{N} &amp;lt;/math&amp;gt;. &lt;br /&gt;
&lt;br /&gt;
Kinetic Friction:&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
::&amp;lt;math&amp;gt; {F}_{k} = {&amp;amp;mu;}_{k}{N} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
Kinetic friction is the frictional force that exists between objects already at motion. It acts to oppose the movement of an object. Kinetic friction can be observed, for example, when a soccer ball is kicked across a field. The friction between the ball and the field will eventually bring the ball to a stop.&lt;br /&gt;
&lt;br /&gt;
Interestingly, friction is also required for rolling motion. Without friction, objects would not be able to roll. This is true because friction results in torque acting on the object, causing the rolling motion. An example of this can be seen in cars that are stuck in a ditch or similar situations. If there is not enough friction between the car&#039;s wheels and the ground, the car&#039;s wheels will simply spin in place, and the car will not move.&lt;br /&gt;
&lt;br /&gt;
===A Mathematical Model===&lt;br /&gt;
&lt;br /&gt;
As stated above:&lt;br /&gt;
&lt;br /&gt;
Static Friction:&lt;br /&gt;
&lt;br /&gt;
::&amp;lt;math&amp;gt; {F}_{s} \le {&amp;amp;mu;}_{s}{N} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
Kinetic Friction:&lt;br /&gt;
&lt;br /&gt;
::&amp;lt;math&amp;gt; {F}_{k} = {&amp;amp;mu;}_{k}{N} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
When attempting to solve problems relating to friction, one possible method of approach is to consider the net force acting on an object. If there is a force &amp;lt;math&amp;gt; {F}&amp;lt;/math&amp;gt; pushing an object to the right, and a frictional force &amp;lt;math&amp;gt;{F}_{f}&amp;lt;/math&amp;gt; opposing the movement, then the net force is &amp;lt;math&amp;gt; {F}_{net} = {F} - {F}_{f} &amp;lt;/math&amp;gt;.&lt;br /&gt;
&lt;br /&gt;
Another possible approach is by using the momentum principle &amp;lt;math&amp;gt; {p}_{f} - {p}_{i} = {F}_{net}{dt} &amp;lt;/math&amp;gt;. The momentum principle can help solve problems where you need to account for time, net force, or change in momentum.&lt;br /&gt;
&lt;br /&gt;
===A Computational Model===&lt;br /&gt;
&lt;br /&gt;
[[File:Friction.gif]]&lt;br /&gt;
&lt;br /&gt;
Link: &lt;br /&gt;
https://trinket.io/glowscript/76028c1809&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
Code: &lt;br /&gt;
 def friction():&lt;br /&gt;
    from __future__ import division&lt;br /&gt;
    from visual import *&lt;br /&gt;
    from visual.graph import *&lt;br /&gt;
&lt;br /&gt;
    mcart = 100&lt;br /&gt;
    mew = vector(2.9,0,0)&lt;br /&gt;
&lt;br /&gt;
    track =  box(pos=vector(0,-0.05,0), size=vector(20.0,0.05,0.10), color=color.white)&lt;br /&gt;
    cart =  box(pos=vector(-10,0.25,0), size=vector(.5,0.6,0.03), color=color.blue)&lt;br /&gt;
    marker = box(pos = vector(2,0,0), size = vector(0,20,5), color = color.red)&lt;br /&gt;
&lt;br /&gt;
    cart.v=vector(2.4,0,0)&lt;br /&gt;
    cart.p = mcart*cart.v&lt;br /&gt;
    F = vector(90,0,0)&lt;br /&gt;
    F2 = vector(-200,0,0)&lt;br /&gt;
    F3 = (mcart * mew)&lt;br /&gt;
    print(F3)&lt;br /&gt;
&lt;br /&gt;
    deltat = 0.01&lt;br /&gt;
    t = 0&lt;br /&gt;
&lt;br /&gt;
    while t &amp;lt; 5.02:&lt;br /&gt;
&lt;br /&gt;
        if cart.pos.x &amp;lt; 2:&lt;br /&gt;
            cart.v = cart.p / cart.m&lt;br /&gt;
            Fnet = F&lt;br /&gt;
            cart.p = cart.p + Fnet*deltat&lt;br /&gt;
            cart.pos = cart.pos + (cart.p/mcart)*deltat&lt;br /&gt;
&lt;br /&gt;
        else:&lt;br /&gt;
            &lt;br /&gt;
            cart.v = cart.p / cart.m&lt;br /&gt;
            Fnet = F-F3&lt;br /&gt;
            cart.p = cart.p + Fnet*deltat&lt;br /&gt;
            cart.pos = cart.pos + (cart.p/mcart)*deltat&lt;br /&gt;
            &lt;br /&gt;
        t = t + deltat&lt;br /&gt;
        rate(100)&lt;br /&gt;
        &lt;br /&gt;
    print(cart.pos)&lt;br /&gt;
    &lt;br /&gt;
 friction()&lt;br /&gt;
&lt;br /&gt;
==Examples==&lt;br /&gt;
&lt;br /&gt;
Be sure to show all steps in your solution and include diagrams whenever possible&lt;br /&gt;
&lt;br /&gt;
===Simple===&lt;br /&gt;
&lt;br /&gt;
A 100Kg box is placed on a flat table. The box does not move. The coefficient of static friction &amp;lt;math&amp;gt; {&amp;amp;mu;}_{s} = {.25} &amp;lt;/math&amp;gt; and the coefficient of kinetic friction &amp;lt;math&amp;gt; {&amp;amp;mu;}_{k} = {.15} &amp;lt;/math&amp;gt;.&lt;br /&gt;
Find the force of friction &amp;lt;math&amp;gt;{F}_{s}&amp;lt;/math&amp;gt;.&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
Solution:&lt;br /&gt;
&lt;br /&gt;
Since the box does not move, there is only static friction. The normal force is equivalent to the force due to gravity: &amp;lt;math&amp;gt; {F}_{N} = {F}_{g} = {100}{g} &amp;lt;/math&amp;gt;. The static friction can be found by: &amp;lt;math&amp;gt; {F}_{s} = {&amp;amp;mu;}_{s}{F}_{N} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
&amp;lt;math&amp;gt; {F}_{s} = {(.25)}{(100)}{(9.8)} = {245.25} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
===Middling===&lt;br /&gt;
&lt;br /&gt;
A cart of mass 3Kg moves across a track pushed by a fan which exerts &amp;lt;math&amp;gt; {F} = &amp;lt;3,0,1&amp;gt; &amp;lt;/math&amp;gt;N with an initial velocity &amp;lt;math&amp;gt; {v}_{i} = &amp;lt;1,0,1&amp;gt;\frac{{m}}{{s}}&amp;lt;/math&amp;gt; . Find the required coefficient of kinetic friction &amp;lt;math&amp;gt; {&amp;amp;mu;}_{k} &amp;lt;/math&amp;gt; needed to bring the cart to a stop in 10 seconds.&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
Solution:&lt;br /&gt;
&lt;br /&gt;
Use the momentum principle: &amp;lt;math&amp;gt;{p}_{f} - {p}_{i} = {F}_{net}{dt}&amp;lt;/math&amp;gt; and &amp;lt;math&amp;gt;{F}_{f} = {&amp;amp;mu;}_{k}{N} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
The final velocity must be 0. The initial velocity, initial force, and time are given. &lt;br /&gt;
&lt;br /&gt;
&amp;lt;math&amp;gt;0- &amp;lt;3,0,3&amp;gt; = {F}_{net}*{10s}&amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
&amp;lt;math&amp;gt; {F}_{net} = &amp;lt;-0.3,0,-0.3&amp;gt; &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
&amp;lt;math&amp;gt; {F}_{net} = {F} - {F}_{f} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
&amp;lt;math&amp;gt; &amp;lt;-0.3,0,-0.3&amp;gt;  = &amp;lt;3,0,1&amp;gt; - {F}_{f}&amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
&amp;lt;math&amp;gt;{F}_{f}  = &amp;lt;3.3,0,1.3&amp;gt; &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
&amp;lt;math&amp;gt; {F}_{f} = &amp;lt;3.3,0,1.3&amp;gt; = {&amp;amp;mu;}_{k}{N} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
&amp;lt;math&amp;gt; {N} = {3Kg} * {&amp;lt;0,9.8,0&amp;gt;} = &amp;lt;0,29.43,0&amp;gt; &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
&amp;lt;math&amp;gt; {&amp;amp;mu;}_{k} = \frac{{F}_{f}}{{N}} = \frac{{&amp;lt;3.3,0,1.3&amp;gt;}}{{0,29.43,0}} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
===Difficult===&lt;br /&gt;
&lt;br /&gt;
Two blocks are stacked on top of one another on a frictionless surface. Block A is stacked on top of Block B. Block A has a mass of 2 Kg while Block B has a mass of 4 Kg. The coefficient of friction between the blocks is &amp;lt;math&amp;gt; {&amp;amp;mu;}_{s} = .35 &amp;lt;/math&amp;gt;. Find the maximum amount of force that can be applied to Block A so that the blocks stay together.&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
Solution:&lt;br /&gt;
&lt;br /&gt;
Momentum Principle:&lt;br /&gt;
&lt;br /&gt;
&amp;lt;math&amp;gt; {p}_{f} - {p}_{i} = {F}_{net}{dt} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
We need to find the force of friction at its maximum to find the maximum amount of force that can be exerted on Block A. &amp;lt;math&amp;gt; {F}_{f} = {&amp;amp;mu;}_{s}{N} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
Forces on Block A:&lt;br /&gt;
&lt;br /&gt;
&amp;lt;math&amp;gt; {F}_{A} - {F}_{f} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
Forces on Block B:&lt;br /&gt;
&lt;br /&gt;
&amp;lt;math&amp;gt; {F}_{f} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
Since we want the blocks to move together, they must therefore have the same acceleration. &lt;br /&gt;
&lt;br /&gt;
&amp;lt;math&amp;gt; {F}_{A} - {F}_{f} = {2 Kg} * {a} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
&amp;lt;math&amp;gt; {F}_{f} = {4 Kg} * {a} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
&amp;lt;math&amp;gt; {F}_{A} - {F}_{f} = {2 Kg} * {a} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
Since they have the same acceleration, we can use the acceleration to solve for the force applied.&lt;br /&gt;
&lt;br /&gt;
&amp;lt;math&amp;gt; {a} = \frac{{F}_{A} - {F}_{f}}{{2 Kg}} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
&amp;lt;math&amp;gt; {a} = \frac{{F}_{f}}{{4}}  &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
&amp;lt;math&amp;gt;\frac{{F}_{A} - {F}_{f}}{{2 Kg}}= \frac{{F}_{f}}{{4 Kg}} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
&amp;lt;math&amp;gt;{F}_{A}= \frac{{3}}{{2}}{F}_{f} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
 &lt;br /&gt;
==Connectedness==&lt;br /&gt;
&lt;br /&gt;
Friction is an important topic to understand because it has many industrial implications. Since friction can cause increases in temperature when objects move, engineers who work with moving objects must understand and account for friction to ensure systems work properly. For example, car engines must have proper oil and lubricants to prevent parts from scraping together and wearing down. Mechanical engineers, aerospace engineers, and civil engineers must deal with friction and its impacts every day!&lt;br /&gt;
&lt;br /&gt;
== See also ==&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
===External links===&lt;br /&gt;
&lt;br /&gt;
Internet resources on this topic&lt;br /&gt;
&lt;br /&gt;
Hyper Physics: http://hyperphysics.phy-astr.gsu.edu/hbase/frict.html#fri&lt;br /&gt;
&lt;br /&gt;
PHET Simulation: https://phet.colorado.edu/en/simulation/friction&lt;br /&gt;
&lt;br /&gt;
==References==&lt;br /&gt;
[1] Serway, Raymond A., and John W. Jewett. Physics for Scientists and Engineers. Boston, MA: Cengage Brooks/Cole, 2014. Print.&lt;br /&gt;
&lt;br /&gt;
[2] Sherwood, Bruce A. Matter &amp;amp; Interactions. By Ruth W. Chabay. 4th ed. Vol. 1. N.p.: John Wiley &amp;amp; Sons, 2015. 45-50. Print. Modern Mechanics.&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
[[Category:Contact Forces]]&lt;/div&gt;</summary>
		<author><name>Drao31</name></author>
	</entry>
	<entry>
		<id>http://www.physicsbook.gatech.edu/index.php?title=Friction&amp;diff=25037</id>
		<title>Friction</title>
		<link rel="alternate" type="text/html" href="http://www.physicsbook.gatech.edu/index.php?title=Friction&amp;diff=25037"/>
		<updated>2016-11-27T20:40:50Z</updated>

		<summary type="html">&lt;p&gt;Drao31: /* Difficult */&lt;/p&gt;
&lt;hr /&gt;
&lt;div&gt;This page discusses the concept of friction and how it relates to both moving and static objects.&lt;br /&gt;
&lt;br /&gt;
Claimed by drao31&lt;br /&gt;
&lt;br /&gt;
==The Main Idea==&lt;br /&gt;
Friction is caused by the interactions between the atoms that make up objects. When objects interact, the atoms that make up the objects also interact. Temperatures of interacting surfaces rise because of such interactions. Friction is a force that resists movement. Generally, friction makes it harder to move objects. There are two main types of friction that are covered in Physics 2211: Static Friction and Kinetic Friction. Static friction can be described as the friction acting on resting objects. Kinetic friction is the friction acting on objects in motion. &lt;br /&gt;
&lt;br /&gt;
Frictional forces depend on a few factors: the normal force and the coefficient of friction. &lt;br /&gt;
&lt;br /&gt;
In simple terms, the normal force &amp;lt;math&amp;gt; {F}_{N} &amp;lt;/math&amp;gt; or &amp;lt;math&amp;gt; {N} &amp;lt;/math&amp;gt; is the equivalent force between objects. For example, when an object of mass &#039;&#039;&#039;M&#039;&#039;&#039; is placed on a table, there is a gravitational force &#039;&#039;&#039;Mg&#039;&#039;&#039; on the table. If the table can support the object without collapsing, the table exerts an equivalent force &#039;&#039;&#039;Mg&#039;&#039;&#039; on the object. According to the momentum principle, since there is no change in momentum, the net force must be &#039;&#039;&#039;0&#039;&#039;&#039;. This is also apparent since there is no movement if the table can support the object.&lt;br /&gt;
&lt;br /&gt;
::&amp;lt;math&amp;gt; {p}_{f} - {p}_{i} = {F}_{net}{dt} = 0 &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
OR&lt;br /&gt;
&lt;br /&gt;
::&amp;lt;math&amp;gt; {F}_{g} = {M}{g} &amp;lt;/math&amp;gt;&lt;br /&gt;
::&amp;lt;math&amp;gt; {N} = {M}{g} &amp;lt;/math&amp;gt;&lt;br /&gt;
::&amp;lt;math&amp;gt; {F}_{net} = {F}_{g} - {N} = {0} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
The coefficient of friction is usually specific to each object or material. The coefficient of static friction is denoted by &amp;lt;math&amp;gt;{&amp;amp;mu;}_{s}&amp;lt;/math&amp;gt; and the coefficient of kinetic friction is denoted by &amp;lt;math&amp;gt;{&amp;amp;mu;}_{k}&amp;lt;/math&amp;gt; &lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
Static Friction:&lt;br /&gt;
&lt;br /&gt;
::&amp;lt;math&amp;gt; {F}_{s} \le {&amp;amp;mu;}_{s}{N} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
Static friction is the frictional force that must be overcome to begin moving an object at rest. The static friction can be no more than the normal force multiplied by the coefficient of static friction. Therefore, the maximum static friction an object can have is &amp;lt;math&amp;gt; {&amp;amp;mu;}_{s}{N} &amp;lt;/math&amp;gt;. &lt;br /&gt;
&lt;br /&gt;
Kinetic Friction:&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
::&amp;lt;math&amp;gt; {F}_{k} = {&amp;amp;mu;}_{k}{N} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
Kinetic friction is the frictional force that exists between objects already at motion. It acts to oppose the movement of an object. Kinetic friction can be observed, for example, when a soccer ball is kicked across a field. The friction between the ball and the field will eventually bring the ball to a stop.&lt;br /&gt;
&lt;br /&gt;
Interestingly, friction is also required for rolling motion. Without friction, objects would not be able to roll. This is true because friction results in torque acting on the object, causing the rolling motion. An example of this can be seen in cars that are stuck in a ditch or similar situations. If there is not enough friction between the car&#039;s wheels and the ground, the car&#039;s wheels will simply spin in place, and the car will not move.&lt;br /&gt;
&lt;br /&gt;
===A Mathematical Model===&lt;br /&gt;
&lt;br /&gt;
As stated above:&lt;br /&gt;
&lt;br /&gt;
Static Friction:&lt;br /&gt;
&lt;br /&gt;
::&amp;lt;math&amp;gt; {F}_{s} \le {&amp;amp;mu;}_{s}{N} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
Kinetic Friction:&lt;br /&gt;
&lt;br /&gt;
::&amp;lt;math&amp;gt; {F}_{k} = {&amp;amp;mu;}_{k}{N} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
When attempting to solve problems relating to friction, one possible method of approach is to consider the net force acting on an object. If there is a force &amp;lt;math&amp;gt; {F}&amp;lt;/math&amp;gt; pushing an object to the right, and a frictional force &amp;lt;math&amp;gt;{F}_{f}&amp;lt;/math&amp;gt; opposing the movement, then the net force is &amp;lt;math&amp;gt; {F}_{net} = {F} - {F}_{f} &amp;lt;/math&amp;gt;.&lt;br /&gt;
&lt;br /&gt;
Another possible approach is by using the momentum principle &amp;lt;math&amp;gt; {p}_{f} - {p}_{i} = {F}_{net}{dt} &amp;lt;/math&amp;gt;. The momentum principle can help solve problems where you need to account for time, net force, or change in momentum.&lt;br /&gt;
&lt;br /&gt;
===A Computational Model===&lt;br /&gt;
&lt;br /&gt;
[[File:Friction.gif]]&lt;br /&gt;
&lt;br /&gt;
Link: &lt;br /&gt;
https://trinket.io/glowscript/76028c1809&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
Code: &lt;br /&gt;
 def friction():&lt;br /&gt;
    from __future__ import division&lt;br /&gt;
    from visual import *&lt;br /&gt;
    from visual.graph import *&lt;br /&gt;
&lt;br /&gt;
    mcart = 100&lt;br /&gt;
    mew = vector(2.9,0,0)&lt;br /&gt;
&lt;br /&gt;
    track =  box(pos=vector(0,-0.05,0), size=vector(20.0,0.05,0.10), color=color.white)&lt;br /&gt;
    cart =  box(pos=vector(-10,0.25,0), size=vector(.5,0.6,0.03), color=color.blue)&lt;br /&gt;
    marker = box(pos = vector(2,0,0), size = vector(0,20,5), color = color.red)&lt;br /&gt;
&lt;br /&gt;
    cart.v=vector(2.4,0,0)&lt;br /&gt;
    cart.p = mcart*cart.v&lt;br /&gt;
    F = vector(90,0,0)&lt;br /&gt;
    F2 = vector(-200,0,0)&lt;br /&gt;
    F3 = (mcart * mew)&lt;br /&gt;
    print(F3)&lt;br /&gt;
&lt;br /&gt;
    deltat = 0.01&lt;br /&gt;
    t = 0&lt;br /&gt;
&lt;br /&gt;
    while t &amp;lt; 5.02:&lt;br /&gt;
&lt;br /&gt;
        if cart.pos.x &amp;lt; 2:&lt;br /&gt;
            cart.v = cart.p / cart.m&lt;br /&gt;
            Fnet = F&lt;br /&gt;
            cart.p = cart.p + Fnet*deltat&lt;br /&gt;
            cart.pos = cart.pos + (cart.p/mcart)*deltat&lt;br /&gt;
&lt;br /&gt;
        else:&lt;br /&gt;
            &lt;br /&gt;
            cart.v = cart.p / cart.m&lt;br /&gt;
            Fnet = F-F3&lt;br /&gt;
            cart.p = cart.p + Fnet*deltat&lt;br /&gt;
            cart.pos = cart.pos + (cart.p/mcart)*deltat&lt;br /&gt;
            &lt;br /&gt;
        t = t + deltat&lt;br /&gt;
        rate(100)&lt;br /&gt;
        &lt;br /&gt;
    print(cart.pos)&lt;br /&gt;
    &lt;br /&gt;
 friction()&lt;br /&gt;
&lt;br /&gt;
==Examples==&lt;br /&gt;
&lt;br /&gt;
Be sure to show all steps in your solution and include diagrams whenever possible&lt;br /&gt;
&lt;br /&gt;
===Simple===&lt;br /&gt;
&lt;br /&gt;
A 100Kg box is placed on a flat table. The box does not move. The coefficient of static friction &amp;lt;math&amp;gt; {&amp;amp;mu;}_{s} = {.25} &amp;lt;/math&amp;gt; and the coefficient of kinetic friction &amp;lt;math&amp;gt; {&amp;amp;mu;}_{k} = {.15} &amp;lt;/math&amp;gt;.&lt;br /&gt;
Find the force of friction &amp;lt;math&amp;gt;{F}_{s}&amp;lt;/math&amp;gt;.&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
Solution:&lt;br /&gt;
&lt;br /&gt;
Since the box does not move, there is only static friction. The normal force is equivalent to the force due to gravity: &amp;lt;math&amp;gt; {F}_{N} = {F}_{g} = {100}{g} &amp;lt;/math&amp;gt;. The static friction can be found by: &amp;lt;math&amp;gt; {F}_{s} = {&amp;amp;mu;}_{s}{F}_{N} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
&amp;lt;math&amp;gt; {F}_{s} = {(.25)}{(100)}{(9.8)} = {245.25} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
===Middling===&lt;br /&gt;
&lt;br /&gt;
A cart of mass 3Kg moves across a track pushed by a fan which exerts &amp;lt;math&amp;gt; {F} = &amp;lt;3,0,1&amp;gt; &amp;lt;/math&amp;gt;N with an initial velocity &amp;lt;math&amp;gt; {v}_{i} = &amp;lt;1,0,1&amp;gt;\frac{{m}}{{s}}&amp;lt;/math&amp;gt; . Find the required coefficient of kinetic friction &amp;lt;math&amp;gt; {&amp;amp;mu;}_{k} &amp;lt;/math&amp;gt; needed to bring the cart to a stop in 10 seconds.&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
Solution:&lt;br /&gt;
&lt;br /&gt;
Use the momentum principle: &amp;lt;math&amp;gt;{p}_{f} - {p}_{i} = {F}_{net}{dt}&amp;lt;/math&amp;gt; and &amp;lt;math&amp;gt;{F}_{f} = {&amp;amp;mu;}_{k}{N} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
The final velocity must be 0. The initial velocity, initial force, and time are given. &lt;br /&gt;
&lt;br /&gt;
&amp;lt;math&amp;gt;0- &amp;lt;3,0,3&amp;gt; = {F}_{net}*{10s}&amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
&amp;lt;math&amp;gt; {F}_{net} = &amp;lt;-0.3,0,-0.3&amp;gt; &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
&amp;lt;math&amp;gt; {F}_{net} = {F} - {F}_{f} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
&amp;lt;math&amp;gt; &amp;lt;-0.3,0,-0.3&amp;gt;  = &amp;lt;3,0,1&amp;gt; - {F}_{f}&amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
&amp;lt;math&amp;gt;{F}_{f}  = &amp;lt;3.3,0,1.3&amp;gt; &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
&amp;lt;math&amp;gt; {F}_{f} = &amp;lt;3.3,0,1.3&amp;gt; = {&amp;amp;mu;}_{k}{N} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
&amp;lt;math&amp;gt; {N} = {3Kg} * {&amp;lt;0,9.8,0&amp;gt;} = &amp;lt;0,29.43,0&amp;gt; &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
&amp;lt;math&amp;gt; {&amp;amp;mu;}_{k} = \frac{{F}_{f}}{{N}} = \frac{{&amp;lt;3.3,0,1.3&amp;gt;}}{{0,29.43,0}} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
===Difficult===&lt;br /&gt;
&lt;br /&gt;
Two blocks are stacked on top of one another on a frictionless surface. Block A is stacked on top of Block B. Block A has a mass of 2 Kg while Block B has a mass of 4 Kg. The coefficient of friction between the blocks is &amp;lt;math&amp;gt; {&amp;amp;mu;}_{s} = .35 &amp;lt;/math&amp;gt;. Find the maximum amount of force that can be applied to Block B so that Block A does not move at all.&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
Solution:&lt;br /&gt;
&lt;br /&gt;
Momentum Principle:&lt;br /&gt;
&lt;br /&gt;
==Connectedness==&lt;br /&gt;
&lt;br /&gt;
Friction is an important topic to understand because it has many industrial implications. Since friction can cause increases in temperature when objects move, engineers who work with moving objects must understand and account for friction to ensure systems work properly. For example, car engines must have proper oil and lubricants to prevent parts from scraping together and wearing down. Mechanical engineers, aerospace engineers, and civil engineers must deal with friction and its impacts every day!&lt;br /&gt;
&lt;br /&gt;
== See also ==&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
===External links===&lt;br /&gt;
&lt;br /&gt;
Internet resources on this topic&lt;br /&gt;
&lt;br /&gt;
Hyper Physics: http://hyperphysics.phy-astr.gsu.edu/hbase/frict.html#fri&lt;br /&gt;
&lt;br /&gt;
PHET Simulation: https://phet.colorado.edu/en/simulation/friction&lt;br /&gt;
&lt;br /&gt;
==References==&lt;br /&gt;
[1] Serway, Raymond A., and John W. Jewett. Physics for Scientists and Engineers. Boston, MA: Cengage Brooks/Cole, 2014. Print.&lt;br /&gt;
&lt;br /&gt;
[2] Sherwood, Bruce A. Matter &amp;amp; Interactions. By Ruth W. Chabay. 4th ed. Vol. 1. N.p.: John Wiley &amp;amp; Sons, 2015. 45-50. Print. Modern Mechanics.&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
[[Category:Contact Forces]]&lt;/div&gt;</summary>
		<author><name>Drao31</name></author>
	</entry>
	<entry>
		<id>http://www.physicsbook.gatech.edu/index.php?title=Friction&amp;diff=25036</id>
		<title>Friction</title>
		<link rel="alternate" type="text/html" href="http://www.physicsbook.gatech.edu/index.php?title=Friction&amp;diff=25036"/>
		<updated>2016-11-27T20:39:55Z</updated>

		<summary type="html">&lt;p&gt;Drao31: /* Further reading */&lt;/p&gt;
&lt;hr /&gt;
&lt;div&gt;This page discusses the concept of friction and how it relates to both moving and static objects.&lt;br /&gt;
&lt;br /&gt;
Claimed by drao31&lt;br /&gt;
&lt;br /&gt;
==The Main Idea==&lt;br /&gt;
Friction is caused by the interactions between the atoms that make up objects. When objects interact, the atoms that make up the objects also interact. Temperatures of interacting surfaces rise because of such interactions. Friction is a force that resists movement. Generally, friction makes it harder to move objects. There are two main types of friction that are covered in Physics 2211: Static Friction and Kinetic Friction. Static friction can be described as the friction acting on resting objects. Kinetic friction is the friction acting on objects in motion. &lt;br /&gt;
&lt;br /&gt;
Frictional forces depend on a few factors: the normal force and the coefficient of friction. &lt;br /&gt;
&lt;br /&gt;
In simple terms, the normal force &amp;lt;math&amp;gt; {F}_{N} &amp;lt;/math&amp;gt; or &amp;lt;math&amp;gt; {N} &amp;lt;/math&amp;gt; is the equivalent force between objects. For example, when an object of mass &#039;&#039;&#039;M&#039;&#039;&#039; is placed on a table, there is a gravitational force &#039;&#039;&#039;Mg&#039;&#039;&#039; on the table. If the table can support the object without collapsing, the table exerts an equivalent force &#039;&#039;&#039;Mg&#039;&#039;&#039; on the object. According to the momentum principle, since there is no change in momentum, the net force must be &#039;&#039;&#039;0&#039;&#039;&#039;. This is also apparent since there is no movement if the table can support the object.&lt;br /&gt;
&lt;br /&gt;
::&amp;lt;math&amp;gt; {p}_{f} - {p}_{i} = {F}_{net}{dt} = 0 &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
OR&lt;br /&gt;
&lt;br /&gt;
::&amp;lt;math&amp;gt; {F}_{g} = {M}{g} &amp;lt;/math&amp;gt;&lt;br /&gt;
::&amp;lt;math&amp;gt; {N} = {M}{g} &amp;lt;/math&amp;gt;&lt;br /&gt;
::&amp;lt;math&amp;gt; {F}_{net} = {F}_{g} - {N} = {0} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
The coefficient of friction is usually specific to each object or material. The coefficient of static friction is denoted by &amp;lt;math&amp;gt;{&amp;amp;mu;}_{s}&amp;lt;/math&amp;gt; and the coefficient of kinetic friction is denoted by &amp;lt;math&amp;gt;{&amp;amp;mu;}_{k}&amp;lt;/math&amp;gt; &lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
Static Friction:&lt;br /&gt;
&lt;br /&gt;
::&amp;lt;math&amp;gt; {F}_{s} \le {&amp;amp;mu;}_{s}{N} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
Static friction is the frictional force that must be overcome to begin moving an object at rest. The static friction can be no more than the normal force multiplied by the coefficient of static friction. Therefore, the maximum static friction an object can have is &amp;lt;math&amp;gt; {&amp;amp;mu;}_{s}{N} &amp;lt;/math&amp;gt;. &lt;br /&gt;
&lt;br /&gt;
Kinetic Friction:&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
::&amp;lt;math&amp;gt; {F}_{k} = {&amp;amp;mu;}_{k}{N} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
Kinetic friction is the frictional force that exists between objects already at motion. It acts to oppose the movement of an object. Kinetic friction can be observed, for example, when a soccer ball is kicked across a field. The friction between the ball and the field will eventually bring the ball to a stop.&lt;br /&gt;
&lt;br /&gt;
Interestingly, friction is also required for rolling motion. Without friction, objects would not be able to roll. This is true because friction results in torque acting on the object, causing the rolling motion. An example of this can be seen in cars that are stuck in a ditch or similar situations. If there is not enough friction between the car&#039;s wheels and the ground, the car&#039;s wheels will simply spin in place, and the car will not move.&lt;br /&gt;
&lt;br /&gt;
===A Mathematical Model===&lt;br /&gt;
&lt;br /&gt;
As stated above:&lt;br /&gt;
&lt;br /&gt;
Static Friction:&lt;br /&gt;
&lt;br /&gt;
::&amp;lt;math&amp;gt; {F}_{s} \le {&amp;amp;mu;}_{s}{N} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
Kinetic Friction:&lt;br /&gt;
&lt;br /&gt;
::&amp;lt;math&amp;gt; {F}_{k} = {&amp;amp;mu;}_{k}{N} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
When attempting to solve problems relating to friction, one possible method of approach is to consider the net force acting on an object. If there is a force &amp;lt;math&amp;gt; {F}&amp;lt;/math&amp;gt; pushing an object to the right, and a frictional force &amp;lt;math&amp;gt;{F}_{f}&amp;lt;/math&amp;gt; opposing the movement, then the net force is &amp;lt;math&amp;gt; {F}_{net} = {F} - {F}_{f} &amp;lt;/math&amp;gt;.&lt;br /&gt;
&lt;br /&gt;
Another possible approach is by using the momentum principle &amp;lt;math&amp;gt; {p}_{f} - {p}_{i} = {F}_{net}{dt} &amp;lt;/math&amp;gt;. The momentum principle can help solve problems where you need to account for time, net force, or change in momentum.&lt;br /&gt;
&lt;br /&gt;
===A Computational Model===&lt;br /&gt;
&lt;br /&gt;
[[File:Friction.gif]]&lt;br /&gt;
&lt;br /&gt;
Link: &lt;br /&gt;
https://trinket.io/glowscript/76028c1809&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
Code: &lt;br /&gt;
 def friction():&lt;br /&gt;
    from __future__ import division&lt;br /&gt;
    from visual import *&lt;br /&gt;
    from visual.graph import *&lt;br /&gt;
&lt;br /&gt;
    mcart = 100&lt;br /&gt;
    mew = vector(2.9,0,0)&lt;br /&gt;
&lt;br /&gt;
    track =  box(pos=vector(0,-0.05,0), size=vector(20.0,0.05,0.10), color=color.white)&lt;br /&gt;
    cart =  box(pos=vector(-10,0.25,0), size=vector(.5,0.6,0.03), color=color.blue)&lt;br /&gt;
    marker = box(pos = vector(2,0,0), size = vector(0,20,5), color = color.red)&lt;br /&gt;
&lt;br /&gt;
    cart.v=vector(2.4,0,0)&lt;br /&gt;
    cart.p = mcart*cart.v&lt;br /&gt;
    F = vector(90,0,0)&lt;br /&gt;
    F2 = vector(-200,0,0)&lt;br /&gt;
    F3 = (mcart * mew)&lt;br /&gt;
    print(F3)&lt;br /&gt;
&lt;br /&gt;
    deltat = 0.01&lt;br /&gt;
    t = 0&lt;br /&gt;
&lt;br /&gt;
    while t &amp;lt; 5.02:&lt;br /&gt;
&lt;br /&gt;
        if cart.pos.x &amp;lt; 2:&lt;br /&gt;
            cart.v = cart.p / cart.m&lt;br /&gt;
            Fnet = F&lt;br /&gt;
            cart.p = cart.p + Fnet*deltat&lt;br /&gt;
            cart.pos = cart.pos + (cart.p/mcart)*deltat&lt;br /&gt;
&lt;br /&gt;
        else:&lt;br /&gt;
            &lt;br /&gt;
            cart.v = cart.p / cart.m&lt;br /&gt;
            Fnet = F-F3&lt;br /&gt;
            cart.p = cart.p + Fnet*deltat&lt;br /&gt;
            cart.pos = cart.pos + (cart.p/mcart)*deltat&lt;br /&gt;
            &lt;br /&gt;
        t = t + deltat&lt;br /&gt;
        rate(100)&lt;br /&gt;
        &lt;br /&gt;
    print(cart.pos)&lt;br /&gt;
    &lt;br /&gt;
 friction()&lt;br /&gt;
&lt;br /&gt;
==Examples==&lt;br /&gt;
&lt;br /&gt;
Be sure to show all steps in your solution and include diagrams whenever possible&lt;br /&gt;
&lt;br /&gt;
===Simple===&lt;br /&gt;
&lt;br /&gt;
A 100Kg box is placed on a flat table. The box does not move. The coefficient of static friction &amp;lt;math&amp;gt; {&amp;amp;mu;}_{s} = {.25} &amp;lt;/math&amp;gt; and the coefficient of kinetic friction &amp;lt;math&amp;gt; {&amp;amp;mu;}_{k} = {.15} &amp;lt;/math&amp;gt;.&lt;br /&gt;
Find the force of friction &amp;lt;math&amp;gt;{F}_{s}&amp;lt;/math&amp;gt;.&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
Solution:&lt;br /&gt;
&lt;br /&gt;
Since the box does not move, there is only static friction. The normal force is equivalent to the force due to gravity: &amp;lt;math&amp;gt; {F}_{N} = {F}_{g} = {100}{g} &amp;lt;/math&amp;gt;. The static friction can be found by: &amp;lt;math&amp;gt; {F}_{s} = {&amp;amp;mu;}_{s}{F}_{N} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
&amp;lt;math&amp;gt; {F}_{s} = {(.25)}{(100)}{(9.8)} = {245.25} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
===Middling===&lt;br /&gt;
&lt;br /&gt;
A cart of mass 3Kg moves across a track pushed by a fan which exerts &amp;lt;math&amp;gt; {F} = &amp;lt;3,0,1&amp;gt; &amp;lt;/math&amp;gt;N with an initial velocity &amp;lt;math&amp;gt; {v}_{i} = &amp;lt;1,0,1&amp;gt;\frac{{m}}{{s}}&amp;lt;/math&amp;gt; . Find the required coefficient of kinetic friction &amp;lt;math&amp;gt; {&amp;amp;mu;}_{k} &amp;lt;/math&amp;gt; needed to bring the cart to a stop in 10 seconds.&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
Solution:&lt;br /&gt;
&lt;br /&gt;
Use the momentum principle: &amp;lt;math&amp;gt;{p}_{f} - {p}_{i} = {F}_{net}{dt}&amp;lt;/math&amp;gt; and &amp;lt;math&amp;gt;{F}_{f} = {&amp;amp;mu;}_{k}{N} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
The final velocity must be 0. The initial velocity, initial force, and time are given. &lt;br /&gt;
&lt;br /&gt;
&amp;lt;math&amp;gt;0- &amp;lt;3,0,3&amp;gt; = {F}_{net}*{10s}&amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
&amp;lt;math&amp;gt; {F}_{net} = &amp;lt;-0.3,0,-0.3&amp;gt; &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
&amp;lt;math&amp;gt; {F}_{net} = {F} - {F}_{f} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
&amp;lt;math&amp;gt; &amp;lt;-0.3,0,-0.3&amp;gt;  = &amp;lt;3,0,1&amp;gt; - {F}_{f}&amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
&amp;lt;math&amp;gt;{F}_{f}  = &amp;lt;3.3,0,1.3&amp;gt; &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
&amp;lt;math&amp;gt; {F}_{f} = &amp;lt;3.3,0,1.3&amp;gt; = {&amp;amp;mu;}_{k}{N} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
&amp;lt;math&amp;gt; {N} = {3Kg} * {&amp;lt;0,9.8,0&amp;gt;} = &amp;lt;0,29.43,0&amp;gt; &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
&amp;lt;math&amp;gt; {&amp;amp;mu;}_{k} = \frac{{F}_{f}}{{N}} = \frac{{&amp;lt;3.3,0,1.3&amp;gt;}}{{0,29.43,0}} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
===Difficult===&lt;br /&gt;
&lt;br /&gt;
Two blocks are stacked on top of one another on a frictionless surface. Block A is stacked on top of Block B. Block A has a mass of 2 Kg while Block B has a mass of 4 Kg. The coefficient of friction between the blocks is &amp;lt;math&amp;gt; {&amp;amp;mu;}_{s} = .35 &amp;lt;/math&amp;gt;. Find the maximum amount of force that can be applied to Block B so that Block A does not move at all.&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
Solution:&lt;br /&gt;
&lt;br /&gt;
==Connectedness==&lt;br /&gt;
&lt;br /&gt;
Friction is an important topic to understand because it has many industrial implications. Since friction can cause increases in temperature when objects move, engineers who work with moving objects must understand and account for friction to ensure systems work properly. For example, car engines must have proper oil and lubricants to prevent parts from scraping together and wearing down. Mechanical engineers, aerospace engineers, and civil engineers must deal with friction and its impacts every day!&lt;br /&gt;
&lt;br /&gt;
== See also ==&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
===External links===&lt;br /&gt;
&lt;br /&gt;
Internet resources on this topic&lt;br /&gt;
&lt;br /&gt;
Hyper Physics: http://hyperphysics.phy-astr.gsu.edu/hbase/frict.html#fri&lt;br /&gt;
&lt;br /&gt;
PHET Simulation: https://phet.colorado.edu/en/simulation/friction&lt;br /&gt;
&lt;br /&gt;
==References==&lt;br /&gt;
[1] Serway, Raymond A., and John W. Jewett. Physics for Scientists and Engineers. Boston, MA: Cengage Brooks/Cole, 2014. Print.&lt;br /&gt;
&lt;br /&gt;
[2] Sherwood, Bruce A. Matter &amp;amp; Interactions. By Ruth W. Chabay. 4th ed. Vol. 1. N.p.: John Wiley &amp;amp; Sons, 2015. 45-50. Print. Modern Mechanics.&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
[[Category:Contact Forces]]&lt;/div&gt;</summary>
		<author><name>Drao31</name></author>
	</entry>
	<entry>
		<id>http://www.physicsbook.gatech.edu/index.php?title=Friction&amp;diff=25034</id>
		<title>Friction</title>
		<link rel="alternate" type="text/html" href="http://www.physicsbook.gatech.edu/index.php?title=Friction&amp;diff=25034"/>
		<updated>2016-11-27T20:39:18Z</updated>

		<summary type="html">&lt;p&gt;Drao31: /* External links */&lt;/p&gt;
&lt;hr /&gt;
&lt;div&gt;This page discusses the concept of friction and how it relates to both moving and static objects.&lt;br /&gt;
&lt;br /&gt;
Claimed by drao31&lt;br /&gt;
&lt;br /&gt;
==The Main Idea==&lt;br /&gt;
Friction is caused by the interactions between the atoms that make up objects. When objects interact, the atoms that make up the objects also interact. Temperatures of interacting surfaces rise because of such interactions. Friction is a force that resists movement. Generally, friction makes it harder to move objects. There are two main types of friction that are covered in Physics 2211: Static Friction and Kinetic Friction. Static friction can be described as the friction acting on resting objects. Kinetic friction is the friction acting on objects in motion. &lt;br /&gt;
&lt;br /&gt;
Frictional forces depend on a few factors: the normal force and the coefficient of friction. &lt;br /&gt;
&lt;br /&gt;
In simple terms, the normal force &amp;lt;math&amp;gt; {F}_{N} &amp;lt;/math&amp;gt; or &amp;lt;math&amp;gt; {N} &amp;lt;/math&amp;gt; is the equivalent force between objects. For example, when an object of mass &#039;&#039;&#039;M&#039;&#039;&#039; is placed on a table, there is a gravitational force &#039;&#039;&#039;Mg&#039;&#039;&#039; on the table. If the table can support the object without collapsing, the table exerts an equivalent force &#039;&#039;&#039;Mg&#039;&#039;&#039; on the object. According to the momentum principle, since there is no change in momentum, the net force must be &#039;&#039;&#039;0&#039;&#039;&#039;. This is also apparent since there is no movement if the table can support the object.&lt;br /&gt;
&lt;br /&gt;
::&amp;lt;math&amp;gt; {p}_{f} - {p}_{i} = {F}_{net}{dt} = 0 &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
OR&lt;br /&gt;
&lt;br /&gt;
::&amp;lt;math&amp;gt; {F}_{g} = {M}{g} &amp;lt;/math&amp;gt;&lt;br /&gt;
::&amp;lt;math&amp;gt; {N} = {M}{g} &amp;lt;/math&amp;gt;&lt;br /&gt;
::&amp;lt;math&amp;gt; {F}_{net} = {F}_{g} - {N} = {0} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
The coefficient of friction is usually specific to each object or material. The coefficient of static friction is denoted by &amp;lt;math&amp;gt;{&amp;amp;mu;}_{s}&amp;lt;/math&amp;gt; and the coefficient of kinetic friction is denoted by &amp;lt;math&amp;gt;{&amp;amp;mu;}_{k}&amp;lt;/math&amp;gt; &lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
Static Friction:&lt;br /&gt;
&lt;br /&gt;
::&amp;lt;math&amp;gt; {F}_{s} \le {&amp;amp;mu;}_{s}{N} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
Static friction is the frictional force that must be overcome to begin moving an object at rest. The static friction can be no more than the normal force multiplied by the coefficient of static friction. Therefore, the maximum static friction an object can have is &amp;lt;math&amp;gt; {&amp;amp;mu;}_{s}{N} &amp;lt;/math&amp;gt;. &lt;br /&gt;
&lt;br /&gt;
Kinetic Friction:&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
::&amp;lt;math&amp;gt; {F}_{k} = {&amp;amp;mu;}_{k}{N} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
Kinetic friction is the frictional force that exists between objects already at motion. It acts to oppose the movement of an object. Kinetic friction can be observed, for example, when a soccer ball is kicked across a field. The friction between the ball and the field will eventually bring the ball to a stop.&lt;br /&gt;
&lt;br /&gt;
Interestingly, friction is also required for rolling motion. Without friction, objects would not be able to roll. This is true because friction results in torque acting on the object, causing the rolling motion. An example of this can be seen in cars that are stuck in a ditch or similar situations. If there is not enough friction between the car&#039;s wheels and the ground, the car&#039;s wheels will simply spin in place, and the car will not move.&lt;br /&gt;
&lt;br /&gt;
===A Mathematical Model===&lt;br /&gt;
&lt;br /&gt;
As stated above:&lt;br /&gt;
&lt;br /&gt;
Static Friction:&lt;br /&gt;
&lt;br /&gt;
::&amp;lt;math&amp;gt; {F}_{s} \le {&amp;amp;mu;}_{s}{N} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
Kinetic Friction:&lt;br /&gt;
&lt;br /&gt;
::&amp;lt;math&amp;gt; {F}_{k} = {&amp;amp;mu;}_{k}{N} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
When attempting to solve problems relating to friction, one possible method of approach is to consider the net force acting on an object. If there is a force &amp;lt;math&amp;gt; {F}&amp;lt;/math&amp;gt; pushing an object to the right, and a frictional force &amp;lt;math&amp;gt;{F}_{f}&amp;lt;/math&amp;gt; opposing the movement, then the net force is &amp;lt;math&amp;gt; {F}_{net} = {F} - {F}_{f} &amp;lt;/math&amp;gt;.&lt;br /&gt;
&lt;br /&gt;
Another possible approach is by using the momentum principle &amp;lt;math&amp;gt; {p}_{f} - {p}_{i} = {F}_{net}{dt} &amp;lt;/math&amp;gt;. The momentum principle can help solve problems where you need to account for time, net force, or change in momentum.&lt;br /&gt;
&lt;br /&gt;
===A Computational Model===&lt;br /&gt;
&lt;br /&gt;
[[File:Friction.gif]]&lt;br /&gt;
&lt;br /&gt;
Link: &lt;br /&gt;
https://trinket.io/glowscript/76028c1809&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
Code: &lt;br /&gt;
 def friction():&lt;br /&gt;
    from __future__ import division&lt;br /&gt;
    from visual import *&lt;br /&gt;
    from visual.graph import *&lt;br /&gt;
&lt;br /&gt;
    mcart = 100&lt;br /&gt;
    mew = vector(2.9,0,0)&lt;br /&gt;
&lt;br /&gt;
    track =  box(pos=vector(0,-0.05,0), size=vector(20.0,0.05,0.10), color=color.white)&lt;br /&gt;
    cart =  box(pos=vector(-10,0.25,0), size=vector(.5,0.6,0.03), color=color.blue)&lt;br /&gt;
    marker = box(pos = vector(2,0,0), size = vector(0,20,5), color = color.red)&lt;br /&gt;
&lt;br /&gt;
    cart.v=vector(2.4,0,0)&lt;br /&gt;
    cart.p = mcart*cart.v&lt;br /&gt;
    F = vector(90,0,0)&lt;br /&gt;
    F2 = vector(-200,0,0)&lt;br /&gt;
    F3 = (mcart * mew)&lt;br /&gt;
    print(F3)&lt;br /&gt;
&lt;br /&gt;
    deltat = 0.01&lt;br /&gt;
    t = 0&lt;br /&gt;
&lt;br /&gt;
    while t &amp;lt; 5.02:&lt;br /&gt;
&lt;br /&gt;
        if cart.pos.x &amp;lt; 2:&lt;br /&gt;
            cart.v = cart.p / cart.m&lt;br /&gt;
            Fnet = F&lt;br /&gt;
            cart.p = cart.p + Fnet*deltat&lt;br /&gt;
            cart.pos = cart.pos + (cart.p/mcart)*deltat&lt;br /&gt;
&lt;br /&gt;
        else:&lt;br /&gt;
            &lt;br /&gt;
            cart.v = cart.p / cart.m&lt;br /&gt;
            Fnet = F-F3&lt;br /&gt;
            cart.p = cart.p + Fnet*deltat&lt;br /&gt;
            cart.pos = cart.pos + (cart.p/mcart)*deltat&lt;br /&gt;
            &lt;br /&gt;
        t = t + deltat&lt;br /&gt;
        rate(100)&lt;br /&gt;
        &lt;br /&gt;
    print(cart.pos)&lt;br /&gt;
    &lt;br /&gt;
 friction()&lt;br /&gt;
&lt;br /&gt;
==Examples==&lt;br /&gt;
&lt;br /&gt;
Be sure to show all steps in your solution and include diagrams whenever possible&lt;br /&gt;
&lt;br /&gt;
===Simple===&lt;br /&gt;
&lt;br /&gt;
A 100Kg box is placed on a flat table. The box does not move. The coefficient of static friction &amp;lt;math&amp;gt; {&amp;amp;mu;}_{s} = {.25} &amp;lt;/math&amp;gt; and the coefficient of kinetic friction &amp;lt;math&amp;gt; {&amp;amp;mu;}_{k} = {.15} &amp;lt;/math&amp;gt;.&lt;br /&gt;
Find the force of friction &amp;lt;math&amp;gt;{F}_{s}&amp;lt;/math&amp;gt;.&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
Solution:&lt;br /&gt;
&lt;br /&gt;
Since the box does not move, there is only static friction. The normal force is equivalent to the force due to gravity: &amp;lt;math&amp;gt; {F}_{N} = {F}_{g} = {100}{g} &amp;lt;/math&amp;gt;. The static friction can be found by: &amp;lt;math&amp;gt; {F}_{s} = {&amp;amp;mu;}_{s}{F}_{N} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
&amp;lt;math&amp;gt; {F}_{s} = {(.25)}{(100)}{(9.8)} = {245.25} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
===Middling===&lt;br /&gt;
&lt;br /&gt;
A cart of mass 3Kg moves across a track pushed by a fan which exerts &amp;lt;math&amp;gt; {F} = &amp;lt;3,0,1&amp;gt; &amp;lt;/math&amp;gt;N with an initial velocity &amp;lt;math&amp;gt; {v}_{i} = &amp;lt;1,0,1&amp;gt;\frac{{m}}{{s}}&amp;lt;/math&amp;gt; . Find the required coefficient of kinetic friction &amp;lt;math&amp;gt; {&amp;amp;mu;}_{k} &amp;lt;/math&amp;gt; needed to bring the cart to a stop in 10 seconds.&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
Solution:&lt;br /&gt;
&lt;br /&gt;
Use the momentum principle: &amp;lt;math&amp;gt;{p}_{f} - {p}_{i} = {F}_{net}{dt}&amp;lt;/math&amp;gt; and &amp;lt;math&amp;gt;{F}_{f} = {&amp;amp;mu;}_{k}{N} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
The final velocity must be 0. The initial velocity, initial force, and time are given. &lt;br /&gt;
&lt;br /&gt;
&amp;lt;math&amp;gt;0- &amp;lt;3,0,3&amp;gt; = {F}_{net}*{10s}&amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
&amp;lt;math&amp;gt; {F}_{net} = &amp;lt;-0.3,0,-0.3&amp;gt; &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
&amp;lt;math&amp;gt; {F}_{net} = {F} - {F}_{f} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
&amp;lt;math&amp;gt; &amp;lt;-0.3,0,-0.3&amp;gt;  = &amp;lt;3,0,1&amp;gt; - {F}_{f}&amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
&amp;lt;math&amp;gt;{F}_{f}  = &amp;lt;3.3,0,1.3&amp;gt; &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
&amp;lt;math&amp;gt; {F}_{f} = &amp;lt;3.3,0,1.3&amp;gt; = {&amp;amp;mu;}_{k}{N} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
&amp;lt;math&amp;gt; {N} = {3Kg} * {&amp;lt;0,9.8,0&amp;gt;} = &amp;lt;0,29.43,0&amp;gt; &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
&amp;lt;math&amp;gt; {&amp;amp;mu;}_{k} = \frac{{F}_{f}}{{N}} = \frac{{&amp;lt;3.3,0,1.3&amp;gt;}}{{0,29.43,0}} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
===Difficult===&lt;br /&gt;
&lt;br /&gt;
Two blocks are stacked on top of one another on a frictionless surface. Block A is stacked on top of Block B. Block A has a mass of 2 Kg while Block B has a mass of 4 Kg. The coefficient of friction between the blocks is &amp;lt;math&amp;gt; {&amp;amp;mu;}_{s} = .35 &amp;lt;/math&amp;gt;. Find the maximum amount of force that can be applied to Block B so that Block A does not move at all.&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
Solution:&lt;br /&gt;
&lt;br /&gt;
==Connectedness==&lt;br /&gt;
&lt;br /&gt;
Friction is an important topic to understand because it has many industrial implications. Since friction can cause increases in temperature when objects move, engineers who work with moving objects must understand and account for friction to ensure systems work properly. For example, car engines must have proper oil and lubricants to prevent parts from scraping together and wearing down. Mechanical engineers, aerospace engineers, and civil engineers must deal with friction and its impacts every day!&lt;br /&gt;
&lt;br /&gt;
== See also ==&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
===Further reading===&lt;br /&gt;
&lt;br /&gt;
Books, Articles or other print media on this topic&lt;br /&gt;
&lt;br /&gt;
===External links===&lt;br /&gt;
&lt;br /&gt;
Internet resources on this topic&lt;br /&gt;
&lt;br /&gt;
Hyper Physics: http://hyperphysics.phy-astr.gsu.edu/hbase/frict.html#fri&lt;br /&gt;
&lt;br /&gt;
PHET Simulation: https://phet.colorado.edu/en/simulation/friction&lt;br /&gt;
&lt;br /&gt;
==References==&lt;br /&gt;
[1] Serway, Raymond A., and John W. Jewett. Physics for Scientists and Engineers. Boston, MA: Cengage Brooks/Cole, 2014. Print.&lt;br /&gt;
&lt;br /&gt;
[2] Sherwood, Bruce A. Matter &amp;amp; Interactions. By Ruth W. Chabay. 4th ed. Vol. 1. N.p.: John Wiley &amp;amp; Sons, 2015. 45-50. Print. Modern Mechanics.&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
[[Category:Contact Forces]]&lt;/div&gt;</summary>
		<author><name>Drao31</name></author>
	</entry>
	<entry>
		<id>http://www.physicsbook.gatech.edu/index.php?title=Friction&amp;diff=25030</id>
		<title>Friction</title>
		<link rel="alternate" type="text/html" href="http://www.physicsbook.gatech.edu/index.php?title=Friction&amp;diff=25030"/>
		<updated>2016-11-27T20:36:35Z</updated>

		<summary type="html">&lt;p&gt;Drao31: &lt;/p&gt;
&lt;hr /&gt;
&lt;div&gt;This page discusses the concept of friction and how it relates to both moving and static objects.&lt;br /&gt;
&lt;br /&gt;
Claimed by drao31&lt;br /&gt;
&lt;br /&gt;
==The Main Idea==&lt;br /&gt;
Friction is caused by the interactions between the atoms that make up objects. When objects interact, the atoms that make up the objects also interact. Temperatures of interacting surfaces rise because of such interactions. Friction is a force that resists movement. Generally, friction makes it harder to move objects. There are two main types of friction that are covered in Physics 2211: Static Friction and Kinetic Friction. Static friction can be described as the friction acting on resting objects. Kinetic friction is the friction acting on objects in motion. &lt;br /&gt;
&lt;br /&gt;
Frictional forces depend on a few factors: the normal force and the coefficient of friction. &lt;br /&gt;
&lt;br /&gt;
In simple terms, the normal force &amp;lt;math&amp;gt; {F}_{N} &amp;lt;/math&amp;gt; or &amp;lt;math&amp;gt; {N} &amp;lt;/math&amp;gt; is the equivalent force between objects. For example, when an object of mass &#039;&#039;&#039;M&#039;&#039;&#039; is placed on a table, there is a gravitational force &#039;&#039;&#039;Mg&#039;&#039;&#039; on the table. If the table can support the object without collapsing, the table exerts an equivalent force &#039;&#039;&#039;Mg&#039;&#039;&#039; on the object. According to the momentum principle, since there is no change in momentum, the net force must be &#039;&#039;&#039;0&#039;&#039;&#039;. This is also apparent since there is no movement if the table can support the object.&lt;br /&gt;
&lt;br /&gt;
::&amp;lt;math&amp;gt; {p}_{f} - {p}_{i} = {F}_{net}{dt} = 0 &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
OR&lt;br /&gt;
&lt;br /&gt;
::&amp;lt;math&amp;gt; {F}_{g} = {M}{g} &amp;lt;/math&amp;gt;&lt;br /&gt;
::&amp;lt;math&amp;gt; {N} = {M}{g} &amp;lt;/math&amp;gt;&lt;br /&gt;
::&amp;lt;math&amp;gt; {F}_{net} = {F}_{g} - {N} = {0} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
The coefficient of friction is usually specific to each object or material. The coefficient of static friction is denoted by &amp;lt;math&amp;gt;{&amp;amp;mu;}_{s}&amp;lt;/math&amp;gt; and the coefficient of kinetic friction is denoted by &amp;lt;math&amp;gt;{&amp;amp;mu;}_{k}&amp;lt;/math&amp;gt; &lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
Static Friction:&lt;br /&gt;
&lt;br /&gt;
::&amp;lt;math&amp;gt; {F}_{s} \le {&amp;amp;mu;}_{s}{N} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
Static friction is the frictional force that must be overcome to begin moving an object at rest. The static friction can be no more than the normal force multiplied by the coefficient of static friction. Therefore, the maximum static friction an object can have is &amp;lt;math&amp;gt; {&amp;amp;mu;}_{s}{N} &amp;lt;/math&amp;gt;. &lt;br /&gt;
&lt;br /&gt;
Kinetic Friction:&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
::&amp;lt;math&amp;gt; {F}_{k} = {&amp;amp;mu;}_{k}{N} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
Kinetic friction is the frictional force that exists between objects already at motion. It acts to oppose the movement of an object. Kinetic friction can be observed, for example, when a soccer ball is kicked across a field. The friction between the ball and the field will eventually bring the ball to a stop.&lt;br /&gt;
&lt;br /&gt;
Interestingly, friction is also required for rolling motion. Without friction, objects would not be able to roll. This is true because friction results in torque acting on the object, causing the rolling motion. An example of this can be seen in cars that are stuck in a ditch or similar situations. If there is not enough friction between the car&#039;s wheels and the ground, the car&#039;s wheels will simply spin in place, and the car will not move.&lt;br /&gt;
&lt;br /&gt;
===A Mathematical Model===&lt;br /&gt;
&lt;br /&gt;
As stated above:&lt;br /&gt;
&lt;br /&gt;
Static Friction:&lt;br /&gt;
&lt;br /&gt;
::&amp;lt;math&amp;gt; {F}_{s} \le {&amp;amp;mu;}_{s}{N} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
Kinetic Friction:&lt;br /&gt;
&lt;br /&gt;
::&amp;lt;math&amp;gt; {F}_{k} = {&amp;amp;mu;}_{k}{N} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
When attempting to solve problems relating to friction, one possible method of approach is to consider the net force acting on an object. If there is a force &amp;lt;math&amp;gt; {F}&amp;lt;/math&amp;gt; pushing an object to the right, and a frictional force &amp;lt;math&amp;gt;{F}_{f}&amp;lt;/math&amp;gt; opposing the movement, then the net force is &amp;lt;math&amp;gt; {F}_{net} = {F} - {F}_{f} &amp;lt;/math&amp;gt;.&lt;br /&gt;
&lt;br /&gt;
Another possible approach is by using the momentum principle &amp;lt;math&amp;gt; {p}_{f} - {p}_{i} = {F}_{net}{dt} &amp;lt;/math&amp;gt;. The momentum principle can help solve problems where you need to account for time, net force, or change in momentum.&lt;br /&gt;
&lt;br /&gt;
===A Computational Model===&lt;br /&gt;
&lt;br /&gt;
[[File:Friction.gif]]&lt;br /&gt;
&lt;br /&gt;
Link: &lt;br /&gt;
https://trinket.io/glowscript/76028c1809&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
Code: &lt;br /&gt;
 def friction():&lt;br /&gt;
    from __future__ import division&lt;br /&gt;
    from visual import *&lt;br /&gt;
    from visual.graph import *&lt;br /&gt;
&lt;br /&gt;
    mcart = 100&lt;br /&gt;
    mew = vector(2.9,0,0)&lt;br /&gt;
&lt;br /&gt;
    track =  box(pos=vector(0,-0.05,0), size=vector(20.0,0.05,0.10), color=color.white)&lt;br /&gt;
    cart =  box(pos=vector(-10,0.25,0), size=vector(.5,0.6,0.03), color=color.blue)&lt;br /&gt;
    marker = box(pos = vector(2,0,0), size = vector(0,20,5), color = color.red)&lt;br /&gt;
&lt;br /&gt;
    cart.v=vector(2.4,0,0)&lt;br /&gt;
    cart.p = mcart*cart.v&lt;br /&gt;
    F = vector(90,0,0)&lt;br /&gt;
    F2 = vector(-200,0,0)&lt;br /&gt;
    F3 = (mcart * mew)&lt;br /&gt;
    print(F3)&lt;br /&gt;
&lt;br /&gt;
    deltat = 0.01&lt;br /&gt;
    t = 0&lt;br /&gt;
&lt;br /&gt;
    while t &amp;lt; 5.02:&lt;br /&gt;
&lt;br /&gt;
        if cart.pos.x &amp;lt; 2:&lt;br /&gt;
            cart.v = cart.p / cart.m&lt;br /&gt;
            Fnet = F&lt;br /&gt;
            cart.p = cart.p + Fnet*deltat&lt;br /&gt;
            cart.pos = cart.pos + (cart.p/mcart)*deltat&lt;br /&gt;
&lt;br /&gt;
        else:&lt;br /&gt;
            &lt;br /&gt;
            cart.v = cart.p / cart.m&lt;br /&gt;
            Fnet = F-F3&lt;br /&gt;
            cart.p = cart.p + Fnet*deltat&lt;br /&gt;
            cart.pos = cart.pos + (cart.p/mcart)*deltat&lt;br /&gt;
            &lt;br /&gt;
        t = t + deltat&lt;br /&gt;
        rate(100)&lt;br /&gt;
        &lt;br /&gt;
    print(cart.pos)&lt;br /&gt;
    &lt;br /&gt;
 friction()&lt;br /&gt;
&lt;br /&gt;
==Examples==&lt;br /&gt;
&lt;br /&gt;
Be sure to show all steps in your solution and include diagrams whenever possible&lt;br /&gt;
&lt;br /&gt;
===Simple===&lt;br /&gt;
&lt;br /&gt;
A 100Kg box is placed on a flat table. The box does not move. The coefficient of static friction &amp;lt;math&amp;gt; {&amp;amp;mu;}_{s} = {.25} &amp;lt;/math&amp;gt; and the coefficient of kinetic friction &amp;lt;math&amp;gt; {&amp;amp;mu;}_{k} = {.15} &amp;lt;/math&amp;gt;.&lt;br /&gt;
Find the force of friction &amp;lt;math&amp;gt;{F}_{s}&amp;lt;/math&amp;gt;.&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
Solution:&lt;br /&gt;
&lt;br /&gt;
Since the box does not move, there is only static friction. The normal force is equivalent to the force due to gravity: &amp;lt;math&amp;gt; {F}_{N} = {F}_{g} = {100}{g} &amp;lt;/math&amp;gt;. The static friction can be found by: &amp;lt;math&amp;gt; {F}_{s} = {&amp;amp;mu;}_{s}{F}_{N} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
&amp;lt;math&amp;gt; {F}_{s} = {(.25)}{(100)}{(9.8)} = {245.25} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
===Middling===&lt;br /&gt;
&lt;br /&gt;
A cart of mass 3Kg moves across a track pushed by a fan which exerts &amp;lt;math&amp;gt; {F} = &amp;lt;3,0,1&amp;gt; &amp;lt;/math&amp;gt;N with an initial velocity &amp;lt;math&amp;gt; {v}_{i} = &amp;lt;1,0,1&amp;gt;\frac{{m}}{{s}}&amp;lt;/math&amp;gt; . Find the required coefficient of kinetic friction &amp;lt;math&amp;gt; {&amp;amp;mu;}_{k} &amp;lt;/math&amp;gt; needed to bring the cart to a stop in 10 seconds.&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
Solution:&lt;br /&gt;
&lt;br /&gt;
Use the momentum principle: &amp;lt;math&amp;gt;{p}_{f} - {p}_{i} = {F}_{net}{dt}&amp;lt;/math&amp;gt; and &amp;lt;math&amp;gt;{F}_{f} = {&amp;amp;mu;}_{k}{N} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
The final velocity must be 0. The initial velocity, initial force, and time are given. &lt;br /&gt;
&lt;br /&gt;
&amp;lt;math&amp;gt;0- &amp;lt;3,0,3&amp;gt; = {F}_{net}*{10s}&amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
&amp;lt;math&amp;gt; {F}_{net} = &amp;lt;-0.3,0,-0.3&amp;gt; &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
&amp;lt;math&amp;gt; {F}_{net} = {F} - {F}_{f} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
&amp;lt;math&amp;gt; &amp;lt;-0.3,0,-0.3&amp;gt;  = &amp;lt;3,0,1&amp;gt; - {F}_{f}&amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
&amp;lt;math&amp;gt;{F}_{f}  = &amp;lt;3.3,0,1.3&amp;gt; &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
&amp;lt;math&amp;gt; {F}_{f} = &amp;lt;3.3,0,1.3&amp;gt; = {&amp;amp;mu;}_{k}{N} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
&amp;lt;math&amp;gt; {N} = {3Kg} * {&amp;lt;0,9.8,0&amp;gt;} = &amp;lt;0,29.43,0&amp;gt; &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
&amp;lt;math&amp;gt; {&amp;amp;mu;}_{k} = \frac{{F}_{f}}{{N}} = \frac{{&amp;lt;3.3,0,1.3&amp;gt;}}{{0,29.43,0}} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
===Difficult===&lt;br /&gt;
&lt;br /&gt;
Two blocks are stacked on top of one another on a frictionless surface. Block A is stacked on top of Block B. Block A has a mass of 2 Kg while Block B has a mass of 4 Kg. The coefficient of friction between the blocks is &amp;lt;math&amp;gt; {&amp;amp;mu;}_{s} = .35 &amp;lt;/math&amp;gt;. Find the maximum amount of force that can be applied to Block B so that Block A does not move at all.&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
Solution:&lt;br /&gt;
&lt;br /&gt;
==Connectedness==&lt;br /&gt;
&lt;br /&gt;
Friction is an important topic to understand because it has many industrial implications. Since friction can cause increases in temperature when objects move, engineers who work with moving objects must understand and account for friction to ensure systems work properly. For example, car engines must have proper oil and lubricants to prevent parts from scraping together and wearing down. Mechanical engineers, aerospace engineers, and civil engineers must deal with friction and its impacts every day!&lt;br /&gt;
&lt;br /&gt;
== See also ==&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
===Further reading===&lt;br /&gt;
&lt;br /&gt;
Books, Articles or other print media on this topic&lt;br /&gt;
&lt;br /&gt;
===External links===&lt;br /&gt;
&lt;br /&gt;
Internet resources on this topic&lt;br /&gt;
&lt;br /&gt;
Hyper Physics: http://hyperphysics.phy-astr.gsu.edu/hbase/frict.html#fri&lt;br /&gt;
&lt;br /&gt;
==References==&lt;br /&gt;
[1] Serway, Raymond A., and John W. Jewett. Physics for Scientists and Engineers. Boston, MA: Cengage Brooks/Cole, 2014. Print.&lt;br /&gt;
&lt;br /&gt;
[2] Sherwood, Bruce A. Matter &amp;amp; Interactions. By Ruth W. Chabay. 4th ed. Vol. 1. N.p.: John Wiley &amp;amp; Sons, 2015. 45-50. Print. Modern Mechanics.&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
[[Category:Contact Forces]]&lt;/div&gt;</summary>
		<author><name>Drao31</name></author>
	</entry>
	<entry>
		<id>http://www.physicsbook.gatech.edu/index.php?title=Friction&amp;diff=25027</id>
		<title>Friction</title>
		<link rel="alternate" type="text/html" href="http://www.physicsbook.gatech.edu/index.php?title=Friction&amp;diff=25027"/>
		<updated>2016-11-27T20:35:37Z</updated>

		<summary type="html">&lt;p&gt;Drao31: /* References */&lt;/p&gt;
&lt;hr /&gt;
&lt;div&gt;This page discusses the concept of friction and how it relates to both moving and static objects.&lt;br /&gt;
&lt;br /&gt;
Claimed by drao31&lt;br /&gt;
&lt;br /&gt;
==The Main Idea==&lt;br /&gt;
Friction is caused by the interactions between the atoms that make up objects. When objects interact, the atoms that make up the objects also interact. Temperatures of interacting surfaces rise because of such interactions. Friction is a force that resists movement. Generally, friction makes it harder to move objects. There are two main types of friction that are covered in Physics 2211: Static Friction and Kinetic Friction. Static friction can be described as the friction acting on resting objects. Kinetic friction is the friction acting on objects in motion. &lt;br /&gt;
&lt;br /&gt;
Frictional forces depend on a few factors: the normal force and the coefficient of friction. &lt;br /&gt;
&lt;br /&gt;
In simple terms, the normal force &amp;lt;math&amp;gt; {F}_{N} &amp;lt;/math&amp;gt; or &amp;lt;math&amp;gt; {N} &amp;lt;/math&amp;gt; is the equivalent force between objects. For example, when an object of mass &#039;&#039;&#039;M&#039;&#039;&#039; is placed on a table, there is a gravitational force &#039;&#039;&#039;Mg&#039;&#039;&#039; on the table. If the table can support the object without collapsing, the table exerts an equivalent force &#039;&#039;&#039;Mg&#039;&#039;&#039; on the object. According to the momentum principle, since there is no change in momentum, the net force must be &#039;&#039;&#039;0&#039;&#039;&#039;. This is also apparent since there is no movement if the table can support the object.&lt;br /&gt;
&lt;br /&gt;
::&amp;lt;math&amp;gt; {p}_{f} - {p}_{i} = {F}_{net}{dt} = 0 &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
OR&lt;br /&gt;
&lt;br /&gt;
::&amp;lt;math&amp;gt; {F}_{g} = {M}{g} &amp;lt;/math&amp;gt;&lt;br /&gt;
::&amp;lt;math&amp;gt; {N} = {M}{g} &amp;lt;/math&amp;gt;&lt;br /&gt;
::&amp;lt;math&amp;gt; {F}_{net} = {F}_{g} - {N} = {0} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
The coefficient of friction is usually specific to each object or material. The coefficient of static friction is denoted by &amp;lt;math&amp;gt;{&amp;amp;mu;}_{s}&amp;lt;/math&amp;gt; and the coefficient of kinetic friction is denoted by &amp;lt;math&amp;gt;{&amp;amp;mu;}_{k}&amp;lt;/math&amp;gt; &lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
Static Friction:&lt;br /&gt;
&lt;br /&gt;
::&amp;lt;math&amp;gt; {F}_{s} \le {&amp;amp;mu;}_{s}{N} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
Static friction is the frictional force that must be overcome to begin moving an object at rest. The static friction can be no more than the normal force multiplied by the coefficient of static friction. Therefore, the maximum static friction an object can have is &amp;lt;math&amp;gt; {&amp;amp;mu;}_{s}{N} &amp;lt;/math&amp;gt;. &lt;br /&gt;
&lt;br /&gt;
Kinetic Friction:&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
::&amp;lt;math&amp;gt; {F}_{k} = {&amp;amp;mu;}_{k}{N} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
Kinetic friction is the frictional force that exists between objects already at motion. It acts to oppose the movement of an object. Kinetic friction can be observed, for example, when a soccer ball is kicked across a field. The friction between the ball and the field will eventually bring the ball to a stop.&lt;br /&gt;
&lt;br /&gt;
Interestingly, friction is also required for rolling motion. Without friction, objects would not be able to roll. This is true because friction results in torque acting on the object, causing the rolling motion. An example of this can be seen in cars that are stuck in a ditch or similar situations. If there is not enough friction between the car&#039;s wheels and the ground, the car&#039;s wheels will simply spin in place, and the car will not move.&lt;br /&gt;
&lt;br /&gt;
===A Mathematical Model===&lt;br /&gt;
&lt;br /&gt;
As stated above:&lt;br /&gt;
&lt;br /&gt;
Static Friction:&lt;br /&gt;
&lt;br /&gt;
::&amp;lt;math&amp;gt; {F}_{s} \le {&amp;amp;mu;}_{s}{N} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
Kinetic Friction:&lt;br /&gt;
&lt;br /&gt;
::&amp;lt;math&amp;gt; {F}_{k} = {&amp;amp;mu;}_{k}{N} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
When attempting to solve problems relating to friction, one possible method of approach is to consider the net force acting on an object. If there is a force &amp;lt;math&amp;gt; {F}&amp;lt;/math&amp;gt; pushing an object to the right, and a frictional force &amp;lt;math&amp;gt;{F}_{f}&amp;lt;/math&amp;gt; opposing the movement, then the net force is &amp;lt;math&amp;gt; {F}_{net} = {F} - {F}_{f} &amp;lt;/math&amp;gt;.&lt;br /&gt;
&lt;br /&gt;
Another possible approach is by using the momentum principle &amp;lt;math&amp;gt; {p}_{f} - {p}_{i} = {F}_{net}{dt} &amp;lt;/math&amp;gt;. The momentum principle can help solve problems where you need to account for time, net force, or change in momentum.&lt;br /&gt;
&lt;br /&gt;
===A Computational Model===&lt;br /&gt;
&lt;br /&gt;
[[File:Friction.gif]]&lt;br /&gt;
&lt;br /&gt;
Link: &lt;br /&gt;
https://trinket.io/glowscript/76028c1809&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
Code: &lt;br /&gt;
 def friction():&lt;br /&gt;
    from __future__ import division&lt;br /&gt;
    from visual import *&lt;br /&gt;
    from visual.graph import *&lt;br /&gt;
&lt;br /&gt;
    mcart = 100&lt;br /&gt;
    mew = vector(2.9,0,0)&lt;br /&gt;
&lt;br /&gt;
    track =  box(pos=vector(0,-0.05,0), size=vector(20.0,0.05,0.10), color=color.white)&lt;br /&gt;
    cart =  box(pos=vector(-10,0.25,0), size=vector(.5,0.6,0.03), color=color.blue)&lt;br /&gt;
    marker = box(pos = vector(2,0,0), size = vector(0,20,5), color = color.red)&lt;br /&gt;
&lt;br /&gt;
    cart.v=vector(2.4,0,0)&lt;br /&gt;
    cart.p = mcart*cart.v&lt;br /&gt;
    F = vector(90,0,0)&lt;br /&gt;
    F2 = vector(-200,0,0)&lt;br /&gt;
    F3 = (mcart * mew)&lt;br /&gt;
    print(F3)&lt;br /&gt;
&lt;br /&gt;
    deltat = 0.01&lt;br /&gt;
    t = 0&lt;br /&gt;
&lt;br /&gt;
    while t &amp;lt; 5.02:&lt;br /&gt;
&lt;br /&gt;
        if cart.pos.x &amp;lt; 2:&lt;br /&gt;
            cart.v = cart.p / cart.m&lt;br /&gt;
            Fnet = F&lt;br /&gt;
            cart.p = cart.p + Fnet*deltat&lt;br /&gt;
            cart.pos = cart.pos + (cart.p/mcart)*deltat&lt;br /&gt;
&lt;br /&gt;
        else:&lt;br /&gt;
            &lt;br /&gt;
            cart.v = cart.p / cart.m&lt;br /&gt;
            Fnet = F-F3&lt;br /&gt;
            cart.p = cart.p + Fnet*deltat&lt;br /&gt;
            cart.pos = cart.pos + (cart.p/mcart)*deltat&lt;br /&gt;
            &lt;br /&gt;
        t = t + deltat&lt;br /&gt;
        rate(100)&lt;br /&gt;
        &lt;br /&gt;
    print(cart.pos)&lt;br /&gt;
    &lt;br /&gt;
 friction()&lt;br /&gt;
&lt;br /&gt;
==Examples==&lt;br /&gt;
&lt;br /&gt;
Be sure to show all steps in your solution and include diagrams whenever possible&lt;br /&gt;
&lt;br /&gt;
===Simple===&lt;br /&gt;
&lt;br /&gt;
A 100Kg box is placed on a flat table. The box does not move. The coefficient of static friction &amp;lt;math&amp;gt; {&amp;amp;mu;}_{s} = {.25} &amp;lt;/math&amp;gt; and the coefficient of kinetic friction &amp;lt;math&amp;gt; {&amp;amp;mu;}_{k} = {.15} &amp;lt;/math&amp;gt;.&lt;br /&gt;
Find the force of friction &amp;lt;math&amp;gt;{F}_{s}&amp;lt;/math&amp;gt;.&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
Solution:&lt;br /&gt;
&lt;br /&gt;
Since the box does not move, there is only static friction. The normal force is equivalent to the force due to gravity: &amp;lt;math&amp;gt; {F}_{N} = {F}_{g} = {100}{g} &amp;lt;/math&amp;gt;. The static friction can be found by: &amp;lt;math&amp;gt; {F}_{s} = {&amp;amp;mu;}_{s}{F}_{N} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
&amp;lt;math&amp;gt; {F}_{s} = {(.25)}{(100)}{(9.8)} = {245.25} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
===Middling===&lt;br /&gt;
&lt;br /&gt;
A cart of mass 3Kg moves across a track pushed by a fan which exerts &amp;lt;math&amp;gt; {F} = &amp;lt;3,0,1&amp;gt; &amp;lt;/math&amp;gt;N with an initial velocity &amp;lt;math&amp;gt; {v}_{i} = &amp;lt;1,0,1&amp;gt;\frac{{m}}{{s}}&amp;lt;/math&amp;gt; . Find the required coefficient of kinetic friction &amp;lt;math&amp;gt; {&amp;amp;mu;}_{k} &amp;lt;/math&amp;gt; needed to bring the cart to a stop in 10 seconds.&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
Solution:&lt;br /&gt;
&lt;br /&gt;
Use the momentum principle: &amp;lt;math&amp;gt;{p}_{f} - {p}_{i} = {F}_{net}{dt}&amp;lt;/math&amp;gt; and &amp;lt;math&amp;gt;{F}_{f} = {&amp;amp;mu;}_{k}{N} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
The final velocity must be 0. The initial velocity, initial force, and time are given. &lt;br /&gt;
&lt;br /&gt;
&amp;lt;math&amp;gt;0- &amp;lt;3,0,3&amp;gt; = {F}_{net}*{10s}&amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
&amp;lt;math&amp;gt; {F}_{net} = &amp;lt;-0.3,0,-0.3&amp;gt; &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
&amp;lt;math&amp;gt; {F}_{net} = {F} - {F}_{f} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
&amp;lt;math&amp;gt; &amp;lt;-0.3,0,-0.3&amp;gt;  = &amp;lt;3,0,1&amp;gt; - {F}_{f}&amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
&amp;lt;math&amp;gt;{F}_{f}  = &amp;lt;3.3,0,1.3&amp;gt; &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
&amp;lt;math&amp;gt; {F}_{f} = &amp;lt;3.3,0,1.3&amp;gt; = {&amp;amp;mu;}_{k}{N} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
&amp;lt;math&amp;gt; {N} = {3Kg} * {&amp;lt;0,9.8,0&amp;gt;} = &amp;lt;0,29.43,0&amp;gt; &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
&amp;lt;math&amp;gt; {&amp;amp;mu;}_{k} = \frac{{F}_{f}}{{N}} = \frac{{&amp;lt;3.3,0,1.3&amp;gt;}}{{0,29.43,0}} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
===Difficult===&lt;br /&gt;
&lt;br /&gt;
Two blocks are stacked on top of one another on a frictionless surface. Block A is stacked on top of Block B. Block A has a mass of 2 Kg while Block B has a mass of 4 Kg. The coefficient of friction between the blocks is &amp;lt;math&amp;gt; {&amp;amp;mu;}_{s} = .35 &amp;lt;/math&amp;gt;. Find the maximum amount of force that can be applied to Block B so that Block A does not move at all.&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
Solution:&lt;br /&gt;
&lt;br /&gt;
==Connectedness==&lt;br /&gt;
&lt;br /&gt;
Friction is an important topic to understand because it has many industrial implications. Since friction can cause increases in temperature when objects move, engineers who work with moving objects must understand and account for friction to ensure systems work properly. For example, car engines must have proper oil and lubricants to prevent parts from scraping together and wearing down. Mechanical engineers, aerospace engineers, and civil engineers must deal with friction and its impacts every day!&lt;br /&gt;
&lt;br /&gt;
== See also ==&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
===Further reading===&lt;br /&gt;
&lt;br /&gt;
Books, Articles or other print media on this topic&lt;br /&gt;
&lt;br /&gt;
===External links===&lt;br /&gt;
&lt;br /&gt;
Internet resources on this topic&lt;br /&gt;
&lt;br /&gt;
Hyper Physics: http://hyperphysics.phy-astr.gsu.edu/hbase/frict.html#fri&lt;br /&gt;
&lt;br /&gt;
==References==&lt;br /&gt;
&lt;br /&gt;
This section contains the the references you used while writing this page&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
==References==&lt;br /&gt;
[1] Serway, Raymond A., and John W. Jewett. Physics for Scientists and Engineers. Boston, MA: Cengage Brooks/Cole, 2014. Print.&lt;br /&gt;
[2] Sherwood, Bruce A. Matter &amp;amp; Interactions. By Ruth W. Chabay. 4th ed. Vol. 1. N.p.: John Wiley &amp;amp; Sons, 2015. 45-50. Print. Modern Mechanics.&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
[[Category:Contact Forces]]&lt;/div&gt;</summary>
		<author><name>Drao31</name></author>
	</entry>
	<entry>
		<id>http://www.physicsbook.gatech.edu/index.php?title=Friction&amp;diff=25020</id>
		<title>Friction</title>
		<link rel="alternate" type="text/html" href="http://www.physicsbook.gatech.edu/index.php?title=Friction&amp;diff=25020"/>
		<updated>2016-11-27T20:27:49Z</updated>

		<summary type="html">&lt;p&gt;Drao31: /* External links */&lt;/p&gt;
&lt;hr /&gt;
&lt;div&gt;This page discusses the concept of friction and how it relates to both moving and static objects.&lt;br /&gt;
&lt;br /&gt;
Claimed by drao31&lt;br /&gt;
&lt;br /&gt;
==The Main Idea==&lt;br /&gt;
Friction is caused by the interactions between the atoms that make up objects. When objects interact, the atoms that make up the objects also interact. Temperatures of interacting surfaces rise because of such interactions. Friction is a force that resists movement. Generally, friction makes it harder to move objects. There are two main types of friction that are covered in Physics 2211: Static Friction and Kinetic Friction. Static friction can be described as the friction acting on resting objects. Kinetic friction is the friction acting on objects in motion. &lt;br /&gt;
&lt;br /&gt;
Frictional forces depend on a few factors: the normal force and the coefficient of friction. &lt;br /&gt;
&lt;br /&gt;
In simple terms, the normal force &amp;lt;math&amp;gt; {F}_{N} &amp;lt;/math&amp;gt; or &amp;lt;math&amp;gt; {N} &amp;lt;/math&amp;gt; is the equivalent force between objects. For example, when an object of mass &#039;&#039;&#039;M&#039;&#039;&#039; is placed on a table, there is a gravitational force &#039;&#039;&#039;Mg&#039;&#039;&#039; on the table. If the table can support the object without collapsing, the table exerts an equivalent force &#039;&#039;&#039;Mg&#039;&#039;&#039; on the object. According to the momentum principle, since there is no change in momentum, the net force must be &#039;&#039;&#039;0&#039;&#039;&#039;. This is also apparent since there is no movement if the table can support the object.&lt;br /&gt;
&lt;br /&gt;
::&amp;lt;math&amp;gt; {p}_{f} - {p}_{i} = {F}_{net}{dt} = 0 &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
OR&lt;br /&gt;
&lt;br /&gt;
::&amp;lt;math&amp;gt; {F}_{g} = {M}{g} &amp;lt;/math&amp;gt;&lt;br /&gt;
::&amp;lt;math&amp;gt; {N} = {M}{g} &amp;lt;/math&amp;gt;&lt;br /&gt;
::&amp;lt;math&amp;gt; {F}_{net} = {F}_{g} - {N} = {0} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
The coefficient of friction is usually specific to each object or material. The coefficient of static friction is denoted by &amp;lt;math&amp;gt;{&amp;amp;mu;}_{s}&amp;lt;/math&amp;gt; and the coefficient of kinetic friction is denoted by &amp;lt;math&amp;gt;{&amp;amp;mu;}_{k}&amp;lt;/math&amp;gt; &lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
Static Friction:&lt;br /&gt;
&lt;br /&gt;
::&amp;lt;math&amp;gt; {F}_{s} \le {&amp;amp;mu;}_{s}{N} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
Static friction is the frictional force that must be overcome to begin moving an object at rest. The static friction can be no more than the normal force multiplied by the coefficient of static friction. Therefore, the maximum static friction an object can have is &amp;lt;math&amp;gt; {&amp;amp;mu;}_{s}{N} &amp;lt;/math&amp;gt;. &lt;br /&gt;
&lt;br /&gt;
Kinetic Friction:&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
::&amp;lt;math&amp;gt; {F}_{k} = {&amp;amp;mu;}_{k}{N} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
Kinetic friction is the frictional force that exists between objects already at motion. It acts to oppose the movement of an object. Kinetic friction can be observed, for example, when a soccer ball is kicked across a field. The friction between the ball and the field will eventually bring the ball to a stop.&lt;br /&gt;
&lt;br /&gt;
Interestingly, friction is also required for rolling motion. Without friction, objects would not be able to roll. This is true because friction results in torque acting on the object, causing the rolling motion. An example of this can be seen in cars that are stuck in a ditch or similar situations. If there is not enough friction between the car&#039;s wheels and the ground, the car&#039;s wheels will simply spin in place, and the car will not move.&lt;br /&gt;
&lt;br /&gt;
===A Mathematical Model===&lt;br /&gt;
&lt;br /&gt;
As stated above:&lt;br /&gt;
&lt;br /&gt;
Static Friction:&lt;br /&gt;
&lt;br /&gt;
::&amp;lt;math&amp;gt; {F}_{s} \le {&amp;amp;mu;}_{s}{N} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
Kinetic Friction:&lt;br /&gt;
&lt;br /&gt;
::&amp;lt;math&amp;gt; {F}_{k} = {&amp;amp;mu;}_{k}{N} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
When attempting to solve problems relating to friction, one possible method of approach is to consider the net force acting on an object. If there is a force &amp;lt;math&amp;gt; {F}&amp;lt;/math&amp;gt; pushing an object to the right, and a frictional force &amp;lt;math&amp;gt;{F}_{f}&amp;lt;/math&amp;gt; opposing the movement, then the net force is &amp;lt;math&amp;gt; {F}_{net} = {F} - {F}_{f} &amp;lt;/math&amp;gt;.&lt;br /&gt;
&lt;br /&gt;
Another possible approach is by using the momentum principle &amp;lt;math&amp;gt; {p}_{f} - {p}_{i} = {F}_{net}{dt} &amp;lt;/math&amp;gt;. The momentum principle can help solve problems where you need to account for time, net force, or change in momentum.&lt;br /&gt;
&lt;br /&gt;
===A Computational Model===&lt;br /&gt;
&lt;br /&gt;
[[File:Friction.gif]]&lt;br /&gt;
&lt;br /&gt;
Link: &lt;br /&gt;
https://trinket.io/glowscript/76028c1809&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
Code: &lt;br /&gt;
 def friction():&lt;br /&gt;
    from __future__ import division&lt;br /&gt;
    from visual import *&lt;br /&gt;
    from visual.graph import *&lt;br /&gt;
&lt;br /&gt;
    mcart = 100&lt;br /&gt;
    mew = vector(2.9,0,0)&lt;br /&gt;
&lt;br /&gt;
    track =  box(pos=vector(0,-0.05,0), size=vector(20.0,0.05,0.10), color=color.white)&lt;br /&gt;
    cart =  box(pos=vector(-10,0.25,0), size=vector(.5,0.6,0.03), color=color.blue)&lt;br /&gt;
    marker = box(pos = vector(2,0,0), size = vector(0,20,5), color = color.red)&lt;br /&gt;
&lt;br /&gt;
    cart.v=vector(2.4,0,0)&lt;br /&gt;
    cart.p = mcart*cart.v&lt;br /&gt;
    F = vector(90,0,0)&lt;br /&gt;
    F2 = vector(-200,0,0)&lt;br /&gt;
    F3 = (mcart * mew)&lt;br /&gt;
    print(F3)&lt;br /&gt;
&lt;br /&gt;
    deltat = 0.01&lt;br /&gt;
    t = 0&lt;br /&gt;
&lt;br /&gt;
    while t &amp;lt; 5.02:&lt;br /&gt;
&lt;br /&gt;
        if cart.pos.x &amp;lt; 2:&lt;br /&gt;
            cart.v = cart.p / cart.m&lt;br /&gt;
            Fnet = F&lt;br /&gt;
            cart.p = cart.p + Fnet*deltat&lt;br /&gt;
            cart.pos = cart.pos + (cart.p/mcart)*deltat&lt;br /&gt;
&lt;br /&gt;
        else:&lt;br /&gt;
            &lt;br /&gt;
            cart.v = cart.p / cart.m&lt;br /&gt;
            Fnet = F-F3&lt;br /&gt;
            cart.p = cart.p + Fnet*deltat&lt;br /&gt;
            cart.pos = cart.pos + (cart.p/mcart)*deltat&lt;br /&gt;
            &lt;br /&gt;
        t = t + deltat&lt;br /&gt;
        rate(100)&lt;br /&gt;
        &lt;br /&gt;
    print(cart.pos)&lt;br /&gt;
    &lt;br /&gt;
 friction()&lt;br /&gt;
&lt;br /&gt;
==Examples==&lt;br /&gt;
&lt;br /&gt;
Be sure to show all steps in your solution and include diagrams whenever possible&lt;br /&gt;
&lt;br /&gt;
===Simple===&lt;br /&gt;
&lt;br /&gt;
A 100Kg box is placed on a flat table. The box does not move. The coefficient of static friction &amp;lt;math&amp;gt; {&amp;amp;mu;}_{s} = {.25} &amp;lt;/math&amp;gt; and the coefficient of kinetic friction &amp;lt;math&amp;gt; {&amp;amp;mu;}_{k} = {.15} &amp;lt;/math&amp;gt;.&lt;br /&gt;
Find the force of friction &amp;lt;math&amp;gt;{F}_{s}&amp;lt;/math&amp;gt;.&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
Solution:&lt;br /&gt;
&lt;br /&gt;
Since the box does not move, there is only static friction. The normal force is equivalent to the force due to gravity: &amp;lt;math&amp;gt; {F}_{N} = {F}_{g} = {100}{g} &amp;lt;/math&amp;gt;. The static friction can be found by: &amp;lt;math&amp;gt; {F}_{s} = {&amp;amp;mu;}_{s}{F}_{N} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
&amp;lt;math&amp;gt; {F}_{s} = {(.25)}{(100)}{(9.8)} = {245.25} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
===Middling===&lt;br /&gt;
&lt;br /&gt;
A cart of mass 3Kg moves across a track pushed by a fan which exerts &amp;lt;math&amp;gt; {F} = &amp;lt;3,0,1&amp;gt; &amp;lt;/math&amp;gt;N with an initial velocity &amp;lt;math&amp;gt; {v}_{i} = &amp;lt;1,0,1&amp;gt;\frac{{m}}{{s}}&amp;lt;/math&amp;gt; . Find the required coefficient of kinetic friction &amp;lt;math&amp;gt; {&amp;amp;mu;}_{k} &amp;lt;/math&amp;gt; needed to bring the cart to a stop in 10 seconds.&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
Solution:&lt;br /&gt;
&lt;br /&gt;
Use the momentum principle: &amp;lt;math&amp;gt;{p}_{f} - {p}_{i} = {F}_{net}{dt}&amp;lt;/math&amp;gt; and &amp;lt;math&amp;gt;{F}_{f} = {&amp;amp;mu;}_{k}{N} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
The final velocity must be 0. The initial velocity, initial force, and time are given. &lt;br /&gt;
&lt;br /&gt;
&amp;lt;math&amp;gt;0- &amp;lt;3,0,3&amp;gt; = {F}_{net}*{10s}&amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
&amp;lt;math&amp;gt; {F}_{net} = &amp;lt;-0.3,0,-0.3&amp;gt; &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
&amp;lt;math&amp;gt; {F}_{net} = {F} - {F}_{f} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
&amp;lt;math&amp;gt; &amp;lt;-0.3,0,-0.3&amp;gt;  = &amp;lt;3,0,1&amp;gt; - {F}_{f}&amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
&amp;lt;math&amp;gt;{F}_{f}  = &amp;lt;3.3,0,1.3&amp;gt; &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
&amp;lt;math&amp;gt; {F}_{f} = &amp;lt;3.3,0,1.3&amp;gt; = {&amp;amp;mu;}_{k}{N} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
&amp;lt;math&amp;gt; {N} = {3Kg} * {&amp;lt;0,9.8,0&amp;gt;} = &amp;lt;0,29.43,0&amp;gt; &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
&amp;lt;math&amp;gt; {&amp;amp;mu;}_{k} = \frac{{F}_{f}}{{N}} = \frac{{&amp;lt;3.3,0,1.3&amp;gt;}}{{0,29.43,0}} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
===Difficult===&lt;br /&gt;
&lt;br /&gt;
Two blocks are stacked on top of one another on a frictionless surface. Block A is stacked on top of Block B. Block A has a mass of 2 Kg while Block B has a mass of 4 Kg. The coefficient of friction between the blocks is &amp;lt;math&amp;gt; {&amp;amp;mu;}_{s} = .35 &amp;lt;/math&amp;gt;. Find the maximum amount of force that can be applied to Block B so that Block A does not move at all.&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
Solution:&lt;br /&gt;
&lt;br /&gt;
==Connectedness==&lt;br /&gt;
&lt;br /&gt;
Friction is an important topic to understand because it has many industrial implications. Since friction can cause increases in temperature when objects move, engineers who work with moving objects must understand and account for friction to ensure systems work properly. For example, car engines must have proper oil and lubricants to prevent parts from scraping together and wearing down. Mechanical engineers, aerospace engineers, and civil engineers must deal with friction and its impacts every day!&lt;br /&gt;
&lt;br /&gt;
== See also ==&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
===Further reading===&lt;br /&gt;
&lt;br /&gt;
Books, Articles or other print media on this topic&lt;br /&gt;
&lt;br /&gt;
===External links===&lt;br /&gt;
&lt;br /&gt;
Internet resources on this topic&lt;br /&gt;
&lt;br /&gt;
Hyper Physics: http://hyperphysics.phy-astr.gsu.edu/hbase/frict.html#fri&lt;br /&gt;
&lt;br /&gt;
==References==&lt;br /&gt;
&lt;br /&gt;
This section contains the the references you used while writing this page&lt;br /&gt;
&lt;br /&gt;
[[Category:Contact Forces]]&lt;/div&gt;</summary>
		<author><name>Drao31</name></author>
	</entry>
	<entry>
		<id>http://www.physicsbook.gatech.edu/index.php?title=Friction&amp;diff=25016</id>
		<title>Friction</title>
		<link rel="alternate" type="text/html" href="http://www.physicsbook.gatech.edu/index.php?title=Friction&amp;diff=25016"/>
		<updated>2016-11-27T20:26:38Z</updated>

		<summary type="html">&lt;p&gt;Drao31: /* External links */&lt;/p&gt;
&lt;hr /&gt;
&lt;div&gt;This page discusses the concept of friction and how it relates to both moving and static objects.&lt;br /&gt;
&lt;br /&gt;
Claimed by drao31&lt;br /&gt;
&lt;br /&gt;
==The Main Idea==&lt;br /&gt;
Friction is caused by the interactions between the atoms that make up objects. When objects interact, the atoms that make up the objects also interact. Temperatures of interacting surfaces rise because of such interactions. Friction is a force that resists movement. Generally, friction makes it harder to move objects. There are two main types of friction that are covered in Physics 2211: Static Friction and Kinetic Friction. Static friction can be described as the friction acting on resting objects. Kinetic friction is the friction acting on objects in motion. &lt;br /&gt;
&lt;br /&gt;
Frictional forces depend on a few factors: the normal force and the coefficient of friction. &lt;br /&gt;
&lt;br /&gt;
In simple terms, the normal force &amp;lt;math&amp;gt; {F}_{N} &amp;lt;/math&amp;gt; or &amp;lt;math&amp;gt; {N} &amp;lt;/math&amp;gt; is the equivalent force between objects. For example, when an object of mass &#039;&#039;&#039;M&#039;&#039;&#039; is placed on a table, there is a gravitational force &#039;&#039;&#039;Mg&#039;&#039;&#039; on the table. If the table can support the object without collapsing, the table exerts an equivalent force &#039;&#039;&#039;Mg&#039;&#039;&#039; on the object. According to the momentum principle, since there is no change in momentum, the net force must be &#039;&#039;&#039;0&#039;&#039;&#039;. This is also apparent since there is no movement if the table can support the object.&lt;br /&gt;
&lt;br /&gt;
::&amp;lt;math&amp;gt; {p}_{f} - {p}_{i} = {F}_{net}{dt} = 0 &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
OR&lt;br /&gt;
&lt;br /&gt;
::&amp;lt;math&amp;gt; {F}_{g} = {M}{g} &amp;lt;/math&amp;gt;&lt;br /&gt;
::&amp;lt;math&amp;gt; {N} = {M}{g} &amp;lt;/math&amp;gt;&lt;br /&gt;
::&amp;lt;math&amp;gt; {F}_{net} = {F}_{g} - {N} = {0} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
The coefficient of friction is usually specific to each object or material. The coefficient of static friction is denoted by &amp;lt;math&amp;gt;{&amp;amp;mu;}_{s}&amp;lt;/math&amp;gt; and the coefficient of kinetic friction is denoted by &amp;lt;math&amp;gt;{&amp;amp;mu;}_{k}&amp;lt;/math&amp;gt; &lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
Static Friction:&lt;br /&gt;
&lt;br /&gt;
::&amp;lt;math&amp;gt; {F}_{s} \le {&amp;amp;mu;}_{s}{N} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
Static friction is the frictional force that must be overcome to begin moving an object at rest. The static friction can be no more than the normal force multiplied by the coefficient of static friction. Therefore, the maximum static friction an object can have is &amp;lt;math&amp;gt; {&amp;amp;mu;}_{s}{N} &amp;lt;/math&amp;gt;. &lt;br /&gt;
&lt;br /&gt;
Kinetic Friction:&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
::&amp;lt;math&amp;gt; {F}_{k} = {&amp;amp;mu;}_{k}{N} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
Kinetic friction is the frictional force that exists between objects already at motion. It acts to oppose the movement of an object. Kinetic friction can be observed, for example, when a soccer ball is kicked across a field. The friction between the ball and the field will eventually bring the ball to a stop.&lt;br /&gt;
&lt;br /&gt;
Interestingly, friction is also required for rolling motion. Without friction, objects would not be able to roll. This is true because friction results in torque acting on the object, causing the rolling motion. An example of this can be seen in cars that are stuck in a ditch or similar situations. If there is not enough friction between the car&#039;s wheels and the ground, the car&#039;s wheels will simply spin in place, and the car will not move.&lt;br /&gt;
&lt;br /&gt;
===A Mathematical Model===&lt;br /&gt;
&lt;br /&gt;
As stated above:&lt;br /&gt;
&lt;br /&gt;
Static Friction:&lt;br /&gt;
&lt;br /&gt;
::&amp;lt;math&amp;gt; {F}_{s} \le {&amp;amp;mu;}_{s}{N} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
Kinetic Friction:&lt;br /&gt;
&lt;br /&gt;
::&amp;lt;math&amp;gt; {F}_{k} = {&amp;amp;mu;}_{k}{N} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
When attempting to solve problems relating to friction, one possible method of approach is to consider the net force acting on an object. If there is a force &amp;lt;math&amp;gt; {F}&amp;lt;/math&amp;gt; pushing an object to the right, and a frictional force &amp;lt;math&amp;gt;{F}_{f}&amp;lt;/math&amp;gt; opposing the movement, then the net force is &amp;lt;math&amp;gt; {F}_{net} = {F} - {F}_{f} &amp;lt;/math&amp;gt;.&lt;br /&gt;
&lt;br /&gt;
Another possible approach is by using the momentum principle &amp;lt;math&amp;gt; {p}_{f} - {p}_{i} = {F}_{net}{dt} &amp;lt;/math&amp;gt;. The momentum principle can help solve problems where you need to account for time, net force, or change in momentum.&lt;br /&gt;
&lt;br /&gt;
===A Computational Model===&lt;br /&gt;
&lt;br /&gt;
[[File:Friction.gif]]&lt;br /&gt;
&lt;br /&gt;
Link: &lt;br /&gt;
https://trinket.io/glowscript/76028c1809&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
Code: &lt;br /&gt;
 def friction():&lt;br /&gt;
    from __future__ import division&lt;br /&gt;
    from visual import *&lt;br /&gt;
    from visual.graph import *&lt;br /&gt;
&lt;br /&gt;
    mcart = 100&lt;br /&gt;
    mew = vector(2.9,0,0)&lt;br /&gt;
&lt;br /&gt;
    track =  box(pos=vector(0,-0.05,0), size=vector(20.0,0.05,0.10), color=color.white)&lt;br /&gt;
    cart =  box(pos=vector(-10,0.25,0), size=vector(.5,0.6,0.03), color=color.blue)&lt;br /&gt;
    marker = box(pos = vector(2,0,0), size = vector(0,20,5), color = color.red)&lt;br /&gt;
&lt;br /&gt;
    cart.v=vector(2.4,0,0)&lt;br /&gt;
    cart.p = mcart*cart.v&lt;br /&gt;
    F = vector(90,0,0)&lt;br /&gt;
    F2 = vector(-200,0,0)&lt;br /&gt;
    F3 = (mcart * mew)&lt;br /&gt;
    print(F3)&lt;br /&gt;
&lt;br /&gt;
    deltat = 0.01&lt;br /&gt;
    t = 0&lt;br /&gt;
&lt;br /&gt;
    while t &amp;lt; 5.02:&lt;br /&gt;
&lt;br /&gt;
        if cart.pos.x &amp;lt; 2:&lt;br /&gt;
            cart.v = cart.p / cart.m&lt;br /&gt;
            Fnet = F&lt;br /&gt;
            cart.p = cart.p + Fnet*deltat&lt;br /&gt;
            cart.pos = cart.pos + (cart.p/mcart)*deltat&lt;br /&gt;
&lt;br /&gt;
        else:&lt;br /&gt;
            &lt;br /&gt;
            cart.v = cart.p / cart.m&lt;br /&gt;
            Fnet = F-F3&lt;br /&gt;
            cart.p = cart.p + Fnet*deltat&lt;br /&gt;
            cart.pos = cart.pos + (cart.p/mcart)*deltat&lt;br /&gt;
            &lt;br /&gt;
        t = t + deltat&lt;br /&gt;
        rate(100)&lt;br /&gt;
        &lt;br /&gt;
    print(cart.pos)&lt;br /&gt;
    &lt;br /&gt;
 friction()&lt;br /&gt;
&lt;br /&gt;
==Examples==&lt;br /&gt;
&lt;br /&gt;
Be sure to show all steps in your solution and include diagrams whenever possible&lt;br /&gt;
&lt;br /&gt;
===Simple===&lt;br /&gt;
&lt;br /&gt;
A 100Kg box is placed on a flat table. The box does not move. The coefficient of static friction &amp;lt;math&amp;gt; {&amp;amp;mu;}_{s} = {.25} &amp;lt;/math&amp;gt; and the coefficient of kinetic friction &amp;lt;math&amp;gt; {&amp;amp;mu;}_{k} = {.15} &amp;lt;/math&amp;gt;.&lt;br /&gt;
Find the force of friction &amp;lt;math&amp;gt;{F}_{s}&amp;lt;/math&amp;gt;.&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
Solution:&lt;br /&gt;
&lt;br /&gt;
Since the box does not move, there is only static friction. The normal force is equivalent to the force due to gravity: &amp;lt;math&amp;gt; {F}_{N} = {F}_{g} = {100}{g} &amp;lt;/math&amp;gt;. The static friction can be found by: &amp;lt;math&amp;gt; {F}_{s} = {&amp;amp;mu;}_{s}{F}_{N} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
&amp;lt;math&amp;gt; {F}_{s} = {(.25)}{(100)}{(9.8)} = {245.25} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
===Middling===&lt;br /&gt;
&lt;br /&gt;
A cart of mass 3Kg moves across a track pushed by a fan which exerts &amp;lt;math&amp;gt; {F} = &amp;lt;3,0,1&amp;gt; &amp;lt;/math&amp;gt;N with an initial velocity &amp;lt;math&amp;gt; {v}_{i} = &amp;lt;1,0,1&amp;gt;\frac{{m}}{{s}}&amp;lt;/math&amp;gt; . Find the required coefficient of kinetic friction &amp;lt;math&amp;gt; {&amp;amp;mu;}_{k} &amp;lt;/math&amp;gt; needed to bring the cart to a stop in 10 seconds.&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
Solution:&lt;br /&gt;
&lt;br /&gt;
Use the momentum principle: &amp;lt;math&amp;gt;{p}_{f} - {p}_{i} = {F}_{net}{dt}&amp;lt;/math&amp;gt; and &amp;lt;math&amp;gt;{F}_{f} = {&amp;amp;mu;}_{k}{N} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
The final velocity must be 0. The initial velocity, initial force, and time are given. &lt;br /&gt;
&lt;br /&gt;
&amp;lt;math&amp;gt;0- &amp;lt;3,0,3&amp;gt; = {F}_{net}*{10s}&amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
&amp;lt;math&amp;gt; {F}_{net} = &amp;lt;-0.3,0,-0.3&amp;gt; &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
&amp;lt;math&amp;gt; {F}_{net} = {F} - {F}_{f} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
&amp;lt;math&amp;gt; &amp;lt;-0.3,0,-0.3&amp;gt;  = &amp;lt;3,0,1&amp;gt; - {F}_{f}&amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
&amp;lt;math&amp;gt;{F}_{f}  = &amp;lt;3.3,0,1.3&amp;gt; &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
&amp;lt;math&amp;gt; {F}_{f} = &amp;lt;3.3,0,1.3&amp;gt; = {&amp;amp;mu;}_{k}{N} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
&amp;lt;math&amp;gt; {N} = {3Kg} * {&amp;lt;0,9.8,0&amp;gt;} = &amp;lt;0,29.43,0&amp;gt; &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
&amp;lt;math&amp;gt; {&amp;amp;mu;}_{k} = \frac{{F}_{f}}{{N}} = \frac{{&amp;lt;3.3,0,1.3&amp;gt;}}{{0,29.43,0}} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
===Difficult===&lt;br /&gt;
&lt;br /&gt;
Two blocks are stacked on top of one another on a frictionless surface. Block A is stacked on top of Block B. Block A has a mass of 2 Kg while Block B has a mass of 4 Kg. The coefficient of friction between the blocks is &amp;lt;math&amp;gt; {&amp;amp;mu;}_{s} = .35 &amp;lt;/math&amp;gt;. Find the maximum amount of force that can be applied to Block B so that Block A does not move at all.&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
Solution:&lt;br /&gt;
&lt;br /&gt;
==Connectedness==&lt;br /&gt;
&lt;br /&gt;
Friction is an important topic to understand because it has many industrial implications. Since friction can cause increases in temperature when objects move, engineers who work with moving objects must understand and account for friction to ensure systems work properly. For example, car engines must have proper oil and lubricants to prevent parts from scraping together and wearing down. Mechanical engineers, aerospace engineers, and civil engineers must deal with friction and its impacts every day!&lt;br /&gt;
&lt;br /&gt;
== See also ==&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
===Further reading===&lt;br /&gt;
&lt;br /&gt;
Books, Articles or other print media on this topic&lt;br /&gt;
&lt;br /&gt;
===External links===&lt;br /&gt;
&lt;br /&gt;
Internet resources on this topic&lt;br /&gt;
&lt;br /&gt;
[http://hyperphysics.phy-astr.gsu.edu/hbase/frict.html#fri]&lt;br /&gt;
&lt;br /&gt;
==References==&lt;br /&gt;
&lt;br /&gt;
This section contains the the references you used while writing this page&lt;br /&gt;
&lt;br /&gt;
[[Category:Contact Forces]]&lt;/div&gt;</summary>
		<author><name>Drao31</name></author>
	</entry>
	<entry>
		<id>http://www.physicsbook.gatech.edu/index.php?title=Friction&amp;diff=25008</id>
		<title>Friction</title>
		<link rel="alternate" type="text/html" href="http://www.physicsbook.gatech.edu/index.php?title=Friction&amp;diff=25008"/>
		<updated>2016-11-27T20:23:30Z</updated>

		<summary type="html">&lt;p&gt;Drao31: /* See also */&lt;/p&gt;
&lt;hr /&gt;
&lt;div&gt;This page discusses the concept of friction and how it relates to both moving and static objects.&lt;br /&gt;
&lt;br /&gt;
Claimed by drao31&lt;br /&gt;
&lt;br /&gt;
==The Main Idea==&lt;br /&gt;
Friction is caused by the interactions between the atoms that make up objects. When objects interact, the atoms that make up the objects also interact. Temperatures of interacting surfaces rise because of such interactions. Friction is a force that resists movement. Generally, friction makes it harder to move objects. There are two main types of friction that are covered in Physics 2211: Static Friction and Kinetic Friction. Static friction can be described as the friction acting on resting objects. Kinetic friction is the friction acting on objects in motion. &lt;br /&gt;
&lt;br /&gt;
Frictional forces depend on a few factors: the normal force and the coefficient of friction. &lt;br /&gt;
&lt;br /&gt;
In simple terms, the normal force &amp;lt;math&amp;gt; {F}_{N} &amp;lt;/math&amp;gt; or &amp;lt;math&amp;gt; {N} &amp;lt;/math&amp;gt; is the equivalent force between objects. For example, when an object of mass &#039;&#039;&#039;M&#039;&#039;&#039; is placed on a table, there is a gravitational force &#039;&#039;&#039;Mg&#039;&#039;&#039; on the table. If the table can support the object without collapsing, the table exerts an equivalent force &#039;&#039;&#039;Mg&#039;&#039;&#039; on the object. According to the momentum principle, since there is no change in momentum, the net force must be &#039;&#039;&#039;0&#039;&#039;&#039;. This is also apparent since there is no movement if the table can support the object.&lt;br /&gt;
&lt;br /&gt;
::&amp;lt;math&amp;gt; {p}_{f} - {p}_{i} = {F}_{net}{dt} = 0 &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
OR&lt;br /&gt;
&lt;br /&gt;
::&amp;lt;math&amp;gt; {F}_{g} = {M}{g} &amp;lt;/math&amp;gt;&lt;br /&gt;
::&amp;lt;math&amp;gt; {N} = {M}{g} &amp;lt;/math&amp;gt;&lt;br /&gt;
::&amp;lt;math&amp;gt; {F}_{net} = {F}_{g} - {N} = {0} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
The coefficient of friction is usually specific to each object or material. The coefficient of static friction is denoted by &amp;lt;math&amp;gt;{&amp;amp;mu;}_{s}&amp;lt;/math&amp;gt; and the coefficient of kinetic friction is denoted by &amp;lt;math&amp;gt;{&amp;amp;mu;}_{k}&amp;lt;/math&amp;gt; &lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
Static Friction:&lt;br /&gt;
&lt;br /&gt;
::&amp;lt;math&amp;gt; {F}_{s} \le {&amp;amp;mu;}_{s}{N} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
Static friction is the frictional force that must be overcome to begin moving an object at rest. The static friction can be no more than the normal force multiplied by the coefficient of static friction. Therefore, the maximum static friction an object can have is &amp;lt;math&amp;gt; {&amp;amp;mu;}_{s}{N} &amp;lt;/math&amp;gt;. &lt;br /&gt;
&lt;br /&gt;
Kinetic Friction:&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
::&amp;lt;math&amp;gt; {F}_{k} = {&amp;amp;mu;}_{k}{N} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
Kinetic friction is the frictional force that exists between objects already at motion. It acts to oppose the movement of an object. Kinetic friction can be observed, for example, when a soccer ball is kicked across a field. The friction between the ball and the field will eventually bring the ball to a stop.&lt;br /&gt;
&lt;br /&gt;
Interestingly, friction is also required for rolling motion. Without friction, objects would not be able to roll. This is true because friction results in torque acting on the object, causing the rolling motion. An example of this can be seen in cars that are stuck in a ditch or similar situations. If there is not enough friction between the car&#039;s wheels and the ground, the car&#039;s wheels will simply spin in place, and the car will not move.&lt;br /&gt;
&lt;br /&gt;
===A Mathematical Model===&lt;br /&gt;
&lt;br /&gt;
As stated above:&lt;br /&gt;
&lt;br /&gt;
Static Friction:&lt;br /&gt;
&lt;br /&gt;
::&amp;lt;math&amp;gt; {F}_{s} \le {&amp;amp;mu;}_{s}{N} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
Kinetic Friction:&lt;br /&gt;
&lt;br /&gt;
::&amp;lt;math&amp;gt; {F}_{k} = {&amp;amp;mu;}_{k}{N} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
When attempting to solve problems relating to friction, one possible method of approach is to consider the net force acting on an object. If there is a force &amp;lt;math&amp;gt; {F}&amp;lt;/math&amp;gt; pushing an object to the right, and a frictional force &amp;lt;math&amp;gt;{F}_{f}&amp;lt;/math&amp;gt; opposing the movement, then the net force is &amp;lt;math&amp;gt; {F}_{net} = {F} - {F}_{f} &amp;lt;/math&amp;gt;.&lt;br /&gt;
&lt;br /&gt;
Another possible approach is by using the momentum principle &amp;lt;math&amp;gt; {p}_{f} - {p}_{i} = {F}_{net}{dt} &amp;lt;/math&amp;gt;. The momentum principle can help solve problems where you need to account for time, net force, or change in momentum.&lt;br /&gt;
&lt;br /&gt;
===A Computational Model===&lt;br /&gt;
&lt;br /&gt;
[[File:Friction.gif]]&lt;br /&gt;
&lt;br /&gt;
Link: &lt;br /&gt;
https://trinket.io/glowscript/76028c1809&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
Code: &lt;br /&gt;
 def friction():&lt;br /&gt;
    from __future__ import division&lt;br /&gt;
    from visual import *&lt;br /&gt;
    from visual.graph import *&lt;br /&gt;
&lt;br /&gt;
    mcart = 100&lt;br /&gt;
    mew = vector(2.9,0,0)&lt;br /&gt;
&lt;br /&gt;
    track =  box(pos=vector(0,-0.05,0), size=vector(20.0,0.05,0.10), color=color.white)&lt;br /&gt;
    cart =  box(pos=vector(-10,0.25,0), size=vector(.5,0.6,0.03), color=color.blue)&lt;br /&gt;
    marker = box(pos = vector(2,0,0), size = vector(0,20,5), color = color.red)&lt;br /&gt;
&lt;br /&gt;
    cart.v=vector(2.4,0,0)&lt;br /&gt;
    cart.p = mcart*cart.v&lt;br /&gt;
    F = vector(90,0,0)&lt;br /&gt;
    F2 = vector(-200,0,0)&lt;br /&gt;
    F3 = (mcart * mew)&lt;br /&gt;
    print(F3)&lt;br /&gt;
&lt;br /&gt;
    deltat = 0.01&lt;br /&gt;
    t = 0&lt;br /&gt;
&lt;br /&gt;
    while t &amp;lt; 5.02:&lt;br /&gt;
&lt;br /&gt;
        if cart.pos.x &amp;lt; 2:&lt;br /&gt;
            cart.v = cart.p / cart.m&lt;br /&gt;
            Fnet = F&lt;br /&gt;
            cart.p = cart.p + Fnet*deltat&lt;br /&gt;
            cart.pos = cart.pos + (cart.p/mcart)*deltat&lt;br /&gt;
&lt;br /&gt;
        else:&lt;br /&gt;
            &lt;br /&gt;
            cart.v = cart.p / cart.m&lt;br /&gt;
            Fnet = F-F3&lt;br /&gt;
            cart.p = cart.p + Fnet*deltat&lt;br /&gt;
            cart.pos = cart.pos + (cart.p/mcart)*deltat&lt;br /&gt;
            &lt;br /&gt;
        t = t + deltat&lt;br /&gt;
        rate(100)&lt;br /&gt;
        &lt;br /&gt;
    print(cart.pos)&lt;br /&gt;
    &lt;br /&gt;
 friction()&lt;br /&gt;
&lt;br /&gt;
==Examples==&lt;br /&gt;
&lt;br /&gt;
Be sure to show all steps in your solution and include diagrams whenever possible&lt;br /&gt;
&lt;br /&gt;
===Simple===&lt;br /&gt;
&lt;br /&gt;
A 100Kg box is placed on a flat table. The box does not move. The coefficient of static friction &amp;lt;math&amp;gt; {&amp;amp;mu;}_{s} = {.25} &amp;lt;/math&amp;gt; and the coefficient of kinetic friction &amp;lt;math&amp;gt; {&amp;amp;mu;}_{k} = {.15} &amp;lt;/math&amp;gt;.&lt;br /&gt;
Find the force of friction &amp;lt;math&amp;gt;{F}_{s}&amp;lt;/math&amp;gt;.&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
Solution:&lt;br /&gt;
&lt;br /&gt;
Since the box does not move, there is only static friction. The normal force is equivalent to the force due to gravity: &amp;lt;math&amp;gt; {F}_{N} = {F}_{g} = {100}{g} &amp;lt;/math&amp;gt;. The static friction can be found by: &amp;lt;math&amp;gt; {F}_{s} = {&amp;amp;mu;}_{s}{F}_{N} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
&amp;lt;math&amp;gt; {F}_{s} = {(.25)}{(100)}{(9.8)} = {245.25} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
===Middling===&lt;br /&gt;
&lt;br /&gt;
A cart of mass 3Kg moves across a track pushed by a fan which exerts &amp;lt;math&amp;gt; {F} = &amp;lt;3,0,1&amp;gt; &amp;lt;/math&amp;gt;N with an initial velocity &amp;lt;math&amp;gt; {v}_{i} = &amp;lt;1,0,1&amp;gt;\frac{{m}}{{s}}&amp;lt;/math&amp;gt; . Find the required coefficient of kinetic friction &amp;lt;math&amp;gt; {&amp;amp;mu;}_{k} &amp;lt;/math&amp;gt; needed to bring the cart to a stop in 10 seconds.&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
Solution:&lt;br /&gt;
&lt;br /&gt;
Use the momentum principle: &amp;lt;math&amp;gt;{p}_{f} - {p}_{i} = {F}_{net}{dt}&amp;lt;/math&amp;gt; and &amp;lt;math&amp;gt;{F}_{f} = {&amp;amp;mu;}_{k}{N} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
The final velocity must be 0. The initial velocity, initial force, and time are given. &lt;br /&gt;
&lt;br /&gt;
&amp;lt;math&amp;gt;0- &amp;lt;3,0,3&amp;gt; = {F}_{net}*{10s}&amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
&amp;lt;math&amp;gt; {F}_{net} = &amp;lt;-0.3,0,-0.3&amp;gt; &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
&amp;lt;math&amp;gt; {F}_{net} = {F} - {F}_{f} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
&amp;lt;math&amp;gt; &amp;lt;-0.3,0,-0.3&amp;gt;  = &amp;lt;3,0,1&amp;gt; - {F}_{f}&amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
&amp;lt;math&amp;gt;{F}_{f}  = &amp;lt;3.3,0,1.3&amp;gt; &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
&amp;lt;math&amp;gt; {F}_{f} = &amp;lt;3.3,0,1.3&amp;gt; = {&amp;amp;mu;}_{k}{N} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
&amp;lt;math&amp;gt; {N} = {3Kg} * {&amp;lt;0,9.8,0&amp;gt;} = &amp;lt;0,29.43,0&amp;gt; &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
&amp;lt;math&amp;gt; {&amp;amp;mu;}_{k} = \frac{{F}_{f}}{{N}} = \frac{{&amp;lt;3.3,0,1.3&amp;gt;}}{{0,29.43,0}} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
===Difficult===&lt;br /&gt;
&lt;br /&gt;
Two blocks are stacked on top of one another on a frictionless surface. Block A is stacked on top of Block B. Block A has a mass of 2 Kg while Block B has a mass of 4 Kg. The coefficient of friction between the blocks is &amp;lt;math&amp;gt; {&amp;amp;mu;}_{s} = .35 &amp;lt;/math&amp;gt;. Find the maximum amount of force that can be applied to Block B so that Block A does not move at all.&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
Solution:&lt;br /&gt;
&lt;br /&gt;
==Connectedness==&lt;br /&gt;
&lt;br /&gt;
Friction is an important topic to understand because it has many industrial implications. Since friction can cause increases in temperature when objects move, engineers who work with moving objects must understand and account for friction to ensure systems work properly. For example, car engines must have proper oil and lubricants to prevent parts from scraping together and wearing down. Mechanical engineers, aerospace engineers, and civil engineers must deal with friction and its impacts every day!&lt;br /&gt;
&lt;br /&gt;
== See also ==&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
===Further reading===&lt;br /&gt;
&lt;br /&gt;
Books, Articles or other print media on this topic&lt;br /&gt;
&lt;br /&gt;
===External links===&lt;br /&gt;
&lt;br /&gt;
Internet resources on this topic&lt;br /&gt;
&lt;br /&gt;
==References==&lt;br /&gt;
&lt;br /&gt;
This section contains the the references you used while writing this page&lt;br /&gt;
&lt;br /&gt;
[[Category:Contact Forces]]&lt;/div&gt;</summary>
		<author><name>Drao31</name></author>
	</entry>
	<entry>
		<id>http://www.physicsbook.gatech.edu/index.php?title=Friction&amp;diff=25004</id>
		<title>Friction</title>
		<link rel="alternate" type="text/html" href="http://www.physicsbook.gatech.edu/index.php?title=Friction&amp;diff=25004"/>
		<updated>2016-11-27T20:22:25Z</updated>

		<summary type="html">&lt;p&gt;Drao31: /* History */&lt;/p&gt;
&lt;hr /&gt;
&lt;div&gt;This page discusses the concept of friction and how it relates to both moving and static objects.&lt;br /&gt;
&lt;br /&gt;
Claimed by drao31&lt;br /&gt;
&lt;br /&gt;
==The Main Idea==&lt;br /&gt;
Friction is caused by the interactions between the atoms that make up objects. When objects interact, the atoms that make up the objects also interact. Temperatures of interacting surfaces rise because of such interactions. Friction is a force that resists movement. Generally, friction makes it harder to move objects. There are two main types of friction that are covered in Physics 2211: Static Friction and Kinetic Friction. Static friction can be described as the friction acting on resting objects. Kinetic friction is the friction acting on objects in motion. &lt;br /&gt;
&lt;br /&gt;
Frictional forces depend on a few factors: the normal force and the coefficient of friction. &lt;br /&gt;
&lt;br /&gt;
In simple terms, the normal force &amp;lt;math&amp;gt; {F}_{N} &amp;lt;/math&amp;gt; or &amp;lt;math&amp;gt; {N} &amp;lt;/math&amp;gt; is the equivalent force between objects. For example, when an object of mass &#039;&#039;&#039;M&#039;&#039;&#039; is placed on a table, there is a gravitational force &#039;&#039;&#039;Mg&#039;&#039;&#039; on the table. If the table can support the object without collapsing, the table exerts an equivalent force &#039;&#039;&#039;Mg&#039;&#039;&#039; on the object. According to the momentum principle, since there is no change in momentum, the net force must be &#039;&#039;&#039;0&#039;&#039;&#039;. This is also apparent since there is no movement if the table can support the object.&lt;br /&gt;
&lt;br /&gt;
::&amp;lt;math&amp;gt; {p}_{f} - {p}_{i} = {F}_{net}{dt} = 0 &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
OR&lt;br /&gt;
&lt;br /&gt;
::&amp;lt;math&amp;gt; {F}_{g} = {M}{g} &amp;lt;/math&amp;gt;&lt;br /&gt;
::&amp;lt;math&amp;gt; {N} = {M}{g} &amp;lt;/math&amp;gt;&lt;br /&gt;
::&amp;lt;math&amp;gt; {F}_{net} = {F}_{g} - {N} = {0} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
The coefficient of friction is usually specific to each object or material. The coefficient of static friction is denoted by &amp;lt;math&amp;gt;{&amp;amp;mu;}_{s}&amp;lt;/math&amp;gt; and the coefficient of kinetic friction is denoted by &amp;lt;math&amp;gt;{&amp;amp;mu;}_{k}&amp;lt;/math&amp;gt; &lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
Static Friction:&lt;br /&gt;
&lt;br /&gt;
::&amp;lt;math&amp;gt; {F}_{s} \le {&amp;amp;mu;}_{s}{N} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
Static friction is the frictional force that must be overcome to begin moving an object at rest. The static friction can be no more than the normal force multiplied by the coefficient of static friction. Therefore, the maximum static friction an object can have is &amp;lt;math&amp;gt; {&amp;amp;mu;}_{s}{N} &amp;lt;/math&amp;gt;. &lt;br /&gt;
&lt;br /&gt;
Kinetic Friction:&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
::&amp;lt;math&amp;gt; {F}_{k} = {&amp;amp;mu;}_{k}{N} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
Kinetic friction is the frictional force that exists between objects already at motion. It acts to oppose the movement of an object. Kinetic friction can be observed, for example, when a soccer ball is kicked across a field. The friction between the ball and the field will eventually bring the ball to a stop.&lt;br /&gt;
&lt;br /&gt;
Interestingly, friction is also required for rolling motion. Without friction, objects would not be able to roll. This is true because friction results in torque acting on the object, causing the rolling motion. An example of this can be seen in cars that are stuck in a ditch or similar situations. If there is not enough friction between the car&#039;s wheels and the ground, the car&#039;s wheels will simply spin in place, and the car will not move.&lt;br /&gt;
&lt;br /&gt;
===A Mathematical Model===&lt;br /&gt;
&lt;br /&gt;
As stated above:&lt;br /&gt;
&lt;br /&gt;
Static Friction:&lt;br /&gt;
&lt;br /&gt;
::&amp;lt;math&amp;gt; {F}_{s} \le {&amp;amp;mu;}_{s}{N} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
Kinetic Friction:&lt;br /&gt;
&lt;br /&gt;
::&amp;lt;math&amp;gt; {F}_{k} = {&amp;amp;mu;}_{k}{N} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
When attempting to solve problems relating to friction, one possible method of approach is to consider the net force acting on an object. If there is a force &amp;lt;math&amp;gt; {F}&amp;lt;/math&amp;gt; pushing an object to the right, and a frictional force &amp;lt;math&amp;gt;{F}_{f}&amp;lt;/math&amp;gt; opposing the movement, then the net force is &amp;lt;math&amp;gt; {F}_{net} = {F} - {F}_{f} &amp;lt;/math&amp;gt;.&lt;br /&gt;
&lt;br /&gt;
Another possible approach is by using the momentum principle &amp;lt;math&amp;gt; {p}_{f} - {p}_{i} = {F}_{net}{dt} &amp;lt;/math&amp;gt;. The momentum principle can help solve problems where you need to account for time, net force, or change in momentum.&lt;br /&gt;
&lt;br /&gt;
===A Computational Model===&lt;br /&gt;
&lt;br /&gt;
[[File:Friction.gif]]&lt;br /&gt;
&lt;br /&gt;
Link: &lt;br /&gt;
https://trinket.io/glowscript/76028c1809&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
Code: &lt;br /&gt;
 def friction():&lt;br /&gt;
    from __future__ import division&lt;br /&gt;
    from visual import *&lt;br /&gt;
    from visual.graph import *&lt;br /&gt;
&lt;br /&gt;
    mcart = 100&lt;br /&gt;
    mew = vector(2.9,0,0)&lt;br /&gt;
&lt;br /&gt;
    track =  box(pos=vector(0,-0.05,0), size=vector(20.0,0.05,0.10), color=color.white)&lt;br /&gt;
    cart =  box(pos=vector(-10,0.25,0), size=vector(.5,0.6,0.03), color=color.blue)&lt;br /&gt;
    marker = box(pos = vector(2,0,0), size = vector(0,20,5), color = color.red)&lt;br /&gt;
&lt;br /&gt;
    cart.v=vector(2.4,0,0)&lt;br /&gt;
    cart.p = mcart*cart.v&lt;br /&gt;
    F = vector(90,0,0)&lt;br /&gt;
    F2 = vector(-200,0,0)&lt;br /&gt;
    F3 = (mcart * mew)&lt;br /&gt;
    print(F3)&lt;br /&gt;
&lt;br /&gt;
    deltat = 0.01&lt;br /&gt;
    t = 0&lt;br /&gt;
&lt;br /&gt;
    while t &amp;lt; 5.02:&lt;br /&gt;
&lt;br /&gt;
        if cart.pos.x &amp;lt; 2:&lt;br /&gt;
            cart.v = cart.p / cart.m&lt;br /&gt;
            Fnet = F&lt;br /&gt;
            cart.p = cart.p + Fnet*deltat&lt;br /&gt;
            cart.pos = cart.pos + (cart.p/mcart)*deltat&lt;br /&gt;
&lt;br /&gt;
        else:&lt;br /&gt;
            &lt;br /&gt;
            cart.v = cart.p / cart.m&lt;br /&gt;
            Fnet = F-F3&lt;br /&gt;
            cart.p = cart.p + Fnet*deltat&lt;br /&gt;
            cart.pos = cart.pos + (cart.p/mcart)*deltat&lt;br /&gt;
            &lt;br /&gt;
        t = t + deltat&lt;br /&gt;
        rate(100)&lt;br /&gt;
        &lt;br /&gt;
    print(cart.pos)&lt;br /&gt;
    &lt;br /&gt;
 friction()&lt;br /&gt;
&lt;br /&gt;
==Examples==&lt;br /&gt;
&lt;br /&gt;
Be sure to show all steps in your solution and include diagrams whenever possible&lt;br /&gt;
&lt;br /&gt;
===Simple===&lt;br /&gt;
&lt;br /&gt;
A 100Kg box is placed on a flat table. The box does not move. The coefficient of static friction &amp;lt;math&amp;gt; {&amp;amp;mu;}_{s} = {.25} &amp;lt;/math&amp;gt; and the coefficient of kinetic friction &amp;lt;math&amp;gt; {&amp;amp;mu;}_{k} = {.15} &amp;lt;/math&amp;gt;.&lt;br /&gt;
Find the force of friction &amp;lt;math&amp;gt;{F}_{s}&amp;lt;/math&amp;gt;.&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
Solution:&lt;br /&gt;
&lt;br /&gt;
Since the box does not move, there is only static friction. The normal force is equivalent to the force due to gravity: &amp;lt;math&amp;gt; {F}_{N} = {F}_{g} = {100}{g} &amp;lt;/math&amp;gt;. The static friction can be found by: &amp;lt;math&amp;gt; {F}_{s} = {&amp;amp;mu;}_{s}{F}_{N} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
&amp;lt;math&amp;gt; {F}_{s} = {(.25)}{(100)}{(9.8)} = {245.25} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
===Middling===&lt;br /&gt;
&lt;br /&gt;
A cart of mass 3Kg moves across a track pushed by a fan which exerts &amp;lt;math&amp;gt; {F} = &amp;lt;3,0,1&amp;gt; &amp;lt;/math&amp;gt;N with an initial velocity &amp;lt;math&amp;gt; {v}_{i} = &amp;lt;1,0,1&amp;gt;\frac{{m}}{{s}}&amp;lt;/math&amp;gt; . Find the required coefficient of kinetic friction &amp;lt;math&amp;gt; {&amp;amp;mu;}_{k} &amp;lt;/math&amp;gt; needed to bring the cart to a stop in 10 seconds.&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
Solution:&lt;br /&gt;
&lt;br /&gt;
Use the momentum principle: &amp;lt;math&amp;gt;{p}_{f} - {p}_{i} = {F}_{net}{dt}&amp;lt;/math&amp;gt; and &amp;lt;math&amp;gt;{F}_{f} = {&amp;amp;mu;}_{k}{N} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
The final velocity must be 0. The initial velocity, initial force, and time are given. &lt;br /&gt;
&lt;br /&gt;
&amp;lt;math&amp;gt;0- &amp;lt;3,0,3&amp;gt; = {F}_{net}*{10s}&amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
&amp;lt;math&amp;gt; {F}_{net} = &amp;lt;-0.3,0,-0.3&amp;gt; &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
&amp;lt;math&amp;gt; {F}_{net} = {F} - {F}_{f} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
&amp;lt;math&amp;gt; &amp;lt;-0.3,0,-0.3&amp;gt;  = &amp;lt;3,0,1&amp;gt; - {F}_{f}&amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
&amp;lt;math&amp;gt;{F}_{f}  = &amp;lt;3.3,0,1.3&amp;gt; &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
&amp;lt;math&amp;gt; {F}_{f} = &amp;lt;3.3,0,1.3&amp;gt; = {&amp;amp;mu;}_{k}{N} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
&amp;lt;math&amp;gt; {N} = {3Kg} * {&amp;lt;0,9.8,0&amp;gt;} = &amp;lt;0,29.43,0&amp;gt; &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
&amp;lt;math&amp;gt; {&amp;amp;mu;}_{k} = \frac{{F}_{f}}{{N}} = \frac{{&amp;lt;3.3,0,1.3&amp;gt;}}{{0,29.43,0}} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
===Difficult===&lt;br /&gt;
&lt;br /&gt;
Two blocks are stacked on top of one another on a frictionless surface. Block A is stacked on top of Block B. Block A has a mass of 2 Kg while Block B has a mass of 4 Kg. The coefficient of friction between the blocks is &amp;lt;math&amp;gt; {&amp;amp;mu;}_{s} = .35 &amp;lt;/math&amp;gt;. Find the maximum amount of force that can be applied to Block B so that Block A does not move at all.&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
Solution:&lt;br /&gt;
&lt;br /&gt;
==Connectedness==&lt;br /&gt;
&lt;br /&gt;
Friction is an important topic to understand because it has many industrial implications. Since friction can cause increases in temperature when objects move, engineers who work with moving objects must understand and account for friction to ensure systems work properly. For example, car engines must have proper oil and lubricants to prevent parts from scraping together and wearing down. Mechanical engineers, aerospace engineers, and civil engineers must deal with friction and its impacts every day!&lt;br /&gt;
&lt;br /&gt;
== See also ==&lt;br /&gt;
&lt;br /&gt;
Are there related topics or categories in this wiki resource for the curious reader to explore?  How does this topic fit into that context?&lt;br /&gt;
&lt;br /&gt;
===Further reading===&lt;br /&gt;
&lt;br /&gt;
Books, Articles or other print media on this topic&lt;br /&gt;
&lt;br /&gt;
===External links===&lt;br /&gt;
&lt;br /&gt;
Internet resources on this topic&lt;br /&gt;
&lt;br /&gt;
==References==&lt;br /&gt;
&lt;br /&gt;
This section contains the the references you used while writing this page&lt;br /&gt;
&lt;br /&gt;
[[Category:Contact Forces]]&lt;/div&gt;</summary>
		<author><name>Drao31</name></author>
	</entry>
	<entry>
		<id>http://www.physicsbook.gatech.edu/index.php?title=Friction&amp;diff=25002</id>
		<title>Friction</title>
		<link rel="alternate" type="text/html" href="http://www.physicsbook.gatech.edu/index.php?title=Friction&amp;diff=25002"/>
		<updated>2016-11-27T20:22:07Z</updated>

		<summary type="html">&lt;p&gt;Drao31: /* Difficult */&lt;/p&gt;
&lt;hr /&gt;
&lt;div&gt;This page discusses the concept of friction and how it relates to both moving and static objects.&lt;br /&gt;
&lt;br /&gt;
Claimed by drao31&lt;br /&gt;
&lt;br /&gt;
==The Main Idea==&lt;br /&gt;
Friction is caused by the interactions between the atoms that make up objects. When objects interact, the atoms that make up the objects also interact. Temperatures of interacting surfaces rise because of such interactions. Friction is a force that resists movement. Generally, friction makes it harder to move objects. There are two main types of friction that are covered in Physics 2211: Static Friction and Kinetic Friction. Static friction can be described as the friction acting on resting objects. Kinetic friction is the friction acting on objects in motion. &lt;br /&gt;
&lt;br /&gt;
Frictional forces depend on a few factors: the normal force and the coefficient of friction. &lt;br /&gt;
&lt;br /&gt;
In simple terms, the normal force &amp;lt;math&amp;gt; {F}_{N} &amp;lt;/math&amp;gt; or &amp;lt;math&amp;gt; {N} &amp;lt;/math&amp;gt; is the equivalent force between objects. For example, when an object of mass &#039;&#039;&#039;M&#039;&#039;&#039; is placed on a table, there is a gravitational force &#039;&#039;&#039;Mg&#039;&#039;&#039; on the table. If the table can support the object without collapsing, the table exerts an equivalent force &#039;&#039;&#039;Mg&#039;&#039;&#039; on the object. According to the momentum principle, since there is no change in momentum, the net force must be &#039;&#039;&#039;0&#039;&#039;&#039;. This is also apparent since there is no movement if the table can support the object.&lt;br /&gt;
&lt;br /&gt;
::&amp;lt;math&amp;gt; {p}_{f} - {p}_{i} = {F}_{net}{dt} = 0 &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
OR&lt;br /&gt;
&lt;br /&gt;
::&amp;lt;math&amp;gt; {F}_{g} = {M}{g} &amp;lt;/math&amp;gt;&lt;br /&gt;
::&amp;lt;math&amp;gt; {N} = {M}{g} &amp;lt;/math&amp;gt;&lt;br /&gt;
::&amp;lt;math&amp;gt; {F}_{net} = {F}_{g} - {N} = {0} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
The coefficient of friction is usually specific to each object or material. The coefficient of static friction is denoted by &amp;lt;math&amp;gt;{&amp;amp;mu;}_{s}&amp;lt;/math&amp;gt; and the coefficient of kinetic friction is denoted by &amp;lt;math&amp;gt;{&amp;amp;mu;}_{k}&amp;lt;/math&amp;gt; &lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
Static Friction:&lt;br /&gt;
&lt;br /&gt;
::&amp;lt;math&amp;gt; {F}_{s} \le {&amp;amp;mu;}_{s}{N} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
Static friction is the frictional force that must be overcome to begin moving an object at rest. The static friction can be no more than the normal force multiplied by the coefficient of static friction. Therefore, the maximum static friction an object can have is &amp;lt;math&amp;gt; {&amp;amp;mu;}_{s}{N} &amp;lt;/math&amp;gt;. &lt;br /&gt;
&lt;br /&gt;
Kinetic Friction:&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
::&amp;lt;math&amp;gt; {F}_{k} = {&amp;amp;mu;}_{k}{N} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
Kinetic friction is the frictional force that exists between objects already at motion. It acts to oppose the movement of an object. Kinetic friction can be observed, for example, when a soccer ball is kicked across a field. The friction between the ball and the field will eventually bring the ball to a stop.&lt;br /&gt;
&lt;br /&gt;
Interestingly, friction is also required for rolling motion. Without friction, objects would not be able to roll. This is true because friction results in torque acting on the object, causing the rolling motion. An example of this can be seen in cars that are stuck in a ditch or similar situations. If there is not enough friction between the car&#039;s wheels and the ground, the car&#039;s wheels will simply spin in place, and the car will not move.&lt;br /&gt;
&lt;br /&gt;
===A Mathematical Model===&lt;br /&gt;
&lt;br /&gt;
As stated above:&lt;br /&gt;
&lt;br /&gt;
Static Friction:&lt;br /&gt;
&lt;br /&gt;
::&amp;lt;math&amp;gt; {F}_{s} \le {&amp;amp;mu;}_{s}{N} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
Kinetic Friction:&lt;br /&gt;
&lt;br /&gt;
::&amp;lt;math&amp;gt; {F}_{k} = {&amp;amp;mu;}_{k}{N} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
When attempting to solve problems relating to friction, one possible method of approach is to consider the net force acting on an object. If there is a force &amp;lt;math&amp;gt; {F}&amp;lt;/math&amp;gt; pushing an object to the right, and a frictional force &amp;lt;math&amp;gt;{F}_{f}&amp;lt;/math&amp;gt; opposing the movement, then the net force is &amp;lt;math&amp;gt; {F}_{net} = {F} - {F}_{f} &amp;lt;/math&amp;gt;.&lt;br /&gt;
&lt;br /&gt;
Another possible approach is by using the momentum principle &amp;lt;math&amp;gt; {p}_{f} - {p}_{i} = {F}_{net}{dt} &amp;lt;/math&amp;gt;. The momentum principle can help solve problems where you need to account for time, net force, or change in momentum.&lt;br /&gt;
&lt;br /&gt;
===A Computational Model===&lt;br /&gt;
&lt;br /&gt;
[[File:Friction.gif]]&lt;br /&gt;
&lt;br /&gt;
Link: &lt;br /&gt;
https://trinket.io/glowscript/76028c1809&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
Code: &lt;br /&gt;
 def friction():&lt;br /&gt;
    from __future__ import division&lt;br /&gt;
    from visual import *&lt;br /&gt;
    from visual.graph import *&lt;br /&gt;
&lt;br /&gt;
    mcart = 100&lt;br /&gt;
    mew = vector(2.9,0,0)&lt;br /&gt;
&lt;br /&gt;
    track =  box(pos=vector(0,-0.05,0), size=vector(20.0,0.05,0.10), color=color.white)&lt;br /&gt;
    cart =  box(pos=vector(-10,0.25,0), size=vector(.5,0.6,0.03), color=color.blue)&lt;br /&gt;
    marker = box(pos = vector(2,0,0), size = vector(0,20,5), color = color.red)&lt;br /&gt;
&lt;br /&gt;
    cart.v=vector(2.4,0,0)&lt;br /&gt;
    cart.p = mcart*cart.v&lt;br /&gt;
    F = vector(90,0,0)&lt;br /&gt;
    F2 = vector(-200,0,0)&lt;br /&gt;
    F3 = (mcart * mew)&lt;br /&gt;
    print(F3)&lt;br /&gt;
&lt;br /&gt;
    deltat = 0.01&lt;br /&gt;
    t = 0&lt;br /&gt;
&lt;br /&gt;
    while t &amp;lt; 5.02:&lt;br /&gt;
&lt;br /&gt;
        if cart.pos.x &amp;lt; 2:&lt;br /&gt;
            cart.v = cart.p / cart.m&lt;br /&gt;
            Fnet = F&lt;br /&gt;
            cart.p = cart.p + Fnet*deltat&lt;br /&gt;
            cart.pos = cart.pos + (cart.p/mcart)*deltat&lt;br /&gt;
&lt;br /&gt;
        else:&lt;br /&gt;
            &lt;br /&gt;
            cart.v = cart.p / cart.m&lt;br /&gt;
            Fnet = F-F3&lt;br /&gt;
            cart.p = cart.p + Fnet*deltat&lt;br /&gt;
            cart.pos = cart.pos + (cart.p/mcart)*deltat&lt;br /&gt;
            &lt;br /&gt;
        t = t + deltat&lt;br /&gt;
        rate(100)&lt;br /&gt;
        &lt;br /&gt;
    print(cart.pos)&lt;br /&gt;
    &lt;br /&gt;
 friction()&lt;br /&gt;
&lt;br /&gt;
==Examples==&lt;br /&gt;
&lt;br /&gt;
Be sure to show all steps in your solution and include diagrams whenever possible&lt;br /&gt;
&lt;br /&gt;
===Simple===&lt;br /&gt;
&lt;br /&gt;
A 100Kg box is placed on a flat table. The box does not move. The coefficient of static friction &amp;lt;math&amp;gt; {&amp;amp;mu;}_{s} = {.25} &amp;lt;/math&amp;gt; and the coefficient of kinetic friction &amp;lt;math&amp;gt; {&amp;amp;mu;}_{k} = {.15} &amp;lt;/math&amp;gt;.&lt;br /&gt;
Find the force of friction &amp;lt;math&amp;gt;{F}_{s}&amp;lt;/math&amp;gt;.&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
Solution:&lt;br /&gt;
&lt;br /&gt;
Since the box does not move, there is only static friction. The normal force is equivalent to the force due to gravity: &amp;lt;math&amp;gt; {F}_{N} = {F}_{g} = {100}{g} &amp;lt;/math&amp;gt;. The static friction can be found by: &amp;lt;math&amp;gt; {F}_{s} = {&amp;amp;mu;}_{s}{F}_{N} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
&amp;lt;math&amp;gt; {F}_{s} = {(.25)}{(100)}{(9.8)} = {245.25} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
===Middling===&lt;br /&gt;
&lt;br /&gt;
A cart of mass 3Kg moves across a track pushed by a fan which exerts &amp;lt;math&amp;gt; {F} = &amp;lt;3,0,1&amp;gt; &amp;lt;/math&amp;gt;N with an initial velocity &amp;lt;math&amp;gt; {v}_{i} = &amp;lt;1,0,1&amp;gt;\frac{{m}}{{s}}&amp;lt;/math&amp;gt; . Find the required coefficient of kinetic friction &amp;lt;math&amp;gt; {&amp;amp;mu;}_{k} &amp;lt;/math&amp;gt; needed to bring the cart to a stop in 10 seconds.&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
Solution:&lt;br /&gt;
&lt;br /&gt;
Use the momentum principle: &amp;lt;math&amp;gt;{p}_{f} - {p}_{i} = {F}_{net}{dt}&amp;lt;/math&amp;gt; and &amp;lt;math&amp;gt;{F}_{f} = {&amp;amp;mu;}_{k}{N} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
The final velocity must be 0. The initial velocity, initial force, and time are given. &lt;br /&gt;
&lt;br /&gt;
&amp;lt;math&amp;gt;0- &amp;lt;3,0,3&amp;gt; = {F}_{net}*{10s}&amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
&amp;lt;math&amp;gt; {F}_{net} = &amp;lt;-0.3,0,-0.3&amp;gt; &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
&amp;lt;math&amp;gt; {F}_{net} = {F} - {F}_{f} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
&amp;lt;math&amp;gt; &amp;lt;-0.3,0,-0.3&amp;gt;  = &amp;lt;3,0,1&amp;gt; - {F}_{f}&amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
&amp;lt;math&amp;gt;{F}_{f}  = &amp;lt;3.3,0,1.3&amp;gt; &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
&amp;lt;math&amp;gt; {F}_{f} = &amp;lt;3.3,0,1.3&amp;gt; = {&amp;amp;mu;}_{k}{N} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
&amp;lt;math&amp;gt; {N} = {3Kg} * {&amp;lt;0,9.8,0&amp;gt;} = &amp;lt;0,29.43,0&amp;gt; &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
&amp;lt;math&amp;gt; {&amp;amp;mu;}_{k} = \frac{{F}_{f}}{{N}} = \frac{{&amp;lt;3.3,0,1.3&amp;gt;}}{{0,29.43,0}} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
===Difficult===&lt;br /&gt;
&lt;br /&gt;
Two blocks are stacked on top of one another on a frictionless surface. Block A is stacked on top of Block B. Block A has a mass of 2 Kg while Block B has a mass of 4 Kg. The coefficient of friction between the blocks is &amp;lt;math&amp;gt; {&amp;amp;mu;}_{s} = .35 &amp;lt;/math&amp;gt;. Find the maximum amount of force that can be applied to Block B so that Block A does not move at all.&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
Solution:&lt;br /&gt;
&lt;br /&gt;
==Connectedness==&lt;br /&gt;
&lt;br /&gt;
Friction is an important topic to understand because it has many industrial implications. Since friction can cause increases in temperature when objects move, engineers who work with moving objects must understand and account for friction to ensure systems work properly. For example, car engines must have proper oil and lubricants to prevent parts from scraping together and wearing down. Mechanical engineers, aerospace engineers, and civil engineers must deal with friction and its impacts every day!&lt;br /&gt;
&lt;br /&gt;
==History==&lt;br /&gt;
&lt;br /&gt;
Put this idea in historical context. Give the reader the Who, What, When, Where, and Why.&lt;br /&gt;
&lt;br /&gt;
== See also ==&lt;br /&gt;
&lt;br /&gt;
Are there related topics or categories in this wiki resource for the curious reader to explore?  How does this topic fit into that context?&lt;br /&gt;
&lt;br /&gt;
===Further reading===&lt;br /&gt;
&lt;br /&gt;
Books, Articles or other print media on this topic&lt;br /&gt;
&lt;br /&gt;
===External links===&lt;br /&gt;
&lt;br /&gt;
Internet resources on this topic&lt;br /&gt;
&lt;br /&gt;
==References==&lt;br /&gt;
&lt;br /&gt;
This section contains the the references you used while writing this page&lt;br /&gt;
&lt;br /&gt;
[[Category:Contact Forces]]&lt;/div&gt;</summary>
		<author><name>Drao31</name></author>
	</entry>
	<entry>
		<id>http://www.physicsbook.gatech.edu/index.php?title=Friction&amp;diff=24989</id>
		<title>Friction</title>
		<link rel="alternate" type="text/html" href="http://www.physicsbook.gatech.edu/index.php?title=Friction&amp;diff=24989"/>
		<updated>2016-11-27T20:14:28Z</updated>

		<summary type="html">&lt;p&gt;Drao31: /* Connectedness */&lt;/p&gt;
&lt;hr /&gt;
&lt;div&gt;This page discusses the concept of friction and how it relates to both moving and static objects.&lt;br /&gt;
&lt;br /&gt;
Claimed by drao31&lt;br /&gt;
&lt;br /&gt;
==The Main Idea==&lt;br /&gt;
Friction is caused by the interactions between the atoms that make up objects. When objects interact, the atoms that make up the objects also interact. Temperatures of interacting surfaces rise because of such interactions. Friction is a force that resists movement. Generally, friction makes it harder to move objects. There are two main types of friction that are covered in Physics 2211: Static Friction and Kinetic Friction. Static friction can be described as the friction acting on resting objects. Kinetic friction is the friction acting on objects in motion. &lt;br /&gt;
&lt;br /&gt;
Frictional forces depend on a few factors: the normal force and the coefficient of friction. &lt;br /&gt;
&lt;br /&gt;
In simple terms, the normal force &amp;lt;math&amp;gt; {F}_{N} &amp;lt;/math&amp;gt; or &amp;lt;math&amp;gt; {N} &amp;lt;/math&amp;gt; is the equivalent force between objects. For example, when an object of mass &#039;&#039;&#039;M&#039;&#039;&#039; is placed on a table, there is a gravitational force &#039;&#039;&#039;Mg&#039;&#039;&#039; on the table. If the table can support the object without collapsing, the table exerts an equivalent force &#039;&#039;&#039;Mg&#039;&#039;&#039; on the object. According to the momentum principle, since there is no change in momentum, the net force must be &#039;&#039;&#039;0&#039;&#039;&#039;. This is also apparent since there is no movement if the table can support the object.&lt;br /&gt;
&lt;br /&gt;
::&amp;lt;math&amp;gt; {p}_{f} - {p}_{i} = {F}_{net}{dt} = 0 &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
OR&lt;br /&gt;
&lt;br /&gt;
::&amp;lt;math&amp;gt; {F}_{g} = {M}{g} &amp;lt;/math&amp;gt;&lt;br /&gt;
::&amp;lt;math&amp;gt; {N} = {M}{g} &amp;lt;/math&amp;gt;&lt;br /&gt;
::&amp;lt;math&amp;gt; {F}_{net} = {F}_{g} - {N} = {0} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
The coefficient of friction is usually specific to each object or material. The coefficient of static friction is denoted by &amp;lt;math&amp;gt;{&amp;amp;mu;}_{s}&amp;lt;/math&amp;gt; and the coefficient of kinetic friction is denoted by &amp;lt;math&amp;gt;{&amp;amp;mu;}_{k}&amp;lt;/math&amp;gt; &lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
Static Friction:&lt;br /&gt;
&lt;br /&gt;
::&amp;lt;math&amp;gt; {F}_{s} \le {&amp;amp;mu;}_{s}{N} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
Static friction is the frictional force that must be overcome to begin moving an object at rest. The static friction can be no more than the normal force multiplied by the coefficient of static friction. Therefore, the maximum static friction an object can have is &amp;lt;math&amp;gt; {&amp;amp;mu;}_{s}{N} &amp;lt;/math&amp;gt;. &lt;br /&gt;
&lt;br /&gt;
Kinetic Friction:&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
::&amp;lt;math&amp;gt; {F}_{k} = {&amp;amp;mu;}_{k}{N} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
Kinetic friction is the frictional force that exists between objects already at motion. It acts to oppose the movement of an object. Kinetic friction can be observed, for example, when a soccer ball is kicked across a field. The friction between the ball and the field will eventually bring the ball to a stop.&lt;br /&gt;
&lt;br /&gt;
Interestingly, friction is also required for rolling motion. Without friction, objects would not be able to roll. This is true because friction results in torque acting on the object, causing the rolling motion. An example of this can be seen in cars that are stuck in a ditch or similar situations. If there is not enough friction between the car&#039;s wheels and the ground, the car&#039;s wheels will simply spin in place, and the car will not move.&lt;br /&gt;
&lt;br /&gt;
===A Mathematical Model===&lt;br /&gt;
&lt;br /&gt;
As stated above:&lt;br /&gt;
&lt;br /&gt;
Static Friction:&lt;br /&gt;
&lt;br /&gt;
::&amp;lt;math&amp;gt; {F}_{s} \le {&amp;amp;mu;}_{s}{N} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
Kinetic Friction:&lt;br /&gt;
&lt;br /&gt;
::&amp;lt;math&amp;gt; {F}_{k} = {&amp;amp;mu;}_{k}{N} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
When attempting to solve problems relating to friction, one possible method of approach is to consider the net force acting on an object. If there is a force &amp;lt;math&amp;gt; {F}&amp;lt;/math&amp;gt; pushing an object to the right, and a frictional force &amp;lt;math&amp;gt;{F}_{f}&amp;lt;/math&amp;gt; opposing the movement, then the net force is &amp;lt;math&amp;gt; {F}_{net} = {F} - {F}_{f} &amp;lt;/math&amp;gt;.&lt;br /&gt;
&lt;br /&gt;
Another possible approach is by using the momentum principle &amp;lt;math&amp;gt; {p}_{f} - {p}_{i} = {F}_{net}{dt} &amp;lt;/math&amp;gt;. The momentum principle can help solve problems where you need to account for time, net force, or change in momentum.&lt;br /&gt;
&lt;br /&gt;
===A Computational Model===&lt;br /&gt;
&lt;br /&gt;
[[File:Friction.gif]]&lt;br /&gt;
&lt;br /&gt;
Link: &lt;br /&gt;
https://trinket.io/glowscript/76028c1809&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
Code: &lt;br /&gt;
 def friction():&lt;br /&gt;
    from __future__ import division&lt;br /&gt;
    from visual import *&lt;br /&gt;
    from visual.graph import *&lt;br /&gt;
&lt;br /&gt;
    mcart = 100&lt;br /&gt;
    mew = vector(2.9,0,0)&lt;br /&gt;
&lt;br /&gt;
    track =  box(pos=vector(0,-0.05,0), size=vector(20.0,0.05,0.10), color=color.white)&lt;br /&gt;
    cart =  box(pos=vector(-10,0.25,0), size=vector(.5,0.6,0.03), color=color.blue)&lt;br /&gt;
    marker = box(pos = vector(2,0,0), size = vector(0,20,5), color = color.red)&lt;br /&gt;
&lt;br /&gt;
    cart.v=vector(2.4,0,0)&lt;br /&gt;
    cart.p = mcart*cart.v&lt;br /&gt;
    F = vector(90,0,0)&lt;br /&gt;
    F2 = vector(-200,0,0)&lt;br /&gt;
    F3 = (mcart * mew)&lt;br /&gt;
    print(F3)&lt;br /&gt;
&lt;br /&gt;
    deltat = 0.01&lt;br /&gt;
    t = 0&lt;br /&gt;
&lt;br /&gt;
    while t &amp;lt; 5.02:&lt;br /&gt;
&lt;br /&gt;
        if cart.pos.x &amp;lt; 2:&lt;br /&gt;
            cart.v = cart.p / cart.m&lt;br /&gt;
            Fnet = F&lt;br /&gt;
            cart.p = cart.p + Fnet*deltat&lt;br /&gt;
            cart.pos = cart.pos + (cart.p/mcart)*deltat&lt;br /&gt;
&lt;br /&gt;
        else:&lt;br /&gt;
            &lt;br /&gt;
            cart.v = cart.p / cart.m&lt;br /&gt;
            Fnet = F-F3&lt;br /&gt;
            cart.p = cart.p + Fnet*deltat&lt;br /&gt;
            cart.pos = cart.pos + (cart.p/mcart)*deltat&lt;br /&gt;
            &lt;br /&gt;
        t = t + deltat&lt;br /&gt;
        rate(100)&lt;br /&gt;
        &lt;br /&gt;
    print(cart.pos)&lt;br /&gt;
    &lt;br /&gt;
 friction()&lt;br /&gt;
&lt;br /&gt;
==Examples==&lt;br /&gt;
&lt;br /&gt;
Be sure to show all steps in your solution and include diagrams whenever possible&lt;br /&gt;
&lt;br /&gt;
===Simple===&lt;br /&gt;
&lt;br /&gt;
A 100Kg box is placed on a flat table. The box does not move. The coefficient of static friction &amp;lt;math&amp;gt; {&amp;amp;mu;}_{s} = {.25} &amp;lt;/math&amp;gt; and the coefficient of kinetic friction &amp;lt;math&amp;gt; {&amp;amp;mu;}_{k} = {.15} &amp;lt;/math&amp;gt;.&lt;br /&gt;
Find the force of friction &amp;lt;math&amp;gt;{F}_{s}&amp;lt;/math&amp;gt;.&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
Solution:&lt;br /&gt;
&lt;br /&gt;
Since the box does not move, there is only static friction. The normal force is equivalent to the force due to gravity: &amp;lt;math&amp;gt; {F}_{N} = {F}_{g} = {100}{g} &amp;lt;/math&amp;gt;. The static friction can be found by: &amp;lt;math&amp;gt; {F}_{s} = {&amp;amp;mu;}_{s}{F}_{N} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
&amp;lt;math&amp;gt; {F}_{s} = {(.25)}{(100)}{(9.8)} = {245.25} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
===Middling===&lt;br /&gt;
&lt;br /&gt;
A cart of mass 3Kg moves across a track pushed by a fan which exerts &amp;lt;math&amp;gt; {F} = &amp;lt;3,0,1&amp;gt; &amp;lt;/math&amp;gt;N with an initial velocity &amp;lt;math&amp;gt; {v}_{i} = &amp;lt;1,0,1&amp;gt;\frac{{m}}{{s}}&amp;lt;/math&amp;gt; . Find the required coefficient of kinetic friction &amp;lt;math&amp;gt; {&amp;amp;mu;}_{k} &amp;lt;/math&amp;gt; needed to bring the cart to a stop in 10 seconds.&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
Solution:&lt;br /&gt;
&lt;br /&gt;
Use the momentum principle: &amp;lt;math&amp;gt;{p}_{f} - {p}_{i} = {F}_{net}{dt}&amp;lt;/math&amp;gt; and &amp;lt;math&amp;gt;{F}_{f} = {&amp;amp;mu;}_{k}{N} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
The final velocity must be 0. The initial velocity, initial force, and time are given. &lt;br /&gt;
&lt;br /&gt;
&amp;lt;math&amp;gt;0- &amp;lt;3,0,3&amp;gt; = {F}_{net}*{10s}&amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
&amp;lt;math&amp;gt; {F}_{net} = &amp;lt;-0.3,0,-0.3&amp;gt; &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
&amp;lt;math&amp;gt; {F}_{net} = {F} - {F}_{f} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
&amp;lt;math&amp;gt; &amp;lt;-0.3,0,-0.3&amp;gt;  = &amp;lt;3,0,1&amp;gt; - {F}_{f}&amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
&amp;lt;math&amp;gt;{F}_{f}  = &amp;lt;3.3,0,1.3&amp;gt; &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
&amp;lt;math&amp;gt; {F}_{f} = &amp;lt;3.3,0,1.3&amp;gt; = {&amp;amp;mu;}_{k}{N} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
&amp;lt;math&amp;gt; {N} = {3Kg} * {&amp;lt;0,9.8,0&amp;gt;} = &amp;lt;0,29.43,0&amp;gt; &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
&amp;lt;math&amp;gt; {&amp;amp;mu;}_{k} = \frac{{F}_{f}}{{N}} = \frac{{&amp;lt;3.3,0,1.3&amp;gt;}}{{0,29.43,0}} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
===Difficult===&lt;br /&gt;
&lt;br /&gt;
Two blocks are stacked on top of one another on a frictio&lt;br /&gt;
&lt;br /&gt;
==Connectedness==&lt;br /&gt;
&lt;br /&gt;
Friction is an important topic to understand because it has many industrial implications. Since friction can cause increases in temperature when objects move, engineers who work with moving objects must understand and account for friction to ensure systems work properly. For example, car engines must have proper oil and lubricants to prevent parts from scraping together and wearing down. Mechanical engineers, aerospace engineers, and civil engineers must deal with friction and its impacts every day!&lt;br /&gt;
&lt;br /&gt;
==History==&lt;br /&gt;
&lt;br /&gt;
Put this idea in historical context. Give the reader the Who, What, When, Where, and Why.&lt;br /&gt;
&lt;br /&gt;
== See also ==&lt;br /&gt;
&lt;br /&gt;
Are there related topics or categories in this wiki resource for the curious reader to explore?  How does this topic fit into that context?&lt;br /&gt;
&lt;br /&gt;
===Further reading===&lt;br /&gt;
&lt;br /&gt;
Books, Articles or other print media on this topic&lt;br /&gt;
&lt;br /&gt;
===External links===&lt;br /&gt;
&lt;br /&gt;
Internet resources on this topic&lt;br /&gt;
&lt;br /&gt;
==References==&lt;br /&gt;
&lt;br /&gt;
This section contains the the references you used while writing this page&lt;br /&gt;
&lt;br /&gt;
[[Category:Contact Forces]]&lt;/div&gt;</summary>
		<author><name>Drao31</name></author>
	</entry>
	<entry>
		<id>http://www.physicsbook.gatech.edu/index.php?title=Friction&amp;diff=24978</id>
		<title>Friction</title>
		<link rel="alternate" type="text/html" href="http://www.physicsbook.gatech.edu/index.php?title=Friction&amp;diff=24978"/>
		<updated>2016-11-27T20:10:38Z</updated>

		<summary type="html">&lt;p&gt;Drao31: /* Middling */&lt;/p&gt;
&lt;hr /&gt;
&lt;div&gt;This page discusses the concept of friction and how it relates to both moving and static objects.&lt;br /&gt;
&lt;br /&gt;
Claimed by drao31&lt;br /&gt;
&lt;br /&gt;
==The Main Idea==&lt;br /&gt;
Friction is caused by the interactions between the atoms that make up objects. When objects interact, the atoms that make up the objects also interact. Temperatures of interacting surfaces rise because of such interactions. Friction is a force that resists movement. Generally, friction makes it harder to move objects. There are two main types of friction that are covered in Physics 2211: Static Friction and Kinetic Friction. Static friction can be described as the friction acting on resting objects. Kinetic friction is the friction acting on objects in motion. &lt;br /&gt;
&lt;br /&gt;
Frictional forces depend on a few factors: the normal force and the coefficient of friction. &lt;br /&gt;
&lt;br /&gt;
In simple terms, the normal force &amp;lt;math&amp;gt; {F}_{N} &amp;lt;/math&amp;gt; or &amp;lt;math&amp;gt; {N} &amp;lt;/math&amp;gt; is the equivalent force between objects. For example, when an object of mass &#039;&#039;&#039;M&#039;&#039;&#039; is placed on a table, there is a gravitational force &#039;&#039;&#039;Mg&#039;&#039;&#039; on the table. If the table can support the object without collapsing, the table exerts an equivalent force &#039;&#039;&#039;Mg&#039;&#039;&#039; on the object. According to the momentum principle, since there is no change in momentum, the net force must be &#039;&#039;&#039;0&#039;&#039;&#039;. This is also apparent since there is no movement if the table can support the object.&lt;br /&gt;
&lt;br /&gt;
::&amp;lt;math&amp;gt; {p}_{f} - {p}_{i} = {F}_{net}{dt} = 0 &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
OR&lt;br /&gt;
&lt;br /&gt;
::&amp;lt;math&amp;gt; {F}_{g} = {M}{g} &amp;lt;/math&amp;gt;&lt;br /&gt;
::&amp;lt;math&amp;gt; {N} = {M}{g} &amp;lt;/math&amp;gt;&lt;br /&gt;
::&amp;lt;math&amp;gt; {F}_{net} = {F}_{g} - {N} = {0} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
The coefficient of friction is usually specific to each object or material. The coefficient of static friction is denoted by &amp;lt;math&amp;gt;{&amp;amp;mu;}_{s}&amp;lt;/math&amp;gt; and the coefficient of kinetic friction is denoted by &amp;lt;math&amp;gt;{&amp;amp;mu;}_{k}&amp;lt;/math&amp;gt; &lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
Static Friction:&lt;br /&gt;
&lt;br /&gt;
::&amp;lt;math&amp;gt; {F}_{s} \le {&amp;amp;mu;}_{s}{N} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
Static friction is the frictional force that must be overcome to begin moving an object at rest. The static friction can be no more than the normal force multiplied by the coefficient of static friction. Therefore, the maximum static friction an object can have is &amp;lt;math&amp;gt; {&amp;amp;mu;}_{s}{N} &amp;lt;/math&amp;gt;. &lt;br /&gt;
&lt;br /&gt;
Kinetic Friction:&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
::&amp;lt;math&amp;gt; {F}_{k} = {&amp;amp;mu;}_{k}{N} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
Kinetic friction is the frictional force that exists between objects already at motion. It acts to oppose the movement of an object. Kinetic friction can be observed, for example, when a soccer ball is kicked across a field. The friction between the ball and the field will eventually bring the ball to a stop.&lt;br /&gt;
&lt;br /&gt;
Interestingly, friction is also required for rolling motion. Without friction, objects would not be able to roll. This is true because friction results in torque acting on the object, causing the rolling motion. An example of this can be seen in cars that are stuck in a ditch or similar situations. If there is not enough friction between the car&#039;s wheels and the ground, the car&#039;s wheels will simply spin in place, and the car will not move.&lt;br /&gt;
&lt;br /&gt;
===A Mathematical Model===&lt;br /&gt;
&lt;br /&gt;
As stated above:&lt;br /&gt;
&lt;br /&gt;
Static Friction:&lt;br /&gt;
&lt;br /&gt;
::&amp;lt;math&amp;gt; {F}_{s} \le {&amp;amp;mu;}_{s}{N} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
Kinetic Friction:&lt;br /&gt;
&lt;br /&gt;
::&amp;lt;math&amp;gt; {F}_{k} = {&amp;amp;mu;}_{k}{N} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
When attempting to solve problems relating to friction, one possible method of approach is to consider the net force acting on an object. If there is a force &amp;lt;math&amp;gt; {F}&amp;lt;/math&amp;gt; pushing an object to the right, and a frictional force &amp;lt;math&amp;gt;{F}_{f}&amp;lt;/math&amp;gt; opposing the movement, then the net force is &amp;lt;math&amp;gt; {F}_{net} = {F} - {F}_{f} &amp;lt;/math&amp;gt;.&lt;br /&gt;
&lt;br /&gt;
Another possible approach is by using the momentum principle &amp;lt;math&amp;gt; {p}_{f} - {p}_{i} = {F}_{net}{dt} &amp;lt;/math&amp;gt;. The momentum principle can help solve problems where you need to account for time, net force, or change in momentum.&lt;br /&gt;
&lt;br /&gt;
===A Computational Model===&lt;br /&gt;
&lt;br /&gt;
[[File:Friction.gif]]&lt;br /&gt;
&lt;br /&gt;
Link: &lt;br /&gt;
https://trinket.io/glowscript/76028c1809&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
Code: &lt;br /&gt;
 def friction():&lt;br /&gt;
    from __future__ import division&lt;br /&gt;
    from visual import *&lt;br /&gt;
    from visual.graph import *&lt;br /&gt;
&lt;br /&gt;
    mcart = 100&lt;br /&gt;
    mew = vector(2.9,0,0)&lt;br /&gt;
&lt;br /&gt;
    track =  box(pos=vector(0,-0.05,0), size=vector(20.0,0.05,0.10), color=color.white)&lt;br /&gt;
    cart =  box(pos=vector(-10,0.25,0), size=vector(.5,0.6,0.03), color=color.blue)&lt;br /&gt;
    marker = box(pos = vector(2,0,0), size = vector(0,20,5), color = color.red)&lt;br /&gt;
&lt;br /&gt;
    cart.v=vector(2.4,0,0)&lt;br /&gt;
    cart.p = mcart*cart.v&lt;br /&gt;
    F = vector(90,0,0)&lt;br /&gt;
    F2 = vector(-200,0,0)&lt;br /&gt;
    F3 = (mcart * mew)&lt;br /&gt;
    print(F3)&lt;br /&gt;
&lt;br /&gt;
    deltat = 0.01&lt;br /&gt;
    t = 0&lt;br /&gt;
&lt;br /&gt;
    while t &amp;lt; 5.02:&lt;br /&gt;
&lt;br /&gt;
        if cart.pos.x &amp;lt; 2:&lt;br /&gt;
            cart.v = cart.p / cart.m&lt;br /&gt;
            Fnet = F&lt;br /&gt;
            cart.p = cart.p + Fnet*deltat&lt;br /&gt;
            cart.pos = cart.pos + (cart.p/mcart)*deltat&lt;br /&gt;
&lt;br /&gt;
        else:&lt;br /&gt;
            &lt;br /&gt;
            cart.v = cart.p / cart.m&lt;br /&gt;
            Fnet = F-F3&lt;br /&gt;
            cart.p = cart.p + Fnet*deltat&lt;br /&gt;
            cart.pos = cart.pos + (cart.p/mcart)*deltat&lt;br /&gt;
            &lt;br /&gt;
        t = t + deltat&lt;br /&gt;
        rate(100)&lt;br /&gt;
        &lt;br /&gt;
    print(cart.pos)&lt;br /&gt;
    &lt;br /&gt;
 friction()&lt;br /&gt;
&lt;br /&gt;
==Examples==&lt;br /&gt;
&lt;br /&gt;
Be sure to show all steps in your solution and include diagrams whenever possible&lt;br /&gt;
&lt;br /&gt;
===Simple===&lt;br /&gt;
&lt;br /&gt;
A 100Kg box is placed on a flat table. The box does not move. The coefficient of static friction &amp;lt;math&amp;gt; {&amp;amp;mu;}_{s} = {.25} &amp;lt;/math&amp;gt; and the coefficient of kinetic friction &amp;lt;math&amp;gt; {&amp;amp;mu;}_{k} = {.15} &amp;lt;/math&amp;gt;.&lt;br /&gt;
Find the force of friction &amp;lt;math&amp;gt;{F}_{s}&amp;lt;/math&amp;gt;.&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
Solution:&lt;br /&gt;
&lt;br /&gt;
Since the box does not move, there is only static friction. The normal force is equivalent to the force due to gravity: &amp;lt;math&amp;gt; {F}_{N} = {F}_{g} = {100}{g} &amp;lt;/math&amp;gt;. The static friction can be found by: &amp;lt;math&amp;gt; {F}_{s} = {&amp;amp;mu;}_{s}{F}_{N} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
&amp;lt;math&amp;gt; {F}_{s} = {(.25)}{(100)}{(9.8)} = {245.25} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
===Middling===&lt;br /&gt;
&lt;br /&gt;
A cart of mass 3Kg moves across a track pushed by a fan which exerts &amp;lt;math&amp;gt; {F} = &amp;lt;3,0,1&amp;gt; &amp;lt;/math&amp;gt;N with an initial velocity &amp;lt;math&amp;gt; {v}_{i} = &amp;lt;1,0,1&amp;gt;\frac{{m}}{{s}}&amp;lt;/math&amp;gt; . Find the required coefficient of kinetic friction &amp;lt;math&amp;gt; {&amp;amp;mu;}_{k} &amp;lt;/math&amp;gt; needed to bring the cart to a stop in 10 seconds.&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
Solution:&lt;br /&gt;
&lt;br /&gt;
Use the momentum principle: &amp;lt;math&amp;gt;{p}_{f} - {p}_{i} = {F}_{net}{dt}&amp;lt;/math&amp;gt; and &amp;lt;math&amp;gt;{F}_{f} = {&amp;amp;mu;}_{k}{N} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
The final velocity must be 0. The initial velocity, initial force, and time are given. &lt;br /&gt;
&lt;br /&gt;
&amp;lt;math&amp;gt;0- &amp;lt;3,0,3&amp;gt; = {F}_{net}*{10s}&amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
&amp;lt;math&amp;gt; {F}_{net} = &amp;lt;-0.3,0,-0.3&amp;gt; &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
&amp;lt;math&amp;gt; {F}_{net} = {F} - {F}_{f} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
&amp;lt;math&amp;gt; &amp;lt;-0.3,0,-0.3&amp;gt;  = &amp;lt;3,0,1&amp;gt; - {F}_{f}&amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
&amp;lt;math&amp;gt;{F}_{f}  = &amp;lt;3.3,0,1.3&amp;gt; &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
&amp;lt;math&amp;gt; {F}_{f} = &amp;lt;3.3,0,1.3&amp;gt; = {&amp;amp;mu;}_{k}{N} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
&amp;lt;math&amp;gt; {N} = {3Kg} * {&amp;lt;0,9.8,0&amp;gt;} = &amp;lt;0,29.43,0&amp;gt; &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
&amp;lt;math&amp;gt; {&amp;amp;mu;}_{k} = \frac{{F}_{f}}{{N}} = \frac{{&amp;lt;3.3,0,1.3&amp;gt;}}{{0,29.43,0}} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
===Difficult===&lt;br /&gt;
&lt;br /&gt;
Two blocks are stacked on top of one another on a frictio&lt;br /&gt;
&lt;br /&gt;
==Connectedness==&lt;br /&gt;
#How is this topic connected to something that you are interested in?&lt;br /&gt;
#How is it connected to your major?&lt;br /&gt;
#Is there an interesting industrial application?&lt;br /&gt;
&lt;br /&gt;
==History==&lt;br /&gt;
&lt;br /&gt;
Put this idea in historical context. Give the reader the Who, What, When, Where, and Why.&lt;br /&gt;
&lt;br /&gt;
== See also ==&lt;br /&gt;
&lt;br /&gt;
Are there related topics or categories in this wiki resource for the curious reader to explore?  How does this topic fit into that context?&lt;br /&gt;
&lt;br /&gt;
===Further reading===&lt;br /&gt;
&lt;br /&gt;
Books, Articles or other print media on this topic&lt;br /&gt;
&lt;br /&gt;
===External links===&lt;br /&gt;
&lt;br /&gt;
Internet resources on this topic&lt;br /&gt;
&lt;br /&gt;
==References==&lt;br /&gt;
&lt;br /&gt;
This section contains the the references you used while writing this page&lt;br /&gt;
&lt;br /&gt;
[[Category:Contact Forces]]&lt;/div&gt;</summary>
		<author><name>Drao31</name></author>
	</entry>
	<entry>
		<id>http://www.physicsbook.gatech.edu/index.php?title=Friction&amp;diff=24974</id>
		<title>Friction</title>
		<link rel="alternate" type="text/html" href="http://www.physicsbook.gatech.edu/index.php?title=Friction&amp;diff=24974"/>
		<updated>2016-11-27T20:08:06Z</updated>

		<summary type="html">&lt;p&gt;Drao31: /* Middling */&lt;/p&gt;
&lt;hr /&gt;
&lt;div&gt;This page discusses the concept of friction and how it relates to both moving and static objects.&lt;br /&gt;
&lt;br /&gt;
Claimed by drao31&lt;br /&gt;
&lt;br /&gt;
==The Main Idea==&lt;br /&gt;
Friction is caused by the interactions between the atoms that make up objects. When objects interact, the atoms that make up the objects also interact. Temperatures of interacting surfaces rise because of such interactions. Friction is a force that resists movement. Generally, friction makes it harder to move objects. There are two main types of friction that are covered in Physics 2211: Static Friction and Kinetic Friction. Static friction can be described as the friction acting on resting objects. Kinetic friction is the friction acting on objects in motion. &lt;br /&gt;
&lt;br /&gt;
Frictional forces depend on a few factors: the normal force and the coefficient of friction. &lt;br /&gt;
&lt;br /&gt;
In simple terms, the normal force &amp;lt;math&amp;gt; {F}_{N} &amp;lt;/math&amp;gt; or &amp;lt;math&amp;gt; {N} &amp;lt;/math&amp;gt; is the equivalent force between objects. For example, when an object of mass &#039;&#039;&#039;M&#039;&#039;&#039; is placed on a table, there is a gravitational force &#039;&#039;&#039;Mg&#039;&#039;&#039; on the table. If the table can support the object without collapsing, the table exerts an equivalent force &#039;&#039;&#039;Mg&#039;&#039;&#039; on the object. According to the momentum principle, since there is no change in momentum, the net force must be &#039;&#039;&#039;0&#039;&#039;&#039;. This is also apparent since there is no movement if the table can support the object.&lt;br /&gt;
&lt;br /&gt;
::&amp;lt;math&amp;gt; {p}_{f} - {p}_{i} = {F}_{net}{dt} = 0 &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
OR&lt;br /&gt;
&lt;br /&gt;
::&amp;lt;math&amp;gt; {F}_{g} = {M}{g} &amp;lt;/math&amp;gt;&lt;br /&gt;
::&amp;lt;math&amp;gt; {N} = {M}{g} &amp;lt;/math&amp;gt;&lt;br /&gt;
::&amp;lt;math&amp;gt; {F}_{net} = {F}_{g} - {N} = {0} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
The coefficient of friction is usually specific to each object or material. The coefficient of static friction is denoted by &amp;lt;math&amp;gt;{&amp;amp;mu;}_{s}&amp;lt;/math&amp;gt; and the coefficient of kinetic friction is denoted by &amp;lt;math&amp;gt;{&amp;amp;mu;}_{k}&amp;lt;/math&amp;gt; &lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
Static Friction:&lt;br /&gt;
&lt;br /&gt;
::&amp;lt;math&amp;gt; {F}_{s} \le {&amp;amp;mu;}_{s}{N} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
Static friction is the frictional force that must be overcome to begin moving an object at rest. The static friction can be no more than the normal force multiplied by the coefficient of static friction. Therefore, the maximum static friction an object can have is &amp;lt;math&amp;gt; {&amp;amp;mu;}_{s}{N} &amp;lt;/math&amp;gt;. &lt;br /&gt;
&lt;br /&gt;
Kinetic Friction:&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
::&amp;lt;math&amp;gt; {F}_{k} = {&amp;amp;mu;}_{k}{N} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
Kinetic friction is the frictional force that exists between objects already at motion. It acts to oppose the movement of an object. Kinetic friction can be observed, for example, when a soccer ball is kicked across a field. The friction between the ball and the field will eventually bring the ball to a stop.&lt;br /&gt;
&lt;br /&gt;
Interestingly, friction is also required for rolling motion. Without friction, objects would not be able to roll. This is true because friction results in torque acting on the object, causing the rolling motion. An example of this can be seen in cars that are stuck in a ditch or similar situations. If there is not enough friction between the car&#039;s wheels and the ground, the car&#039;s wheels will simply spin in place, and the car will not move.&lt;br /&gt;
&lt;br /&gt;
===A Mathematical Model===&lt;br /&gt;
&lt;br /&gt;
As stated above:&lt;br /&gt;
&lt;br /&gt;
Static Friction:&lt;br /&gt;
&lt;br /&gt;
::&amp;lt;math&amp;gt; {F}_{s} \le {&amp;amp;mu;}_{s}{N} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
Kinetic Friction:&lt;br /&gt;
&lt;br /&gt;
::&amp;lt;math&amp;gt; {F}_{k} = {&amp;amp;mu;}_{k}{N} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
When attempting to solve problems relating to friction, one possible method of approach is to consider the net force acting on an object. If there is a force &amp;lt;math&amp;gt; {F}&amp;lt;/math&amp;gt; pushing an object to the right, and a frictional force &amp;lt;math&amp;gt;{F}_{f}&amp;lt;/math&amp;gt; opposing the movement, then the net force is &amp;lt;math&amp;gt; {F}_{net} = {F} - {F}_{f} &amp;lt;/math&amp;gt;.&lt;br /&gt;
&lt;br /&gt;
Another possible approach is by using the momentum principle &amp;lt;math&amp;gt; {p}_{f} - {p}_{i} = {F}_{net}{dt} &amp;lt;/math&amp;gt;. The momentum principle can help solve problems where you need to account for time, net force, or change in momentum.&lt;br /&gt;
&lt;br /&gt;
===A Computational Model===&lt;br /&gt;
&lt;br /&gt;
[[File:Friction.gif]]&lt;br /&gt;
&lt;br /&gt;
Link: &lt;br /&gt;
https://trinket.io/glowscript/76028c1809&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
Code: &lt;br /&gt;
 def friction():&lt;br /&gt;
    from __future__ import division&lt;br /&gt;
    from visual import *&lt;br /&gt;
    from visual.graph import *&lt;br /&gt;
&lt;br /&gt;
    mcart = 100&lt;br /&gt;
    mew = vector(2.9,0,0)&lt;br /&gt;
&lt;br /&gt;
    track =  box(pos=vector(0,-0.05,0), size=vector(20.0,0.05,0.10), color=color.white)&lt;br /&gt;
    cart =  box(pos=vector(-10,0.25,0), size=vector(.5,0.6,0.03), color=color.blue)&lt;br /&gt;
    marker = box(pos = vector(2,0,0), size = vector(0,20,5), color = color.red)&lt;br /&gt;
&lt;br /&gt;
    cart.v=vector(2.4,0,0)&lt;br /&gt;
    cart.p = mcart*cart.v&lt;br /&gt;
    F = vector(90,0,0)&lt;br /&gt;
    F2 = vector(-200,0,0)&lt;br /&gt;
    F3 = (mcart * mew)&lt;br /&gt;
    print(F3)&lt;br /&gt;
&lt;br /&gt;
    deltat = 0.01&lt;br /&gt;
    t = 0&lt;br /&gt;
&lt;br /&gt;
    while t &amp;lt; 5.02:&lt;br /&gt;
&lt;br /&gt;
        if cart.pos.x &amp;lt; 2:&lt;br /&gt;
            cart.v = cart.p / cart.m&lt;br /&gt;
            Fnet = F&lt;br /&gt;
            cart.p = cart.p + Fnet*deltat&lt;br /&gt;
            cart.pos = cart.pos + (cart.p/mcart)*deltat&lt;br /&gt;
&lt;br /&gt;
        else:&lt;br /&gt;
            &lt;br /&gt;
            cart.v = cart.p / cart.m&lt;br /&gt;
            Fnet = F-F3&lt;br /&gt;
            cart.p = cart.p + Fnet*deltat&lt;br /&gt;
            cart.pos = cart.pos + (cart.p/mcart)*deltat&lt;br /&gt;
            &lt;br /&gt;
        t = t + deltat&lt;br /&gt;
        rate(100)&lt;br /&gt;
        &lt;br /&gt;
    print(cart.pos)&lt;br /&gt;
    &lt;br /&gt;
 friction()&lt;br /&gt;
&lt;br /&gt;
==Examples==&lt;br /&gt;
&lt;br /&gt;
Be sure to show all steps in your solution and include diagrams whenever possible&lt;br /&gt;
&lt;br /&gt;
===Simple===&lt;br /&gt;
&lt;br /&gt;
A 100Kg box is placed on a flat table. The box does not move. The coefficient of static friction &amp;lt;math&amp;gt; {&amp;amp;mu;}_{s} = {.25} &amp;lt;/math&amp;gt; and the coefficient of kinetic friction &amp;lt;math&amp;gt; {&amp;amp;mu;}_{k} = {.15} &amp;lt;/math&amp;gt;.&lt;br /&gt;
Find the force of friction &amp;lt;math&amp;gt;{F}_{s}&amp;lt;/math&amp;gt;.&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
Solution:&lt;br /&gt;
&lt;br /&gt;
Since the box does not move, there is only static friction. The normal force is equivalent to the force due to gravity: &amp;lt;math&amp;gt; {F}_{N} = {F}_{g} = {100}{g} &amp;lt;/math&amp;gt;. The static friction can be found by: &amp;lt;math&amp;gt; {F}_{s} = {&amp;amp;mu;}_{s}{F}_{N} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
&amp;lt;math&amp;gt; {F}_{s} = {(.25)}{(100)}{(9.8)} = {245.25} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
===Middling===&lt;br /&gt;
&lt;br /&gt;
A cart of mass 3Kg moves across a track pushed by a fan which exerts &amp;lt;math&amp;gt; {F} = &amp;lt;3,0,1&amp;gt; &amp;lt;/math&amp;gt;N with an initial velocity &amp;lt;math&amp;gt; {v}_{i} = &amp;lt;1,0,1&amp;gt;\frac{{m}}{{s}}&amp;lt;/math&amp;gt; . Find the required coefficient of kinetic friction &amp;lt;math&amp;gt; {&amp;amp;mu;}_{k} &amp;lt;/math&amp;gt; needed to bring the cart to a stop in 10 seconds.&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
Solution:&lt;br /&gt;
&lt;br /&gt;
Use the momentum principle: &amp;lt;math&amp;gt;{p}_{f} - {p}_{i} = {F}_{net}{dt}&amp;lt;/math&amp;gt; and &amp;lt;math&amp;gt;{F}_{f} = {&amp;amp;mu;}_{k}{N} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
The final velocity must be 0. The initial velocity, initial force, and time are given. &lt;br /&gt;
&lt;br /&gt;
&amp;lt;math&amp;gt;0- &amp;lt;3,0,3&amp;gt; = {F}_{net}{10s}&amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
&amp;lt;math&amp;gt; {F}_{net} = &amp;lt;-0.3,0,-0.3&amp;gt; &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
&amp;lt;math&amp;gt; &amp;lt;-0.3,0,-0.3&amp;gt;  = &amp;lt;3,0,1&amp;gt; - {F}_{f}&amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
&amp;lt;math&amp;gt;{F}_{f}  = &amp;lt;3.3,0,1.3&amp;gt; &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
&amp;lt;math&amp;gt; {F}_{f} = &amp;lt;3.3,0,1.3&amp;gt; = {&amp;amp;mu;}_{k}{N} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
&amp;lt;math&amp;gt; {N} = {3Kg} * {&amp;lt;0,9.8,0&amp;gt;} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
&amp;lt;math&amp;gt; {&amp;amp;mu;}_{k} = \frac{{F}_{f}}{{N}} = \frac{{&amp;lt;3.3,0,1.3&amp;gt;}}{{0,29.43,0}} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
===Difficult===&lt;br /&gt;
&lt;br /&gt;
Two blocks are stacked on top of one another on a frictio&lt;br /&gt;
&lt;br /&gt;
==Connectedness==&lt;br /&gt;
#How is this topic connected to something that you are interested in?&lt;br /&gt;
#How is it connected to your major?&lt;br /&gt;
#Is there an interesting industrial application?&lt;br /&gt;
&lt;br /&gt;
==History==&lt;br /&gt;
&lt;br /&gt;
Put this idea in historical context. Give the reader the Who, What, When, Where, and Why.&lt;br /&gt;
&lt;br /&gt;
== See also ==&lt;br /&gt;
&lt;br /&gt;
Are there related topics or categories in this wiki resource for the curious reader to explore?  How does this topic fit into that context?&lt;br /&gt;
&lt;br /&gt;
===Further reading===&lt;br /&gt;
&lt;br /&gt;
Books, Articles or other print media on this topic&lt;br /&gt;
&lt;br /&gt;
===External links===&lt;br /&gt;
&lt;br /&gt;
Internet resources on this topic&lt;br /&gt;
&lt;br /&gt;
==References==&lt;br /&gt;
&lt;br /&gt;
This section contains the the references you used while writing this page&lt;br /&gt;
&lt;br /&gt;
[[Category:Contact Forces]]&lt;/div&gt;</summary>
		<author><name>Drao31</name></author>
	</entry>
	<entry>
		<id>http://www.physicsbook.gatech.edu/index.php?title=Friction&amp;diff=24972</id>
		<title>Friction</title>
		<link rel="alternate" type="text/html" href="http://www.physicsbook.gatech.edu/index.php?title=Friction&amp;diff=24972"/>
		<updated>2016-11-27T20:07:30Z</updated>

		<summary type="html">&lt;p&gt;Drao31: /* Middling */&lt;/p&gt;
&lt;hr /&gt;
&lt;div&gt;This page discusses the concept of friction and how it relates to both moving and static objects.&lt;br /&gt;
&lt;br /&gt;
Claimed by drao31&lt;br /&gt;
&lt;br /&gt;
==The Main Idea==&lt;br /&gt;
Friction is caused by the interactions between the atoms that make up objects. When objects interact, the atoms that make up the objects also interact. Temperatures of interacting surfaces rise because of such interactions. Friction is a force that resists movement. Generally, friction makes it harder to move objects. There are two main types of friction that are covered in Physics 2211: Static Friction and Kinetic Friction. Static friction can be described as the friction acting on resting objects. Kinetic friction is the friction acting on objects in motion. &lt;br /&gt;
&lt;br /&gt;
Frictional forces depend on a few factors: the normal force and the coefficient of friction. &lt;br /&gt;
&lt;br /&gt;
In simple terms, the normal force &amp;lt;math&amp;gt; {F}_{N} &amp;lt;/math&amp;gt; or &amp;lt;math&amp;gt; {N} &amp;lt;/math&amp;gt; is the equivalent force between objects. For example, when an object of mass &#039;&#039;&#039;M&#039;&#039;&#039; is placed on a table, there is a gravitational force &#039;&#039;&#039;Mg&#039;&#039;&#039; on the table. If the table can support the object without collapsing, the table exerts an equivalent force &#039;&#039;&#039;Mg&#039;&#039;&#039; on the object. According to the momentum principle, since there is no change in momentum, the net force must be &#039;&#039;&#039;0&#039;&#039;&#039;. This is also apparent since there is no movement if the table can support the object.&lt;br /&gt;
&lt;br /&gt;
::&amp;lt;math&amp;gt; {p}_{f} - {p}_{i} = {F}_{net}{dt} = 0 &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
OR&lt;br /&gt;
&lt;br /&gt;
::&amp;lt;math&amp;gt; {F}_{g} = {M}{g} &amp;lt;/math&amp;gt;&lt;br /&gt;
::&amp;lt;math&amp;gt; {N} = {M}{g} &amp;lt;/math&amp;gt;&lt;br /&gt;
::&amp;lt;math&amp;gt; {F}_{net} = {F}_{g} - {N} = {0} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
The coefficient of friction is usually specific to each object or material. The coefficient of static friction is denoted by &amp;lt;math&amp;gt;{&amp;amp;mu;}_{s}&amp;lt;/math&amp;gt; and the coefficient of kinetic friction is denoted by &amp;lt;math&amp;gt;{&amp;amp;mu;}_{k}&amp;lt;/math&amp;gt; &lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
Static Friction:&lt;br /&gt;
&lt;br /&gt;
::&amp;lt;math&amp;gt; {F}_{s} \le {&amp;amp;mu;}_{s}{N} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
Static friction is the frictional force that must be overcome to begin moving an object at rest. The static friction can be no more than the normal force multiplied by the coefficient of static friction. Therefore, the maximum static friction an object can have is &amp;lt;math&amp;gt; {&amp;amp;mu;}_{s}{N} &amp;lt;/math&amp;gt;. &lt;br /&gt;
&lt;br /&gt;
Kinetic Friction:&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
::&amp;lt;math&amp;gt; {F}_{k} = {&amp;amp;mu;}_{k}{N} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
Kinetic friction is the frictional force that exists between objects already at motion. It acts to oppose the movement of an object. Kinetic friction can be observed, for example, when a soccer ball is kicked across a field. The friction between the ball and the field will eventually bring the ball to a stop.&lt;br /&gt;
&lt;br /&gt;
Interestingly, friction is also required for rolling motion. Without friction, objects would not be able to roll. This is true because friction results in torque acting on the object, causing the rolling motion. An example of this can be seen in cars that are stuck in a ditch or similar situations. If there is not enough friction between the car&#039;s wheels and the ground, the car&#039;s wheels will simply spin in place, and the car will not move.&lt;br /&gt;
&lt;br /&gt;
===A Mathematical Model===&lt;br /&gt;
&lt;br /&gt;
As stated above:&lt;br /&gt;
&lt;br /&gt;
Static Friction:&lt;br /&gt;
&lt;br /&gt;
::&amp;lt;math&amp;gt; {F}_{s} \le {&amp;amp;mu;}_{s}{N} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
Kinetic Friction:&lt;br /&gt;
&lt;br /&gt;
::&amp;lt;math&amp;gt; {F}_{k} = {&amp;amp;mu;}_{k}{N} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
When attempting to solve problems relating to friction, one possible method of approach is to consider the net force acting on an object. If there is a force &amp;lt;math&amp;gt; {F}&amp;lt;/math&amp;gt; pushing an object to the right, and a frictional force &amp;lt;math&amp;gt;{F}_{f}&amp;lt;/math&amp;gt; opposing the movement, then the net force is &amp;lt;math&amp;gt; {F}_{net} = {F} - {F}_{f} &amp;lt;/math&amp;gt;.&lt;br /&gt;
&lt;br /&gt;
Another possible approach is by using the momentum principle &amp;lt;math&amp;gt; {p}_{f} - {p}_{i} = {F}_{net}{dt} &amp;lt;/math&amp;gt;. The momentum principle can help solve problems where you need to account for time, net force, or change in momentum.&lt;br /&gt;
&lt;br /&gt;
===A Computational Model===&lt;br /&gt;
&lt;br /&gt;
[[File:Friction.gif]]&lt;br /&gt;
&lt;br /&gt;
Link: &lt;br /&gt;
https://trinket.io/glowscript/76028c1809&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
Code: &lt;br /&gt;
 def friction():&lt;br /&gt;
    from __future__ import division&lt;br /&gt;
    from visual import *&lt;br /&gt;
    from visual.graph import *&lt;br /&gt;
&lt;br /&gt;
    mcart = 100&lt;br /&gt;
    mew = vector(2.9,0,0)&lt;br /&gt;
&lt;br /&gt;
    track =  box(pos=vector(0,-0.05,0), size=vector(20.0,0.05,0.10), color=color.white)&lt;br /&gt;
    cart =  box(pos=vector(-10,0.25,0), size=vector(.5,0.6,0.03), color=color.blue)&lt;br /&gt;
    marker = box(pos = vector(2,0,0), size = vector(0,20,5), color = color.red)&lt;br /&gt;
&lt;br /&gt;
    cart.v=vector(2.4,0,0)&lt;br /&gt;
    cart.p = mcart*cart.v&lt;br /&gt;
    F = vector(90,0,0)&lt;br /&gt;
    F2 = vector(-200,0,0)&lt;br /&gt;
    F3 = (mcart * mew)&lt;br /&gt;
    print(F3)&lt;br /&gt;
&lt;br /&gt;
    deltat = 0.01&lt;br /&gt;
    t = 0&lt;br /&gt;
&lt;br /&gt;
    while t &amp;lt; 5.02:&lt;br /&gt;
&lt;br /&gt;
        if cart.pos.x &amp;lt; 2:&lt;br /&gt;
            cart.v = cart.p / cart.m&lt;br /&gt;
            Fnet = F&lt;br /&gt;
            cart.p = cart.p + Fnet*deltat&lt;br /&gt;
            cart.pos = cart.pos + (cart.p/mcart)*deltat&lt;br /&gt;
&lt;br /&gt;
        else:&lt;br /&gt;
            &lt;br /&gt;
            cart.v = cart.p / cart.m&lt;br /&gt;
            Fnet = F-F3&lt;br /&gt;
            cart.p = cart.p + Fnet*deltat&lt;br /&gt;
            cart.pos = cart.pos + (cart.p/mcart)*deltat&lt;br /&gt;
            &lt;br /&gt;
        t = t + deltat&lt;br /&gt;
        rate(100)&lt;br /&gt;
        &lt;br /&gt;
    print(cart.pos)&lt;br /&gt;
    &lt;br /&gt;
 friction()&lt;br /&gt;
&lt;br /&gt;
==Examples==&lt;br /&gt;
&lt;br /&gt;
Be sure to show all steps in your solution and include diagrams whenever possible&lt;br /&gt;
&lt;br /&gt;
===Simple===&lt;br /&gt;
&lt;br /&gt;
A 100Kg box is placed on a flat table. The box does not move. The coefficient of static friction &amp;lt;math&amp;gt; {&amp;amp;mu;}_{s} = {.25} &amp;lt;/math&amp;gt; and the coefficient of kinetic friction &amp;lt;math&amp;gt; {&amp;amp;mu;}_{k} = {.15} &amp;lt;/math&amp;gt;.&lt;br /&gt;
Find the force of friction &amp;lt;math&amp;gt;{F}_{s}&amp;lt;/math&amp;gt;.&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
Solution:&lt;br /&gt;
&lt;br /&gt;
Since the box does not move, there is only static friction. The normal force is equivalent to the force due to gravity: &amp;lt;math&amp;gt; {F}_{N} = {F}_{g} = {100}{g} &amp;lt;/math&amp;gt;. The static friction can be found by: &amp;lt;math&amp;gt; {F}_{s} = {&amp;amp;mu;}_{s}{F}_{N} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
&amp;lt;math&amp;gt; {F}_{s} = {(.25)}{(100)}{(9.8)} = {245.25} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
===Middling===&lt;br /&gt;
&lt;br /&gt;
A cart of mass 3Kg moves across a track pushed by a fan which exerts &amp;lt;math&amp;gt; {F} = &amp;lt;3,0,1&amp;gt; &amp;lt;/math&amp;gt;N with an initial velocity &amp;lt;math&amp;gt; {v}_{i} = &amp;lt;1,0,1&amp;gt;\frac{{m}}{{s}}&amp;lt;/math&amp;gt; . Find the required coefficient of kinetic friction &amp;lt;math&amp;gt; {&amp;amp;mu;}_{k} &amp;lt;/math&amp;gt; needed to bring the cart to a stop in 10 seconds.&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
Solution:&lt;br /&gt;
&lt;br /&gt;
Use the momentum principle: &amp;lt;math&amp;gt;{p}_{f} - {p}_{i} = {F}_{net}{dt}&amp;lt;/math&amp;gt; and &amp;lt;math&amp;gt;{F}_{f} = {&amp;amp;mu;}_{k}{N} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
The final velocity must be 0. The initial velocity, initial force, and time are given. &lt;br /&gt;
&lt;br /&gt;
&amp;lt;math&amp;gt;0- &amp;lt;3,0,3&amp;gt; = {F}_{net}{10s}&amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
&amp;lt;math&amp;gt; {F}_{net} = &amp;lt;-0.3,0,-0.3&amp;gt; &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
&amp;lt;math&amp;gt; &amp;lt;-0.3,0,-0.3&amp;gt;  = &amp;lt;3,0,1&amp;gt; - {F}_{f}&amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
&amp;lt;math&amp;gt;{F}_{f}  = &amp;lt;3.3,0,1.3&amp;gt; &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
&amp;lt;math&amp;gt; {F}_{f} = &amp;lt;3.3,0,1.3&amp;gt; = {&amp;amp;mu;}_{k}{N} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
&amp;lt;math&amp;gt; {N} = {3Kg} * {0,9.8,0} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
&amp;lt;math&amp;gt; {&amp;amp;mu;}_{k} = \frac{{F}_{f}}{{N}} = \frac{{&amp;lt;3.3,0,1.3&amp;gt;}}{{0,29.43,0}} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
===Difficult===&lt;br /&gt;
&lt;br /&gt;
Two blocks are stacked on top of one another on a frictio&lt;br /&gt;
&lt;br /&gt;
==Connectedness==&lt;br /&gt;
#How is this topic connected to something that you are interested in?&lt;br /&gt;
#How is it connected to your major?&lt;br /&gt;
#Is there an interesting industrial application?&lt;br /&gt;
&lt;br /&gt;
==History==&lt;br /&gt;
&lt;br /&gt;
Put this idea in historical context. Give the reader the Who, What, When, Where, and Why.&lt;br /&gt;
&lt;br /&gt;
== See also ==&lt;br /&gt;
&lt;br /&gt;
Are there related topics or categories in this wiki resource for the curious reader to explore?  How does this topic fit into that context?&lt;br /&gt;
&lt;br /&gt;
===Further reading===&lt;br /&gt;
&lt;br /&gt;
Books, Articles or other print media on this topic&lt;br /&gt;
&lt;br /&gt;
===External links===&lt;br /&gt;
&lt;br /&gt;
Internet resources on this topic&lt;br /&gt;
&lt;br /&gt;
==References==&lt;br /&gt;
&lt;br /&gt;
This section contains the the references you used while writing this page&lt;br /&gt;
&lt;br /&gt;
[[Category:Contact Forces]]&lt;/div&gt;</summary>
		<author><name>Drao31</name></author>
	</entry>
	<entry>
		<id>http://www.physicsbook.gatech.edu/index.php?title=Friction&amp;diff=24966</id>
		<title>Friction</title>
		<link rel="alternate" type="text/html" href="http://www.physicsbook.gatech.edu/index.php?title=Friction&amp;diff=24966"/>
		<updated>2016-11-27T20:04:44Z</updated>

		<summary type="html">&lt;p&gt;Drao31: &lt;/p&gt;
&lt;hr /&gt;
&lt;div&gt;This page discusses the concept of friction and how it relates to both moving and static objects.&lt;br /&gt;
&lt;br /&gt;
Claimed by drao31&lt;br /&gt;
&lt;br /&gt;
==The Main Idea==&lt;br /&gt;
Friction is caused by the interactions between the atoms that make up objects. When objects interact, the atoms that make up the objects also interact. Temperatures of interacting surfaces rise because of such interactions. Friction is a force that resists movement. Generally, friction makes it harder to move objects. There are two main types of friction that are covered in Physics 2211: Static Friction and Kinetic Friction. Static friction can be described as the friction acting on resting objects. Kinetic friction is the friction acting on objects in motion. &lt;br /&gt;
&lt;br /&gt;
Frictional forces depend on a few factors: the normal force and the coefficient of friction. &lt;br /&gt;
&lt;br /&gt;
In simple terms, the normal force &amp;lt;math&amp;gt; {F}_{N} &amp;lt;/math&amp;gt; or &amp;lt;math&amp;gt; {N} &amp;lt;/math&amp;gt; is the equivalent force between objects. For example, when an object of mass &#039;&#039;&#039;M&#039;&#039;&#039; is placed on a table, there is a gravitational force &#039;&#039;&#039;Mg&#039;&#039;&#039; on the table. If the table can support the object without collapsing, the table exerts an equivalent force &#039;&#039;&#039;Mg&#039;&#039;&#039; on the object. According to the momentum principle, since there is no change in momentum, the net force must be &#039;&#039;&#039;0&#039;&#039;&#039;. This is also apparent since there is no movement if the table can support the object.&lt;br /&gt;
&lt;br /&gt;
::&amp;lt;math&amp;gt; {p}_{f} - {p}_{i} = {F}_{net}{dt} = 0 &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
OR&lt;br /&gt;
&lt;br /&gt;
::&amp;lt;math&amp;gt; {F}_{g} = {M}{g} &amp;lt;/math&amp;gt;&lt;br /&gt;
::&amp;lt;math&amp;gt; {N} = {M}{g} &amp;lt;/math&amp;gt;&lt;br /&gt;
::&amp;lt;math&amp;gt; {F}_{net} = {F}_{g} - {N} = {0} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
The coefficient of friction is usually specific to each object or material. The coefficient of static friction is denoted by &amp;lt;math&amp;gt;{&amp;amp;mu;}_{s}&amp;lt;/math&amp;gt; and the coefficient of kinetic friction is denoted by &amp;lt;math&amp;gt;{&amp;amp;mu;}_{k}&amp;lt;/math&amp;gt; &lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
Static Friction:&lt;br /&gt;
&lt;br /&gt;
::&amp;lt;math&amp;gt; {F}_{s} \le {&amp;amp;mu;}_{s}{N} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
Static friction is the frictional force that must be overcome to begin moving an object at rest. The static friction can be no more than the normal force multiplied by the coefficient of static friction. Therefore, the maximum static friction an object can have is &amp;lt;math&amp;gt; {&amp;amp;mu;}_{s}{N} &amp;lt;/math&amp;gt;. &lt;br /&gt;
&lt;br /&gt;
Kinetic Friction:&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
::&amp;lt;math&amp;gt; {F}_{k} = {&amp;amp;mu;}_{k}{N} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
Kinetic friction is the frictional force that exists between objects already at motion. It acts to oppose the movement of an object. Kinetic friction can be observed, for example, when a soccer ball is kicked across a field. The friction between the ball and the field will eventually bring the ball to a stop.&lt;br /&gt;
&lt;br /&gt;
Interestingly, friction is also required for rolling motion. Without friction, objects would not be able to roll. This is true because friction results in torque acting on the object, causing the rolling motion. An example of this can be seen in cars that are stuck in a ditch or similar situations. If there is not enough friction between the car&#039;s wheels and the ground, the car&#039;s wheels will simply spin in place, and the car will not move.&lt;br /&gt;
&lt;br /&gt;
===A Mathematical Model===&lt;br /&gt;
&lt;br /&gt;
As stated above:&lt;br /&gt;
&lt;br /&gt;
Static Friction:&lt;br /&gt;
&lt;br /&gt;
::&amp;lt;math&amp;gt; {F}_{s} \le {&amp;amp;mu;}_{s}{N} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
Kinetic Friction:&lt;br /&gt;
&lt;br /&gt;
::&amp;lt;math&amp;gt; {F}_{k} = {&amp;amp;mu;}_{k}{N} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
When attempting to solve problems relating to friction, one possible method of approach is to consider the net force acting on an object. If there is a force &amp;lt;math&amp;gt; {F}&amp;lt;/math&amp;gt; pushing an object to the right, and a frictional force &amp;lt;math&amp;gt;{F}_{f}&amp;lt;/math&amp;gt; opposing the movement, then the net force is &amp;lt;math&amp;gt; {F}_{net} = {F} - {F}_{f} &amp;lt;/math&amp;gt;.&lt;br /&gt;
&lt;br /&gt;
Another possible approach is by using the momentum principle &amp;lt;math&amp;gt; {p}_{f} - {p}_{i} = {F}_{net}{dt} &amp;lt;/math&amp;gt;. The momentum principle can help solve problems where you need to account for time, net force, or change in momentum.&lt;br /&gt;
&lt;br /&gt;
===A Computational Model===&lt;br /&gt;
&lt;br /&gt;
[[File:Friction.gif]]&lt;br /&gt;
&lt;br /&gt;
Link: &lt;br /&gt;
https://trinket.io/glowscript/76028c1809&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
Code: &lt;br /&gt;
 def friction():&lt;br /&gt;
    from __future__ import division&lt;br /&gt;
    from visual import *&lt;br /&gt;
    from visual.graph import *&lt;br /&gt;
&lt;br /&gt;
    mcart = 100&lt;br /&gt;
    mew = vector(2.9,0,0)&lt;br /&gt;
&lt;br /&gt;
    track =  box(pos=vector(0,-0.05,0), size=vector(20.0,0.05,0.10), color=color.white)&lt;br /&gt;
    cart =  box(pos=vector(-10,0.25,0), size=vector(.5,0.6,0.03), color=color.blue)&lt;br /&gt;
    marker = box(pos = vector(2,0,0), size = vector(0,20,5), color = color.red)&lt;br /&gt;
&lt;br /&gt;
    cart.v=vector(2.4,0,0)&lt;br /&gt;
    cart.p = mcart*cart.v&lt;br /&gt;
    F = vector(90,0,0)&lt;br /&gt;
    F2 = vector(-200,0,0)&lt;br /&gt;
    F3 = (mcart * mew)&lt;br /&gt;
    print(F3)&lt;br /&gt;
&lt;br /&gt;
    deltat = 0.01&lt;br /&gt;
    t = 0&lt;br /&gt;
&lt;br /&gt;
    while t &amp;lt; 5.02:&lt;br /&gt;
&lt;br /&gt;
        if cart.pos.x &amp;lt; 2:&lt;br /&gt;
            cart.v = cart.p / cart.m&lt;br /&gt;
            Fnet = F&lt;br /&gt;
            cart.p = cart.p + Fnet*deltat&lt;br /&gt;
            cart.pos = cart.pos + (cart.p/mcart)*deltat&lt;br /&gt;
&lt;br /&gt;
        else:&lt;br /&gt;
            &lt;br /&gt;
            cart.v = cart.p / cart.m&lt;br /&gt;
            Fnet = F-F3&lt;br /&gt;
            cart.p = cart.p + Fnet*deltat&lt;br /&gt;
            cart.pos = cart.pos + (cart.p/mcart)*deltat&lt;br /&gt;
            &lt;br /&gt;
        t = t + deltat&lt;br /&gt;
        rate(100)&lt;br /&gt;
        &lt;br /&gt;
    print(cart.pos)&lt;br /&gt;
    &lt;br /&gt;
 friction()&lt;br /&gt;
&lt;br /&gt;
==Examples==&lt;br /&gt;
&lt;br /&gt;
Be sure to show all steps in your solution and include diagrams whenever possible&lt;br /&gt;
&lt;br /&gt;
===Simple===&lt;br /&gt;
&lt;br /&gt;
A 100Kg box is placed on a flat table. The box does not move. The coefficient of static friction &amp;lt;math&amp;gt; {&amp;amp;mu;}_{s} = {.25} &amp;lt;/math&amp;gt; and the coefficient of kinetic friction &amp;lt;math&amp;gt; {&amp;amp;mu;}_{k} = {.15} &amp;lt;/math&amp;gt;.&lt;br /&gt;
Find the force of friction &amp;lt;math&amp;gt;{F}_{s}&amp;lt;/math&amp;gt;.&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
Solution:&lt;br /&gt;
&lt;br /&gt;
Since the box does not move, there is only static friction. The normal force is equivalent to the force due to gravity: &amp;lt;math&amp;gt; {F}_{N} = {F}_{g} = {100}{g} &amp;lt;/math&amp;gt;. The static friction can be found by: &amp;lt;math&amp;gt; {F}_{s} = {&amp;amp;mu;}_{s}{F}_{N} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
&amp;lt;math&amp;gt; {F}_{s} = {(.25)}{(100)}{(9.8)} = {245.25} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
===Middling===&lt;br /&gt;
&lt;br /&gt;
A cart of mass 3Kg moves across a track pushed by a fan which exerts &amp;lt;math&amp;gt; {F} = &amp;lt;3,0,1&amp;gt; &amp;lt;/math&amp;gt;N with an initial velocity &amp;lt;math&amp;gt; {v}_{i} = &amp;lt;1,0,1&amp;gt;\frac{{m}}{{s}}&amp;lt;/math&amp;gt; . Find the required coefficient of kinetic friction &amp;lt;math&amp;gt; {%mu;}_{k} &amp;lt;/math&amp;gt; needed to bring the cart to a stop in 10 seconds.&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
Solution:&lt;br /&gt;
&lt;br /&gt;
Use the momentum principle: &amp;lt;math&amp;gt;{p}_{f} - {p}_{i} = {F}_{net}{dt}&amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
The final velocity must be 0. The initial velocity, initial force, and time are given. &lt;br /&gt;
&lt;br /&gt;
&amp;lt;math&amp;gt;0- &amp;lt;3,0,3&amp;gt; = {F}_{net}{10s}&amp;lt;/math&amp;gt;&lt;br /&gt;
&amp;lt;math&amp;gt; {F}_{net} = &amp;lt;-0.3,0,-0.3&amp;gt; &amp;lt;/math&amp;gt;&lt;br /&gt;
&amp;lt;math&amp;gt; &amp;lt;-0.3,0,-0.3&amp;gt;  = &amp;lt;3,0,1&amp;gt; - {F}_{f}&amp;lt;/math&amp;gt;&lt;br /&gt;
&amp;lt;math&amp;gt;{F}_{f}  = &amp;lt;3.3,0,1.3&amp;gt; &amp;lt;/math&amp;gt;&lt;br /&gt;
&amp;lt;math&amp;gt; {F}_{f} = &amp;lt;3.3,0,1.3&amp;gt; = {&amp;amp;mu}_{k}{N} &amp;lt;/math&amp;gt;&lt;br /&gt;
&amp;lt;math&amp;gt; {N} = {3Kg} * {0,9.8,0} &amp;lt;/math&amp;gt;&lt;br /&gt;
&amp;lt;math&amp;gt; {&amp;amp;mu}_{k} = \frac{{F}_{f}}{{N}} = \frac{{&amp;lt;3.3,0,1.3&amp;gt;}}{{0,29.43,0}} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
===Difficult===&lt;br /&gt;
&lt;br /&gt;
Two blocks are stacked on top of one another on a frictio&lt;br /&gt;
&lt;br /&gt;
==Connectedness==&lt;br /&gt;
#How is this topic connected to something that you are interested in?&lt;br /&gt;
#How is it connected to your major?&lt;br /&gt;
#Is there an interesting industrial application?&lt;br /&gt;
&lt;br /&gt;
==History==&lt;br /&gt;
&lt;br /&gt;
Put this idea in historical context. Give the reader the Who, What, When, Where, and Why.&lt;br /&gt;
&lt;br /&gt;
== See also ==&lt;br /&gt;
&lt;br /&gt;
Are there related topics or categories in this wiki resource for the curious reader to explore?  How does this topic fit into that context?&lt;br /&gt;
&lt;br /&gt;
===Further reading===&lt;br /&gt;
&lt;br /&gt;
Books, Articles or other print media on this topic&lt;br /&gt;
&lt;br /&gt;
===External links===&lt;br /&gt;
&lt;br /&gt;
Internet resources on this topic&lt;br /&gt;
&lt;br /&gt;
==References==&lt;br /&gt;
&lt;br /&gt;
This section contains the the references you used while writing this page&lt;br /&gt;
&lt;br /&gt;
[[Category:Contact Forces]]&lt;/div&gt;</summary>
		<author><name>Drao31</name></author>
	</entry>
	<entry>
		<id>http://www.physicsbook.gatech.edu/index.php?title=Friction&amp;diff=24954</id>
		<title>Friction</title>
		<link rel="alternate" type="text/html" href="http://www.physicsbook.gatech.edu/index.php?title=Friction&amp;diff=24954"/>
		<updated>2016-11-27T19:58:03Z</updated>

		<summary type="html">&lt;p&gt;Drao31: /* Middling */&lt;/p&gt;
&lt;hr /&gt;
&lt;div&gt;This page discusses the concept of friction and how it relates to both moving and static objects.&lt;br /&gt;
&lt;br /&gt;
Claimed by drao31&lt;br /&gt;
&lt;br /&gt;
==The Main Idea==&lt;br /&gt;
Friction is caused by the interactions between the atoms that make up objects. When objects interact, the atoms that make up the objects also interact. Temperatures of interacting surfaces rise because of such interactions. Friction is a force that resists movement. Generally, friction makes it harder to move objects. There are two main types of friction that are covered in Physics 2211: Static Friction and Kinetic Friction. Static friction can be described as the friction acting on resting objects. Kinetic friction is the friction acting on objects in motion. &lt;br /&gt;
&lt;br /&gt;
Frictional forces depend on a few factors: the normal force and the coefficient of friction. &lt;br /&gt;
&lt;br /&gt;
In simple terms, the normal force &amp;lt;math&amp;gt; {F}_{N} &amp;lt;/math&amp;gt; or &amp;lt;math&amp;gt; {N} &amp;lt;/math&amp;gt; is the equivalent force between objects. For example, when an object of mass &#039;&#039;&#039;M&#039;&#039;&#039; is placed on a table, there is a gravitational force &#039;&#039;&#039;Mg&#039;&#039;&#039; on the table. If the table can support the object without collapsing, the table exerts an equivalent force &#039;&#039;&#039;Mg&#039;&#039;&#039; on the object. According to the momentum principle, since there is no change in momentum, the net force must be &#039;&#039;&#039;0&#039;&#039;&#039;. This is also apparent since there is no movement if the table can support the object.&lt;br /&gt;
&lt;br /&gt;
::&amp;lt;math&amp;gt; {p}_{f} - {p}_{i} = {F}_{net}{dt} = 0 &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
OR&lt;br /&gt;
&lt;br /&gt;
::&amp;lt;math&amp;gt; {F}_{g} = {M}{g} &amp;lt;/math&amp;gt;&lt;br /&gt;
::&amp;lt;math&amp;gt; {N} = {M}{g} &amp;lt;/math&amp;gt;&lt;br /&gt;
::&amp;lt;math&amp;gt; {F}_{net} = {F}_{g} - {N} = {0} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
The coefficient of friction is usually specific to each object or material. The coefficient of static friction is denoted by &amp;lt;math&amp;gt;{&amp;amp;mu;}_{s}&amp;lt;/math&amp;gt; and the coefficient of kinetic friction is denoted by &amp;lt;math&amp;gt;{&amp;amp;mu;}_{k}&amp;lt;/math&amp;gt; &lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
Static Friction:&lt;br /&gt;
&lt;br /&gt;
::&amp;lt;math&amp;gt; {F}_{s} \le {&amp;amp;mu;}_{s}{N} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
Static friction is the frictional force that must be overcome to begin moving an object at rest. The static friction can be no more than the normal force multiplied by the coefficient of static friction. Therefore, the maximum static friction an object can have is &amp;lt;math&amp;gt; {&amp;amp;mu;}_{s}{N} &amp;lt;/math&amp;gt;. &lt;br /&gt;
&lt;br /&gt;
Kinetic Friction:&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
::&amp;lt;math&amp;gt; {F}_{k} = {&amp;amp;mu;}_{k}{N} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
Kinetic friction is the frictional force that exists between objects already at motion. It acts to oppose the movement of an object. Kinetic friction can be observed, for example, when a soccer ball is kicked across a field. The friction between the ball and the field will eventually bring the ball to a stop.&lt;br /&gt;
&lt;br /&gt;
Interestingly, friction is also required for rolling motion. Without friction, objects would not be able to roll. This is true because friction results in torque acting on the object, causing the rolling motion. An example of this can be seen in cars that are stuck in a ditch or similar situations. If there is not enough friction between the car&#039;s wheels and the ground, the car&#039;s wheels will simply spin in place, and the car will not move.&lt;br /&gt;
&lt;br /&gt;
===A Mathematical Model===&lt;br /&gt;
&lt;br /&gt;
As stated above:&lt;br /&gt;
&lt;br /&gt;
Static Friction:&lt;br /&gt;
&lt;br /&gt;
::&amp;lt;math&amp;gt; {F}_{s} \le {&amp;amp;mu;}_{s}{N} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
Kinetic Friction:&lt;br /&gt;
&lt;br /&gt;
::&amp;lt;math&amp;gt; {F}_{k} = {&amp;amp;mu;}_{k}{N} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
When attempting to solve problems relating to friction, one possible method of approach is to consider the net force acting on an object. If there is a force &amp;lt;math&amp;gt; {F}&amp;lt;/math&amp;gt; pushing an object to the right, and a frictional force &amp;lt;math&amp;gt;{F}_{f}&amp;lt;/math&amp;gt; opposing the movement, then the net force is &amp;lt;math&amp;gt; {F}_{net} = {F} - {F}_{f} &amp;lt;/math&amp;gt;.&lt;br /&gt;
&lt;br /&gt;
Another possible approach is by using the momentum principle &amp;lt;math&amp;gt; {p}_{f} - {p}_{i} = {F}_{net}{dt} &amp;lt;/math&amp;gt;. The momentum principle can help solve problems where you need to account for time, net force, or change in momentum.&lt;br /&gt;
&lt;br /&gt;
===A Computational Model===&lt;br /&gt;
&lt;br /&gt;
[[File:Friction.gif]]&lt;br /&gt;
&lt;br /&gt;
Link: &lt;br /&gt;
https://trinket.io/glowscript/76028c1809&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
Code: &lt;br /&gt;
 def friction():&lt;br /&gt;
    from __future__ import division&lt;br /&gt;
    from visual import *&lt;br /&gt;
    from visual.graph import *&lt;br /&gt;
&lt;br /&gt;
    mcart = 100&lt;br /&gt;
    mew = vector(2.9,0,0)&lt;br /&gt;
&lt;br /&gt;
    track =  box(pos=vector(0,-0.05,0), size=vector(20.0,0.05,0.10), color=color.white)&lt;br /&gt;
    cart =  box(pos=vector(-10,0.25,0), size=vector(.5,0.6,0.03), color=color.blue)&lt;br /&gt;
    marker = box(pos = vector(2,0,0), size = vector(0,20,5), color = color.red)&lt;br /&gt;
&lt;br /&gt;
    cart.v=vector(2.4,0,0)&lt;br /&gt;
    cart.p = mcart*cart.v&lt;br /&gt;
    F = vector(90,0,0)&lt;br /&gt;
    F2 = vector(-200,0,0)&lt;br /&gt;
    F3 = (mcart * mew)&lt;br /&gt;
    print(F3)&lt;br /&gt;
&lt;br /&gt;
    deltat = 0.01&lt;br /&gt;
    t = 0&lt;br /&gt;
&lt;br /&gt;
    while t &amp;lt; 5.02:&lt;br /&gt;
&lt;br /&gt;
        if cart.pos.x &amp;lt; 2:&lt;br /&gt;
            cart.v = cart.p / cart.m&lt;br /&gt;
            Fnet = F&lt;br /&gt;
            cart.p = cart.p + Fnet*deltat&lt;br /&gt;
            cart.pos = cart.pos + (cart.p/mcart)*deltat&lt;br /&gt;
&lt;br /&gt;
        else:&lt;br /&gt;
            &lt;br /&gt;
            cart.v = cart.p / cart.m&lt;br /&gt;
            Fnet = F-F3&lt;br /&gt;
            cart.p = cart.p + Fnet*deltat&lt;br /&gt;
            cart.pos = cart.pos + (cart.p/mcart)*deltat&lt;br /&gt;
            &lt;br /&gt;
        t = t + deltat&lt;br /&gt;
        rate(100)&lt;br /&gt;
        &lt;br /&gt;
    print(cart.pos)&lt;br /&gt;
    &lt;br /&gt;
 friction()&lt;br /&gt;
&lt;br /&gt;
==Examples==&lt;br /&gt;
&lt;br /&gt;
Be sure to show all steps in your solution and include diagrams whenever possible&lt;br /&gt;
&lt;br /&gt;
===Simple===&lt;br /&gt;
&lt;br /&gt;
A 100Kg box is placed on a flat table. The box does not move. The coefficient of static friction &amp;lt;math&amp;gt; {&amp;amp;mu;}_{s} = {.25} &amp;lt;/math&amp;gt; and the coefficient of kinetic friction &amp;lt;math&amp;gt; {&amp;amp;mu;}_{k} = {.15} &amp;lt;/math&amp;gt;.&lt;br /&gt;
Find the force of friction &amp;lt;math&amp;gt;{F}_{s}&amp;lt;/math&amp;gt;.&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
Solution:&lt;br /&gt;
&lt;br /&gt;
Since the box does not move, there is only static friction. The normal force is equivalent to the force due to gravity: &amp;lt;math&amp;gt; {F}_{N} = {F}_{g} = {100}{g} &amp;lt;/math&amp;gt;. The static friction can be found by: &amp;lt;math&amp;gt; {F}_{s} = {&amp;amp;mu;}_{s}{F}_{N} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
&amp;lt;math&amp;gt; {F}_{s} = {(.25)}{(100)}{(9.8)} = {245.25} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
===Middling===&lt;br /&gt;
&lt;br /&gt;
A cart of mass 3Kg moves across a track pushed by a fan which exerts &amp;lt;math&amp;gt; {F} = &amp;lt;3,0,1&amp;gt; &amp;lt;/math&amp;gt;N with an initial velocity &amp;lt;math&amp;gt; {v}_{i} = &amp;lt;1,0,1&amp;gt;\frac{{m}}{{s}}&amp;lt;/math&amp;gt; . Find the required coefficient of kinetic friction &amp;lt;math&amp;gt; {%mu;}_{k} &amp;lt;/math&amp;gt; needed to bring the cart to a stop in 10 seconds.&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
Solution:&lt;br /&gt;
&lt;br /&gt;
Use the momentum principle&lt;br /&gt;
&lt;br /&gt;
===Difficult===&lt;br /&gt;
&lt;br /&gt;
Two blocks are stacked on top of one another on a frictio&lt;br /&gt;
&lt;br /&gt;
==Connectedness==&lt;br /&gt;
#How is this topic connected to something that you are interested in?&lt;br /&gt;
#How is it connected to your major?&lt;br /&gt;
#Is there an interesting industrial application?&lt;br /&gt;
&lt;br /&gt;
==History==&lt;br /&gt;
&lt;br /&gt;
Put this idea in historical context. Give the reader the Who, What, When, Where, and Why.&lt;br /&gt;
&lt;br /&gt;
== See also ==&lt;br /&gt;
&lt;br /&gt;
Are there related topics or categories in this wiki resource for the curious reader to explore?  How does this topic fit into that context?&lt;br /&gt;
&lt;br /&gt;
===Further reading===&lt;br /&gt;
&lt;br /&gt;
Books, Articles or other print media on this topic&lt;br /&gt;
&lt;br /&gt;
===External links===&lt;br /&gt;
&lt;br /&gt;
Internet resources on this topic&lt;br /&gt;
&lt;br /&gt;
==References==&lt;br /&gt;
&lt;br /&gt;
This section contains the the references you used while writing this page&lt;br /&gt;
&lt;br /&gt;
[[Category:Contact Forces]]&lt;/div&gt;</summary>
		<author><name>Drao31</name></author>
	</entry>
	<entry>
		<id>http://www.physicsbook.gatech.edu/index.php?title=Friction&amp;diff=24942</id>
		<title>Friction</title>
		<link rel="alternate" type="text/html" href="http://www.physicsbook.gatech.edu/index.php?title=Friction&amp;diff=24942"/>
		<updated>2016-11-27T19:54:59Z</updated>

		<summary type="html">&lt;p&gt;Drao31: /* Middling */&lt;/p&gt;
&lt;hr /&gt;
&lt;div&gt;This page discusses the concept of friction and how it relates to both moving and static objects.&lt;br /&gt;
&lt;br /&gt;
Claimed by drao31&lt;br /&gt;
&lt;br /&gt;
==The Main Idea==&lt;br /&gt;
Friction is caused by the interactions between the atoms that make up objects. When objects interact, the atoms that make up the objects also interact. Temperatures of interacting surfaces rise because of such interactions. Friction is a force that resists movement. Generally, friction makes it harder to move objects. There are two main types of friction that are covered in Physics 2211: Static Friction and Kinetic Friction. Static friction can be described as the friction acting on resting objects. Kinetic friction is the friction acting on objects in motion. &lt;br /&gt;
&lt;br /&gt;
Frictional forces depend on a few factors: the normal force and the coefficient of friction. &lt;br /&gt;
&lt;br /&gt;
In simple terms, the normal force &amp;lt;math&amp;gt; {F}_{N} &amp;lt;/math&amp;gt; or &amp;lt;math&amp;gt; {N} &amp;lt;/math&amp;gt; is the equivalent force between objects. For example, when an object of mass &#039;&#039;&#039;M&#039;&#039;&#039; is placed on a table, there is a gravitational force &#039;&#039;&#039;Mg&#039;&#039;&#039; on the table. If the table can support the object without collapsing, the table exerts an equivalent force &#039;&#039;&#039;Mg&#039;&#039;&#039; on the object. According to the momentum principle, since there is no change in momentum, the net force must be &#039;&#039;&#039;0&#039;&#039;&#039;. This is also apparent since there is no movement if the table can support the object.&lt;br /&gt;
&lt;br /&gt;
::&amp;lt;math&amp;gt; {p}_{f} - {p}_{i} = {F}_{net}{dt} = 0 &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
OR&lt;br /&gt;
&lt;br /&gt;
::&amp;lt;math&amp;gt; {F}_{g} = {M}{g} &amp;lt;/math&amp;gt;&lt;br /&gt;
::&amp;lt;math&amp;gt; {N} = {M}{g} &amp;lt;/math&amp;gt;&lt;br /&gt;
::&amp;lt;math&amp;gt; {F}_{net} = {F}_{g} - {N} = {0} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
The coefficient of friction is usually specific to each object or material. The coefficient of static friction is denoted by &amp;lt;math&amp;gt;{&amp;amp;mu;}_{s}&amp;lt;/math&amp;gt; and the coefficient of kinetic friction is denoted by &amp;lt;math&amp;gt;{&amp;amp;mu;}_{k}&amp;lt;/math&amp;gt; &lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
Static Friction:&lt;br /&gt;
&lt;br /&gt;
::&amp;lt;math&amp;gt; {F}_{s} \le {&amp;amp;mu;}_{s}{N} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
Static friction is the frictional force that must be overcome to begin moving an object at rest. The static friction can be no more than the normal force multiplied by the coefficient of static friction. Therefore, the maximum static friction an object can have is &amp;lt;math&amp;gt; {&amp;amp;mu;}_{s}{N} &amp;lt;/math&amp;gt;. &lt;br /&gt;
&lt;br /&gt;
Kinetic Friction:&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
::&amp;lt;math&amp;gt; {F}_{k} = {&amp;amp;mu;}_{k}{N} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
Kinetic friction is the frictional force that exists between objects already at motion. It acts to oppose the movement of an object. Kinetic friction can be observed, for example, when a soccer ball is kicked across a field. The friction between the ball and the field will eventually bring the ball to a stop.&lt;br /&gt;
&lt;br /&gt;
Interestingly, friction is also required for rolling motion. Without friction, objects would not be able to roll. This is true because friction results in torque acting on the object, causing the rolling motion. An example of this can be seen in cars that are stuck in a ditch or similar situations. If there is not enough friction between the car&#039;s wheels and the ground, the car&#039;s wheels will simply spin in place, and the car will not move.&lt;br /&gt;
&lt;br /&gt;
===A Mathematical Model===&lt;br /&gt;
&lt;br /&gt;
As stated above:&lt;br /&gt;
&lt;br /&gt;
Static Friction:&lt;br /&gt;
&lt;br /&gt;
::&amp;lt;math&amp;gt; {F}_{s} \le {&amp;amp;mu;}_{s}{N} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
Kinetic Friction:&lt;br /&gt;
&lt;br /&gt;
::&amp;lt;math&amp;gt; {F}_{k} = {&amp;amp;mu;}_{k}{N} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
When attempting to solve problems relating to friction, one possible method of approach is to consider the net force acting on an object. If there is a force &amp;lt;math&amp;gt; {F}&amp;lt;/math&amp;gt; pushing an object to the right, and a frictional force &amp;lt;math&amp;gt;{F}_{f}&amp;lt;/math&amp;gt; opposing the movement, then the net force is &amp;lt;math&amp;gt; {F}_{net} = {F} - {F}_{f} &amp;lt;/math&amp;gt;.&lt;br /&gt;
&lt;br /&gt;
Another possible approach is by using the momentum principle &amp;lt;math&amp;gt; {p}_{f} - {p}_{i} = {F}_{net}{dt} &amp;lt;/math&amp;gt;. The momentum principle can help solve problems where you need to account for time, net force, or change in momentum.&lt;br /&gt;
&lt;br /&gt;
===A Computational Model===&lt;br /&gt;
&lt;br /&gt;
[[File:Friction.gif]]&lt;br /&gt;
&lt;br /&gt;
Link: &lt;br /&gt;
https://trinket.io/glowscript/76028c1809&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
Code: &lt;br /&gt;
 def friction():&lt;br /&gt;
    from __future__ import division&lt;br /&gt;
    from visual import *&lt;br /&gt;
    from visual.graph import *&lt;br /&gt;
&lt;br /&gt;
    mcart = 100&lt;br /&gt;
    mew = vector(2.9,0,0)&lt;br /&gt;
&lt;br /&gt;
    track =  box(pos=vector(0,-0.05,0), size=vector(20.0,0.05,0.10), color=color.white)&lt;br /&gt;
    cart =  box(pos=vector(-10,0.25,0), size=vector(.5,0.6,0.03), color=color.blue)&lt;br /&gt;
    marker = box(pos = vector(2,0,0), size = vector(0,20,5), color = color.red)&lt;br /&gt;
&lt;br /&gt;
    cart.v=vector(2.4,0,0)&lt;br /&gt;
    cart.p = mcart*cart.v&lt;br /&gt;
    F = vector(90,0,0)&lt;br /&gt;
    F2 = vector(-200,0,0)&lt;br /&gt;
    F3 = (mcart * mew)&lt;br /&gt;
    print(F3)&lt;br /&gt;
&lt;br /&gt;
    deltat = 0.01&lt;br /&gt;
    t = 0&lt;br /&gt;
&lt;br /&gt;
    while t &amp;lt; 5.02:&lt;br /&gt;
&lt;br /&gt;
        if cart.pos.x &amp;lt; 2:&lt;br /&gt;
            cart.v = cart.p / cart.m&lt;br /&gt;
            Fnet = F&lt;br /&gt;
            cart.p = cart.p + Fnet*deltat&lt;br /&gt;
            cart.pos = cart.pos + (cart.p/mcart)*deltat&lt;br /&gt;
&lt;br /&gt;
        else:&lt;br /&gt;
            &lt;br /&gt;
            cart.v = cart.p / cart.m&lt;br /&gt;
            Fnet = F-F3&lt;br /&gt;
            cart.p = cart.p + Fnet*deltat&lt;br /&gt;
            cart.pos = cart.pos + (cart.p/mcart)*deltat&lt;br /&gt;
            &lt;br /&gt;
        t = t + deltat&lt;br /&gt;
        rate(100)&lt;br /&gt;
        &lt;br /&gt;
    print(cart.pos)&lt;br /&gt;
    &lt;br /&gt;
 friction()&lt;br /&gt;
&lt;br /&gt;
==Examples==&lt;br /&gt;
&lt;br /&gt;
Be sure to show all steps in your solution and include diagrams whenever possible&lt;br /&gt;
&lt;br /&gt;
===Simple===&lt;br /&gt;
&lt;br /&gt;
A 100Kg box is placed on a flat table. The box does not move. The coefficient of static friction &amp;lt;math&amp;gt; {&amp;amp;mu;}_{s} = {.25} &amp;lt;/math&amp;gt; and the coefficient of kinetic friction &amp;lt;math&amp;gt; {&amp;amp;mu;}_{k} = {.15} &amp;lt;/math&amp;gt;.&lt;br /&gt;
Find the force of friction &amp;lt;math&amp;gt;{F}_{s}&amp;lt;/math&amp;gt;.&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
Solution:&lt;br /&gt;
&lt;br /&gt;
Since the box does not move, there is only static friction. The normal force is equivalent to the force due to gravity: &amp;lt;math&amp;gt; {F}_{N} = {F}_{g} = {100}{g} &amp;lt;/math&amp;gt;. The static friction can be found by: &amp;lt;math&amp;gt; {F}_{s} = {&amp;amp;mu;}_{s}{F}_{N} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
&amp;lt;math&amp;gt; {F}_{s} = {(.25)}{(100)}{(9.8)} = {245.25} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
===Middling===&lt;br /&gt;
&lt;br /&gt;
A cart of mass 3Kg moves across a track pushed by a fan which exerts &amp;lt;math&amp;gt; {F} = &amp;lt;3,0,1&amp;gt; &amp;lt;/math&amp;gt;N with an initial velocity &amp;lt;math&amp;gt; {v}_{i} = &amp;lt;1,0,1&amp;gt;&amp;lt;/math&amp;gt; . Find the required coefficient of kinetic friction &amp;lt;math&amp;gt; {%mu;}_{k} &amp;lt;/math&amp;gt; needed to bring the cart to a stop.&lt;br /&gt;
&lt;br /&gt;
===Difficult===&lt;br /&gt;
&lt;br /&gt;
Two blocks are stacked on top of one another on a frictio&lt;br /&gt;
&lt;br /&gt;
==Connectedness==&lt;br /&gt;
#How is this topic connected to something that you are interested in?&lt;br /&gt;
#How is it connected to your major?&lt;br /&gt;
#Is there an interesting industrial application?&lt;br /&gt;
&lt;br /&gt;
==History==&lt;br /&gt;
&lt;br /&gt;
Put this idea in historical context. Give the reader the Who, What, When, Where, and Why.&lt;br /&gt;
&lt;br /&gt;
== See also ==&lt;br /&gt;
&lt;br /&gt;
Are there related topics or categories in this wiki resource for the curious reader to explore?  How does this topic fit into that context?&lt;br /&gt;
&lt;br /&gt;
===Further reading===&lt;br /&gt;
&lt;br /&gt;
Books, Articles or other print media on this topic&lt;br /&gt;
&lt;br /&gt;
===External links===&lt;br /&gt;
&lt;br /&gt;
Internet resources on this topic&lt;br /&gt;
&lt;br /&gt;
==References==&lt;br /&gt;
&lt;br /&gt;
This section contains the the references you used while writing this page&lt;br /&gt;
&lt;br /&gt;
[[Category:Contact Forces]]&lt;/div&gt;</summary>
		<author><name>Drao31</name></author>
	</entry>
	<entry>
		<id>http://www.physicsbook.gatech.edu/index.php?title=Friction&amp;diff=24938</id>
		<title>Friction</title>
		<link rel="alternate" type="text/html" href="http://www.physicsbook.gatech.edu/index.php?title=Friction&amp;diff=24938"/>
		<updated>2016-11-27T19:52:57Z</updated>

		<summary type="html">&lt;p&gt;Drao31: /* Middling */&lt;/p&gt;
&lt;hr /&gt;
&lt;div&gt;This page discusses the concept of friction and how it relates to both moving and static objects.&lt;br /&gt;
&lt;br /&gt;
Claimed by drao31&lt;br /&gt;
&lt;br /&gt;
==The Main Idea==&lt;br /&gt;
Friction is caused by the interactions between the atoms that make up objects. When objects interact, the atoms that make up the objects also interact. Temperatures of interacting surfaces rise because of such interactions. Friction is a force that resists movement. Generally, friction makes it harder to move objects. There are two main types of friction that are covered in Physics 2211: Static Friction and Kinetic Friction. Static friction can be described as the friction acting on resting objects. Kinetic friction is the friction acting on objects in motion. &lt;br /&gt;
&lt;br /&gt;
Frictional forces depend on a few factors: the normal force and the coefficient of friction. &lt;br /&gt;
&lt;br /&gt;
In simple terms, the normal force &amp;lt;math&amp;gt; {F}_{N} &amp;lt;/math&amp;gt; or &amp;lt;math&amp;gt; {N} &amp;lt;/math&amp;gt; is the equivalent force between objects. For example, when an object of mass &#039;&#039;&#039;M&#039;&#039;&#039; is placed on a table, there is a gravitational force &#039;&#039;&#039;Mg&#039;&#039;&#039; on the table. If the table can support the object without collapsing, the table exerts an equivalent force &#039;&#039;&#039;Mg&#039;&#039;&#039; on the object. According to the momentum principle, since there is no change in momentum, the net force must be &#039;&#039;&#039;0&#039;&#039;&#039;. This is also apparent since there is no movement if the table can support the object.&lt;br /&gt;
&lt;br /&gt;
::&amp;lt;math&amp;gt; {p}_{f} - {p}_{i} = {F}_{net}{dt} = 0 &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
OR&lt;br /&gt;
&lt;br /&gt;
::&amp;lt;math&amp;gt; {F}_{g} = {M}{g} &amp;lt;/math&amp;gt;&lt;br /&gt;
::&amp;lt;math&amp;gt; {N} = {M}{g} &amp;lt;/math&amp;gt;&lt;br /&gt;
::&amp;lt;math&amp;gt; {F}_{net} = {F}_{g} - {N} = {0} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
The coefficient of friction is usually specific to each object or material. The coefficient of static friction is denoted by &amp;lt;math&amp;gt;{&amp;amp;mu;}_{s}&amp;lt;/math&amp;gt; and the coefficient of kinetic friction is denoted by &amp;lt;math&amp;gt;{&amp;amp;mu;}_{k}&amp;lt;/math&amp;gt; &lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
Static Friction:&lt;br /&gt;
&lt;br /&gt;
::&amp;lt;math&amp;gt; {F}_{s} \le {&amp;amp;mu;}_{s}{N} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
Static friction is the frictional force that must be overcome to begin moving an object at rest. The static friction can be no more than the normal force multiplied by the coefficient of static friction. Therefore, the maximum static friction an object can have is &amp;lt;math&amp;gt; {&amp;amp;mu;}_{s}{N} &amp;lt;/math&amp;gt;. &lt;br /&gt;
&lt;br /&gt;
Kinetic Friction:&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
::&amp;lt;math&amp;gt; {F}_{k} = {&amp;amp;mu;}_{k}{N} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
Kinetic friction is the frictional force that exists between objects already at motion. It acts to oppose the movement of an object. Kinetic friction can be observed, for example, when a soccer ball is kicked across a field. The friction between the ball and the field will eventually bring the ball to a stop.&lt;br /&gt;
&lt;br /&gt;
Interestingly, friction is also required for rolling motion. Without friction, objects would not be able to roll. This is true because friction results in torque acting on the object, causing the rolling motion. An example of this can be seen in cars that are stuck in a ditch or similar situations. If there is not enough friction between the car&#039;s wheels and the ground, the car&#039;s wheels will simply spin in place, and the car will not move.&lt;br /&gt;
&lt;br /&gt;
===A Mathematical Model===&lt;br /&gt;
&lt;br /&gt;
As stated above:&lt;br /&gt;
&lt;br /&gt;
Static Friction:&lt;br /&gt;
&lt;br /&gt;
::&amp;lt;math&amp;gt; {F}_{s} \le {&amp;amp;mu;}_{s}{N} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
Kinetic Friction:&lt;br /&gt;
&lt;br /&gt;
::&amp;lt;math&amp;gt; {F}_{k} = {&amp;amp;mu;}_{k}{N} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
When attempting to solve problems relating to friction, one possible method of approach is to consider the net force acting on an object. If there is a force &amp;lt;math&amp;gt; {F}&amp;lt;/math&amp;gt; pushing an object to the right, and a frictional force &amp;lt;math&amp;gt;{F}_{f}&amp;lt;/math&amp;gt; opposing the movement, then the net force is &amp;lt;math&amp;gt; {F}_{net} = {F} - {F}_{f} &amp;lt;/math&amp;gt;.&lt;br /&gt;
&lt;br /&gt;
Another possible approach is by using the momentum principle &amp;lt;math&amp;gt; {p}_{f} - {p}_{i} = {F}_{net}{dt} &amp;lt;/math&amp;gt;. The momentum principle can help solve problems where you need to account for time, net force, or change in momentum.&lt;br /&gt;
&lt;br /&gt;
===A Computational Model===&lt;br /&gt;
&lt;br /&gt;
[[File:Friction.gif]]&lt;br /&gt;
&lt;br /&gt;
Link: &lt;br /&gt;
https://trinket.io/glowscript/76028c1809&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
Code: &lt;br /&gt;
 def friction():&lt;br /&gt;
    from __future__ import division&lt;br /&gt;
    from visual import *&lt;br /&gt;
    from visual.graph import *&lt;br /&gt;
&lt;br /&gt;
    mcart = 100&lt;br /&gt;
    mew = vector(2.9,0,0)&lt;br /&gt;
&lt;br /&gt;
    track =  box(pos=vector(0,-0.05,0), size=vector(20.0,0.05,0.10), color=color.white)&lt;br /&gt;
    cart =  box(pos=vector(-10,0.25,0), size=vector(.5,0.6,0.03), color=color.blue)&lt;br /&gt;
    marker = box(pos = vector(2,0,0), size = vector(0,20,5), color = color.red)&lt;br /&gt;
&lt;br /&gt;
    cart.v=vector(2.4,0,0)&lt;br /&gt;
    cart.p = mcart*cart.v&lt;br /&gt;
    F = vector(90,0,0)&lt;br /&gt;
    F2 = vector(-200,0,0)&lt;br /&gt;
    F3 = (mcart * mew)&lt;br /&gt;
    print(F3)&lt;br /&gt;
&lt;br /&gt;
    deltat = 0.01&lt;br /&gt;
    t = 0&lt;br /&gt;
&lt;br /&gt;
    while t &amp;lt; 5.02:&lt;br /&gt;
&lt;br /&gt;
        if cart.pos.x &amp;lt; 2:&lt;br /&gt;
            cart.v = cart.p / cart.m&lt;br /&gt;
            Fnet = F&lt;br /&gt;
            cart.p = cart.p + Fnet*deltat&lt;br /&gt;
            cart.pos = cart.pos + (cart.p/mcart)*deltat&lt;br /&gt;
&lt;br /&gt;
        else:&lt;br /&gt;
            &lt;br /&gt;
            cart.v = cart.p / cart.m&lt;br /&gt;
            Fnet = F-F3&lt;br /&gt;
            cart.p = cart.p + Fnet*deltat&lt;br /&gt;
            cart.pos = cart.pos + (cart.p/mcart)*deltat&lt;br /&gt;
            &lt;br /&gt;
        t = t + deltat&lt;br /&gt;
        rate(100)&lt;br /&gt;
        &lt;br /&gt;
    print(cart.pos)&lt;br /&gt;
    &lt;br /&gt;
 friction()&lt;br /&gt;
&lt;br /&gt;
==Examples==&lt;br /&gt;
&lt;br /&gt;
Be sure to show all steps in your solution and include diagrams whenever possible&lt;br /&gt;
&lt;br /&gt;
===Simple===&lt;br /&gt;
&lt;br /&gt;
A 100Kg box is placed on a flat table. The box does not move. The coefficient of static friction &amp;lt;math&amp;gt; {&amp;amp;mu;}_{s} = {.25} &amp;lt;/math&amp;gt; and the coefficient of kinetic friction &amp;lt;math&amp;gt; {&amp;amp;mu;}_{k} = {.15} &amp;lt;/math&amp;gt;.&lt;br /&gt;
Find the force of friction &amp;lt;math&amp;gt;{F}_{s}&amp;lt;/math&amp;gt;.&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
Solution:&lt;br /&gt;
&lt;br /&gt;
Since the box does not move, there is only static friction. The normal force is equivalent to the force due to gravity: &amp;lt;math&amp;gt; {F}_{N} = {F}_{g} = {100}{g} &amp;lt;/math&amp;gt;. The static friction can be found by: &amp;lt;math&amp;gt; {F}_{s} = {&amp;amp;mu;}_{s}{F}_{N} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
&amp;lt;math&amp;gt; {F}_{s} = {(.25)}{(100)}{(9.8)} = {245.25} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
===Middling===&lt;br /&gt;
&lt;br /&gt;
A cart of mass &#039;&#039;&#039;3Kg&#039;&#039;&#039; moves across a track pushed by a fan which exerts &amp;lt;math&amp;gt; {F} = &amp;lt;3,0,1&amp;gt; &amp;lt;/math&amp;gt;. Find the required coefficient of kinetic friction &amp;lt;math&amp;gt; {%mu;}_{k} &amp;lt;/math&amp;gt; needed to bring the cart to a stop.&lt;br /&gt;
&lt;br /&gt;
===Difficult===&lt;br /&gt;
&lt;br /&gt;
Two blocks are stacked on top of one another on a frictio&lt;br /&gt;
&lt;br /&gt;
==Connectedness==&lt;br /&gt;
#How is this topic connected to something that you are interested in?&lt;br /&gt;
#How is it connected to your major?&lt;br /&gt;
#Is there an interesting industrial application?&lt;br /&gt;
&lt;br /&gt;
==History==&lt;br /&gt;
&lt;br /&gt;
Put this idea in historical context. Give the reader the Who, What, When, Where, and Why.&lt;br /&gt;
&lt;br /&gt;
== See also ==&lt;br /&gt;
&lt;br /&gt;
Are there related topics or categories in this wiki resource for the curious reader to explore?  How does this topic fit into that context?&lt;br /&gt;
&lt;br /&gt;
===Further reading===&lt;br /&gt;
&lt;br /&gt;
Books, Articles or other print media on this topic&lt;br /&gt;
&lt;br /&gt;
===External links===&lt;br /&gt;
&lt;br /&gt;
Internet resources on this topic&lt;br /&gt;
&lt;br /&gt;
==References==&lt;br /&gt;
&lt;br /&gt;
This section contains the the references you used while writing this page&lt;br /&gt;
&lt;br /&gt;
[[Category:Contact Forces]]&lt;/div&gt;</summary>
		<author><name>Drao31</name></author>
	</entry>
	<entry>
		<id>http://www.physicsbook.gatech.edu/index.php?title=Friction&amp;diff=24930</id>
		<title>Friction</title>
		<link rel="alternate" type="text/html" href="http://www.physicsbook.gatech.edu/index.php?title=Friction&amp;diff=24930"/>
		<updated>2016-11-27T19:50:10Z</updated>

		<summary type="html">&lt;p&gt;Drao31: /* Difficult */&lt;/p&gt;
&lt;hr /&gt;
&lt;div&gt;This page discusses the concept of friction and how it relates to both moving and static objects.&lt;br /&gt;
&lt;br /&gt;
Claimed by drao31&lt;br /&gt;
&lt;br /&gt;
==The Main Idea==&lt;br /&gt;
Friction is caused by the interactions between the atoms that make up objects. When objects interact, the atoms that make up the objects also interact. Temperatures of interacting surfaces rise because of such interactions. Friction is a force that resists movement. Generally, friction makes it harder to move objects. There are two main types of friction that are covered in Physics 2211: Static Friction and Kinetic Friction. Static friction can be described as the friction acting on resting objects. Kinetic friction is the friction acting on objects in motion. &lt;br /&gt;
&lt;br /&gt;
Frictional forces depend on a few factors: the normal force and the coefficient of friction. &lt;br /&gt;
&lt;br /&gt;
In simple terms, the normal force &amp;lt;math&amp;gt; {F}_{N} &amp;lt;/math&amp;gt; or &amp;lt;math&amp;gt; {N} &amp;lt;/math&amp;gt; is the equivalent force between objects. For example, when an object of mass &#039;&#039;&#039;M&#039;&#039;&#039; is placed on a table, there is a gravitational force &#039;&#039;&#039;Mg&#039;&#039;&#039; on the table. If the table can support the object without collapsing, the table exerts an equivalent force &#039;&#039;&#039;Mg&#039;&#039;&#039; on the object. According to the momentum principle, since there is no change in momentum, the net force must be &#039;&#039;&#039;0&#039;&#039;&#039;. This is also apparent since there is no movement if the table can support the object.&lt;br /&gt;
&lt;br /&gt;
::&amp;lt;math&amp;gt; {p}_{f} - {p}_{i} = {F}_{net}{dt} = 0 &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
OR&lt;br /&gt;
&lt;br /&gt;
::&amp;lt;math&amp;gt; {F}_{g} = {M}{g} &amp;lt;/math&amp;gt;&lt;br /&gt;
::&amp;lt;math&amp;gt; {N} = {M}{g} &amp;lt;/math&amp;gt;&lt;br /&gt;
::&amp;lt;math&amp;gt; {F}_{net} = {F}_{g} - {N} = {0} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
The coefficient of friction is usually specific to each object or material. The coefficient of static friction is denoted by &amp;lt;math&amp;gt;{&amp;amp;mu;}_{s}&amp;lt;/math&amp;gt; and the coefficient of kinetic friction is denoted by &amp;lt;math&amp;gt;{&amp;amp;mu;}_{k}&amp;lt;/math&amp;gt; &lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
Static Friction:&lt;br /&gt;
&lt;br /&gt;
::&amp;lt;math&amp;gt; {F}_{s} \le {&amp;amp;mu;}_{s}{N} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
Static friction is the frictional force that must be overcome to begin moving an object at rest. The static friction can be no more than the normal force multiplied by the coefficient of static friction. Therefore, the maximum static friction an object can have is &amp;lt;math&amp;gt; {&amp;amp;mu;}_{s}{N} &amp;lt;/math&amp;gt;. &lt;br /&gt;
&lt;br /&gt;
Kinetic Friction:&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
::&amp;lt;math&amp;gt; {F}_{k} = {&amp;amp;mu;}_{k}{N} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
Kinetic friction is the frictional force that exists between objects already at motion. It acts to oppose the movement of an object. Kinetic friction can be observed, for example, when a soccer ball is kicked across a field. The friction between the ball and the field will eventually bring the ball to a stop.&lt;br /&gt;
&lt;br /&gt;
Interestingly, friction is also required for rolling motion. Without friction, objects would not be able to roll. This is true because friction results in torque acting on the object, causing the rolling motion. An example of this can be seen in cars that are stuck in a ditch or similar situations. If there is not enough friction between the car&#039;s wheels and the ground, the car&#039;s wheels will simply spin in place, and the car will not move.&lt;br /&gt;
&lt;br /&gt;
===A Mathematical Model===&lt;br /&gt;
&lt;br /&gt;
As stated above:&lt;br /&gt;
&lt;br /&gt;
Static Friction:&lt;br /&gt;
&lt;br /&gt;
::&amp;lt;math&amp;gt; {F}_{s} \le {&amp;amp;mu;}_{s}{N} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
Kinetic Friction:&lt;br /&gt;
&lt;br /&gt;
::&amp;lt;math&amp;gt; {F}_{k} = {&amp;amp;mu;}_{k}{N} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
When attempting to solve problems relating to friction, one possible method of approach is to consider the net force acting on an object. If there is a force &amp;lt;math&amp;gt; {F}&amp;lt;/math&amp;gt; pushing an object to the right, and a frictional force &amp;lt;math&amp;gt;{F}_{f}&amp;lt;/math&amp;gt; opposing the movement, then the net force is &amp;lt;math&amp;gt; {F}_{net} = {F} - {F}_{f} &amp;lt;/math&amp;gt;.&lt;br /&gt;
&lt;br /&gt;
Another possible approach is by using the momentum principle &amp;lt;math&amp;gt; {p}_{f} - {p}_{i} = {F}_{net}{dt} &amp;lt;/math&amp;gt;. The momentum principle can help solve problems where you need to account for time, net force, or change in momentum.&lt;br /&gt;
&lt;br /&gt;
===A Computational Model===&lt;br /&gt;
&lt;br /&gt;
[[File:Friction.gif]]&lt;br /&gt;
&lt;br /&gt;
Link: &lt;br /&gt;
https://trinket.io/glowscript/76028c1809&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
Code: &lt;br /&gt;
 def friction():&lt;br /&gt;
    from __future__ import division&lt;br /&gt;
    from visual import *&lt;br /&gt;
    from visual.graph import *&lt;br /&gt;
&lt;br /&gt;
    mcart = 100&lt;br /&gt;
    mew = vector(2.9,0,0)&lt;br /&gt;
&lt;br /&gt;
    track =  box(pos=vector(0,-0.05,0), size=vector(20.0,0.05,0.10), color=color.white)&lt;br /&gt;
    cart =  box(pos=vector(-10,0.25,0), size=vector(.5,0.6,0.03), color=color.blue)&lt;br /&gt;
    marker = box(pos = vector(2,0,0), size = vector(0,20,5), color = color.red)&lt;br /&gt;
&lt;br /&gt;
    cart.v=vector(2.4,0,0)&lt;br /&gt;
    cart.p = mcart*cart.v&lt;br /&gt;
    F = vector(90,0,0)&lt;br /&gt;
    F2 = vector(-200,0,0)&lt;br /&gt;
    F3 = (mcart * mew)&lt;br /&gt;
    print(F3)&lt;br /&gt;
&lt;br /&gt;
    deltat = 0.01&lt;br /&gt;
    t = 0&lt;br /&gt;
&lt;br /&gt;
    while t &amp;lt; 5.02:&lt;br /&gt;
&lt;br /&gt;
        if cart.pos.x &amp;lt; 2:&lt;br /&gt;
            cart.v = cart.p / cart.m&lt;br /&gt;
            Fnet = F&lt;br /&gt;
            cart.p = cart.p + Fnet*deltat&lt;br /&gt;
            cart.pos = cart.pos + (cart.p/mcart)*deltat&lt;br /&gt;
&lt;br /&gt;
        else:&lt;br /&gt;
            &lt;br /&gt;
            cart.v = cart.p / cart.m&lt;br /&gt;
            Fnet = F-F3&lt;br /&gt;
            cart.p = cart.p + Fnet*deltat&lt;br /&gt;
            cart.pos = cart.pos + (cart.p/mcart)*deltat&lt;br /&gt;
            &lt;br /&gt;
        t = t + deltat&lt;br /&gt;
        rate(100)&lt;br /&gt;
        &lt;br /&gt;
    print(cart.pos)&lt;br /&gt;
    &lt;br /&gt;
 friction()&lt;br /&gt;
&lt;br /&gt;
==Examples==&lt;br /&gt;
&lt;br /&gt;
Be sure to show all steps in your solution and include diagrams whenever possible&lt;br /&gt;
&lt;br /&gt;
===Simple===&lt;br /&gt;
&lt;br /&gt;
A 100Kg box is placed on a flat table. The box does not move. The coefficient of static friction &amp;lt;math&amp;gt; {&amp;amp;mu;}_{s} = {.25} &amp;lt;/math&amp;gt; and the coefficient of kinetic friction &amp;lt;math&amp;gt; {&amp;amp;mu;}_{k} = {.15} &amp;lt;/math&amp;gt;.&lt;br /&gt;
Find the force of friction &amp;lt;math&amp;gt;{F}_{s}&amp;lt;/math&amp;gt;.&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
Solution:&lt;br /&gt;
&lt;br /&gt;
Since the box does not move, there is only static friction. The normal force is equivalent to the force due to gravity: &amp;lt;math&amp;gt; {F}_{N} = {F}_{g} = {100}{g} &amp;lt;/math&amp;gt;. The static friction can be found by: &amp;lt;math&amp;gt; {F}_{s} = {&amp;amp;mu;}_{s}{F}_{N} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
&amp;lt;math&amp;gt; {F}_{s} = {(.25)}{(100)}{(9.8)} = {245.25} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
===Middling===&lt;br /&gt;
===Difficult===&lt;br /&gt;
&lt;br /&gt;
Two blocks are stacked on top of one another on a frictio&lt;br /&gt;
&lt;br /&gt;
==Connectedness==&lt;br /&gt;
#How is this topic connected to something that you are interested in?&lt;br /&gt;
#How is it connected to your major?&lt;br /&gt;
#Is there an interesting industrial application?&lt;br /&gt;
&lt;br /&gt;
==History==&lt;br /&gt;
&lt;br /&gt;
Put this idea in historical context. Give the reader the Who, What, When, Where, and Why.&lt;br /&gt;
&lt;br /&gt;
== See also ==&lt;br /&gt;
&lt;br /&gt;
Are there related topics or categories in this wiki resource for the curious reader to explore?  How does this topic fit into that context?&lt;br /&gt;
&lt;br /&gt;
===Further reading===&lt;br /&gt;
&lt;br /&gt;
Books, Articles or other print media on this topic&lt;br /&gt;
&lt;br /&gt;
===External links===&lt;br /&gt;
&lt;br /&gt;
Internet resources on this topic&lt;br /&gt;
&lt;br /&gt;
==References==&lt;br /&gt;
&lt;br /&gt;
This section contains the the references you used while writing this page&lt;br /&gt;
&lt;br /&gt;
[[Category:Contact Forces]]&lt;/div&gt;</summary>
		<author><name>Drao31</name></author>
	</entry>
	<entry>
		<id>http://www.physicsbook.gatech.edu/index.php?title=Friction&amp;diff=24921</id>
		<title>Friction</title>
		<link rel="alternate" type="text/html" href="http://www.physicsbook.gatech.edu/index.php?title=Friction&amp;diff=24921"/>
		<updated>2016-11-27T19:40:40Z</updated>

		<summary type="html">&lt;p&gt;Drao31: /* The Main Idea */&lt;/p&gt;
&lt;hr /&gt;
&lt;div&gt;This page discusses the concept of friction and how it relates to both moving and static objects.&lt;br /&gt;
&lt;br /&gt;
Claimed by drao31&lt;br /&gt;
&lt;br /&gt;
==The Main Idea==&lt;br /&gt;
Friction is caused by the interactions between the atoms that make up objects. When objects interact, the atoms that make up the objects also interact. Temperatures of interacting surfaces rise because of such interactions. Friction is a force that resists movement. Generally, friction makes it harder to move objects. There are two main types of friction that are covered in Physics 2211: Static Friction and Kinetic Friction. Static friction can be described as the friction acting on resting objects. Kinetic friction is the friction acting on objects in motion. &lt;br /&gt;
&lt;br /&gt;
Frictional forces depend on a few factors: the normal force and the coefficient of friction. &lt;br /&gt;
&lt;br /&gt;
In simple terms, the normal force &amp;lt;math&amp;gt; {F}_{N} &amp;lt;/math&amp;gt; or &amp;lt;math&amp;gt; {N} &amp;lt;/math&amp;gt; is the equivalent force between objects. For example, when an object of mass &#039;&#039;&#039;M&#039;&#039;&#039; is placed on a table, there is a gravitational force &#039;&#039;&#039;Mg&#039;&#039;&#039; on the table. If the table can support the object without collapsing, the table exerts an equivalent force &#039;&#039;&#039;Mg&#039;&#039;&#039; on the object. According to the momentum principle, since there is no change in momentum, the net force must be &#039;&#039;&#039;0&#039;&#039;&#039;. This is also apparent since there is no movement if the table can support the object.&lt;br /&gt;
&lt;br /&gt;
::&amp;lt;math&amp;gt; {p}_{f} - {p}_{i} = {F}_{net}{dt} = 0 &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
OR&lt;br /&gt;
&lt;br /&gt;
::&amp;lt;math&amp;gt; {F}_{g} = {M}{g} &amp;lt;/math&amp;gt;&lt;br /&gt;
::&amp;lt;math&amp;gt; {N} = {M}{g} &amp;lt;/math&amp;gt;&lt;br /&gt;
::&amp;lt;math&amp;gt; {F}_{net} = {F}_{g} - {N} = {0} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
The coefficient of friction is usually specific to each object or material. The coefficient of static friction is denoted by &amp;lt;math&amp;gt;{&amp;amp;mu;}_{s}&amp;lt;/math&amp;gt; and the coefficient of kinetic friction is denoted by &amp;lt;math&amp;gt;{&amp;amp;mu;}_{k}&amp;lt;/math&amp;gt; &lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
Static Friction:&lt;br /&gt;
&lt;br /&gt;
::&amp;lt;math&amp;gt; {F}_{s} \le {&amp;amp;mu;}_{s}{N} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
Static friction is the frictional force that must be overcome to begin moving an object at rest. The static friction can be no more than the normal force multiplied by the coefficient of static friction. Therefore, the maximum static friction an object can have is &amp;lt;math&amp;gt; {&amp;amp;mu;}_{s}{N} &amp;lt;/math&amp;gt;. &lt;br /&gt;
&lt;br /&gt;
Kinetic Friction:&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
::&amp;lt;math&amp;gt; {F}_{k} = {&amp;amp;mu;}_{k}{N} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
Kinetic friction is the frictional force that exists between objects already at motion. It acts to oppose the movement of an object. Kinetic friction can be observed, for example, when a soccer ball is kicked across a field. The friction between the ball and the field will eventually bring the ball to a stop.&lt;br /&gt;
&lt;br /&gt;
Interestingly, friction is also required for rolling motion. Without friction, objects would not be able to roll. This is true because friction results in torque acting on the object, causing the rolling motion. An example of this can be seen in cars that are stuck in a ditch or similar situations. If there is not enough friction between the car&#039;s wheels and the ground, the car&#039;s wheels will simply spin in place, and the car will not move.&lt;br /&gt;
&lt;br /&gt;
===A Mathematical Model===&lt;br /&gt;
&lt;br /&gt;
As stated above:&lt;br /&gt;
&lt;br /&gt;
Static Friction:&lt;br /&gt;
&lt;br /&gt;
::&amp;lt;math&amp;gt; {F}_{s} \le {&amp;amp;mu;}_{s}{N} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
Kinetic Friction:&lt;br /&gt;
&lt;br /&gt;
::&amp;lt;math&amp;gt; {F}_{k} = {&amp;amp;mu;}_{k}{N} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
When attempting to solve problems relating to friction, one possible method of approach is to consider the net force acting on an object. If there is a force &amp;lt;math&amp;gt; {F}&amp;lt;/math&amp;gt; pushing an object to the right, and a frictional force &amp;lt;math&amp;gt;{F}_{f}&amp;lt;/math&amp;gt; opposing the movement, then the net force is &amp;lt;math&amp;gt; {F}_{net} = {F} - {F}_{f} &amp;lt;/math&amp;gt;.&lt;br /&gt;
&lt;br /&gt;
Another possible approach is by using the momentum principle &amp;lt;math&amp;gt; {p}_{f} - {p}_{i} = {F}_{net}{dt} &amp;lt;/math&amp;gt;. The momentum principle can help solve problems where you need to account for time, net force, or change in momentum.&lt;br /&gt;
&lt;br /&gt;
===A Computational Model===&lt;br /&gt;
&lt;br /&gt;
[[File:Friction.gif]]&lt;br /&gt;
&lt;br /&gt;
Link: &lt;br /&gt;
https://trinket.io/glowscript/76028c1809&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
Code: &lt;br /&gt;
 def friction():&lt;br /&gt;
    from __future__ import division&lt;br /&gt;
    from visual import *&lt;br /&gt;
    from visual.graph import *&lt;br /&gt;
&lt;br /&gt;
    mcart = 100&lt;br /&gt;
    mew = vector(2.9,0,0)&lt;br /&gt;
&lt;br /&gt;
    track =  box(pos=vector(0,-0.05,0), size=vector(20.0,0.05,0.10), color=color.white)&lt;br /&gt;
    cart =  box(pos=vector(-10,0.25,0), size=vector(.5,0.6,0.03), color=color.blue)&lt;br /&gt;
    marker = box(pos = vector(2,0,0), size = vector(0,20,5), color = color.red)&lt;br /&gt;
&lt;br /&gt;
    cart.v=vector(2.4,0,0)&lt;br /&gt;
    cart.p = mcart*cart.v&lt;br /&gt;
    F = vector(90,0,0)&lt;br /&gt;
    F2 = vector(-200,0,0)&lt;br /&gt;
    F3 = (mcart * mew)&lt;br /&gt;
    print(F3)&lt;br /&gt;
&lt;br /&gt;
    deltat = 0.01&lt;br /&gt;
    t = 0&lt;br /&gt;
&lt;br /&gt;
    while t &amp;lt; 5.02:&lt;br /&gt;
&lt;br /&gt;
        if cart.pos.x &amp;lt; 2:&lt;br /&gt;
            cart.v = cart.p / cart.m&lt;br /&gt;
            Fnet = F&lt;br /&gt;
            cart.p = cart.p + Fnet*deltat&lt;br /&gt;
            cart.pos = cart.pos + (cart.p/mcart)*deltat&lt;br /&gt;
&lt;br /&gt;
        else:&lt;br /&gt;
            &lt;br /&gt;
            cart.v = cart.p / cart.m&lt;br /&gt;
            Fnet = F-F3&lt;br /&gt;
            cart.p = cart.p + Fnet*deltat&lt;br /&gt;
            cart.pos = cart.pos + (cart.p/mcart)*deltat&lt;br /&gt;
            &lt;br /&gt;
        t = t + deltat&lt;br /&gt;
        rate(100)&lt;br /&gt;
        &lt;br /&gt;
    print(cart.pos)&lt;br /&gt;
    &lt;br /&gt;
 friction()&lt;br /&gt;
&lt;br /&gt;
==Examples==&lt;br /&gt;
&lt;br /&gt;
Be sure to show all steps in your solution and include diagrams whenever possible&lt;br /&gt;
&lt;br /&gt;
===Simple===&lt;br /&gt;
&lt;br /&gt;
A 100Kg box is placed on a flat table. The box does not move. The coefficient of static friction &amp;lt;math&amp;gt; {&amp;amp;mu;}_{s} = {.25} &amp;lt;/math&amp;gt; and the coefficient of kinetic friction &amp;lt;math&amp;gt; {&amp;amp;mu;}_{k} = {.15} &amp;lt;/math&amp;gt;.&lt;br /&gt;
Find the force of friction &amp;lt;math&amp;gt;{F}_{s}&amp;lt;/math&amp;gt;.&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
Solution:&lt;br /&gt;
&lt;br /&gt;
Since the box does not move, there is only static friction. The normal force is equivalent to the force due to gravity: &amp;lt;math&amp;gt; {F}_{N} = {F}_{g} = {100}{g} &amp;lt;/math&amp;gt;. The static friction can be found by: &amp;lt;math&amp;gt; {F}_{s} = {&amp;amp;mu;}_{s}{F}_{N} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
&amp;lt;math&amp;gt; {F}_{s} = {(.25)}{(100)}{(9.8)} = {245.25} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
===Middling===&lt;br /&gt;
===Difficult===&lt;br /&gt;
&lt;br /&gt;
==Connectedness==&lt;br /&gt;
#How is this topic connected to something that you are interested in?&lt;br /&gt;
#How is it connected to your major?&lt;br /&gt;
#Is there an interesting industrial application?&lt;br /&gt;
&lt;br /&gt;
==History==&lt;br /&gt;
&lt;br /&gt;
Put this idea in historical context. Give the reader the Who, What, When, Where, and Why.&lt;br /&gt;
&lt;br /&gt;
== See also ==&lt;br /&gt;
&lt;br /&gt;
Are there related topics or categories in this wiki resource for the curious reader to explore?  How does this topic fit into that context?&lt;br /&gt;
&lt;br /&gt;
===Further reading===&lt;br /&gt;
&lt;br /&gt;
Books, Articles or other print media on this topic&lt;br /&gt;
&lt;br /&gt;
===External links===&lt;br /&gt;
&lt;br /&gt;
Internet resources on this topic&lt;br /&gt;
&lt;br /&gt;
==References==&lt;br /&gt;
&lt;br /&gt;
This section contains the the references you used while writing this page&lt;br /&gt;
&lt;br /&gt;
[[Category:Contact Forces]]&lt;/div&gt;</summary>
		<author><name>Drao31</name></author>
	</entry>
	<entry>
		<id>http://www.physicsbook.gatech.edu/index.php?title=Friction&amp;diff=24913</id>
		<title>Friction</title>
		<link rel="alternate" type="text/html" href="http://www.physicsbook.gatech.edu/index.php?title=Friction&amp;diff=24913"/>
		<updated>2016-11-27T19:34:20Z</updated>

		<summary type="html">&lt;p&gt;Drao31: /* A Mathematical Model */&lt;/p&gt;
&lt;hr /&gt;
&lt;div&gt;This page discusses the concept of friction and how it relates to both moving and static objects.&lt;br /&gt;
&lt;br /&gt;
Claimed by drao31&lt;br /&gt;
&lt;br /&gt;
==The Main Idea==&lt;br /&gt;
Friction is caused by the interactions between the atoms that make up objects. When objects interact, the atoms that make up the objects also interact. Temperatures of interacting surfaces rise because of such interactions. Friction is a force that resists movement. Generally, friction makes it harder to move objects. There are two main types of friction that are covered in Physics 2211: Static Friction and Kinetic Friction. Static friction can be described as the friction acting on resting objects. Kinetic friction is the friction acting on objects in motion. &lt;br /&gt;
&lt;br /&gt;
Frictional forces depend on a few factors: the normal force and the coefficient of friction. &lt;br /&gt;
&lt;br /&gt;
In simple terms, the normal force &amp;lt;math&amp;gt; {F}_{N} &amp;lt;/math&amp;gt; or &amp;lt;math&amp;gt; {N} &amp;lt;/math&amp;gt; is the equivalent force between objects. For example, when an object of mass &#039;&#039;&#039;M&#039;&#039;&#039; is placed on a table, there is a gravitational force &#039;&#039;&#039;Mg&#039;&#039;&#039; on the table. If the table can support the object without collapsing, the table exerts an equivalent force &#039;&#039;&#039;Mg&#039;&#039;&#039; on the object. According to the momentum principle, since there is no change in momentum, the net force must be &#039;&#039;&#039;0&#039;&#039;&#039;. This is also apparent since there is no movement if the table can support the object.&lt;br /&gt;
&lt;br /&gt;
::&amp;lt;math&amp;gt; {p}_{f} - {p}_{i} = {F}_{net}{dt} = 0 &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
OR&lt;br /&gt;
&lt;br /&gt;
::&amp;lt;math&amp;gt; {F}_{g} = {M}{g} &amp;lt;/math&amp;gt;&lt;br /&gt;
::&amp;lt;math&amp;gt; {N} = {M}{g} &amp;lt;/math&amp;gt;&lt;br /&gt;
::&amp;lt;math&amp;gt; {F}_{net} = {F}_{g} - {N} = {0} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
The coefficient of friction is usually specific to each object or material. The coefficient of static friction is denoted by &amp;lt;math&amp;gt;{&amp;amp;mu;}_{s}&amp;lt;/math&amp;gt; and the coefficient of kinetic friction is denoted by &amp;lt;math&amp;gt;{&amp;amp;mu;}_{k}&amp;lt;/math&amp;gt; &lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
Static Friction:&lt;br /&gt;
&lt;br /&gt;
::&amp;lt;math&amp;gt; {F}_{s} \le {&amp;amp;mu;}_{s}{N} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
Static friction is the frictional force that must be overcome to begin moving an object at rest. The static friction can be no more than the normal force multiplied by the coefficient of static friction. Therefore, the maximum static friction an object can have is &amp;lt;math&amp;gt; {&amp;amp;mu;}_{s}{N} &amp;lt;/math&amp;gt;. &lt;br /&gt;
&lt;br /&gt;
Kinetic Friction:&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
::&amp;lt;math&amp;gt; {F}_{k} = {&amp;amp;mu;}_{k}{N} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
Kinetic friction is the frictional force that exists between objects already at motion. It acts to oppose the movement of an object. Kinetic friction can be observed, for example, when a soccer ball is kicked across a field. The friction between the ball and the field will eventually bring the ball to a stop.&lt;br /&gt;
&lt;br /&gt;
Interestingly, friction is also required for rolling motion. Without friction, objects would not be able to roll. This is true because friction results in torque acting on the object, causing the rolling motion. An example of this can be seen in cars that are stuck in a ditch or similar situations. If there is not enough friction between the car&#039;s wheels and the ground, the car&#039;s wheels will simply spin in place, and the car will not move.&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
===A Computational Model===&lt;br /&gt;
&lt;br /&gt;
[[File:Friction.gif]]&lt;br /&gt;
&lt;br /&gt;
Link: &lt;br /&gt;
https://trinket.io/glowscript/76028c1809&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
Code: &lt;br /&gt;
 def friction():&lt;br /&gt;
    from __future__ import division&lt;br /&gt;
    from visual import *&lt;br /&gt;
    from visual.graph import *&lt;br /&gt;
&lt;br /&gt;
    mcart = 100&lt;br /&gt;
    mew = vector(2.9,0,0)&lt;br /&gt;
&lt;br /&gt;
    track =  box(pos=vector(0,-0.05,0), size=vector(20.0,0.05,0.10), color=color.white)&lt;br /&gt;
    cart =  box(pos=vector(-10,0.25,0), size=vector(.5,0.6,0.03), color=color.blue)&lt;br /&gt;
    marker = box(pos = vector(2,0,0), size = vector(0,20,5), color = color.red)&lt;br /&gt;
&lt;br /&gt;
    cart.v=vector(2.4,0,0)&lt;br /&gt;
    cart.p = mcart*cart.v&lt;br /&gt;
    F = vector(90,0,0)&lt;br /&gt;
    F2 = vector(-200,0,0)&lt;br /&gt;
    F3 = (mcart * mew)&lt;br /&gt;
    print(F3)&lt;br /&gt;
&lt;br /&gt;
    deltat = 0.01&lt;br /&gt;
    t = 0&lt;br /&gt;
&lt;br /&gt;
    while t &amp;lt; 5.02:&lt;br /&gt;
&lt;br /&gt;
        if cart.pos.x &amp;lt; 2:&lt;br /&gt;
            cart.v = cart.p / cart.m&lt;br /&gt;
            Fnet = F&lt;br /&gt;
            cart.p = cart.p + Fnet*deltat&lt;br /&gt;
            cart.pos = cart.pos + (cart.p/mcart)*deltat&lt;br /&gt;
&lt;br /&gt;
        else:&lt;br /&gt;
            &lt;br /&gt;
            cart.v = cart.p / cart.m&lt;br /&gt;
            Fnet = F-F3&lt;br /&gt;
            cart.p = cart.p + Fnet*deltat&lt;br /&gt;
            cart.pos = cart.pos + (cart.p/mcart)*deltat&lt;br /&gt;
            &lt;br /&gt;
        t = t + deltat&lt;br /&gt;
        rate(100)&lt;br /&gt;
        &lt;br /&gt;
    print(cart.pos)&lt;br /&gt;
    &lt;br /&gt;
 friction()&lt;br /&gt;
&lt;br /&gt;
==Examples==&lt;br /&gt;
&lt;br /&gt;
Be sure to show all steps in your solution and include diagrams whenever possible&lt;br /&gt;
&lt;br /&gt;
===Simple===&lt;br /&gt;
&lt;br /&gt;
A 100Kg box is placed on a flat table. The box does not move. The coefficient of static friction &amp;lt;math&amp;gt; {&amp;amp;mu;}_{s} = {.25} &amp;lt;/math&amp;gt; and the coefficient of kinetic friction &amp;lt;math&amp;gt; {&amp;amp;mu;}_{k} = {.15} &amp;lt;/math&amp;gt;.&lt;br /&gt;
Find the force of friction &amp;lt;math&amp;gt;{F}_{s}&amp;lt;/math&amp;gt;.&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
Solution:&lt;br /&gt;
&lt;br /&gt;
Since the box does not move, there is only static friction. The normal force is equivalent to the force due to gravity: &amp;lt;math&amp;gt; {F}_{N} = {F}_{g} = {100}{g} &amp;lt;/math&amp;gt;. The static friction can be found by: &amp;lt;math&amp;gt; {F}_{s} = {&amp;amp;mu;}_{s}{F}_{N} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
&amp;lt;math&amp;gt; {F}_{s} = {(.25)}{(100)}{(9.8)} = {245.25} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
===Middling===&lt;br /&gt;
===Difficult===&lt;br /&gt;
&lt;br /&gt;
==Connectedness==&lt;br /&gt;
#How is this topic connected to something that you are interested in?&lt;br /&gt;
#How is it connected to your major?&lt;br /&gt;
#Is there an interesting industrial application?&lt;br /&gt;
&lt;br /&gt;
==History==&lt;br /&gt;
&lt;br /&gt;
Put this idea in historical context. Give the reader the Who, What, When, Where, and Why.&lt;br /&gt;
&lt;br /&gt;
== See also ==&lt;br /&gt;
&lt;br /&gt;
Are there related topics or categories in this wiki resource for the curious reader to explore?  How does this topic fit into that context?&lt;br /&gt;
&lt;br /&gt;
===Further reading===&lt;br /&gt;
&lt;br /&gt;
Books, Articles or other print media on this topic&lt;br /&gt;
&lt;br /&gt;
===External links===&lt;br /&gt;
&lt;br /&gt;
Internet resources on this topic&lt;br /&gt;
&lt;br /&gt;
==References==&lt;br /&gt;
&lt;br /&gt;
This section contains the the references you used while writing this page&lt;br /&gt;
&lt;br /&gt;
[[Category:Contact Forces]]&lt;/div&gt;</summary>
		<author><name>Drao31</name></author>
	</entry>
	<entry>
		<id>http://www.physicsbook.gatech.edu/index.php?title=Friction&amp;diff=24912</id>
		<title>Friction</title>
		<link rel="alternate" type="text/html" href="http://www.physicsbook.gatech.edu/index.php?title=Friction&amp;diff=24912"/>
		<updated>2016-11-27T19:33:42Z</updated>

		<summary type="html">&lt;p&gt;Drao31: /* The Main Idea */&lt;/p&gt;
&lt;hr /&gt;
&lt;div&gt;This page discusses the concept of friction and how it relates to both moving and static objects.&lt;br /&gt;
&lt;br /&gt;
Claimed by drao31&lt;br /&gt;
&lt;br /&gt;
==The Main Idea==&lt;br /&gt;
Friction is caused by the interactions between the atoms that make up objects. When objects interact, the atoms that make up the objects also interact. Temperatures of interacting surfaces rise because of such interactions. Friction is a force that resists movement. Generally, friction makes it harder to move objects. There are two main types of friction that are covered in Physics 2211: Static Friction and Kinetic Friction. Static friction can be described as the friction acting on resting objects. Kinetic friction is the friction acting on objects in motion. &lt;br /&gt;
&lt;br /&gt;
Frictional forces depend on a few factors: the normal force and the coefficient of friction. &lt;br /&gt;
&lt;br /&gt;
In simple terms, the normal force &amp;lt;math&amp;gt; {F}_{N} &amp;lt;/math&amp;gt; or &amp;lt;math&amp;gt; {N} &amp;lt;/math&amp;gt; is the equivalent force between objects. For example, when an object of mass &#039;&#039;&#039;M&#039;&#039;&#039; is placed on a table, there is a gravitational force &#039;&#039;&#039;Mg&#039;&#039;&#039; on the table. If the table can support the object without collapsing, the table exerts an equivalent force &#039;&#039;&#039;Mg&#039;&#039;&#039; on the object. According to the momentum principle, since there is no change in momentum, the net force must be &#039;&#039;&#039;0&#039;&#039;&#039;. This is also apparent since there is no movement if the table can support the object.&lt;br /&gt;
&lt;br /&gt;
::&amp;lt;math&amp;gt; {p}_{f} - {p}_{i} = {F}_{net}{dt} = 0 &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
OR&lt;br /&gt;
&lt;br /&gt;
::&amp;lt;math&amp;gt; {F}_{g} = {M}{g} &amp;lt;/math&amp;gt;&lt;br /&gt;
::&amp;lt;math&amp;gt; {N} = {M}{g} &amp;lt;/math&amp;gt;&lt;br /&gt;
::&amp;lt;math&amp;gt; {F}_{net} = {F}_{g} - {N} = {0} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
The coefficient of friction is usually specific to each object or material. The coefficient of static friction is denoted by &amp;lt;math&amp;gt;{&amp;amp;mu;}_{s}&amp;lt;/math&amp;gt; and the coefficient of kinetic friction is denoted by &amp;lt;math&amp;gt;{&amp;amp;mu;}_{k}&amp;lt;/math&amp;gt; &lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
Static Friction:&lt;br /&gt;
&lt;br /&gt;
::&amp;lt;math&amp;gt; {F}_{s} \le {&amp;amp;mu;}_{s}{N} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
Static friction is the frictional force that must be overcome to begin moving an object at rest. The static friction can be no more than the normal force multiplied by the coefficient of static friction. Therefore, the maximum static friction an object can have is &amp;lt;math&amp;gt; {&amp;amp;mu;}_{s}{N} &amp;lt;/math&amp;gt;. &lt;br /&gt;
&lt;br /&gt;
Kinetic Friction:&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
::&amp;lt;math&amp;gt; {F}_{k} = {&amp;amp;mu;}_{k}{N} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
Kinetic friction is the frictional force that exists between objects already at motion. It acts to oppose the movement of an object. Kinetic friction can be observed, for example, when a soccer ball is kicked across a field. The friction between the ball and the field will eventually bring the ball to a stop.&lt;br /&gt;
&lt;br /&gt;
Interestingly, friction is also required for rolling motion. Without friction, objects would not be able to roll. This is true because friction results in torque acting on the object, causing the rolling motion. An example of this can be seen in cars that are stuck in a ditch or similar situations. If there is not enough friction between the car&#039;s wheels and the ground, the car&#039;s wheels will simply spin in place, and the car will not move.&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
===A Mathematical Model===&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
===A Computational Model===&lt;br /&gt;
&lt;br /&gt;
[[File:Friction.gif]]&lt;br /&gt;
&lt;br /&gt;
Link: &lt;br /&gt;
https://trinket.io/glowscript/76028c1809&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
Code: &lt;br /&gt;
 def friction():&lt;br /&gt;
    from __future__ import division&lt;br /&gt;
    from visual import *&lt;br /&gt;
    from visual.graph import *&lt;br /&gt;
&lt;br /&gt;
    mcart = 100&lt;br /&gt;
    mew = vector(2.9,0,0)&lt;br /&gt;
&lt;br /&gt;
    track =  box(pos=vector(0,-0.05,0), size=vector(20.0,0.05,0.10), color=color.white)&lt;br /&gt;
    cart =  box(pos=vector(-10,0.25,0), size=vector(.5,0.6,0.03), color=color.blue)&lt;br /&gt;
    marker = box(pos = vector(2,0,0), size = vector(0,20,5), color = color.red)&lt;br /&gt;
&lt;br /&gt;
    cart.v=vector(2.4,0,0)&lt;br /&gt;
    cart.p = mcart*cart.v&lt;br /&gt;
    F = vector(90,0,0)&lt;br /&gt;
    F2 = vector(-200,0,0)&lt;br /&gt;
    F3 = (mcart * mew)&lt;br /&gt;
    print(F3)&lt;br /&gt;
&lt;br /&gt;
    deltat = 0.01&lt;br /&gt;
    t = 0&lt;br /&gt;
&lt;br /&gt;
    while t &amp;lt; 5.02:&lt;br /&gt;
&lt;br /&gt;
        if cart.pos.x &amp;lt; 2:&lt;br /&gt;
            cart.v = cart.p / cart.m&lt;br /&gt;
            Fnet = F&lt;br /&gt;
            cart.p = cart.p + Fnet*deltat&lt;br /&gt;
            cart.pos = cart.pos + (cart.p/mcart)*deltat&lt;br /&gt;
&lt;br /&gt;
        else:&lt;br /&gt;
            &lt;br /&gt;
            cart.v = cart.p / cart.m&lt;br /&gt;
            Fnet = F-F3&lt;br /&gt;
            cart.p = cart.p + Fnet*deltat&lt;br /&gt;
            cart.pos = cart.pos + (cart.p/mcart)*deltat&lt;br /&gt;
            &lt;br /&gt;
        t = t + deltat&lt;br /&gt;
        rate(100)&lt;br /&gt;
        &lt;br /&gt;
    print(cart.pos)&lt;br /&gt;
    &lt;br /&gt;
 friction()&lt;br /&gt;
&lt;br /&gt;
==Examples==&lt;br /&gt;
&lt;br /&gt;
Be sure to show all steps in your solution and include diagrams whenever possible&lt;br /&gt;
&lt;br /&gt;
===Simple===&lt;br /&gt;
&lt;br /&gt;
A 100Kg box is placed on a flat table. The box does not move. The coefficient of static friction &amp;lt;math&amp;gt; {&amp;amp;mu;}_{s} = {.25} &amp;lt;/math&amp;gt; and the coefficient of kinetic friction &amp;lt;math&amp;gt; {&amp;amp;mu;}_{k} = {.15} &amp;lt;/math&amp;gt;.&lt;br /&gt;
Find the force of friction &amp;lt;math&amp;gt;{F}_{s}&amp;lt;/math&amp;gt;.&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
Solution:&lt;br /&gt;
&lt;br /&gt;
Since the box does not move, there is only static friction. The normal force is equivalent to the force due to gravity: &amp;lt;math&amp;gt; {F}_{N} = {F}_{g} = {100}{g} &amp;lt;/math&amp;gt;. The static friction can be found by: &amp;lt;math&amp;gt; {F}_{s} = {&amp;amp;mu;}_{s}{F}_{N} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
&amp;lt;math&amp;gt; {F}_{s} = {(.25)}{(100)}{(9.8)} = {245.25} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
===Middling===&lt;br /&gt;
===Difficult===&lt;br /&gt;
&lt;br /&gt;
==Connectedness==&lt;br /&gt;
#How is this topic connected to something that you are interested in?&lt;br /&gt;
#How is it connected to your major?&lt;br /&gt;
#Is there an interesting industrial application?&lt;br /&gt;
&lt;br /&gt;
==History==&lt;br /&gt;
&lt;br /&gt;
Put this idea in historical context. Give the reader the Who, What, When, Where, and Why.&lt;br /&gt;
&lt;br /&gt;
== See also ==&lt;br /&gt;
&lt;br /&gt;
Are there related topics or categories in this wiki resource for the curious reader to explore?  How does this topic fit into that context?&lt;br /&gt;
&lt;br /&gt;
===Further reading===&lt;br /&gt;
&lt;br /&gt;
Books, Articles or other print media on this topic&lt;br /&gt;
&lt;br /&gt;
===External links===&lt;br /&gt;
&lt;br /&gt;
Internet resources on this topic&lt;br /&gt;
&lt;br /&gt;
==References==&lt;br /&gt;
&lt;br /&gt;
This section contains the the references you used while writing this page&lt;br /&gt;
&lt;br /&gt;
[[Category:Contact Forces]]&lt;/div&gt;</summary>
		<author><name>Drao31</name></author>
	</entry>
	<entry>
		<id>http://www.physicsbook.gatech.edu/index.php?title=Rotational_Kinematics&amp;diff=24745</id>
		<title>Rotational Kinematics</title>
		<link rel="alternate" type="text/html" href="http://www.physicsbook.gatech.edu/index.php?title=Rotational_Kinematics&amp;diff=24745"/>
		<updated>2016-11-27T07:57:29Z</updated>

		<summary type="html">&lt;p&gt;Drao31: &lt;/p&gt;
&lt;hr /&gt;
&lt;div&gt;&lt;br /&gt;
==The Main Idea==&lt;br /&gt;
&lt;br /&gt;
Rotational motion is defined as an object moving around an axis in contrast to translational motion which involves the object moving in a straight trajectory.  &lt;br /&gt;
&lt;br /&gt;
===A Mathematical Model===&lt;br /&gt;
&lt;br /&gt;
Rotation can be characterized by its angular velocity and angular acceleration. The equations are listed below.&lt;br /&gt;
&lt;br /&gt;
Angular velocity:&lt;br /&gt;
&lt;br /&gt;
:&amp;lt;math&amp;gt;\boldsymbol{{w}} = \frac{\boldsymbol{v}}{\boldsymbol{r}}&amp;lt;/math&amp;gt; , &lt;br /&gt;
where &amp;lt;math&amp;gt;{\boldsymbol{v}}&amp;lt;/math&amp;gt; is the velocity of the object and &amp;lt;math&amp;gt;{\boldsymbol{r}}&amp;lt;/math&amp;gt; is the radius of the circle of motion. It can also be represented as the change in angle over the distance traveled in the formula shown below:&lt;br /&gt;
&lt;br /&gt;
:&amp;lt;math&amp;gt;\boldsymbol{{w}} = \frac{\boldsymbol{d\theta}}{\boldsymbol{dt}}&amp;lt;/math&amp;gt; , where &amp;lt;math&amp;gt;{\boldsymbol{d\theta}}&amp;lt;/math&amp;gt; is the change in angle and &amp;lt;math&amp;gt;{\boldsymbol{dt}}&amp;lt;/math&amp;gt; is the change in time. &lt;br /&gt;
&lt;br /&gt;
[[File:angularvelocity.png]]&lt;br /&gt;
&lt;br /&gt;
 Angular velocity always has a unit of radians (radians/sec or radians/hr). &lt;br /&gt;
&lt;br /&gt;
Angular acceleration is equal to alpha:&lt;br /&gt;
&lt;br /&gt;
:&amp;lt;math&amp;gt;\boldsymbol{{\alpha}} = \frac{\boldsymbol{a_t}}{\boldsymbol{r}}&amp;lt;/math&amp;gt; , &lt;br /&gt;
where &amp;lt;math&amp;gt;{\boldsymbol{a_t}}&amp;lt;/math&amp;gt; is the tangential acceleration of the object and &amp;lt;math&amp;gt;{\boldsymbol{r}}&amp;lt;/math&amp;gt; is the radius of the circle of motion.&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
Rotational Kinetic Energy:&lt;br /&gt;
An object with a center of mass at rest can still have rotational kinetic energy. For example, if a disk is suspended in the air and spun, it has no translational kinetic energy. The position of the disk does not change. However, since it is spinning (rotating), it still has kinetic energy. To account for this, we can relate angular velocity with the moment of inertia of the object to find a value for the rotational kinetic energy.&lt;br /&gt;
&lt;br /&gt;
Rotational Kinetic Energy:&lt;br /&gt;
&lt;br /&gt;
::&amp;lt;math&amp;gt;{KE}_{rot} = \frac{{1}}{{2}}{I}_{cm}{&amp;amp;omega;^2}&amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
Relation to Work and Energy Principle:&lt;br /&gt;
&lt;br /&gt;
The energy principle states:&lt;br /&gt;
::&amp;lt;math&amp;gt;{E}_{f} = {E}_{i} + W &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
We can apply the energy principle to rotational kinetic energy as well to find changes in kinetic energy and work done on the system.&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
===A Computational Model===&lt;br /&gt;
&lt;br /&gt;
==Examples==&lt;br /&gt;
&lt;br /&gt;
Be sure to show all steps in your solution and include diagrams whenever possible&lt;br /&gt;
&lt;br /&gt;
===Simple===&lt;br /&gt;
&lt;br /&gt;
A simple example and application of the concept of rotation is the earth&#039;s rotation on it&#039;s axis. It rotates once every 24 hours. What is the angular velocity?&lt;br /&gt;
&lt;br /&gt;
:&amp;lt;math&amp;gt;\boldsymbol{{w}} = \frac{\boldsymbol{d\theta}}{\boldsymbol{dt}}&amp;lt;/math&amp;gt;&lt;br /&gt;
:&amp;lt;math&amp;gt;\boldsymbol{{w}} = \frac{\boldsymbol{2\pi}}{\boldsymbol{24}}&amp;lt;/math&amp;gt;&lt;br /&gt;
:&amp;lt;math&amp;gt;\boldsymbol{{w}} = \frac{\boldsymbol{\pi}}{\boldsymbol{12}}&amp;lt;/math&amp;gt;&lt;br /&gt;
:&amp;lt;math&amp;gt;\boldsymbol{{w}} = \frac{\boldsymbol{\pi}}{\boldsymbol{12}}*\frac{\boldsymbol{180}}{\boldsymbol{\pi}}&amp;lt;/math&amp;gt;&lt;br /&gt;
:&amp;lt;math&amp;gt;\boldsymbol{{w}} = {\boldsymbol{15 degrees}}&amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
Angular velocity can also be represented as change in angle (theta) over change in time. In this case, the earth rotates 2pi radians in 24 hours which reduces to pi/12 radians and that becomes 15 degrees.&lt;br /&gt;
&lt;br /&gt;
===Middling===&lt;br /&gt;
&lt;br /&gt;
A cylinder with a 2.5 ft radius is rotating at 120 rpm. Find the angular velocity in rad/sec and in degrees/sec. Find the linear velocity of a point on its rim in mph.&lt;br /&gt;
&lt;br /&gt;
To find the solution of this problem, rpm (revolutions per minute) should be converted to radians/second. Following this, the linear velocity can be calculated by using the v=wr formula shown above. The angular velocity is 720 degrees per sec and the linear velocity is 21.42 mph.&lt;br /&gt;
&lt;br /&gt;
Details of Explanation:&lt;br /&gt;
&lt;br /&gt;
[[File:MiddlePrb.jpg]]&lt;br /&gt;
&lt;br /&gt;
===Difficult===&lt;br /&gt;
&lt;br /&gt;
A tire with a 9 inch radius is rotating at 30 mph. Find the angular velocity at a point on its rim. Also express the result in revolutions per minute.&lt;br /&gt;
&lt;br /&gt;
[[File:Difficultprb.jpg]]&lt;br /&gt;
&lt;br /&gt;
==Connectedness==&lt;br /&gt;
Rotation is an extremely important aspect of dynamics (the study of moving objects) which plays a big role in biomechanics. Rotation relates to several important body parts such as the shoulder where there are two axis of rotation, the medial-lateral axis and the anterior-posterior axis. A study of the movement of the shoulder helps to treat medical conditions that may affect this area. Dynamics is also very important in many other disciples, including mechanical engineering and aerospace engineering.&lt;br /&gt;
&lt;br /&gt;
== See also ==&lt;br /&gt;
&lt;br /&gt;
To learn more about Rotation in a more complete context, please refer to Torque or Rigid-Body Objects or Angular Momentum.&lt;br /&gt;
&lt;br /&gt;
===Further reading===&lt;br /&gt;
&lt;br /&gt;
Books, Articles or other print media on this topic&lt;br /&gt;
&lt;br /&gt;
===External links===&lt;br /&gt;
&lt;br /&gt;
Some other resources to further understand rotation are the following:&lt;br /&gt;
&lt;br /&gt;
http://www.mathwarehouse.com/transformations/rotations-in-math.php&lt;br /&gt;
&lt;br /&gt;
http://demonstrations.wolfram.com/Understanding3DRotation/&lt;br /&gt;
&lt;br /&gt;
==References==&lt;br /&gt;
&lt;br /&gt;
[1] Biomechanics, Basic. &amp;lt;i&amp;gt;“It Is Important When Learning about&amp;lt;/i&amp;gt; (n.d.): n. pag. Web.&lt;br /&gt;
&lt;br /&gt;
[2] &amp;quot;Angular Velocity and Angular Acceleration.&amp;quot; Van Nostrand&#039;s Scientific Encyclopedia (2005): n. pag. Web&lt;/div&gt;</summary>
		<author><name>Drao31</name></author>
	</entry>
	<entry>
		<id>http://www.physicsbook.gatech.edu/index.php?title=Friction&amp;diff=24664</id>
		<title>Friction</title>
		<link rel="alternate" type="text/html" href="http://www.physicsbook.gatech.edu/index.php?title=Friction&amp;diff=24664"/>
		<updated>2016-11-27T05:29:38Z</updated>

		<summary type="html">&lt;p&gt;Drao31: /* A Computational Model */&lt;/p&gt;
&lt;hr /&gt;
&lt;div&gt;This page discusses the concept of friction and how it relates to both moving and static objects.&lt;br /&gt;
&lt;br /&gt;
Claimed by drao31&lt;br /&gt;
&lt;br /&gt;
==The Main Idea==&lt;br /&gt;
Friction is caused by the interactions between the atoms that make up objects. When objects interact, the atoms that make up the objects also interact. Temperatures of interacting surfaces rise because of such interactions. Friction is a force that resists movement. Generally, friction makes it harder to move objects. There are two main types of friction that are covered in Physics 2211: Static Friction and Kinetic Friction. Static friction can be described as the friction acting on resting objects. Kinetic friction is the friction acting on objects in motion. &lt;br /&gt;
&lt;br /&gt;
Frictional forces depend on a few factors: the normal force and the coefficient of friction. &lt;br /&gt;
&lt;br /&gt;
In simple terms, the normal force &amp;lt;math&amp;gt; {F}_{N} &amp;lt;/math&amp;gt; or &amp;lt;math&amp;gt; {N} &amp;lt;/math&amp;gt; is the equivalent force between objects. For example, when an object of mass &#039;&#039;&#039;M&#039;&#039;&#039; is placed on a table, there is a gravitational force &#039;&#039;&#039;Mg&#039;&#039;&#039; on the table. If the table can support the object without collapsing, the table exerts an equivalent force &#039;&#039;&#039;Mg&#039;&#039;&#039; on the object. According to the momentum principle, since there is no change in momentum, the net force must be &#039;&#039;&#039;0&#039;&#039;&#039;. This is also apparent since there is no movement if the table can support the object.&lt;br /&gt;
&lt;br /&gt;
::&amp;lt;math&amp;gt; {p}_{f} - {p}_{i} = {F}_{net}{dt} = 0 &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
OR&lt;br /&gt;
&lt;br /&gt;
::&amp;lt;math&amp;gt; {F}_{g} = {M}{g} &amp;lt;/math&amp;gt;&lt;br /&gt;
::&amp;lt;math&amp;gt; {N} = {M}{g} &amp;lt;/math&amp;gt;&lt;br /&gt;
::&amp;lt;math&amp;gt; {F}_{net} = {F}_{g} - {N} = {0} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
The coefficient of friction is usually specific to each object or material. The coefficient of static friction is denoted by &amp;lt;math&amp;gt;{&amp;amp;mu;}_{s}&amp;lt;/math&amp;gt; and the coefficient of kinetic friction is denoted by &amp;lt;math&amp;gt;{&amp;amp;mu;}_{k}&amp;lt;/math&amp;gt; &lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
Static Friction:&lt;br /&gt;
&lt;br /&gt;
::&amp;lt;math&amp;gt; {F}_{s} \le {&amp;amp;mu;}_{s}{N} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
Static friction is the frictional force that must be overcome to begin moving an object at rest. The static friction can be no more than the normal force multiplied by the coefficient of static friction. Therefore, the maximum static friction an object can have is &amp;lt;math&amp;gt; {&amp;amp;mu;}_{s}{N} &amp;lt;/math&amp;gt;. &lt;br /&gt;
&lt;br /&gt;
Kinetic Friction:&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
::&amp;lt;math&amp;gt; {F}_{k} = {&amp;amp;mu;}_{k}{N} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
Kinetic friction is the frictional force that exists between objects already at motion. &lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
===A Mathematical Model===&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
===A Computational Model===&lt;br /&gt;
&lt;br /&gt;
[[File:Friction.gif]]&lt;br /&gt;
&lt;br /&gt;
Link: &lt;br /&gt;
https://trinket.io/glowscript/76028c1809&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
Code: &lt;br /&gt;
 def friction():&lt;br /&gt;
    from __future__ import division&lt;br /&gt;
    from visual import *&lt;br /&gt;
    from visual.graph import *&lt;br /&gt;
&lt;br /&gt;
    mcart = 100&lt;br /&gt;
    mew = vector(2.9,0,0)&lt;br /&gt;
&lt;br /&gt;
    track =  box(pos=vector(0,-0.05,0), size=vector(20.0,0.05,0.10), color=color.white)&lt;br /&gt;
    cart =  box(pos=vector(-10,0.25,0), size=vector(.5,0.6,0.03), color=color.blue)&lt;br /&gt;
    marker = box(pos = vector(2,0,0), size = vector(0,20,5), color = color.red)&lt;br /&gt;
&lt;br /&gt;
    cart.v=vector(2.4,0,0)&lt;br /&gt;
    cart.p = mcart*cart.v&lt;br /&gt;
    F = vector(90,0,0)&lt;br /&gt;
    F2 = vector(-200,0,0)&lt;br /&gt;
    F3 = (mcart * mew)&lt;br /&gt;
    print(F3)&lt;br /&gt;
&lt;br /&gt;
    deltat = 0.01&lt;br /&gt;
    t = 0&lt;br /&gt;
&lt;br /&gt;
    while t &amp;lt; 5.02:&lt;br /&gt;
&lt;br /&gt;
        if cart.pos.x &amp;lt; 2:&lt;br /&gt;
            cart.v = cart.p / cart.m&lt;br /&gt;
            Fnet = F&lt;br /&gt;
            cart.p = cart.p + Fnet*deltat&lt;br /&gt;
            cart.pos = cart.pos + (cart.p/mcart)*deltat&lt;br /&gt;
&lt;br /&gt;
        else:&lt;br /&gt;
            &lt;br /&gt;
            cart.v = cart.p / cart.m&lt;br /&gt;
            Fnet = F-F3&lt;br /&gt;
            cart.p = cart.p + Fnet*deltat&lt;br /&gt;
            cart.pos = cart.pos + (cart.p/mcart)*deltat&lt;br /&gt;
            &lt;br /&gt;
        t = t + deltat&lt;br /&gt;
        rate(100)&lt;br /&gt;
        &lt;br /&gt;
    print(cart.pos)&lt;br /&gt;
    &lt;br /&gt;
 friction()&lt;br /&gt;
&lt;br /&gt;
==Examples==&lt;br /&gt;
&lt;br /&gt;
Be sure to show all steps in your solution and include diagrams whenever possible&lt;br /&gt;
&lt;br /&gt;
===Simple===&lt;br /&gt;
&lt;br /&gt;
A 100Kg box is placed on a flat table. The box does not move. The coefficient of static friction &amp;lt;math&amp;gt; {&amp;amp;mu;}_{s} = {.25} &amp;lt;/math&amp;gt; and the coefficient of kinetic friction &amp;lt;math&amp;gt; {&amp;amp;mu;}_{k} = {.15} &amp;lt;/math&amp;gt;.&lt;br /&gt;
Find the force of friction &amp;lt;math&amp;gt;{F}_{s}&amp;lt;/math&amp;gt;.&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
Solution:&lt;br /&gt;
&lt;br /&gt;
Since the box does not move, there is only static friction. The normal force is equivalent to the force due to gravity: &amp;lt;math&amp;gt; {F}_{N} = {F}_{g} = {100}{g} &amp;lt;/math&amp;gt;. The static friction can be found by: &amp;lt;math&amp;gt; {F}_{s} = {&amp;amp;mu;}_{s}{F}_{N} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
&amp;lt;math&amp;gt; {F}_{s} = {(.25)}{(100)}{(9.8)} = {245.25} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
===Middling===&lt;br /&gt;
===Difficult===&lt;br /&gt;
&lt;br /&gt;
==Connectedness==&lt;br /&gt;
#How is this topic connected to something that you are interested in?&lt;br /&gt;
#How is it connected to your major?&lt;br /&gt;
#Is there an interesting industrial application?&lt;br /&gt;
&lt;br /&gt;
==History==&lt;br /&gt;
&lt;br /&gt;
Put this idea in historical context. Give the reader the Who, What, When, Where, and Why.&lt;br /&gt;
&lt;br /&gt;
== See also ==&lt;br /&gt;
&lt;br /&gt;
Are there related topics or categories in this wiki resource for the curious reader to explore?  How does this topic fit into that context?&lt;br /&gt;
&lt;br /&gt;
===Further reading===&lt;br /&gt;
&lt;br /&gt;
Books, Articles or other print media on this topic&lt;br /&gt;
&lt;br /&gt;
===External links===&lt;br /&gt;
&lt;br /&gt;
Internet resources on this topic&lt;br /&gt;
&lt;br /&gt;
==References==&lt;br /&gt;
&lt;br /&gt;
This section contains the the references you used while writing this page&lt;br /&gt;
&lt;br /&gt;
[[Category:Contact Forces]]&lt;/div&gt;</summary>
		<author><name>Drao31</name></author>
	</entry>
	<entry>
		<id>http://www.physicsbook.gatech.edu/index.php?title=Friction&amp;diff=24657</id>
		<title>Friction</title>
		<link rel="alternate" type="text/html" href="http://www.physicsbook.gatech.edu/index.php?title=Friction&amp;diff=24657"/>
		<updated>2016-11-27T05:26:14Z</updated>

		<summary type="html">&lt;p&gt;Drao31: /* A Computational Model */&lt;/p&gt;
&lt;hr /&gt;
&lt;div&gt;This page discusses the concept of friction and how it relates to both moving and static objects.&lt;br /&gt;
&lt;br /&gt;
Claimed by drao31&lt;br /&gt;
&lt;br /&gt;
==The Main Idea==&lt;br /&gt;
Friction is caused by the interactions between the atoms that make up objects. When objects interact, the atoms that make up the objects also interact. Temperatures of interacting surfaces rise because of such interactions. Friction is a force that resists movement. Generally, friction makes it harder to move objects. There are two main types of friction that are covered in Physics 2211: Static Friction and Kinetic Friction. Static friction can be described as the friction acting on resting objects. Kinetic friction is the friction acting on objects in motion. &lt;br /&gt;
&lt;br /&gt;
Frictional forces depend on a few factors: the normal force and the coefficient of friction. &lt;br /&gt;
&lt;br /&gt;
In simple terms, the normal force &amp;lt;math&amp;gt; {F}_{N} &amp;lt;/math&amp;gt; or &amp;lt;math&amp;gt; {N} &amp;lt;/math&amp;gt; is the equivalent force between objects. For example, when an object of mass &#039;&#039;&#039;M&#039;&#039;&#039; is placed on a table, there is a gravitational force &#039;&#039;&#039;Mg&#039;&#039;&#039; on the table. If the table can support the object without collapsing, the table exerts an equivalent force &#039;&#039;&#039;Mg&#039;&#039;&#039; on the object. According to the momentum principle, since there is no change in momentum, the net force must be &#039;&#039;&#039;0&#039;&#039;&#039;. This is also apparent since there is no movement if the table can support the object.&lt;br /&gt;
&lt;br /&gt;
::&amp;lt;math&amp;gt; {p}_{f} - {p}_{i} = {F}_{net}{dt} = 0 &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
OR&lt;br /&gt;
&lt;br /&gt;
::&amp;lt;math&amp;gt; {F}_{g} = {M}{g} &amp;lt;/math&amp;gt;&lt;br /&gt;
::&amp;lt;math&amp;gt; {N} = {M}{g} &amp;lt;/math&amp;gt;&lt;br /&gt;
::&amp;lt;math&amp;gt; {F}_{net} = {F}_{g} - {N} = {0} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
The coefficient of friction is usually specific to each object or material. The coefficient of static friction is denoted by &amp;lt;math&amp;gt;{&amp;amp;mu;}_{s}&amp;lt;/math&amp;gt; and the coefficient of kinetic friction is denoted by &amp;lt;math&amp;gt;{&amp;amp;mu;}_{k}&amp;lt;/math&amp;gt; &lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
Static Friction:&lt;br /&gt;
&lt;br /&gt;
::&amp;lt;math&amp;gt; {F}_{s} \le {&amp;amp;mu;}_{s}{N} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
Static friction is the frictional force that must be overcome to begin moving an object at rest. The static friction can be no more than the normal force multiplied by the coefficient of static friction. Therefore, the maximum static friction an object can have is &amp;lt;math&amp;gt; {&amp;amp;mu;}_{s}{N} &amp;lt;/math&amp;gt;. &lt;br /&gt;
&lt;br /&gt;
Kinetic Friction:&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
::&amp;lt;math&amp;gt; {F}_{k} = {&amp;amp;mu;}_{k}{N} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
Kinetic friction is the frictional force that exists between objects already at motion. &lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
===A Mathematical Model===&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
===A Computational Model===&lt;br /&gt;
&lt;br /&gt;
[[File:Friction.gif]]&lt;br /&gt;
&lt;br /&gt;
&amp;lt;iframe src=&amp;quot;https://trinket.io/embed/glowscript/76028c1809&amp;quot; width=&amp;quot;100%&amp;quot; height=&amp;quot;600&amp;quot; frameborder=&amp;quot;0&amp;quot; marginwidth=&amp;quot;0&amp;quot; marginheight=&amp;quot;0&amp;quot; allowfullscreen&amp;gt;&amp;lt;/iframe&amp;gt;&lt;br /&gt;
&lt;br /&gt;
==Examples==&lt;br /&gt;
&lt;br /&gt;
Be sure to show all steps in your solution and include diagrams whenever possible&lt;br /&gt;
&lt;br /&gt;
===Simple===&lt;br /&gt;
&lt;br /&gt;
A 100Kg box is placed on a flat table. The box does not move. The coefficient of static friction &amp;lt;math&amp;gt; {&amp;amp;mu;}_{s} = {.25} &amp;lt;/math&amp;gt; and the coefficient of kinetic friction &amp;lt;math&amp;gt; {&amp;amp;mu;}_{k} = {.15} &amp;lt;/math&amp;gt;.&lt;br /&gt;
Find the force of friction &amp;lt;math&amp;gt;{F}_{s}&amp;lt;/math&amp;gt;.&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
Solution:&lt;br /&gt;
&lt;br /&gt;
Since the box does not move, there is only static friction. The normal force is equivalent to the force due to gravity: &amp;lt;math&amp;gt; {F}_{N} = {F}_{g} = {100}{g} &amp;lt;/math&amp;gt;. The static friction can be found by: &amp;lt;math&amp;gt; {F}_{s} = {&amp;amp;mu;}_{s}{F}_{N} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
&amp;lt;math&amp;gt; {F}_{s} = {(.25)}{(100)}{(9.8)} = {245.25} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
===Middling===&lt;br /&gt;
===Difficult===&lt;br /&gt;
&lt;br /&gt;
==Connectedness==&lt;br /&gt;
#How is this topic connected to something that you are interested in?&lt;br /&gt;
#How is it connected to your major?&lt;br /&gt;
#Is there an interesting industrial application?&lt;br /&gt;
&lt;br /&gt;
==History==&lt;br /&gt;
&lt;br /&gt;
Put this idea in historical context. Give the reader the Who, What, When, Where, and Why.&lt;br /&gt;
&lt;br /&gt;
== See also ==&lt;br /&gt;
&lt;br /&gt;
Are there related topics or categories in this wiki resource for the curious reader to explore?  How does this topic fit into that context?&lt;br /&gt;
&lt;br /&gt;
===Further reading===&lt;br /&gt;
&lt;br /&gt;
Books, Articles or other print media on this topic&lt;br /&gt;
&lt;br /&gt;
===External links===&lt;br /&gt;
&lt;br /&gt;
Internet resources on this topic&lt;br /&gt;
&lt;br /&gt;
==References==&lt;br /&gt;
&lt;br /&gt;
This section contains the the references you used while writing this page&lt;br /&gt;
&lt;br /&gt;
[[Category:Contact Forces]]&lt;/div&gt;</summary>
		<author><name>Drao31</name></author>
	</entry>
	<entry>
		<id>http://www.physicsbook.gatech.edu/index.php?title=File:Friction.gif&amp;diff=24652</id>
		<title>File:Friction.gif</title>
		<link rel="alternate" type="text/html" href="http://www.physicsbook.gatech.edu/index.php?title=File:Friction.gif&amp;diff=24652"/>
		<updated>2016-11-27T05:24:07Z</updated>

		<summary type="html">&lt;p&gt;Drao31: GIF of a basic example of frictional force done in vPython.&lt;/p&gt;
&lt;hr /&gt;
&lt;div&gt;GIF of a basic example of frictional force done in vPython.&lt;/div&gt;</summary>
		<author><name>Drao31</name></author>
	</entry>
	<entry>
		<id>http://www.physicsbook.gatech.edu/index.php?title=Friction&amp;diff=24600</id>
		<title>Friction</title>
		<link rel="alternate" type="text/html" href="http://www.physicsbook.gatech.edu/index.php?title=Friction&amp;diff=24600"/>
		<updated>2016-11-27T04:51:00Z</updated>

		<summary type="html">&lt;p&gt;Drao31: /* A Computational Model */&lt;/p&gt;
&lt;hr /&gt;
&lt;div&gt;This page discusses the concept of friction and how it relates to both moving and static objects.&lt;br /&gt;
&lt;br /&gt;
Claimed by drao31&lt;br /&gt;
&lt;br /&gt;
==The Main Idea==&lt;br /&gt;
Friction is caused by the interactions between the atoms that make up objects. When objects interact, the atoms that make up the objects also interact. Temperatures of interacting surfaces rise because of such interactions. Friction is a force that resists movement. Generally, friction makes it harder to move objects. There are two main types of friction that are covered in Physics 2211: Static Friction and Kinetic Friction. Static friction can be described as the friction acting on resting objects. Kinetic friction is the friction acting on objects in motion. &lt;br /&gt;
&lt;br /&gt;
Frictional forces depend on a few factors: the normal force and the coefficient of friction. &lt;br /&gt;
&lt;br /&gt;
In simple terms, the normal force &amp;lt;math&amp;gt; {F}_{N} &amp;lt;/math&amp;gt; or &amp;lt;math&amp;gt; {N} &amp;lt;/math&amp;gt; is the equivalent force between objects. For example, when an object of mass &#039;&#039;&#039;M&#039;&#039;&#039; is placed on a table, there is a gravitational force &#039;&#039;&#039;Mg&#039;&#039;&#039; on the table. If the table can support the object without collapsing, the table exerts an equivalent force &#039;&#039;&#039;Mg&#039;&#039;&#039; on the object. According to the momentum principle, since there is no change in momentum, the net force must be &#039;&#039;&#039;0&#039;&#039;&#039;. This is also apparent since there is no movement if the table can support the object.&lt;br /&gt;
&lt;br /&gt;
::&amp;lt;math&amp;gt; {p}_{f} - {p}_{i} = {F}_{net}{dt} = 0 &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
OR&lt;br /&gt;
&lt;br /&gt;
::&amp;lt;math&amp;gt; {F}_{g} = {M}{g} &amp;lt;/math&amp;gt;&lt;br /&gt;
::&amp;lt;math&amp;gt; {N} = {M}{g} &amp;lt;/math&amp;gt;&lt;br /&gt;
::&amp;lt;math&amp;gt; {F}_{net} = {F}_{g} - {N} = {0} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
The coefficient of friction is usually specific to each object or material. The coefficient of static friction is denoted by &amp;lt;math&amp;gt;{&amp;amp;mu;}_{s}&amp;lt;/math&amp;gt; and the coefficient of kinetic friction is denoted by &amp;lt;math&amp;gt;{&amp;amp;mu;}_{k}&amp;lt;/math&amp;gt; &lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
Static Friction:&lt;br /&gt;
&lt;br /&gt;
::&amp;lt;math&amp;gt; {F}_{s} \le {&amp;amp;mu;}_{s}{N} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
Static friction is the frictional force that must be overcome to begin moving an object at rest. The static friction can be no more than the normal force multiplied by the coefficient of static friction. Therefore, the maximum static friction an object can have is &amp;lt;math&amp;gt; {&amp;amp;mu;}_{s}{N} &amp;lt;/math&amp;gt;. &lt;br /&gt;
&lt;br /&gt;
Kinetic Friction:&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
::&amp;lt;math&amp;gt; {F}_{k} = {&amp;amp;mu;}_{k}{N} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
Kinetic friction is the frictional force that exists between objects already at motion. &lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
===A Mathematical Model===&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
===A Computational Model===&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
&amp;lt;iframe src=&amp;quot;https://trinket.io/embed/glowscript/76028c1809&amp;quot; width=&amp;quot;100%&amp;quot; height=&amp;quot;600&amp;quot; frameborder=&amp;quot;0&amp;quot; marginwidth=&amp;quot;0&amp;quot; marginheight=&amp;quot;0&amp;quot; allowfullscreen&amp;gt;&amp;lt;/iframe&amp;gt;&lt;br /&gt;
&lt;br /&gt;
==Examples==&lt;br /&gt;
&lt;br /&gt;
Be sure to show all steps in your solution and include diagrams whenever possible&lt;br /&gt;
&lt;br /&gt;
===Simple===&lt;br /&gt;
&lt;br /&gt;
A 100Kg box is placed on a flat table. The box does not move. The coefficient of static friction &amp;lt;math&amp;gt; {&amp;amp;mu;}_{s} = {.25} &amp;lt;/math&amp;gt; and the coefficient of kinetic friction &amp;lt;math&amp;gt; {&amp;amp;mu;}_{k} = {.15} &amp;lt;/math&amp;gt;.&lt;br /&gt;
Find the force of friction &amp;lt;math&amp;gt;{F}_{s}&amp;lt;/math&amp;gt;.&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
Solution:&lt;br /&gt;
&lt;br /&gt;
Since the box does not move, there is only static friction. The normal force is equivalent to the force due to gravity: &amp;lt;math&amp;gt; {F}_{N} = {F}_{g} = {100}{g} &amp;lt;/math&amp;gt;. The static friction can be found by: &amp;lt;math&amp;gt; {F}_{s} = {&amp;amp;mu;}_{s}{F}_{N} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
&amp;lt;math&amp;gt; {F}_{s} = {(.25)}{(100)}{(9.8)} = {245.25} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
===Middling===&lt;br /&gt;
===Difficult===&lt;br /&gt;
&lt;br /&gt;
==Connectedness==&lt;br /&gt;
#How is this topic connected to something that you are interested in?&lt;br /&gt;
#How is it connected to your major?&lt;br /&gt;
#Is there an interesting industrial application?&lt;br /&gt;
&lt;br /&gt;
==History==&lt;br /&gt;
&lt;br /&gt;
Put this idea in historical context. Give the reader the Who, What, When, Where, and Why.&lt;br /&gt;
&lt;br /&gt;
== See also ==&lt;br /&gt;
&lt;br /&gt;
Are there related topics or categories in this wiki resource for the curious reader to explore?  How does this topic fit into that context?&lt;br /&gt;
&lt;br /&gt;
===Further reading===&lt;br /&gt;
&lt;br /&gt;
Books, Articles or other print media on this topic&lt;br /&gt;
&lt;br /&gt;
===External links===&lt;br /&gt;
&lt;br /&gt;
Internet resources on this topic&lt;br /&gt;
&lt;br /&gt;
==References==&lt;br /&gt;
&lt;br /&gt;
This section contains the the references you used while writing this page&lt;br /&gt;
&lt;br /&gt;
[[Category:Contact Forces]]&lt;/div&gt;</summary>
		<author><name>Drao31</name></author>
	</entry>
	<entry>
		<id>http://www.physicsbook.gatech.edu/index.php?title=Friction&amp;diff=24570</id>
		<title>Friction</title>
		<link rel="alternate" type="text/html" href="http://www.physicsbook.gatech.edu/index.php?title=Friction&amp;diff=24570"/>
		<updated>2016-11-27T03:33:43Z</updated>

		<summary type="html">&lt;p&gt;Drao31: &lt;/p&gt;
&lt;hr /&gt;
&lt;div&gt;This page discusses the concept of friction and how it relates to both moving and static objects.&lt;br /&gt;
&lt;br /&gt;
Claimed by drao31&lt;br /&gt;
&lt;br /&gt;
==The Main Idea==&lt;br /&gt;
Friction is caused by the interactions between the atoms that make up objects. When objects interact, the atoms that make up the objects also interact. Temperatures of interacting surfaces rise because of such interactions. Friction is a force that resists movement. Generally, friction makes it harder to move objects. There are two main types of friction that are covered in Physics 2211: Static Friction and Kinetic Friction. Static friction can be described as the friction acting on resting objects. Kinetic friction is the friction acting on objects in motion. &lt;br /&gt;
&lt;br /&gt;
Frictional forces depend on a few factors: the normal force and the coefficient of friction. &lt;br /&gt;
&lt;br /&gt;
In simple terms, the normal force &amp;lt;math&amp;gt; {F}_{N} &amp;lt;/math&amp;gt; or &amp;lt;math&amp;gt; {N} &amp;lt;/math&amp;gt; is the equivalent force between objects. For example, when an object of mass &#039;&#039;&#039;M&#039;&#039;&#039; is placed on a table, there is a gravitational force &#039;&#039;&#039;Mg&#039;&#039;&#039; on the table. If the table can support the object without collapsing, the table exerts an equivalent force &#039;&#039;&#039;Mg&#039;&#039;&#039; on the object. According to the momentum principle, since there is no change in momentum, the net force must be &#039;&#039;&#039;0&#039;&#039;&#039;. This is also apparent since there is no movement if the table can support the object.&lt;br /&gt;
&lt;br /&gt;
::&amp;lt;math&amp;gt; {p}_{f} - {p}_{i} = {F}_{net}{dt} = 0 &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
OR&lt;br /&gt;
&lt;br /&gt;
::&amp;lt;math&amp;gt; {F}_{g} = {M}{g} &amp;lt;/math&amp;gt;&lt;br /&gt;
::&amp;lt;math&amp;gt; {N} = {M}{g} &amp;lt;/math&amp;gt;&lt;br /&gt;
::&amp;lt;math&amp;gt; {F}_{net} = {F}_{g} - {N} = {0} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
The coefficient of friction is usually specific to each object or material. The coefficient of static friction is denoted by &amp;lt;math&amp;gt;{&amp;amp;mu;}_{s}&amp;lt;/math&amp;gt; and the coefficient of kinetic friction is denoted by &amp;lt;math&amp;gt;{&amp;amp;mu;}_{k}&amp;lt;/math&amp;gt; &lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
Static Friction:&lt;br /&gt;
&lt;br /&gt;
::&amp;lt;math&amp;gt; {F}_{s} \le {&amp;amp;mu;}_{s}{N} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
Static friction is the frictional force that must be overcome to begin moving an object at rest. The static friction can be no more than the normal force multiplied by the coefficient of static friction. Therefore, the maximum static friction an object can have is &amp;lt;math&amp;gt; {&amp;amp;mu;}_{s}{N} &amp;lt;/math&amp;gt;. &lt;br /&gt;
&lt;br /&gt;
Kinetic Friction:&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
::&amp;lt;math&amp;gt; {F}_{k} = {&amp;amp;mu;}_{k}{N} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
Kinetic friction is the frictional force that exists between objects already at motion. &lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
===A Mathematical Model===&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
===A Computational Model===&lt;br /&gt;
&lt;br /&gt;
How do we visualize or predict using this topic. Consider embedding some vpython code here [https://trinket.io/glowscript/31d0f9ad9e Teach hands-on with GlowScript]&lt;br /&gt;
&lt;br /&gt;
==Examples==&lt;br /&gt;
&lt;br /&gt;
Be sure to show all steps in your solution and include diagrams whenever possible&lt;br /&gt;
&lt;br /&gt;
===Simple===&lt;br /&gt;
&lt;br /&gt;
A 100Kg box is placed on a flat table. The box does not move. The coefficient of static friction &amp;lt;math&amp;gt; {&amp;amp;mu;}_{s} = {.25} &amp;lt;/math&amp;gt; and the coefficient of kinetic friction &amp;lt;math&amp;gt; {&amp;amp;mu;}_{k} = {.15} &amp;lt;/math&amp;gt;.&lt;br /&gt;
Find the force of friction &amp;lt;math&amp;gt;{F}_{s}&amp;lt;/math&amp;gt;.&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
Solution:&lt;br /&gt;
&lt;br /&gt;
Since the box does not move, there is only static friction. The normal force is equivalent to the force due to gravity: &amp;lt;math&amp;gt; {F}_{N} = {F}_{g} = {100}{g} &amp;lt;/math&amp;gt;. The static friction can be found by: &amp;lt;math&amp;gt; {F}_{s} = {&amp;amp;mu;}_{s}{F}_{N} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
&amp;lt;math&amp;gt; {F}_{s} = {(.25)}{(100)}{(9.8)} = {245.25} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
===Middling===&lt;br /&gt;
===Difficult===&lt;br /&gt;
&lt;br /&gt;
==Connectedness==&lt;br /&gt;
#How is this topic connected to something that you are interested in?&lt;br /&gt;
#How is it connected to your major?&lt;br /&gt;
#Is there an interesting industrial application?&lt;br /&gt;
&lt;br /&gt;
==History==&lt;br /&gt;
&lt;br /&gt;
Put this idea in historical context. Give the reader the Who, What, When, Where, and Why.&lt;br /&gt;
&lt;br /&gt;
== See also ==&lt;br /&gt;
&lt;br /&gt;
Are there related topics or categories in this wiki resource for the curious reader to explore?  How does this topic fit into that context?&lt;br /&gt;
&lt;br /&gt;
===Further reading===&lt;br /&gt;
&lt;br /&gt;
Books, Articles or other print media on this topic&lt;br /&gt;
&lt;br /&gt;
===External links===&lt;br /&gt;
&lt;br /&gt;
Internet resources on this topic&lt;br /&gt;
&lt;br /&gt;
==References==&lt;br /&gt;
&lt;br /&gt;
This section contains the the references you used while writing this page&lt;br /&gt;
&lt;br /&gt;
[[Category:Contact Forces]]&lt;/div&gt;</summary>
		<author><name>Drao31</name></author>
	</entry>
	<entry>
		<id>http://www.physicsbook.gatech.edu/index.php?title=Friction&amp;diff=24561</id>
		<title>Friction</title>
		<link rel="alternate" type="text/html" href="http://www.physicsbook.gatech.edu/index.php?title=Friction&amp;diff=24561"/>
		<updated>2016-11-27T03:20:36Z</updated>

		<summary type="html">&lt;p&gt;Drao31: /* Simple */&lt;/p&gt;
&lt;hr /&gt;
&lt;div&gt;This page discusses the concept of friction and how it relates to both moving and static objects.&lt;br /&gt;
&lt;br /&gt;
Claimed by drao31&lt;br /&gt;
&lt;br /&gt;
==The Main Idea==&lt;br /&gt;
Friction is caused by the interactions between the atoms that make up objects. When objects interact, the atoms that make up the objects also interact. Temperatures of interacting surfaces rise because of such interactions. Friction is a force that resists movement. Generally, friction makes it harder to move objects. There are two main types of friction that are covered in Physics 2211: Static Friction and Kinetic Friction. Static friction can be described as the friction acting on resting objects. Kinetic friction is the friction acting on objects in motion. &lt;br /&gt;
&lt;br /&gt;
Frictional forces depend on a few factors: the normal force and the coefficient of friction. &lt;br /&gt;
&lt;br /&gt;
In simple terms, the normal force is the equivalent force between objects. For example, when an object of mass &#039;&#039;&#039;M&#039;&#039;&#039; is placed on a table, there is a gravitational force &#039;&#039;&#039;Mg&#039;&#039;&#039; on the table. If the table can support the object without collapsing, the table exerts an equivalent force &#039;&#039;&#039;Mg&#039;&#039;&#039; on the object. According to the momentum principle, since there is no change in momentum, the net force must be &#039;&#039;&#039;0&#039;&#039;&#039;. This is also apparent since there is no movement if the table can support the object.&lt;br /&gt;
&lt;br /&gt;
::&amp;lt;math&amp;gt; {p}_{f} - {p}_{i} = {F}_{net}{dt} = 0 &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
OR&lt;br /&gt;
&lt;br /&gt;
::&amp;lt;math&amp;gt; {F}_{g} = {M}{g} &amp;lt;/math&amp;gt;&lt;br /&gt;
::&amp;lt;math&amp;gt; {F}_{N} = {M}{g} &amp;lt;/math&amp;gt;&lt;br /&gt;
::&amp;lt;math&amp;gt; {F}_{net} = {F}_{g} - {F}_{N} = {0} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
The coefficient of friction is usually specific to each object or material. The coefficient of static friction is denoted by &amp;lt;math&amp;gt;{&amp;amp;mu;}_{s}&amp;lt;/math&amp;gt; and the coefficient of kinetic friction is denoted by &amp;lt;math&amp;gt;{&amp;amp;mu;}_{k}&amp;lt;/math&amp;gt; &lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
===A Mathematical Model===&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
===A Computational Model===&lt;br /&gt;
&lt;br /&gt;
How do we visualize or predict using this topic. Consider embedding some vpython code here [https://trinket.io/glowscript/31d0f9ad9e Teach hands-on with GlowScript]&lt;br /&gt;
&lt;br /&gt;
==Examples==&lt;br /&gt;
&lt;br /&gt;
Be sure to show all steps in your solution and include diagrams whenever possible&lt;br /&gt;
&lt;br /&gt;
===Simple===&lt;br /&gt;
&lt;br /&gt;
A 100Kg box is placed on a flat table. The box does not move. The coefficient of static friction &amp;lt;math&amp;gt; {&amp;amp;mu;}_{s} = {.25} &amp;lt;/math&amp;gt; and the coefficient of kinetic friction &amp;lt;math&amp;gt; {&amp;amp;mu;}_{k} = {.15} &amp;lt;/math&amp;gt;.&lt;br /&gt;
Find the force of friction &amp;lt;math&amp;gt;{F}_{s}&amp;lt;/math&amp;gt;.&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
Solution:&lt;br /&gt;
&lt;br /&gt;
Since the box does not move, there is only static friction. The normal force is equivalent to the force due to gravity: &amp;lt;math&amp;gt; {F}_{N} = {F}_{g} = {100}{g} &amp;lt;/math&amp;gt;. The static friction can be found by: &amp;lt;math&amp;gt; {F}_{s} = {&amp;amp;mu;}_{s}{F}_{N} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
&amp;lt;math&amp;gt; {F}_{s} = {(.25)}{(100)}{(9.8)} = {245.25} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
===Middling===&lt;br /&gt;
===Difficult===&lt;br /&gt;
&lt;br /&gt;
==Connectedness==&lt;br /&gt;
#How is this topic connected to something that you are interested in?&lt;br /&gt;
#How is it connected to your major?&lt;br /&gt;
#Is there an interesting industrial application?&lt;br /&gt;
&lt;br /&gt;
==History==&lt;br /&gt;
&lt;br /&gt;
Put this idea in historical context. Give the reader the Who, What, When, Where, and Why.&lt;br /&gt;
&lt;br /&gt;
== See also ==&lt;br /&gt;
&lt;br /&gt;
Are there related topics or categories in this wiki resource for the curious reader to explore?  How does this topic fit into that context?&lt;br /&gt;
&lt;br /&gt;
===Further reading===&lt;br /&gt;
&lt;br /&gt;
Books, Articles or other print media on this topic&lt;br /&gt;
&lt;br /&gt;
===External links===&lt;br /&gt;
&lt;br /&gt;
Internet resources on this topic&lt;br /&gt;
&lt;br /&gt;
==References==&lt;br /&gt;
&lt;br /&gt;
This section contains the the references you used while writing this page&lt;br /&gt;
&lt;br /&gt;
[[Category:Contact Forces]]&lt;/div&gt;</summary>
		<author><name>Drao31</name></author>
	</entry>
	<entry>
		<id>http://www.physicsbook.gatech.edu/index.php?title=Friction&amp;diff=24559</id>
		<title>Friction</title>
		<link rel="alternate" type="text/html" href="http://www.physicsbook.gatech.edu/index.php?title=Friction&amp;diff=24559"/>
		<updated>2016-11-27T03:08:23Z</updated>

		<summary type="html">&lt;p&gt;Drao31: &lt;/p&gt;
&lt;hr /&gt;
&lt;div&gt;This page discusses the concept of friction and how it relates to both moving and static objects.&lt;br /&gt;
&lt;br /&gt;
Claimed by drao31&lt;br /&gt;
&lt;br /&gt;
==The Main Idea==&lt;br /&gt;
Friction is caused by the interactions between the atoms that make up objects. When objects interact, the atoms that make up the objects also interact. Temperatures of interacting surfaces rise because of such interactions. Friction is a force that resists movement. Generally, friction makes it harder to move objects. There are two main types of friction that are covered in Physics 2211: Static Friction and Kinetic Friction. Static friction can be described as the friction acting on resting objects. Kinetic friction is the friction acting on objects in motion. &lt;br /&gt;
&lt;br /&gt;
Frictional forces depend on a few factors: the normal force and the coefficient of friction. &lt;br /&gt;
&lt;br /&gt;
In simple terms, the normal force is the equivalent force between objects. For example, when an object of mass &#039;&#039;&#039;M&#039;&#039;&#039; is placed on a table, there is a gravitational force &#039;&#039;&#039;Mg&#039;&#039;&#039; on the table. If the table can support the object without collapsing, the table exerts an equivalent force &#039;&#039;&#039;Mg&#039;&#039;&#039; on the object. According to the momentum principle, since there is no change in momentum, the net force must be &#039;&#039;&#039;0&#039;&#039;&#039;. This is also apparent since there is no movement if the table can support the object.&lt;br /&gt;
&lt;br /&gt;
::&amp;lt;math&amp;gt; {p}_{f} - {p}_{i} = {F}_{net}{dt} = 0 &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
OR&lt;br /&gt;
&lt;br /&gt;
::&amp;lt;math&amp;gt; {F}_{g} = {M}{g} &amp;lt;/math&amp;gt;&lt;br /&gt;
::&amp;lt;math&amp;gt; {F}_{N} = {M}{g} &amp;lt;/math&amp;gt;&lt;br /&gt;
::&amp;lt;math&amp;gt; {F}_{net} = {F}_{g} - {F}_{N} = {0} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
The coefficient of friction is usually specific to each object or material. The coefficient of static friction is denoted by &amp;lt;math&amp;gt;{&amp;amp;mu;}_{s}&amp;lt;/math&amp;gt; and the coefficient of kinetic friction is denoted by &amp;lt;math&amp;gt;{&amp;amp;mu;}_{k}&amp;lt;/math&amp;gt; &lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
===A Mathematical Model===&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
===A Computational Model===&lt;br /&gt;
&lt;br /&gt;
How do we visualize or predict using this topic. Consider embedding some vpython code here [https://trinket.io/glowscript/31d0f9ad9e Teach hands-on with GlowScript]&lt;br /&gt;
&lt;br /&gt;
==Examples==&lt;br /&gt;
&lt;br /&gt;
Be sure to show all steps in your solution and include diagrams whenever possible&lt;br /&gt;
&lt;br /&gt;
===Simple===&lt;br /&gt;
===Middling===&lt;br /&gt;
===Difficult===&lt;br /&gt;
&lt;br /&gt;
==Connectedness==&lt;br /&gt;
#How is this topic connected to something that you are interested in?&lt;br /&gt;
#How is it connected to your major?&lt;br /&gt;
#Is there an interesting industrial application?&lt;br /&gt;
&lt;br /&gt;
==History==&lt;br /&gt;
&lt;br /&gt;
Put this idea in historical context. Give the reader the Who, What, When, Where, and Why.&lt;br /&gt;
&lt;br /&gt;
== See also ==&lt;br /&gt;
&lt;br /&gt;
Are there related topics or categories in this wiki resource for the curious reader to explore?  How does this topic fit into that context?&lt;br /&gt;
&lt;br /&gt;
===Further reading===&lt;br /&gt;
&lt;br /&gt;
Books, Articles or other print media on this topic&lt;br /&gt;
&lt;br /&gt;
===External links===&lt;br /&gt;
&lt;br /&gt;
Internet resources on this topic&lt;br /&gt;
&lt;br /&gt;
==References==&lt;br /&gt;
&lt;br /&gt;
This section contains the the references you used while writing this page&lt;br /&gt;
&lt;br /&gt;
[[Category:Contact Forces]]&lt;/div&gt;</summary>
		<author><name>Drao31</name></author>
	</entry>
	<entry>
		<id>http://www.physicsbook.gatech.edu/index.php?title=Friction&amp;diff=24557</id>
		<title>Friction</title>
		<link rel="alternate" type="text/html" href="http://www.physicsbook.gatech.edu/index.php?title=Friction&amp;diff=24557"/>
		<updated>2016-11-27T03:07:37Z</updated>

		<summary type="html">&lt;p&gt;Drao31: &lt;/p&gt;
&lt;hr /&gt;
&lt;div&gt;This page discusses the concept of friction and how it relates to both moving and static objects.&lt;br /&gt;
&lt;br /&gt;
Claimed by drao31&lt;br /&gt;
&lt;br /&gt;
==The Main Idea==&lt;br /&gt;
Friction is caused by the interactions between the atoms that make up objects. When objects interact, the atoms that make up the objects also interact. Temperatures of interacting surfaces rise because of such interactions. Friction is a force that resists movement. Generally, friction makes it harder to move objects. There are two main types of friction that are covered in Physics 2211: Static Friction and Kinetic Friction. Static friction can be described as the friction acting on resting objects. Kinetic friction is the friction acting on objects in motion. &lt;br /&gt;
&lt;br /&gt;
Frictional forces depend on a few factors: the normal force and the coefficient of friction. &lt;br /&gt;
&lt;br /&gt;
In simple terms, the normal force is the equivalent force between objects. For example, when an object of mass &#039;&#039;&#039;M&#039;&#039;&#039; is placed on a table, there is a gravitational force &#039;&#039;&#039;Mg&#039;&#039;&#039; on the table. If the table can support the object without collapsing, the table exerts an equivalent force &#039;&#039;&#039;Mg&#039;&#039;&#039; on the object. According to the momentum principle, since there is no change in momentum, the net force must be &#039;&#039;&#039;0&#039;&#039;&#039;. This is also apparent since there is no movement if the table can support the object.&lt;br /&gt;
&lt;br /&gt;
::&amp;lt;math&amp;gt; {p}_{f} - {p}_{i} = {F}_{net}{dt} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
::&amp;lt;math&amp;gt; {F}_{g} = {M}{g} &amp;lt;/math&amp;gt;&lt;br /&gt;
::&amp;lt;math&amp;gt; {F}_{N} = {M}{g} &amp;lt;/math&amp;gt;&lt;br /&gt;
::&amp;lt;math&amp;gt; {F}_{net} = {F}_{g} - {F}_{N} = {0} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
The coefficient of friction is usually specific to each object or material. The coefficient of static friction is denoted by &amp;lt;math&amp;gt;{&amp;amp;mu;}_{s}&amp;lt;/math&amp;gt; and the coefficient of kinetic friction is denoted by &amp;lt;math&amp;gt;{&amp;amp;mu;}_{k}&amp;lt;/math&amp;gt; &lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
===A Mathematical Model===&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
===A Computational Model===&lt;br /&gt;
&lt;br /&gt;
How do we visualize or predict using this topic. Consider embedding some vpython code here [https://trinket.io/glowscript/31d0f9ad9e Teach hands-on with GlowScript]&lt;br /&gt;
&lt;br /&gt;
==Examples==&lt;br /&gt;
&lt;br /&gt;
Be sure to show all steps in your solution and include diagrams whenever possible&lt;br /&gt;
&lt;br /&gt;
===Simple===&lt;br /&gt;
===Middling===&lt;br /&gt;
===Difficult===&lt;br /&gt;
&lt;br /&gt;
==Connectedness==&lt;br /&gt;
#How is this topic connected to something that you are interested in?&lt;br /&gt;
#How is it connected to your major?&lt;br /&gt;
#Is there an interesting industrial application?&lt;br /&gt;
&lt;br /&gt;
==History==&lt;br /&gt;
&lt;br /&gt;
Put this idea in historical context. Give the reader the Who, What, When, Where, and Why.&lt;br /&gt;
&lt;br /&gt;
== See also ==&lt;br /&gt;
&lt;br /&gt;
Are there related topics or categories in this wiki resource for the curious reader to explore?  How does this topic fit into that context?&lt;br /&gt;
&lt;br /&gt;
===Further reading===&lt;br /&gt;
&lt;br /&gt;
Books, Articles or other print media on this topic&lt;br /&gt;
&lt;br /&gt;
===External links===&lt;br /&gt;
&lt;br /&gt;
Internet resources on this topic&lt;br /&gt;
&lt;br /&gt;
==References==&lt;br /&gt;
&lt;br /&gt;
This section contains the the references you used while writing this page&lt;br /&gt;
&lt;br /&gt;
[[Category:Contact Forces]]&lt;/div&gt;</summary>
		<author><name>Drao31</name></author>
	</entry>
	<entry>
		<id>http://www.physicsbook.gatech.edu/index.php?title=Friction&amp;diff=24555</id>
		<title>Friction</title>
		<link rel="alternate" type="text/html" href="http://www.physicsbook.gatech.edu/index.php?title=Friction&amp;diff=24555"/>
		<updated>2016-11-27T03:05:53Z</updated>

		<summary type="html">&lt;p&gt;Drao31: &lt;/p&gt;
&lt;hr /&gt;
&lt;div&gt;This page discusses the concept of friction and how it relates to both moving and static objects.&lt;br /&gt;
&lt;br /&gt;
Claimed by drao31&lt;br /&gt;
&lt;br /&gt;
==The Main Idea==&lt;br /&gt;
Friction is caused by the interactions between the atoms that make up objects. When objects interact, the atoms that make up the objects also interact. Temperatures of interacting surfaces rise because of such interactions. Friction is a force that resists movement. Generally, friction makes it harder to move objects. There are two main types of friction that are covered in Physics 2211: Static Friction and Kinetic Friction. Static friction can be described as the friction acting on resting objects. Kinetic friction is the friction acting on objects in motion. &lt;br /&gt;
&lt;br /&gt;
Frictional forces depend on a few factors: the normal force and the coefficient of friction. &lt;br /&gt;
&lt;br /&gt;
In simple terms, the normal force is the equivalent force between objects. For example, when an object of mass &#039;&#039;&#039;M&#039;&#039;&#039; is placed on a table, there is a gravitational force &#039;&#039;&#039;Mg&#039;&#039;&#039; on the table. If the table can support the object without collapsing, the table exerts an equivalent force &#039;&#039;&#039;Mg&#039;&#039;&#039; on the object. According to the momentum principle, since there is no change in momentum, the net force must be &#039;&#039;&#039;0&#039;&#039;&#039;. This is also apparent since there is no movement if the table can support the object.&lt;br /&gt;
&lt;br /&gt;
::&amp;lt;math&amp;gt; {F}_{g} = {M}{g} &amp;lt;/math&amp;gt;&lt;br /&gt;
::&amp;lt;math&amp;gt; {F}_{N} = {M}{g} &amp;lt;/math&amp;gt;&lt;br /&gt;
::&amp;lt;math&amp;gt; {F}_{net} = {F}_{g} - {F}_{N} = {0} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
The coefficient of friction is usually specific to each object or material. The coefficient of static friction is denoted by &amp;lt;math&amp;gt;{&amp;amp;mu;}_{s}&amp;lt;/math&amp;gt; and the coefficient of kinetic friction is denoted by &amp;lt;math&amp;gt;{&amp;amp;mu;}_{k}&amp;lt;/math&amp;gt; &lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
===A Mathematical Model===&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
===A Computational Model===&lt;br /&gt;
&lt;br /&gt;
How do we visualize or predict using this topic. Consider embedding some vpython code here [https://trinket.io/glowscript/31d0f9ad9e Teach hands-on with GlowScript]&lt;br /&gt;
&lt;br /&gt;
==Examples==&lt;br /&gt;
&lt;br /&gt;
Be sure to show all steps in your solution and include diagrams whenever possible&lt;br /&gt;
&lt;br /&gt;
===Simple===&lt;br /&gt;
===Middling===&lt;br /&gt;
===Difficult===&lt;br /&gt;
&lt;br /&gt;
==Connectedness==&lt;br /&gt;
#How is this topic connected to something that you are interested in?&lt;br /&gt;
#How is it connected to your major?&lt;br /&gt;
#Is there an interesting industrial application?&lt;br /&gt;
&lt;br /&gt;
==History==&lt;br /&gt;
&lt;br /&gt;
Put this idea in historical context. Give the reader the Who, What, When, Where, and Why.&lt;br /&gt;
&lt;br /&gt;
== See also ==&lt;br /&gt;
&lt;br /&gt;
Are there related topics or categories in this wiki resource for the curious reader to explore?  How does this topic fit into that context?&lt;br /&gt;
&lt;br /&gt;
===Further reading===&lt;br /&gt;
&lt;br /&gt;
Books, Articles or other print media on this topic&lt;br /&gt;
&lt;br /&gt;
===External links===&lt;br /&gt;
&lt;br /&gt;
Internet resources on this topic&lt;br /&gt;
&lt;br /&gt;
==References==&lt;br /&gt;
&lt;br /&gt;
This section contains the the references you used while writing this page&lt;br /&gt;
&lt;br /&gt;
[[Category:Contact Forces]]&lt;/div&gt;</summary>
		<author><name>Drao31</name></author>
	</entry>
	<entry>
		<id>http://www.physicsbook.gatech.edu/index.php?title=Friction&amp;diff=24553</id>
		<title>Friction</title>
		<link rel="alternate" type="text/html" href="http://www.physicsbook.gatech.edu/index.php?title=Friction&amp;diff=24553"/>
		<updated>2016-11-27T03:04:50Z</updated>

		<summary type="html">&lt;p&gt;Drao31: &lt;/p&gt;
&lt;hr /&gt;
&lt;div&gt;This page discusses the concept of friction and how it relates to both moving and static objects.&lt;br /&gt;
&lt;br /&gt;
Claimed by drao31&lt;br /&gt;
&lt;br /&gt;
==The Main Idea==&lt;br /&gt;
Friction is caused by the interactions between the atoms that make up objects. When objects interact, the atoms that make up the objects also interact. Temperatures of interacting surfaces rise because of such interactions. Friction is a force that resists movement. Generally, friction makes it harder to move objects. There are two main types of friction that are covered in Physics 2211: Static Friction and Kinetic Friction. Static friction can be described as the friction acting on resting objects. Kinetic friction is the friction acting on objects in motion. &lt;br /&gt;
&lt;br /&gt;
Frictional forces depend on a few factors: the normal force and the coefficient of friction. &lt;br /&gt;
&lt;br /&gt;
In simple terms, the normal force is the equivalent force between objects. For example, when an object of mass &#039;&#039;&#039;M&#039;&#039;&#039; is placed on a table, the object exerts a gravitational force &#039;&#039;&#039;Mg&#039;&#039;&#039; on the table. If the table can support the object without collapsing, the table exerts an equivalent force &#039;&#039;&#039;Mg&#039;&#039;&#039; on the object. According to the momentum principle, since there is no change in momentum, the net force must be &#039;&#039;&#039;0&#039;&#039;&#039;. This is also apparent since there is no movement if the table can support the object.&lt;br /&gt;
&lt;br /&gt;
::&amp;lt;math&amp;gt; {F}_{g} = {M}{g} &amp;lt;/math&amp;gt;&lt;br /&gt;
::&amp;lt;math&amp;gt; {F}_{N} = {M}{g} &amp;lt;/math&amp;gt;&lt;br /&gt;
::&amp;lt;math&amp;gt; {F}_{net} = {F}_{g} - {F}_{N} = {0} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
The coefficient of friction is usually specific to each object or material. The coefficient of static friction is denoted by &amp;lt;math&amp;gt;{&amp;amp;mu;}_{s}&amp;lt;/math&amp;gt; and the coefficient of kinetic friction is denoted by &amp;lt;math&amp;gt;{&amp;amp;mu;}_{k}&amp;lt;/math&amp;gt; &lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
===A Mathematical Model===&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
===A Computational Model===&lt;br /&gt;
&lt;br /&gt;
How do we visualize or predict using this topic. Consider embedding some vpython code here [https://trinket.io/glowscript/31d0f9ad9e Teach hands-on with GlowScript]&lt;br /&gt;
&lt;br /&gt;
==Examples==&lt;br /&gt;
&lt;br /&gt;
Be sure to show all steps in your solution and include diagrams whenever possible&lt;br /&gt;
&lt;br /&gt;
===Simple===&lt;br /&gt;
===Middling===&lt;br /&gt;
===Difficult===&lt;br /&gt;
&lt;br /&gt;
==Connectedness==&lt;br /&gt;
#How is this topic connected to something that you are interested in?&lt;br /&gt;
#How is it connected to your major?&lt;br /&gt;
#Is there an interesting industrial application?&lt;br /&gt;
&lt;br /&gt;
==History==&lt;br /&gt;
&lt;br /&gt;
Put this idea in historical context. Give the reader the Who, What, When, Where, and Why.&lt;br /&gt;
&lt;br /&gt;
== See also ==&lt;br /&gt;
&lt;br /&gt;
Are there related topics or categories in this wiki resource for the curious reader to explore?  How does this topic fit into that context?&lt;br /&gt;
&lt;br /&gt;
===Further reading===&lt;br /&gt;
&lt;br /&gt;
Books, Articles or other print media on this topic&lt;br /&gt;
&lt;br /&gt;
===External links===&lt;br /&gt;
&lt;br /&gt;
Internet resources on this topic&lt;br /&gt;
&lt;br /&gt;
==References==&lt;br /&gt;
&lt;br /&gt;
This section contains the the references you used while writing this page&lt;br /&gt;
&lt;br /&gt;
[[Category:Contact Forces]]&lt;/div&gt;</summary>
		<author><name>Drao31</name></author>
	</entry>
	<entry>
		<id>http://www.physicsbook.gatech.edu/index.php?title=Friction&amp;diff=24552</id>
		<title>Friction</title>
		<link rel="alternate" type="text/html" href="http://www.physicsbook.gatech.edu/index.php?title=Friction&amp;diff=24552"/>
		<updated>2016-11-27T03:04:27Z</updated>

		<summary type="html">&lt;p&gt;Drao31: &lt;/p&gt;
&lt;hr /&gt;
&lt;div&gt;This page discusses the concept of friction and how it relates to both moving and static objects.&lt;br /&gt;
&lt;br /&gt;
Claimed by drao31&lt;br /&gt;
&lt;br /&gt;
==The Main Idea==&lt;br /&gt;
Friction is caused by the interactions between the atoms that make up objects. When objects interact, the atoms that make up the objects also interact. Temperatures of interacting surfaces rise because of such interactions. Friction is a force that resists movement. Generally, friction makes it harder to move objects. There are two main types of friction that are covered in Physics 2211: Static Friction and Kinetic Friction. Static friction can be described as the friction acting on resting objects. Kinetic friction is the friction acting on objects in motion. &lt;br /&gt;
&lt;br /&gt;
Frictional forces depend on a few factors: the normal force and the coefficient of friction. &lt;br /&gt;
&lt;br /&gt;
In simple terms, the normal force is the equivalent force between objects. For example, when an object of mass &#039;&#039;&#039;M&#039;&#039;&#039; is placed on a table, the object exerts a gravitational force &#039;&#039;&#039;Mg&#039;&#039;&#039; on the table. If the table can support the object without collapsing, the table exerts an equivalent force &#039;&#039;&#039;Mg&#039;&#039;&#039; on the object. According to the momentum principle, since there is no change in momentum, the net force must be &#039;&#039;&#039;0&#039;&#039;&#039;. This is also apparent since there is no movement if the table can support the object.&lt;br /&gt;
&lt;br /&gt;
::&amp;lt;math&amp;gt; {F}_{g} = {M}{g} &amp;lt;/math&amp;gt;&lt;br /&gt;
::&amp;lt;math&amp;gt; {F}_{N} = {M}{g} &amp;lt;/math&amp;gt;&lt;br /&gt;
::&amp;lt;math&amp;gt; {F}_{net} = {F}_{g} - {F}_{N} = {0} &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
The coefficient of friction is usually specific to each object or material. The coefficient of static friction is denoted by ::&amp;lt;math&amp;gt;{&amp;amp;mu;}_{s}&amp;lt;/math&amp;gt; and the coefficient of kinetic friction is denoted by ::&amp;lt;math&amp;gt;{&amp;amp;mu;}_{k}&amp;lt;/math&amp;gt; &lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
===A Mathematical Model===&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
===A Computational Model===&lt;br /&gt;
&lt;br /&gt;
How do we visualize or predict using this topic. Consider embedding some vpython code here [https://trinket.io/glowscript/31d0f9ad9e Teach hands-on with GlowScript]&lt;br /&gt;
&lt;br /&gt;
==Examples==&lt;br /&gt;
&lt;br /&gt;
Be sure to show all steps in your solution and include diagrams whenever possible&lt;br /&gt;
&lt;br /&gt;
===Simple===&lt;br /&gt;
===Middling===&lt;br /&gt;
===Difficult===&lt;br /&gt;
&lt;br /&gt;
==Connectedness==&lt;br /&gt;
#How is this topic connected to something that you are interested in?&lt;br /&gt;
#How is it connected to your major?&lt;br /&gt;
#Is there an interesting industrial application?&lt;br /&gt;
&lt;br /&gt;
==History==&lt;br /&gt;
&lt;br /&gt;
Put this idea in historical context. Give the reader the Who, What, When, Where, and Why.&lt;br /&gt;
&lt;br /&gt;
== See also ==&lt;br /&gt;
&lt;br /&gt;
Are there related topics or categories in this wiki resource for the curious reader to explore?  How does this topic fit into that context?&lt;br /&gt;
&lt;br /&gt;
===Further reading===&lt;br /&gt;
&lt;br /&gt;
Books, Articles or other print media on this topic&lt;br /&gt;
&lt;br /&gt;
===External links===&lt;br /&gt;
&lt;br /&gt;
Internet resources on this topic&lt;br /&gt;
&lt;br /&gt;
==References==&lt;br /&gt;
&lt;br /&gt;
This section contains the the references you used while writing this page&lt;br /&gt;
&lt;br /&gt;
[[Category:Contact Forces]]&lt;/div&gt;</summary>
		<author><name>Drao31</name></author>
	</entry>
	<entry>
		<id>http://www.physicsbook.gatech.edu/index.php?title=Friction&amp;diff=24549</id>
		<title>Friction</title>
		<link rel="alternate" type="text/html" href="http://www.physicsbook.gatech.edu/index.php?title=Friction&amp;diff=24549"/>
		<updated>2016-11-27T02:46:14Z</updated>

		<summary type="html">&lt;p&gt;Drao31: &lt;/p&gt;
&lt;hr /&gt;
&lt;div&gt;This page discusses the concept of friction and how it relates to both moving and static objects.&lt;br /&gt;
&lt;br /&gt;
Claimed by drao31&lt;br /&gt;
&lt;br /&gt;
==The Main Idea==&lt;br /&gt;
Friction is caused by the interactions between the atoms that make up objects. When objects interact, the atoms that make up the objects also interact. Temperatures of interacting surfaces rise because of such interactions. Friction is a force that resists movement. Generally, friction makes it harder to move objects. There are two main types of friction that are covered in Physics 2211: Static Friction and Kinetic Friction. Static friction can be described as the friction acting on resting objects. Kinetic friction is the friction acting on objects in motion.&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
===A Mathematical Model===&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
===A Computational Model===&lt;br /&gt;
&lt;br /&gt;
How do we visualize or predict using this topic. Consider embedding some vpython code here [https://trinket.io/glowscript/31d0f9ad9e Teach hands-on with GlowScript]&lt;br /&gt;
&lt;br /&gt;
==Examples==&lt;br /&gt;
&lt;br /&gt;
Be sure to show all steps in your solution and include diagrams whenever possible&lt;br /&gt;
&lt;br /&gt;
===Simple===&lt;br /&gt;
===Middling===&lt;br /&gt;
===Difficult===&lt;br /&gt;
&lt;br /&gt;
==Connectedness==&lt;br /&gt;
#How is this topic connected to something that you are interested in?&lt;br /&gt;
#How is it connected to your major?&lt;br /&gt;
#Is there an interesting industrial application?&lt;br /&gt;
&lt;br /&gt;
==History==&lt;br /&gt;
&lt;br /&gt;
Put this idea in historical context. Give the reader the Who, What, When, Where, and Why.&lt;br /&gt;
&lt;br /&gt;
== See also ==&lt;br /&gt;
&lt;br /&gt;
Are there related topics or categories in this wiki resource for the curious reader to explore?  How does this topic fit into that context?&lt;br /&gt;
&lt;br /&gt;
===Further reading===&lt;br /&gt;
&lt;br /&gt;
Books, Articles or other print media on this topic&lt;br /&gt;
&lt;br /&gt;
===External links===&lt;br /&gt;
&lt;br /&gt;
Internet resources on this topic&lt;br /&gt;
&lt;br /&gt;
==References==&lt;br /&gt;
&lt;br /&gt;
This section contains the the references you used while writing this page&lt;br /&gt;
&lt;br /&gt;
[[Category:Contact Forces]]&lt;/div&gt;</summary>
		<author><name>Drao31</name></author>
	</entry>
	<entry>
		<id>http://www.physicsbook.gatech.edu/index.php?title=Friction&amp;diff=24542</id>
		<title>Friction</title>
		<link rel="alternate" type="text/html" href="http://www.physicsbook.gatech.edu/index.php?title=Friction&amp;diff=24542"/>
		<updated>2016-11-27T02:32:49Z</updated>

		<summary type="html">&lt;p&gt;Drao31: &lt;/p&gt;
&lt;hr /&gt;
&lt;div&gt;This page discusses the concept of friction and how it relates to both moving and static objects.&lt;br /&gt;
&lt;br /&gt;
Claimed by drao31&lt;br /&gt;
&lt;br /&gt;
==The Main Idea==&lt;br /&gt;
&lt;br /&gt;
===A Mathematical Model===&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
===A Computational Model===&lt;br /&gt;
&lt;br /&gt;
How do we visualize or predict using this topic. Consider embedding some vpython code here [https://trinket.io/glowscript/31d0f9ad9e Teach hands-on with GlowScript]&lt;br /&gt;
&lt;br /&gt;
==Examples==&lt;br /&gt;
&lt;br /&gt;
Be sure to show all steps in your solution and include diagrams whenever possible&lt;br /&gt;
&lt;br /&gt;
===Simple===&lt;br /&gt;
===Middling===&lt;br /&gt;
===Difficult===&lt;br /&gt;
&lt;br /&gt;
==Connectedness==&lt;br /&gt;
#How is this topic connected to something that you are interested in?&lt;br /&gt;
#How is it connected to your major?&lt;br /&gt;
#Is there an interesting industrial application?&lt;br /&gt;
&lt;br /&gt;
==History==&lt;br /&gt;
&lt;br /&gt;
Put this idea in historical context. Give the reader the Who, What, When, Where, and Why.&lt;br /&gt;
&lt;br /&gt;
== See also ==&lt;br /&gt;
&lt;br /&gt;
Are there related topics or categories in this wiki resource for the curious reader to explore?  How does this topic fit into that context?&lt;br /&gt;
&lt;br /&gt;
===Further reading===&lt;br /&gt;
&lt;br /&gt;
Books, Articles or other print media on this topic&lt;br /&gt;
&lt;br /&gt;
===External links===&lt;br /&gt;
&lt;br /&gt;
Internet resources on this topic&lt;br /&gt;
&lt;br /&gt;
==References==&lt;br /&gt;
&lt;br /&gt;
This section contains the the references you used while writing this page&lt;br /&gt;
&lt;br /&gt;
[[Category:Contact Forces]]&lt;/div&gt;</summary>
		<author><name>Drao31</name></author>
	</entry>
	<entry>
		<id>http://www.physicsbook.gatech.edu/index.php?title=Rotational_Kinematics&amp;diff=24539</id>
		<title>Rotational Kinematics</title>
		<link rel="alternate" type="text/html" href="http://www.physicsbook.gatech.edu/index.php?title=Rotational_Kinematics&amp;diff=24539"/>
		<updated>2016-11-27T02:28:02Z</updated>

		<summary type="html">&lt;p&gt;Drao31: &lt;/p&gt;
&lt;hr /&gt;
&lt;div&gt;drao31&lt;br /&gt;
==The Main Idea==&lt;br /&gt;
&lt;br /&gt;
Rotational motion is defined as an object moving around an axis in contrast to translational motion which involves the object moving in a straight trajectory.  &lt;br /&gt;
&lt;br /&gt;
===A Mathematical Model===&lt;br /&gt;
&lt;br /&gt;
Rotation can be characterized by its angular velocity and angular acceleration. The equations are listed below.&lt;br /&gt;
&lt;br /&gt;
Angular velocity:&lt;br /&gt;
&lt;br /&gt;
:&amp;lt;math&amp;gt;\boldsymbol{{w}} = \frac{\boldsymbol{v}}{\boldsymbol{r}}&amp;lt;/math&amp;gt; , &lt;br /&gt;
where &amp;lt;math&amp;gt;{\boldsymbol{v}}&amp;lt;/math&amp;gt; is the velocity of the object and &amp;lt;math&amp;gt;{\boldsymbol{r}}&amp;lt;/math&amp;gt; is the radius of the circle of motion. It can also be represented as the change in angle over the distance traveled in the formula shown below:&lt;br /&gt;
&lt;br /&gt;
:&amp;lt;math&amp;gt;\boldsymbol{{w}} = \frac{\boldsymbol{d\theta}}{\boldsymbol{dt}}&amp;lt;/math&amp;gt; , where &amp;lt;math&amp;gt;{\boldsymbol{d\theta}}&amp;lt;/math&amp;gt; is the change in angle and &amp;lt;math&amp;gt;{\boldsymbol{dt}}&amp;lt;/math&amp;gt; is the change in time. &lt;br /&gt;
&lt;br /&gt;
[[File:angularvelocity.png]]&lt;br /&gt;
&lt;br /&gt;
 Angular velocity always has a unit of radians (radians/sec or radians/hr). &lt;br /&gt;
&lt;br /&gt;
Angular acceleration is equal to alpha:&lt;br /&gt;
&lt;br /&gt;
:&amp;lt;math&amp;gt;\boldsymbol{{\alpha}} = \frac{\boldsymbol{a_t}}{\boldsymbol{r}}&amp;lt;/math&amp;gt; , &lt;br /&gt;
where &amp;lt;math&amp;gt;{\boldsymbol{a_t}}&amp;lt;/math&amp;gt; is the tangential acceleration of the object and &amp;lt;math&amp;gt;{\boldsymbol{r}}&amp;lt;/math&amp;gt; is the radius of the circle of motion.&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
Rotational Kinetic Energy:&lt;br /&gt;
An object with a center of mass at rest can still have rotational kinetic energy. For example, if a disk is suspended in the air and spun, it has no translational kinetic energy. The position of the disk does not change. However, since it is spinning (rotating), it still has kinetic energy. To account for this, we can relate angular velocity with the moment of inertia of the object to find a value for the rotational kinetic energy.&lt;br /&gt;
&lt;br /&gt;
Rotational Kinetic Energy:&lt;br /&gt;
&lt;br /&gt;
::&amp;lt;math&amp;gt;{KE}_{rot} = \frac{{1}}{{2}}{I}_{cm}{&amp;amp;omega;^2}&amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
Relation to Work and Energy Principle:&lt;br /&gt;
&lt;br /&gt;
The energy principle states:&lt;br /&gt;
::&amp;lt;math&amp;gt;{E}_{f} = {E}_{i} + W &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
We can apply the energy principle to rotational kinetic energy as well to find changes in kinetic energy and work done on the system.&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
===A Computational Model===&lt;br /&gt;
&lt;br /&gt;
==Examples==&lt;br /&gt;
&lt;br /&gt;
Be sure to show all steps in your solution and include diagrams whenever possible&lt;br /&gt;
&lt;br /&gt;
===Simple===&lt;br /&gt;
&lt;br /&gt;
A simple example and application of the concept of rotation is the earth&#039;s rotation on it&#039;s axis. It rotates once every 24 hours. What is the angular velocity?&lt;br /&gt;
&lt;br /&gt;
:&amp;lt;math&amp;gt;\boldsymbol{{w}} = \frac{\boldsymbol{d\theta}}{\boldsymbol{dt}}&amp;lt;/math&amp;gt;&lt;br /&gt;
:&amp;lt;math&amp;gt;\boldsymbol{{w}} = \frac{\boldsymbol{2\pi}}{\boldsymbol{24}}&amp;lt;/math&amp;gt;&lt;br /&gt;
:&amp;lt;math&amp;gt;\boldsymbol{{w}} = \frac{\boldsymbol{\pi}}{\boldsymbol{12}}&amp;lt;/math&amp;gt;&lt;br /&gt;
:&amp;lt;math&amp;gt;\boldsymbol{{w}} = \frac{\boldsymbol{\pi}}{\boldsymbol{12}}*\frac{\boldsymbol{180}}{\boldsymbol{\pi}}&amp;lt;/math&amp;gt;&lt;br /&gt;
:&amp;lt;math&amp;gt;\boldsymbol{{w}} = {\boldsymbol{15 degrees}}&amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
Angular velocity can also be represented as change in angle (theta) over change in time. In this case, the earth rotates 2pi radians in 24 hours which reduces to pi/12 radians and that becomes 15 degrees.&lt;br /&gt;
&lt;br /&gt;
===Middling===&lt;br /&gt;
&lt;br /&gt;
A cylinder with a 2.5 ft radius is rotating at 120 rpm. Find the angular velocity in rad/sec and in degrees/sec. Find the linear velocity of a point on its rim in mph.&lt;br /&gt;
&lt;br /&gt;
To find the solution of this problem, rpm (revolutions per minute) should be converted to radians/second. Following this, the linear velocity can be calculated by using the v=wr formula shown above. The angular velocity is 720 degrees per sec and the linear velocity is 21.42 mph.&lt;br /&gt;
&lt;br /&gt;
Details of Explanation:&lt;br /&gt;
&lt;br /&gt;
[[File:MiddlePrb.jpg]]&lt;br /&gt;
&lt;br /&gt;
===Difficult===&lt;br /&gt;
&lt;br /&gt;
A tire with a 9 inch radius is rotating at 30 mph. Find the angular velocity at a point on its rim. Also express the result in revolutions per minute.&lt;br /&gt;
&lt;br /&gt;
[[File:Difficultprb.jpg]]&lt;br /&gt;
&lt;br /&gt;
==Connectedness==&lt;br /&gt;
Rotation is an extremely important aspect of dynamics (the study of moving objects) which plays a big role in biomechanics. Rotation relates to several important body parts such as the shoulder where there are two axis of rotation, the medial-lateral axis and the anterior-posterior axis. A study of the movement of the shoulder helps to treat medical conditions that may affect this area. Dynamics is also very important in many other disciples, including mechanical engineering and aerospace engineering.&lt;br /&gt;
&lt;br /&gt;
== See also ==&lt;br /&gt;
&lt;br /&gt;
To learn more about Rotation in a more complete context, please refer to Torque or Rigid-Body Objects or Angular Momentum.&lt;br /&gt;
&lt;br /&gt;
===Further reading===&lt;br /&gt;
&lt;br /&gt;
Books, Articles or other print media on this topic&lt;br /&gt;
&lt;br /&gt;
===External links===&lt;br /&gt;
&lt;br /&gt;
Some other resources to further understand rotation are the following:&lt;br /&gt;
&lt;br /&gt;
http://www.mathwarehouse.com/transformations/rotations-in-math.php&lt;br /&gt;
&lt;br /&gt;
http://demonstrations.wolfram.com/Understanding3DRotation/&lt;br /&gt;
&lt;br /&gt;
==References==&lt;br /&gt;
&lt;br /&gt;
[1] Biomechanics, Basic. &amp;lt;i&amp;gt;“It Is Important When Learning about&amp;lt;/i&amp;gt; (n.d.): n. pag. Web.&lt;br /&gt;
&lt;br /&gt;
[2] &amp;quot;Angular Velocity and Angular Acceleration.&amp;quot; Van Nostrand&#039;s Scientific Encyclopedia (2005): n. pag. Web&lt;/div&gt;</summary>
		<author><name>Drao31</name></author>
	</entry>
	<entry>
		<id>http://www.physicsbook.gatech.edu/index.php?title=Rotational_Kinematics&amp;diff=24538</id>
		<title>Rotational Kinematics</title>
		<link rel="alternate" type="text/html" href="http://www.physicsbook.gatech.edu/index.php?title=Rotational_Kinematics&amp;diff=24538"/>
		<updated>2016-11-27T02:27:01Z</updated>

		<summary type="html">&lt;p&gt;Drao31: &lt;/p&gt;
&lt;hr /&gt;
&lt;div&gt;&lt;br /&gt;
==The Main Idea==&lt;br /&gt;
&lt;br /&gt;
Rotational motion is defined as an object moving around an axis in contrast to translational motion which involves the object moving in a straight trajectory.  &lt;br /&gt;
&lt;br /&gt;
===A Mathematical Model===&lt;br /&gt;
&lt;br /&gt;
Rotation can be characterized by its angular velocity and angular acceleration. The equations are listed below.&lt;br /&gt;
&lt;br /&gt;
Angular velocity:&lt;br /&gt;
&lt;br /&gt;
:&amp;lt;math&amp;gt;\boldsymbol{{w}} = \frac{\boldsymbol{v}}{\boldsymbol{r}}&amp;lt;/math&amp;gt; , &lt;br /&gt;
where &amp;lt;math&amp;gt;{\boldsymbol{v}}&amp;lt;/math&amp;gt; is the velocity of the object and &amp;lt;math&amp;gt;{\boldsymbol{r}}&amp;lt;/math&amp;gt; is the radius of the circle of motion. It can also be represented as the change in angle over the distance traveled in the formula shown below:&lt;br /&gt;
&lt;br /&gt;
:&amp;lt;math&amp;gt;\boldsymbol{{w}} = \frac{\boldsymbol{d\theta}}{\boldsymbol{dt}}&amp;lt;/math&amp;gt; , where &amp;lt;math&amp;gt;{\boldsymbol{d\theta}}&amp;lt;/math&amp;gt; is the change in angle and &amp;lt;math&amp;gt;{\boldsymbol{dt}}&amp;lt;/math&amp;gt; is the change in time. &lt;br /&gt;
&lt;br /&gt;
[[File:angularvelocity.png]]&lt;br /&gt;
&lt;br /&gt;
 Angular velocity always has a unit of radians (radians/sec or radians/hr). &lt;br /&gt;
&lt;br /&gt;
Angular acceleration is equal to alpha:&lt;br /&gt;
&lt;br /&gt;
:&amp;lt;math&amp;gt;\boldsymbol{{\alpha}} = \frac{\boldsymbol{a_t}}{\boldsymbol{r}}&amp;lt;/math&amp;gt; , &lt;br /&gt;
where &amp;lt;math&amp;gt;{\boldsymbol{a_t}}&amp;lt;/math&amp;gt; is the tangential acceleration of the object and &amp;lt;math&amp;gt;{\boldsymbol{r}}&amp;lt;/math&amp;gt; is the radius of the circle of motion.&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
Rotational Kinetic Energy:&lt;br /&gt;
An object with a center of mass at rest can still have rotational kinetic energy. For example, if a disk is suspended in the air and spun, it has no translational kinetic energy. The position of the disk does not change. However, since it is spinning (rotating), it still has kinetic energy. To account for this, we can relate angular velocity with the moment of inertia of the object to find a value for the rotational kinetic energy.&lt;br /&gt;
&lt;br /&gt;
Rotational Kinetic Energy:&lt;br /&gt;
&lt;br /&gt;
::&amp;lt;math&amp;gt;{KE}_{rot} = \frac{{1}}{{2}}{I}_{cm}{&amp;amp;omega;^2}&amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
Relation to Work and Energy Principle:&lt;br /&gt;
&lt;br /&gt;
The energy principle states:&lt;br /&gt;
::&amp;lt;math&amp;gt;{E}_{f} = {E}_{i} + W &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
We can apply the energy principle to rotational kinetic energy as well to find changes in kinetic energy and work done on the system.&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
===A Computational Model===&lt;br /&gt;
&lt;br /&gt;
==Examples==&lt;br /&gt;
&lt;br /&gt;
Be sure to show all steps in your solution and include diagrams whenever possible&lt;br /&gt;
&lt;br /&gt;
===Simple===&lt;br /&gt;
&lt;br /&gt;
A simple example and application of the concept of rotation is the earth&#039;s rotation on it&#039;s axis. It rotates once every 24 hours. What is the angular velocity?&lt;br /&gt;
&lt;br /&gt;
:&amp;lt;math&amp;gt;\boldsymbol{{w}} = \frac{\boldsymbol{d\theta}}{\boldsymbol{dt}}&amp;lt;/math&amp;gt;&lt;br /&gt;
:&amp;lt;math&amp;gt;\boldsymbol{{w}} = \frac{\boldsymbol{2\pi}}{\boldsymbol{24}}&amp;lt;/math&amp;gt;&lt;br /&gt;
:&amp;lt;math&amp;gt;\boldsymbol{{w}} = \frac{\boldsymbol{\pi}}{\boldsymbol{12}}&amp;lt;/math&amp;gt;&lt;br /&gt;
:&amp;lt;math&amp;gt;\boldsymbol{{w}} = \frac{\boldsymbol{\pi}}{\boldsymbol{12}}*\frac{\boldsymbol{180}}{\boldsymbol{\pi}}&amp;lt;/math&amp;gt;&lt;br /&gt;
:&amp;lt;math&amp;gt;\boldsymbol{{w}} = {\boldsymbol{15 degrees}}&amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
Angular velocity can also be represented as change in angle (theta) over change in time. In this case, the earth rotates 2pi radians in 24 hours which reduces to pi/12 radians and that becomes 15 degrees.&lt;br /&gt;
&lt;br /&gt;
===Middling===&lt;br /&gt;
&lt;br /&gt;
A cylinder with a 2.5 ft radius is rotating at 120 rpm. Find the angular velocity in rad/sec and in degrees/sec. Find the linear velocity of a point on its rim in mph.&lt;br /&gt;
&lt;br /&gt;
To find the solution of this problem, rpm (revolutions per minute) should be converted to radians/second. Following this, the linear velocity can be calculated by using the v=wr formula shown above. The angular velocity is 720 degrees per sec and the linear velocity is 21.42 mph.&lt;br /&gt;
&lt;br /&gt;
Details of Explanation:&lt;br /&gt;
&lt;br /&gt;
[[File:MiddlePrb.jpg]]&lt;br /&gt;
&lt;br /&gt;
===Difficult===&lt;br /&gt;
&lt;br /&gt;
A tire with a 9 inch radius is rotating at 30 mph. Find the angular velocity at a point on its rim. Also express the result in revolutions per minute.&lt;br /&gt;
&lt;br /&gt;
[[File:Difficultprb.jpg]]&lt;br /&gt;
&lt;br /&gt;
==Connectedness==&lt;br /&gt;
Rotation is an extremely important aspect of dynamics (the study of moving objects) which plays a big role in biomechanics. Rotation relates to several important body parts such as the shoulder where there are two axis of rotation, the medial-lateral axis and the anterior-posterior axis. A study of the movement of the shoulder helps to treat medical conditions that may affect this area. Dynamics is also very important in many other disciples, including mechanical engineering and aerospace engineering.&lt;br /&gt;
&lt;br /&gt;
== See also ==&lt;br /&gt;
&lt;br /&gt;
To learn more about Rotation in a more complete context, please refer to Torque or Rigid-Body Objects or Angular Momentum.&lt;br /&gt;
&lt;br /&gt;
===Further reading===&lt;br /&gt;
&lt;br /&gt;
Books, Articles or other print media on this topic&lt;br /&gt;
&lt;br /&gt;
===External links===&lt;br /&gt;
&lt;br /&gt;
Some other resources to further understand rotation are the following:&lt;br /&gt;
&lt;br /&gt;
http://www.mathwarehouse.com/transformations/rotations-in-math.php&lt;br /&gt;
&lt;br /&gt;
http://demonstrations.wolfram.com/Understanding3DRotation/&lt;br /&gt;
&lt;br /&gt;
==References==&lt;br /&gt;
&lt;br /&gt;
[1] Biomechanics, Basic. &amp;lt;i&amp;gt;“It Is Important When Learning about&amp;lt;/i&amp;gt; (n.d.): n. pag. Web.&lt;br /&gt;
&lt;br /&gt;
[2] &amp;quot;Angular Velocity and Angular Acceleration.&amp;quot; Van Nostrand&#039;s Scientific Encyclopedia (2005): n. pag. Web&lt;/div&gt;</summary>
		<author><name>Drao31</name></author>
	</entry>
	<entry>
		<id>http://www.physicsbook.gatech.edu/index.php?title=Rotational_Kinematics&amp;diff=24537</id>
		<title>Rotational Kinematics</title>
		<link rel="alternate" type="text/html" href="http://www.physicsbook.gatech.edu/index.php?title=Rotational_Kinematics&amp;diff=24537"/>
		<updated>2016-11-27T02:26:47Z</updated>

		<summary type="html">&lt;p&gt;Drao31: &lt;/p&gt;
&lt;hr /&gt;
&lt;div&gt;by Sthevuthasan3&lt;br /&gt;
==The Main Idea==&lt;br /&gt;
&lt;br /&gt;
Rotational motion is defined as an object moving around an axis in contrast to translational motion which involves the object moving in a straight trajectory.  &lt;br /&gt;
&lt;br /&gt;
===A Mathematical Model===&lt;br /&gt;
&lt;br /&gt;
Rotation can be characterized by its angular velocity and angular acceleration. The equations are listed below.&lt;br /&gt;
&lt;br /&gt;
Angular velocity:&lt;br /&gt;
&lt;br /&gt;
:&amp;lt;math&amp;gt;\boldsymbol{{w}} = \frac{\boldsymbol{v}}{\boldsymbol{r}}&amp;lt;/math&amp;gt; , &lt;br /&gt;
where &amp;lt;math&amp;gt;{\boldsymbol{v}}&amp;lt;/math&amp;gt; is the velocity of the object and &amp;lt;math&amp;gt;{\boldsymbol{r}}&amp;lt;/math&amp;gt; is the radius of the circle of motion. It can also be represented as the change in angle over the distance traveled in the formula shown below:&lt;br /&gt;
&lt;br /&gt;
:&amp;lt;math&amp;gt;\boldsymbol{{w}} = \frac{\boldsymbol{d\theta}}{\boldsymbol{dt}}&amp;lt;/math&amp;gt; , where &amp;lt;math&amp;gt;{\boldsymbol{d\theta}}&amp;lt;/math&amp;gt; is the change in angle and &amp;lt;math&amp;gt;{\boldsymbol{dt}}&amp;lt;/math&amp;gt; is the change in time. &lt;br /&gt;
&lt;br /&gt;
[[File:angularvelocity.png]]&lt;br /&gt;
&lt;br /&gt;
 Angular velocity always has a unit of radians (radians/sec or radians/hr). &lt;br /&gt;
&lt;br /&gt;
Angular acceleration is equal to alpha:&lt;br /&gt;
&lt;br /&gt;
:&amp;lt;math&amp;gt;\boldsymbol{{\alpha}} = \frac{\boldsymbol{a_t}}{\boldsymbol{r}}&amp;lt;/math&amp;gt; , &lt;br /&gt;
where &amp;lt;math&amp;gt;{\boldsymbol{a_t}}&amp;lt;/math&amp;gt; is the tangential acceleration of the object and &amp;lt;math&amp;gt;{\boldsymbol{r}}&amp;lt;/math&amp;gt; is the radius of the circle of motion.&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
Rotational Kinetic Energy:&lt;br /&gt;
An object with a center of mass at rest can still have rotational kinetic energy. For example, if a disk is suspended in the air and spun, it has no translational kinetic energy. The position of the disk does not change. However, since it is spinning (rotating), it still has kinetic energy. To account for this, we can relate angular velocity with the moment of inertia of the object to find a value for the rotational kinetic energy.&lt;br /&gt;
&lt;br /&gt;
Rotational Kinetic Energy:&lt;br /&gt;
&lt;br /&gt;
::&amp;lt;math&amp;gt;{KE}_{rot} = \frac{{1}}{{2}}{I}_{cm}{&amp;amp;omega;^2}&amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
Relation to Work and Energy Principle:&lt;br /&gt;
&lt;br /&gt;
The energy principle states:&lt;br /&gt;
::&amp;lt;math&amp;gt;{E}_{f} = {E}_{i} + W &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
We can apply the energy principle to rotational kinetic energy as well to find changes in kinetic energy and work done on the system.&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
===A Computational Model===&lt;br /&gt;
&lt;br /&gt;
==Examples==&lt;br /&gt;
&lt;br /&gt;
Be sure to show all steps in your solution and include diagrams whenever possible&lt;br /&gt;
&lt;br /&gt;
===Simple===&lt;br /&gt;
&lt;br /&gt;
A simple example and application of the concept of rotation is the earth&#039;s rotation on it&#039;s axis. It rotates once every 24 hours. What is the angular velocity?&lt;br /&gt;
&lt;br /&gt;
:&amp;lt;math&amp;gt;\boldsymbol{{w}} = \frac{\boldsymbol{d\theta}}{\boldsymbol{dt}}&amp;lt;/math&amp;gt;&lt;br /&gt;
:&amp;lt;math&amp;gt;\boldsymbol{{w}} = \frac{\boldsymbol{2\pi}}{\boldsymbol{24}}&amp;lt;/math&amp;gt;&lt;br /&gt;
:&amp;lt;math&amp;gt;\boldsymbol{{w}} = \frac{\boldsymbol{\pi}}{\boldsymbol{12}}&amp;lt;/math&amp;gt;&lt;br /&gt;
:&amp;lt;math&amp;gt;\boldsymbol{{w}} = \frac{\boldsymbol{\pi}}{\boldsymbol{12}}*\frac{\boldsymbol{180}}{\boldsymbol{\pi}}&amp;lt;/math&amp;gt;&lt;br /&gt;
:&amp;lt;math&amp;gt;\boldsymbol{{w}} = {\boldsymbol{15 degrees}}&amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
Angular velocity can also be represented as change in angle (theta) over change in time. In this case, the earth rotates 2pi radians in 24 hours which reduces to pi/12 radians and that becomes 15 degrees.&lt;br /&gt;
&lt;br /&gt;
===Middling===&lt;br /&gt;
&lt;br /&gt;
A cylinder with a 2.5 ft radius is rotating at 120 rpm. Find the angular velocity in rad/sec and in degrees/sec. Find the linear velocity of a point on its rim in mph.&lt;br /&gt;
&lt;br /&gt;
To find the solution of this problem, rpm (revolutions per minute) should be converted to radians/second. Following this, the linear velocity can be calculated by using the v=wr formula shown above. The angular velocity is 720 degrees per sec and the linear velocity is 21.42 mph.&lt;br /&gt;
&lt;br /&gt;
Details of Explanation:&lt;br /&gt;
&lt;br /&gt;
[[File:MiddlePrb.jpg]]&lt;br /&gt;
&lt;br /&gt;
===Difficult===&lt;br /&gt;
&lt;br /&gt;
A tire with a 9 inch radius is rotating at 30 mph. Find the angular velocity at a point on its rim. Also express the result in revolutions per minute.&lt;br /&gt;
&lt;br /&gt;
[[File:Difficultprb.jpg]]&lt;br /&gt;
&lt;br /&gt;
==Connectedness==&lt;br /&gt;
Rotation is an extremely important aspect of dynamics (the study of moving objects) which plays a big role in biomechanics. Rotation relates to several important body parts such as the shoulder where there are two axis of rotation, the medial-lateral axis and the anterior-posterior axis. A study of the movement of the shoulder helps to treat medical conditions that may affect this area. Dynamics is also very important in many other disciples, including mechanical engineering and aerospace engineering.&lt;br /&gt;
&lt;br /&gt;
== See also ==&lt;br /&gt;
&lt;br /&gt;
To learn more about Rotation in a more complete context, please refer to Torque or Rigid-Body Objects or Angular Momentum.&lt;br /&gt;
&lt;br /&gt;
===Further reading===&lt;br /&gt;
&lt;br /&gt;
Books, Articles or other print media on this topic&lt;br /&gt;
&lt;br /&gt;
===External links===&lt;br /&gt;
&lt;br /&gt;
Some other resources to further understand rotation are the following:&lt;br /&gt;
&lt;br /&gt;
http://www.mathwarehouse.com/transformations/rotations-in-math.php&lt;br /&gt;
&lt;br /&gt;
http://demonstrations.wolfram.com/Understanding3DRotation/&lt;br /&gt;
&lt;br /&gt;
==References==&lt;br /&gt;
&lt;br /&gt;
[1] Biomechanics, Basic. &amp;lt;i&amp;gt;“It Is Important When Learning about&amp;lt;/i&amp;gt; (n.d.): n. pag. Web.&lt;br /&gt;
&lt;br /&gt;
[2] &amp;quot;Angular Velocity and Angular Acceleration.&amp;quot; Van Nostrand&#039;s Scientific Encyclopedia (2005): n. pag. Web&lt;/div&gt;</summary>
		<author><name>Drao31</name></author>
	</entry>
	<entry>
		<id>http://www.physicsbook.gatech.edu/index.php?title=Rotational_Kinematics&amp;diff=24529</id>
		<title>Rotational Kinematics</title>
		<link rel="alternate" type="text/html" href="http://www.physicsbook.gatech.edu/index.php?title=Rotational_Kinematics&amp;diff=24529"/>
		<updated>2016-11-27T02:21:58Z</updated>

		<summary type="html">&lt;p&gt;Drao31: &lt;/p&gt;
&lt;hr /&gt;
&lt;div&gt;Claimed by drao31 10/2016&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
==The Main Idea==&lt;br /&gt;
&lt;br /&gt;
Rotational motion is defined as an object moving around an axis in contrast to translational motion which involves the object moving in a straight trajectory.  &lt;br /&gt;
&lt;br /&gt;
===A Mathematical Model===&lt;br /&gt;
&lt;br /&gt;
Rotation can be characterized by its angular velocity and angular acceleration. The equations are listed below.&lt;br /&gt;
&lt;br /&gt;
Angular velocity:&lt;br /&gt;
&lt;br /&gt;
:&amp;lt;math&amp;gt;\boldsymbol{{w}} = \frac{\boldsymbol{v}}{\boldsymbol{r}}&amp;lt;/math&amp;gt; , &lt;br /&gt;
where &amp;lt;math&amp;gt;{\boldsymbol{v}}&amp;lt;/math&amp;gt; is the velocity of the object and &amp;lt;math&amp;gt;{\boldsymbol{r}}&amp;lt;/math&amp;gt; is the radius of the circle of motion. It can also be represented as the change in angle over the distance traveled in the formula shown below:&lt;br /&gt;
&lt;br /&gt;
:&amp;lt;math&amp;gt;\boldsymbol{{w}} = \frac{\boldsymbol{d\theta}}{\boldsymbol{dt}}&amp;lt;/math&amp;gt; , where &amp;lt;math&amp;gt;{\boldsymbol{d\theta}}&amp;lt;/math&amp;gt; is the change in angle and &amp;lt;math&amp;gt;{\boldsymbol{dt}}&amp;lt;/math&amp;gt; is the change in time. &lt;br /&gt;
&lt;br /&gt;
[[File:angularvelocity.png]]&lt;br /&gt;
&lt;br /&gt;
 Angular velocity always has a unit of radians (radians/sec or radians/hr). &lt;br /&gt;
&lt;br /&gt;
Angular acceleration is equal to alpha:&lt;br /&gt;
&lt;br /&gt;
:&amp;lt;math&amp;gt;\boldsymbol{{\alpha}} = \frac{\boldsymbol{a_t}}{\boldsymbol{r}}&amp;lt;/math&amp;gt; , &lt;br /&gt;
where &amp;lt;math&amp;gt;{\boldsymbol{a_t}}&amp;lt;/math&amp;gt; is the tangential acceleration of the object and &amp;lt;math&amp;gt;{\boldsymbol{r}}&amp;lt;/math&amp;gt; is the radius of the circle of motion.&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
Rotational Kinetic Energy:&lt;br /&gt;
An object with a center of mass at rest can still have rotational kinetic energy. For example, if a disk is suspended in the air and spun, it has no translational kinetic energy. The position of the disk does not change. However, since it is spinning (rotating), it still has kinetic energy. To account for this, we can relate angular velocity with the moment of inertia of the object to find a value for the rotational kinetic energy.&lt;br /&gt;
&lt;br /&gt;
Rotational Kinetic Energy:&lt;br /&gt;
&lt;br /&gt;
::&amp;lt;math&amp;gt;{KE}_{rot} = \frac{{1}}{{2}}{I}_{cm}{&amp;amp;omega;^2}&amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
Relation to Work and Energy Principle:&lt;br /&gt;
&lt;br /&gt;
The energy principle states:&lt;br /&gt;
::&amp;lt;math&amp;gt;{E}_{f} = {E}_{i} + W &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
We can apply the energy principle to rotational kinetic energy as well to find changes in kinetic energy and work done on the system.&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
===A Computational Model===&lt;br /&gt;
&lt;br /&gt;
==Examples==&lt;br /&gt;
&lt;br /&gt;
Be sure to show all steps in your solution and include diagrams whenever possible&lt;br /&gt;
&lt;br /&gt;
===Simple===&lt;br /&gt;
&lt;br /&gt;
A simple example and application of the concept of rotation is the earth&#039;s rotation on it&#039;s axis. It rotates once every 24 hours. What is the angular velocity?&lt;br /&gt;
&lt;br /&gt;
:&amp;lt;math&amp;gt;\boldsymbol{{w}} = \frac{\boldsymbol{d\theta}}{\boldsymbol{dt}}&amp;lt;/math&amp;gt;&lt;br /&gt;
:&amp;lt;math&amp;gt;\boldsymbol{{w}} = \frac{\boldsymbol{2\pi}}{\boldsymbol{24}}&amp;lt;/math&amp;gt;&lt;br /&gt;
:&amp;lt;math&amp;gt;\boldsymbol{{w}} = \frac{\boldsymbol{\pi}}{\boldsymbol{12}}&amp;lt;/math&amp;gt;&lt;br /&gt;
:&amp;lt;math&amp;gt;\boldsymbol{{w}} = \frac{\boldsymbol{\pi}}{\boldsymbol{12}}*\frac{\boldsymbol{180}}{\boldsymbol{\pi}}&amp;lt;/math&amp;gt;&lt;br /&gt;
:&amp;lt;math&amp;gt;\boldsymbol{{w}} = {\boldsymbol{15 degrees}}&amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
Angular velocity can also be represented as change in angle (theta) over change in time. In this case, the earth rotates 2pi radians in 24 hours which reduces to pi/12 radians and that becomes 15 degrees.&lt;br /&gt;
&lt;br /&gt;
===Middling===&lt;br /&gt;
&lt;br /&gt;
A cylinder with a 2.5 ft radius is rotating at 120 rpm. Find the angular velocity in rad/sec and in degrees/sec. Find the linear velocity of a point on its rim in mph.&lt;br /&gt;
&lt;br /&gt;
To find the solution of this problem, rpm (revolutions per minute) should be converted to radians/second. Following this, the linear velocity can be calculated by using the v=wr formula shown above. The angular velocity is 720 degrees per sec and the linear velocity is 21.42 mph.&lt;br /&gt;
&lt;br /&gt;
Details of Explanation:&lt;br /&gt;
&lt;br /&gt;
[[File:MiddlePrb.jpg]]&lt;br /&gt;
&lt;br /&gt;
===Difficult===&lt;br /&gt;
&lt;br /&gt;
A tire with a 9 inch radius is rotating at 30 mph. Find the angular velocity at a point on its rim. Also express the result in revolutions per minute.&lt;br /&gt;
&lt;br /&gt;
[[File:Difficultprb.jpg]]&lt;br /&gt;
&lt;br /&gt;
==Connectedness==&lt;br /&gt;
Rotation is an extremely important aspect of dynamics (the study of moving objects) which plays a big role in biomechanics. Rotation relates to several important body parts such as the shoulder where there are two axis of rotation, the medial-lateral axis and the anterior-posterior axis. A study of the movement of the shoulder helps to treat medical conditions that may affect this area. Dynamics is also very important in many other disciples, including mechanical engineering and aerospace engineering.&lt;br /&gt;
&lt;br /&gt;
== See also ==&lt;br /&gt;
&lt;br /&gt;
To learn more about Rotation in a more complete context, please refer to Torque or Rigid-Body Objects or Angular Momentum.&lt;br /&gt;
&lt;br /&gt;
===Further reading===&lt;br /&gt;
&lt;br /&gt;
Books, Articles or other print media on this topic&lt;br /&gt;
&lt;br /&gt;
===External links===&lt;br /&gt;
&lt;br /&gt;
Some other resources to further understand rotation are the following:&lt;br /&gt;
&lt;br /&gt;
http://www.mathwarehouse.com/transformations/rotations-in-math.php&lt;br /&gt;
&lt;br /&gt;
http://demonstrations.wolfram.com/Understanding3DRotation/&lt;br /&gt;
&lt;br /&gt;
==References==&lt;br /&gt;
&lt;br /&gt;
[1] Biomechanics, Basic. &amp;lt;i&amp;gt;“It Is Important When Learning about&amp;lt;/i&amp;gt; (n.d.): n. pag. Web.&lt;br /&gt;
&lt;br /&gt;
[2] &amp;quot;Angular Velocity and Angular Acceleration.&amp;quot; Van Nostrand&#039;s Scientific Encyclopedia (2005): n. pag. Web&lt;/div&gt;</summary>
		<author><name>Drao31</name></author>
	</entry>
	<entry>
		<id>http://www.physicsbook.gatech.edu/index.php?title=Rotational_Kinematics&amp;diff=24384</id>
		<title>Rotational Kinematics</title>
		<link rel="alternate" type="text/html" href="http://www.physicsbook.gatech.edu/index.php?title=Rotational_Kinematics&amp;diff=24384"/>
		<updated>2016-11-27T00:03:18Z</updated>

		<summary type="html">&lt;p&gt;Drao31: &lt;/p&gt;
&lt;hr /&gt;
&lt;div&gt;Claimed by drao31 10/2016&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
==The Main Idea==&lt;br /&gt;
&lt;br /&gt;
Rotational motion is defined as an object moving around an axis in contrast to translational motion which involves the object moving in a straight trajectory.  &lt;br /&gt;
&lt;br /&gt;
===A Mathematical Model===&lt;br /&gt;
&lt;br /&gt;
Rotation can be characterized by its angular velocity and angular acceleration. The equations are listed below.&lt;br /&gt;
&lt;br /&gt;
Angular velocity:&lt;br /&gt;
&lt;br /&gt;
:&amp;lt;math&amp;gt;\boldsymbol{{w}} = \frac{\boldsymbol{v}}{\boldsymbol{r}}&amp;lt;/math&amp;gt; , &lt;br /&gt;
where &amp;lt;math&amp;gt;{\boldsymbol{v}}&amp;lt;/math&amp;gt; is the velocity of the object and &amp;lt;math&amp;gt;{\boldsymbol{r}}&amp;lt;/math&amp;gt; is the radius of the circle of motion. It can also be represented as the change in angle over the distance traveled in the formula shown below:&lt;br /&gt;
&lt;br /&gt;
:&amp;lt;math&amp;gt;\boldsymbol{{w}} = \frac{\boldsymbol{d\theta}}{\boldsymbol{dt}}&amp;lt;/math&amp;gt; , where &amp;lt;math&amp;gt;{\boldsymbol{d\theta}}&amp;lt;/math&amp;gt; is the change in angle and &amp;lt;math&amp;gt;{\boldsymbol{dt}}&amp;lt;/math&amp;gt; is the change in time. &lt;br /&gt;
&lt;br /&gt;
[[File:angularvelocity.png]]&lt;br /&gt;
&lt;br /&gt;
 Angular velocity always has a unit of radians (radians/sec or radians/hr). &lt;br /&gt;
&lt;br /&gt;
Angular acceleration is equal to alpha:&lt;br /&gt;
&lt;br /&gt;
:&amp;lt;math&amp;gt;\boldsymbol{{\alpha}} = \frac{\boldsymbol{a_t}}{\boldsymbol{r}}&amp;lt;/math&amp;gt; , &lt;br /&gt;
where &amp;lt;math&amp;gt;{\boldsymbol{a_t}}&amp;lt;/math&amp;gt; is the tangential acceleration of the object and &amp;lt;math&amp;gt;{\boldsymbol{r}}&amp;lt;/math&amp;gt; is the radius of the circle of motion.&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
Rotational Kinetic Energy:&lt;br /&gt;
An object with a center of mass at rest can still have rotational kinetic energy. For example, if a disk is suspended in the air and spun, it has no translational kinetic energy. The position of the disk does not change. However, since it is spinning (rotating), it still has kinetic energy. To account for this, we can relate angular velocity with the moment of inertia of the object to find a value for the rotational kinetic energy.&lt;br /&gt;
&lt;br /&gt;
Rotational Kinetic Energy:&lt;br /&gt;
&lt;br /&gt;
::&amp;lt;math&amp;gt;{KE}_{rot} = \frac{{1}}{{2}}{I}_{cm}{&amp;amp;omega;^2}&amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
Relation to Work and Energy Principle&lt;br /&gt;
&lt;br /&gt;
The energy principle states:&lt;br /&gt;
::&amp;lt;math&amp;gt;{E}_{f} = {E}_{i} + W &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
We can apply the energy principle to rotational kinetic energy as well to find changes in kinetic energy and work done on the system.&lt;br /&gt;
&lt;br /&gt;
Force&lt;br /&gt;
The most simple equation to relate force and rotating objects is:&lt;br /&gt;
::&amp;lt;math&amp;gt;{F} = \frac{{m}{v}^2}{{R}}&amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
However, the &lt;br /&gt;
===A Computational Model===&lt;br /&gt;
&lt;br /&gt;
==Examples==&lt;br /&gt;
&lt;br /&gt;
Be sure to show all steps in your solution and include diagrams whenever possible&lt;br /&gt;
&lt;br /&gt;
===Simple===&lt;br /&gt;
&lt;br /&gt;
A simple example and application of the concept of rotation is the earth&#039;s rotation on it&#039;s axis. It rotates once every 24 hours. What is the angular velocity?&lt;br /&gt;
&lt;br /&gt;
:&amp;lt;math&amp;gt;\boldsymbol{{w}} = \frac{\boldsymbol{d\theta}}{\boldsymbol{dt}}&amp;lt;/math&amp;gt;&lt;br /&gt;
:&amp;lt;math&amp;gt;\boldsymbol{{w}} = \frac{\boldsymbol{2\pi}}{\boldsymbol{24}}&amp;lt;/math&amp;gt;&lt;br /&gt;
:&amp;lt;math&amp;gt;\boldsymbol{{w}} = \frac{\boldsymbol{\pi}}{\boldsymbol{12}}&amp;lt;/math&amp;gt;&lt;br /&gt;
:&amp;lt;math&amp;gt;\boldsymbol{{w}} = \frac{\boldsymbol{\pi}}{\boldsymbol{12}}*\frac{\boldsymbol{180}}{\boldsymbol{\pi}}&amp;lt;/math&amp;gt;&lt;br /&gt;
:&amp;lt;math&amp;gt;\boldsymbol{{w}} = {\boldsymbol{15 degrees}}&amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
Angular velocity can also be represented as change in angle (theta) over change in time. In this case, the earth rotates 2pi radians in 24 hours which reduces to pi/12 radians and that becomes 15 degrees.&lt;br /&gt;
&lt;br /&gt;
===Middling===&lt;br /&gt;
&lt;br /&gt;
A cylinder with a 2.5 ft radius is rotating at 120 rpm. Find the angular velocity in rad/sec and in degrees/sec. Find the linear velocity of a point on its rim in mph.&lt;br /&gt;
&lt;br /&gt;
To find the solution of this problem, rpm (revolutions per minute) should be converted to radians/second. Following this, the linear velocity can be calculated by using the v=wr formula shown above. The angular velocity is 720 degrees per sec and the linear velocity is 21.42 mph.&lt;br /&gt;
&lt;br /&gt;
Details of Explanation:&lt;br /&gt;
&lt;br /&gt;
[[File:MiddlePrb.jpg]]&lt;br /&gt;
&lt;br /&gt;
===Difficult===&lt;br /&gt;
&lt;br /&gt;
A tire with a 9 inch radius is rotating at 30 mph. Find the angular velocity at a point on its rim. Also express the result in revolutions per minute.&lt;br /&gt;
&lt;br /&gt;
[[File:Difficultprb.jpg]]&lt;br /&gt;
&lt;br /&gt;
==Connectedness==&lt;br /&gt;
Rotation is an extremely important aspect of dynamics (the study of moving objects) which plays a big role in biomechanics. Rotation relates to several important body parts such as the shoulder where there are two axis of rotation, the medial-lateral axis and the anterior-posterior axis. A study of the movement of the shoulder helps to treat medical conditions that may affect this area. Dynamics is also very important in many other disciples, including mechanical engineering and aerospace engineering.&lt;br /&gt;
&lt;br /&gt;
== See also ==&lt;br /&gt;
&lt;br /&gt;
To learn more about Rotation in a more complete context, please refer to Torque or Rigid-Body Objects or Angular Momentum.&lt;br /&gt;
&lt;br /&gt;
===Further reading===&lt;br /&gt;
&lt;br /&gt;
Books, Articles or other print media on this topic&lt;br /&gt;
&lt;br /&gt;
===External links===&lt;br /&gt;
&lt;br /&gt;
Some other resources to further understand rotation are the following:&lt;br /&gt;
&lt;br /&gt;
http://www.mathwarehouse.com/transformations/rotations-in-math.php&lt;br /&gt;
&lt;br /&gt;
http://demonstrations.wolfram.com/Understanding3DRotation/&lt;br /&gt;
&lt;br /&gt;
==References==&lt;br /&gt;
&lt;br /&gt;
[1] Biomechanics, Basic. &amp;lt;i&amp;gt;“It Is Important When Learning about&amp;lt;/i&amp;gt; (n.d.): n. pag. Web.&lt;br /&gt;
&lt;br /&gt;
[2] &amp;quot;Angular Velocity and Angular Acceleration.&amp;quot; Van Nostrand&#039;s Scientific Encyclopedia (2005): n. pag. Web&lt;/div&gt;</summary>
		<author><name>Drao31</name></author>
	</entry>
	<entry>
		<id>http://www.physicsbook.gatech.edu/index.php?title=Rotational_Kinematics&amp;diff=24376</id>
		<title>Rotational Kinematics</title>
		<link rel="alternate" type="text/html" href="http://www.physicsbook.gatech.edu/index.php?title=Rotational_Kinematics&amp;diff=24376"/>
		<updated>2016-11-26T23:46:59Z</updated>

		<summary type="html">&lt;p&gt;Drao31: &lt;/p&gt;
&lt;hr /&gt;
&lt;div&gt;Claimed by drao31 10/2016&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
==The Main Idea==&lt;br /&gt;
&lt;br /&gt;
Rotational motion is defined as an object moving around an axis in contrast to translational motion which involves the object moving in a straight trajectory.  &lt;br /&gt;
&lt;br /&gt;
===A Mathematical Model===&lt;br /&gt;
&lt;br /&gt;
Rotation can be characterized by its angular velocity and angular acceleration. The equations are listed below.&lt;br /&gt;
&lt;br /&gt;
Angular velocity:&lt;br /&gt;
&lt;br /&gt;
:&amp;lt;math&amp;gt;\boldsymbol{{w}} = \frac{\boldsymbol{v}}{\boldsymbol{r}}&amp;lt;/math&amp;gt; , &lt;br /&gt;
where &amp;lt;math&amp;gt;{\boldsymbol{v}}&amp;lt;/math&amp;gt; is the velocity of the object and &amp;lt;math&amp;gt;{\boldsymbol{r}}&amp;lt;/math&amp;gt; is the radius of the circle of motion. It can also be represented as the change in angle over the distance traveled in the formula shown below:&lt;br /&gt;
&lt;br /&gt;
:&amp;lt;math&amp;gt;\boldsymbol{{w}} = \frac{\boldsymbol{d\theta}}{\boldsymbol{dt}}&amp;lt;/math&amp;gt; , where &amp;lt;math&amp;gt;{\boldsymbol{d\theta}}&amp;lt;/math&amp;gt; is the change in angle and &amp;lt;math&amp;gt;{\boldsymbol{dt}}&amp;lt;/math&amp;gt; is the change in time. &lt;br /&gt;
&lt;br /&gt;
[[File:angularvelocity.png]]&lt;br /&gt;
&lt;br /&gt;
 Angular velocity always has a unit of radians (radians/sec or radians/hr). &lt;br /&gt;
&lt;br /&gt;
Angular acceleration is equal to alpha:&lt;br /&gt;
&lt;br /&gt;
:&amp;lt;math&amp;gt;\boldsymbol{{\alpha}} = \frac{\boldsymbol{a_t}}{\boldsymbol{r}}&amp;lt;/math&amp;gt; , &lt;br /&gt;
where &amp;lt;math&amp;gt;{\boldsymbol{a_t}}&amp;lt;/math&amp;gt; is the tangential acceleration of the object and &amp;lt;math&amp;gt;{\boldsymbol{r}}&amp;lt;/math&amp;gt; is the radius of the circle of motion.&lt;br /&gt;
&lt;br /&gt;
===A Computational Model===&lt;br /&gt;
&lt;br /&gt;
===Rotational Kinetic Energy===&lt;br /&gt;
An object with a center of mass at rest can still have rotational kinetic energy. For example, if a disk is suspended in the air and spun, it has no translational kinetic energy. The position of the disk does not change. However, since it is spinning (rotating), it still has kinetic energy. To account for this, we can relate angular velocity with the moment of inertia of the object to find a value for the rotational kinetic energy.&lt;br /&gt;
&lt;br /&gt;
Rotational Kinetic Energy:&lt;br /&gt;
&lt;br /&gt;
::&amp;lt;math&amp;gt;{KE}_{rot} = \frac{{1}}{{2}}{I}_{cm}{&amp;amp;omega;^2}&amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
Relation to Work and Energy Principle&lt;br /&gt;
&lt;br /&gt;
The energy principle states:&lt;br /&gt;
::&amp;lt;math&amp;gt;{E}_{f} = {E}_{i} + W &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
We can apply the energy principle to rotational kinetic energy as well to find changes in kinetic energy and work done on the system.&lt;br /&gt;
&lt;br /&gt;
==Examples==&lt;br /&gt;
&lt;br /&gt;
Be sure to show all steps in your solution and include diagrams whenever possible&lt;br /&gt;
&lt;br /&gt;
===Simple===&lt;br /&gt;
&lt;br /&gt;
A simple example and application of the concept of rotation is the earth&#039;s rotation on it&#039;s axis. It rotates once every 24 hours. What is the angular velocity?&lt;br /&gt;
&lt;br /&gt;
:&amp;lt;math&amp;gt;\boldsymbol{{w}} = \frac{\boldsymbol{d\theta}}{\boldsymbol{dt}}&amp;lt;/math&amp;gt;&lt;br /&gt;
:&amp;lt;math&amp;gt;\boldsymbol{{w}} = \frac{\boldsymbol{2\pi}}{\boldsymbol{24}}&amp;lt;/math&amp;gt;&lt;br /&gt;
:&amp;lt;math&amp;gt;\boldsymbol{{w}} = \frac{\boldsymbol{\pi}}{\boldsymbol{12}}&amp;lt;/math&amp;gt;&lt;br /&gt;
:&amp;lt;math&amp;gt;\boldsymbol{{w}} = \frac{\boldsymbol{\pi}}{\boldsymbol{12}}*\frac{\boldsymbol{180}}{\boldsymbol{\pi}}&amp;lt;/math&amp;gt;&lt;br /&gt;
:&amp;lt;math&amp;gt;\boldsymbol{{w}} = {\boldsymbol{15 degrees}}&amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
Angular velocity can also be represented as change in angle (theta) over change in time. In this case, the earth rotates 2pi radians in 24 hours which reduces to pi/12 radians and that becomes 15 degrees.&lt;br /&gt;
&lt;br /&gt;
===Middling===&lt;br /&gt;
&lt;br /&gt;
A cylinder with a 2.5 ft radius is rotating at 120 rpm. Find the angular velocity in rad/sec and in degrees/sec. Find the linear velocity of a point on its rim in mph.&lt;br /&gt;
&lt;br /&gt;
To find the solution of this problem, rpm (revolutions per minute) should be converted to radians/second. Following this, the linear velocity can be calculated by using the v=wr formula shown above. The angular velocity is 720 degrees per sec and the linear velocity is 21.42 mph.&lt;br /&gt;
&lt;br /&gt;
Details of Explanation:&lt;br /&gt;
&lt;br /&gt;
[[File:MiddlePrb.jpg]]&lt;br /&gt;
&lt;br /&gt;
===Difficult===&lt;br /&gt;
&lt;br /&gt;
A tire with a 9 inch radius is rotating at 30 mph. Find the angular velocity at a point on its rim. Also express the result in revolutions per minute.&lt;br /&gt;
&lt;br /&gt;
[[File:Difficultprb.jpg]]&lt;br /&gt;
&lt;br /&gt;
==Connectedness==&lt;br /&gt;
Rotation is an extremely important aspect of dynamics (the study of moving objects) which plays a big role in biomechanics. Rotation relates to several important body parts such as the shoulder where there are two axis of rotation, the medial-lateral axis and the anterior-posterior axis. A study of the movement of the shoulder helps to treat medical conditions that may affect this area. Dynamics is also very important in many other disciples, including mechanical engineering and aerospace engineering.&lt;br /&gt;
&lt;br /&gt;
== See also ==&lt;br /&gt;
&lt;br /&gt;
To learn more about Rotation in a more complete context, please refer to Torque or Rigid-Body Objects or Angular Momentum.&lt;br /&gt;
&lt;br /&gt;
===Further reading===&lt;br /&gt;
&lt;br /&gt;
Books, Articles or other print media on this topic&lt;br /&gt;
&lt;br /&gt;
===External links===&lt;br /&gt;
&lt;br /&gt;
Some other resources to further understand rotation are the following:&lt;br /&gt;
&lt;br /&gt;
http://www.mathwarehouse.com/transformations/rotations-in-math.php&lt;br /&gt;
&lt;br /&gt;
http://demonstrations.wolfram.com/Understanding3DRotation/&lt;br /&gt;
&lt;br /&gt;
==References==&lt;br /&gt;
&lt;br /&gt;
[1] Biomechanics, Basic. &amp;lt;i&amp;gt;“It Is Important When Learning about&amp;lt;/i&amp;gt; (n.d.): n. pag. Web.&lt;br /&gt;
&lt;br /&gt;
[2] &amp;quot;Angular Velocity and Angular Acceleration.&amp;quot; Van Nostrand&#039;s Scientific Encyclopedia (2005): n. pag. Web&lt;/div&gt;</summary>
		<author><name>Drao31</name></author>
	</entry>
	<entry>
		<id>http://www.physicsbook.gatech.edu/index.php?title=Rotational_Kinematics&amp;diff=24369</id>
		<title>Rotational Kinematics</title>
		<link rel="alternate" type="text/html" href="http://www.physicsbook.gatech.edu/index.php?title=Rotational_Kinematics&amp;diff=24369"/>
		<updated>2016-11-26T23:35:27Z</updated>

		<summary type="html">&lt;p&gt;Drao31: &lt;/p&gt;
&lt;hr /&gt;
&lt;div&gt;Claimed by drao31 10/2016&lt;br /&gt;
&lt;br /&gt;
This page is all about rotation and it&#039;s relation to torque. This page is very much a work still in progress by sthevuthasan3.&lt;br /&gt;
&lt;br /&gt;
==The Main Idea==&lt;br /&gt;
&lt;br /&gt;
Rotational motion is defined as when an object moves about an axis in a circle versus translational motion which involves the object moving in a straight trajectory.  &lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
===A Mathematical Model===&lt;br /&gt;
&lt;br /&gt;
Rotation can be characterized by its angular velocity and angular acceleration. The equations are listed below.&lt;br /&gt;
&lt;br /&gt;
Angular velocity:&lt;br /&gt;
&lt;br /&gt;
:&amp;lt;math&amp;gt;\boldsymbol{{w}} = \frac{\boldsymbol{v}}{\boldsymbol{r}}&amp;lt;/math&amp;gt; , &lt;br /&gt;
where &amp;lt;math&amp;gt;{\boldsymbol{v}}&amp;lt;/math&amp;gt; is the velocity of the object and &amp;lt;math&amp;gt;{\boldsymbol{r}}&amp;lt;/math&amp;gt; is the radius of the circle of motion. It can also be represented as the change in angle over the distance traveled in the formula shown below:&lt;br /&gt;
&lt;br /&gt;
:&amp;lt;math&amp;gt;\boldsymbol{{w}} = \frac{\boldsymbol{d\theta}}{\boldsymbol{dt}}&amp;lt;/math&amp;gt; , where &amp;lt;math&amp;gt;{\boldsymbol{d\theta}}&amp;lt;/math&amp;gt; is the change in angle and &amp;lt;math&amp;gt;{\boldsymbol{dt}}&amp;lt;/math&amp;gt; is the change in time. &lt;br /&gt;
&lt;br /&gt;
[[File:angularvelocity.png]]&lt;br /&gt;
&lt;br /&gt;
 Angular velocity always has a unit of radians (radians/sec or radians/hr). &lt;br /&gt;
&lt;br /&gt;
Angular acceleration is equal to alpha:&lt;br /&gt;
&lt;br /&gt;
:&amp;lt;math&amp;gt;\boldsymbol{{\alpha}} = \frac{\boldsymbol{a_t}}{\boldsymbol{r}}&amp;lt;/math&amp;gt; , &lt;br /&gt;
where &amp;lt;math&amp;gt;{\boldsymbol{a_t}}&amp;lt;/math&amp;gt; is the tangential acceleration of the object and &amp;lt;math&amp;gt;{\boldsymbol{r}}&amp;lt;/math&amp;gt; is the radius of the circle of motion.&lt;br /&gt;
&lt;br /&gt;
===A Computational Model===&lt;br /&gt;
&lt;br /&gt;
===Rotational Kinetic Energy===&lt;br /&gt;
An object with a center of mass at rest can still have rotational kinetic energy. For example, if a disk is suspended in the air and spun, it has no translational kinetic energy. The position of the disk does not change. However, since it is spinning (rotating), it still has kinetic energy. To account for this, we can relate angular velocity with the moment of inertia of the object to find a value for the rotational kinetic energy.&lt;br /&gt;
&lt;br /&gt;
Rotational Kinetic Energy:&lt;br /&gt;
&lt;br /&gt;
::&amp;lt;math&amp;gt;{KE}_{rot} = \frac{{1}}{{2}}{I}_{cm}{&amp;amp;omega;^2}&amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
==Examples==&lt;br /&gt;
&lt;br /&gt;
Be sure to show all steps in your solution and include diagrams whenever possible&lt;br /&gt;
&lt;br /&gt;
===Simple===&lt;br /&gt;
&lt;br /&gt;
A simple example and application of the concept of rotation is the earth&#039;s rotation on it&#039;s axis. It rotates once every 24 hours. What is the angular velocity?&lt;br /&gt;
&lt;br /&gt;
:&amp;lt;math&amp;gt;\boldsymbol{{w}} = \frac{\boldsymbol{d\theta}}{\boldsymbol{dt}}&amp;lt;/math&amp;gt;&lt;br /&gt;
:&amp;lt;math&amp;gt;\boldsymbol{{w}} = \frac{\boldsymbol{2\pi}}{\boldsymbol{24}}&amp;lt;/math&amp;gt;&lt;br /&gt;
:&amp;lt;math&amp;gt;\boldsymbol{{w}} = \frac{\boldsymbol{\pi}}{\boldsymbol{12}}&amp;lt;/math&amp;gt;&lt;br /&gt;
:&amp;lt;math&amp;gt;\boldsymbol{{w}} = \frac{\boldsymbol{\pi}}{\boldsymbol{12}}*\frac{\boldsymbol{180}}{\boldsymbol{\pi}}&amp;lt;/math&amp;gt;&lt;br /&gt;
:&amp;lt;math&amp;gt;\boldsymbol{{w}} = {\boldsymbol{15 degrees}}&amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
Angular velocity can also be represented as change in angle (theta) over change in time. In this case, the earth rotates 2pi radians in 24 hours which reduces to pi/12 radians and that becomes 15 degrees.&lt;br /&gt;
&lt;br /&gt;
===Middling===&lt;br /&gt;
&lt;br /&gt;
A cylinder with a 2.5 ft radius is rotating at 120 rpm. Find the angular velocity in rad/sec and in degrees/sec. Find the linear velocity of a point on its rim in mph.&lt;br /&gt;
&lt;br /&gt;
To find the solution of this problem, rpm (revolutions per minute) should be converted to radians/second. Following this, the linear velocity can be calculated by using the v=wr formula shown above. The angular velocity is 720 degrees per sec and the linear velocity is 21.42 mph.&lt;br /&gt;
&lt;br /&gt;
Details of Explanation:&lt;br /&gt;
&lt;br /&gt;
[[File:MiddlePrb.jpg]]&lt;br /&gt;
&lt;br /&gt;
===Difficult===&lt;br /&gt;
&lt;br /&gt;
A tire with a 9 inch radius is rotating at 30 mph. Find the angular velocity at a point on its rim. Also express the result in revolutions per minute.&lt;br /&gt;
&lt;br /&gt;
[[File:Difficultprb.jpg]]&lt;br /&gt;
&lt;br /&gt;
==Connectedness==&lt;br /&gt;
Rotation is an extremely important aspect of dynamics (the study of moving objects) which plays a big role in biomechanics. Rotation relates to several important body parts such as the shoulder where there are two axis of rotation, the medial-lateral axis and the anterior-posterior axis. A study of the movement of the shoulder helps to treat medical conditions that may affect this area. Dynamics is also very important in many other disciples, including mechanical engineering and aerospace engineering.&lt;br /&gt;
&lt;br /&gt;
== See also ==&lt;br /&gt;
&lt;br /&gt;
To learn more about Rotation in a more complete context, please refer to Torque or Rigid-Body Objects or Angular Momentum.&lt;br /&gt;
&lt;br /&gt;
===Further reading===&lt;br /&gt;
&lt;br /&gt;
Books, Articles or other print media on this topic&lt;br /&gt;
&lt;br /&gt;
===External links===&lt;br /&gt;
&lt;br /&gt;
Some other resources to further understand rotation are the following:&lt;br /&gt;
&lt;br /&gt;
http://www.mathwarehouse.com/transformations/rotations-in-math.php&lt;br /&gt;
&lt;br /&gt;
http://demonstrations.wolfram.com/Understanding3DRotation/&lt;br /&gt;
&lt;br /&gt;
==References==&lt;br /&gt;
&lt;br /&gt;
[1] Biomechanics, Basic. &amp;lt;i&amp;gt;“It Is Important When Learning about&amp;lt;/i&amp;gt; (n.d.): n. pag. Web.&lt;br /&gt;
&lt;br /&gt;
[2] &amp;quot;Angular Velocity and Angular Acceleration.&amp;quot; Van Nostrand&#039;s Scientific Encyclopedia (2005): n. pag. Web&lt;/div&gt;</summary>
		<author><name>Drao31</name></author>
	</entry>
	<entry>
		<id>http://www.physicsbook.gatech.edu/index.php?title=Rotational_Kinematics&amp;diff=24358</id>
		<title>Rotational Kinematics</title>
		<link rel="alternate" type="text/html" href="http://www.physicsbook.gatech.edu/index.php?title=Rotational_Kinematics&amp;diff=24358"/>
		<updated>2016-11-26T23:05:28Z</updated>

		<summary type="html">&lt;p&gt;Drao31: &lt;/p&gt;
&lt;hr /&gt;
&lt;div&gt;Claimed by drao31 10/2016&lt;br /&gt;
&lt;br /&gt;
This page is all about rotation and it&#039;s relation to torque. This page is very much a work still in progress by sthevuthasan3.&lt;br /&gt;
&lt;br /&gt;
==The Main Idea==&lt;br /&gt;
&lt;br /&gt;
Rotational motion is defined as when an object moves about an axis in a circle versus translational motion which involves the object moving in a straight trajectory.  &lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
===A Mathematical Model===&lt;br /&gt;
&lt;br /&gt;
Rotation can be characterized by its angular velocity and angular acceleration. The equations are listed below.&lt;br /&gt;
&lt;br /&gt;
Angular velocity:&lt;br /&gt;
&lt;br /&gt;
:&amp;lt;math&amp;gt;\boldsymbol{{w}} = \frac{\boldsymbol{v}}{\boldsymbol{r}}&amp;lt;/math&amp;gt; , &lt;br /&gt;
where &amp;lt;math&amp;gt;{\boldsymbol{v}}&amp;lt;/math&amp;gt; is the velocity of the object and &amp;lt;math&amp;gt;{\boldsymbol{r}}&amp;lt;/math&amp;gt; is the radius of the circle of motion. It can also be represented as the change in angle over the distance traveled in the formula shown below:&lt;br /&gt;
&lt;br /&gt;
:&amp;lt;math&amp;gt;\boldsymbol{{w}} = \frac{\boldsymbol{d\theta}}{\boldsymbol{dt}}&amp;lt;/math&amp;gt; , where &amp;lt;math&amp;gt;{\boldsymbol{d\theta}}&amp;lt;/math&amp;gt; is the change in angle and &amp;lt;math&amp;gt;{\boldsymbol{dt}}&amp;lt;/math&amp;gt; is the change in time. &lt;br /&gt;
&lt;br /&gt;
[[File:angularvelocity.png]]&lt;br /&gt;
&lt;br /&gt;
 Angular velocity always has a unit of radians (radians/sec or radians/hr). &lt;br /&gt;
&lt;br /&gt;
Angular acceleration is equal to alpha:&lt;br /&gt;
&lt;br /&gt;
:&amp;lt;math&amp;gt;\boldsymbol{{\alpha}} = \frac{\boldsymbol{a_t}}{\boldsymbol{r}}&amp;lt;/math&amp;gt; , &lt;br /&gt;
where &amp;lt;math&amp;gt;{\boldsymbol{a_t}}&amp;lt;/math&amp;gt; is the tangential acceleration of the object and &amp;lt;math&amp;gt;{\boldsymbol{r}}&amp;lt;/math&amp;gt; is the radius of the circle of motion.&lt;br /&gt;
&lt;br /&gt;
===A Computational Model===&lt;br /&gt;
&lt;br /&gt;
===Rotational Kinetic Energy===&lt;br /&gt;
An object with a center of mass at rest can still have rotational kinetic energy. For example, if a disk is suspended in the air and spun, it has no translational kinetic energy. The position of the disk does not change. However, since it is spinning (rotating), it still has kinetic energy. To account for this, we can relate angular velocity with the moment of inertia of the object to find a value for the rotational kinetic energy.&lt;br /&gt;
&lt;br /&gt;
Rotational Kinetic Energy:&lt;br /&gt;
&lt;br /&gt;
::&amp;lt;math&amp;gt;{KE}_{rot} = \frac{{1}}{{2}}{I}{w^2}&amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
==Examples==&lt;br /&gt;
&lt;br /&gt;
Be sure to show all steps in your solution and include diagrams whenever possible&lt;br /&gt;
&lt;br /&gt;
===Simple===&lt;br /&gt;
&lt;br /&gt;
A simple example and application of the concept of rotation is the earth&#039;s rotation on it&#039;s axis. It rotates once every 24 hours. What is the angular velocity?&lt;br /&gt;
&lt;br /&gt;
:&amp;lt;math&amp;gt;\boldsymbol{{w}} = \frac{\boldsymbol{d\theta}}{\boldsymbol{dt}}&amp;lt;/math&amp;gt;&lt;br /&gt;
:&amp;lt;math&amp;gt;\boldsymbol{{w}} = \frac{\boldsymbol{2\pi}}{\boldsymbol{24}}&amp;lt;/math&amp;gt;&lt;br /&gt;
:&amp;lt;math&amp;gt;\boldsymbol{{w}} = \frac{\boldsymbol{\pi}}{\boldsymbol{12}}&amp;lt;/math&amp;gt;&lt;br /&gt;
:&amp;lt;math&amp;gt;\boldsymbol{{w}} = \frac{\boldsymbol{\pi}}{\boldsymbol{12}}*\frac{\boldsymbol{180}}{\boldsymbol{\pi}}&amp;lt;/math&amp;gt;&lt;br /&gt;
:&amp;lt;math&amp;gt;\boldsymbol{{w}} = {\boldsymbol{15 degrees}}&amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
Angular velocity can also be represented as change in angle (theta) over change in time. In this case, the earth rotates 2pi radians in 24 hours which reduces to pi/12 radians and that becomes 15 degrees.&lt;br /&gt;
&lt;br /&gt;
===Middling===&lt;br /&gt;
&lt;br /&gt;
A cylinder with a 2.5 ft radius is rotating at 120 rpm. Find the angular velocity in rad/sec and in degrees/sec. Find the linear velocity of a point on its rim in mph.&lt;br /&gt;
&lt;br /&gt;
To find the solution of this problem, rpm (revolutions per minute) should be converted to radians/second. Following this, the linear velocity can be calculated by using the v=wr formula shown above. The angular velocity is 720 degrees per sec and the linear velocity is 21.42 mph.&lt;br /&gt;
&lt;br /&gt;
Details of Explanation:&lt;br /&gt;
&lt;br /&gt;
[[File:MiddlePrb.jpg]]&lt;br /&gt;
&lt;br /&gt;
===Difficult===&lt;br /&gt;
&lt;br /&gt;
A tire with a 9 inch radius is rotating at 30 mph. Find the angular velocity at a point on its rim. Also express the result in revolutions per minute.&lt;br /&gt;
&lt;br /&gt;
[[File:Difficultprb.jpg]]&lt;br /&gt;
&lt;br /&gt;
==Connectedness==&lt;br /&gt;
Rotation is an extremely important aspect of dynamics (the study of moving objects) which plays a big role in biomechanics. Rotation relates to several important body parts such as the shoulder where there are two axis of rotation, the medial-lateral axis and the anterior-posterior axis. A study of the movement of the shoulder helps to treat medical conditions that may affect this area. Dynamics is also very important in many other disciples, including mechanical engineering and aerospace engineering.&lt;br /&gt;
&lt;br /&gt;
== See also ==&lt;br /&gt;
&lt;br /&gt;
To learn more about Rotation in a more complete context, please refer to Torque or Rigid-Body Objects or Angular Momentum.&lt;br /&gt;
&lt;br /&gt;
===Further reading===&lt;br /&gt;
&lt;br /&gt;
Books, Articles or other print media on this topic&lt;br /&gt;
&lt;br /&gt;
===External links===&lt;br /&gt;
&lt;br /&gt;
Some other resources to further understand rotation are the following:&lt;br /&gt;
&lt;br /&gt;
http://www.mathwarehouse.com/transformations/rotations-in-math.php&lt;br /&gt;
&lt;br /&gt;
http://demonstrations.wolfram.com/Understanding3DRotation/&lt;br /&gt;
&lt;br /&gt;
==References==&lt;br /&gt;
&lt;br /&gt;
[1] Biomechanics, Basic. &amp;lt;i&amp;gt;“It Is Important When Learning about&amp;lt;/i&amp;gt; (n.d.): n. pag. Web.&lt;br /&gt;
&lt;br /&gt;
[2] &amp;quot;Angular Velocity and Angular Acceleration.&amp;quot; Van Nostrand&#039;s Scientific Encyclopedia (2005): n. pag. Web&lt;/div&gt;</summary>
		<author><name>Drao31</name></author>
	</entry>
	<entry>
		<id>http://www.physicsbook.gatech.edu/index.php?title=Rotational_Kinematics&amp;diff=24348</id>
		<title>Rotational Kinematics</title>
		<link rel="alternate" type="text/html" href="http://www.physicsbook.gatech.edu/index.php?title=Rotational_Kinematics&amp;diff=24348"/>
		<updated>2016-11-26T22:46:20Z</updated>

		<summary type="html">&lt;p&gt;Drao31: &lt;/p&gt;
&lt;hr /&gt;
&lt;div&gt;Claimed by drao31 10/2016&lt;br /&gt;
&lt;br /&gt;
This page is all about rotation and it&#039;s relation to torque. This page is very much a work still in progress by sthevuthasan3.&lt;br /&gt;
&lt;br /&gt;
==The Main Idea==&lt;br /&gt;
&lt;br /&gt;
Rotational motion is defined as when an object moves about an axis in a circle versus translational motion which involves the object moving in a straight trajectory.  &lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
===A Mathematical Model===&lt;br /&gt;
&lt;br /&gt;
Rotation can be characterized by its angular velocity and angular acceleration. The equations are listed below.&lt;br /&gt;
&lt;br /&gt;
Angular velocity:&lt;br /&gt;
&lt;br /&gt;
:&amp;lt;math&amp;gt;\boldsymbol{{w}} = \frac{\boldsymbol{v}}{\boldsymbol{r}}&amp;lt;/math&amp;gt; , &lt;br /&gt;
where &amp;lt;math&amp;gt;{\boldsymbol{v}}&amp;lt;/math&amp;gt; is the velocity of the object and &amp;lt;math&amp;gt;{\boldsymbol{r}}&amp;lt;/math&amp;gt; is the radius of the circle of motion. It can also be represented as the change in angle over the distance traveled in the formula shown below:&lt;br /&gt;
&lt;br /&gt;
:&amp;lt;math&amp;gt;\boldsymbol{{w}} = \frac{\boldsymbol{d\theta}}{\boldsymbol{dt}}&amp;lt;/math&amp;gt; , where &amp;lt;math&amp;gt;{\boldsymbol{d\theta}}&amp;lt;/math&amp;gt; is the change in angle and &amp;lt;math&amp;gt;{\boldsymbol{dt}}&amp;lt;/math&amp;gt; is the change in time. &lt;br /&gt;
&lt;br /&gt;
[[File:angularvelocity.png]]&lt;br /&gt;
&lt;br /&gt;
 Angular velocity always has a unit of radians (radians/sec or radians/hr). &lt;br /&gt;
&lt;br /&gt;
Angular acceleration is equal to alpha:&lt;br /&gt;
&lt;br /&gt;
:&amp;lt;math&amp;gt;\boldsymbol{{\alpha}} = \frac{\boldsymbol{a_t}}{\boldsymbol{r}}&amp;lt;/math&amp;gt; , &lt;br /&gt;
where &amp;lt;math&amp;gt;{\boldsymbol{a_t}}&amp;lt;/math&amp;gt; is the tangential acceleration of the object and &amp;lt;math&amp;gt;{\boldsymbol{r}}&amp;lt;/math&amp;gt; is the radius of the circle of motion.&lt;br /&gt;
&lt;br /&gt;
===A Computational Model===&lt;br /&gt;
&lt;br /&gt;
==Examples==&lt;br /&gt;
&lt;br /&gt;
Be sure to show all steps in your solution and include diagrams whenever possible&lt;br /&gt;
&lt;br /&gt;
===Simple===&lt;br /&gt;
&lt;br /&gt;
A simple example and application of the concept of rotation is the earth&#039;s rotation on it&#039;s axis. It rotates once every 24 hours. What is the angular velocity?&lt;br /&gt;
&lt;br /&gt;
:&amp;lt;math&amp;gt;\boldsymbol{{w}} = \frac{\boldsymbol{d\theta}}{\boldsymbol{dt}}&amp;lt;/math&amp;gt;&lt;br /&gt;
:&amp;lt;math&amp;gt;\boldsymbol{{w}} = \frac{\boldsymbol{2\pi}}{\boldsymbol{24}}&amp;lt;/math&amp;gt;&lt;br /&gt;
:&amp;lt;math&amp;gt;\boldsymbol{{w}} = \frac{\boldsymbol{\pi}}{\boldsymbol{12}}&amp;lt;/math&amp;gt;&lt;br /&gt;
:&amp;lt;math&amp;gt;\boldsymbol{{w}} = \frac{\boldsymbol{\pi}}{\boldsymbol{12}}*\frac{\boldsymbol{180}}{\boldsymbol{\pi}}&amp;lt;/math&amp;gt;&lt;br /&gt;
:&amp;lt;math&amp;gt;\boldsymbol{{w}} = {\boldsymbol{15 degrees}}&amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
Angular velocity can also be represented as change in angle (theta) over change in time. In this case, the earth rotates 2pi radians in 24 hours which reduces to pi/12 radians and that becomes 15 degrees.&lt;br /&gt;
&lt;br /&gt;
===Middling===&lt;br /&gt;
&lt;br /&gt;
A cylinder with a 2.5 ft radius is rotating at 120 rpm. Find the angular velocity in rad/sec and in degrees/sec. Find the linear velocity of a point on its rim in mph.&lt;br /&gt;
&lt;br /&gt;
To find the solution of this problem, rpm (revolutions per minute) should be converted to radians/second. Following this, the linear velocity can be calculated by using the v=wr formula shown above. The angular velocity is 720 degrees per sec and the linear velocity is 21.42 mph.&lt;br /&gt;
&lt;br /&gt;
Details of Explanation:&lt;br /&gt;
&lt;br /&gt;
[[File:MiddlePrb.jpg]]&lt;br /&gt;
&lt;br /&gt;
===Difficult===&lt;br /&gt;
&lt;br /&gt;
A tire with a 9 inch radius is rotating at 30 mph. Find the angular velocity at a point on its rim. Also express the result in revolutions per minute.&lt;br /&gt;
&lt;br /&gt;
[[File:Difficultprb.jpg]]&lt;br /&gt;
&lt;br /&gt;
==Connectedness==&lt;br /&gt;
Rotation is an extremely important aspect of dynamics (the study of moving objects) which plays a big role in biomechanics. Rotation relates to several important body parts such as the shoulder where there are two axis of rotation, the medial-lateral axis and the anterior-posterior axis. A study of the movement of the shoulder helps to treat medical conditions that may affect this area. Dynamics is also very important in many other disciples, including mechanical engineering and aerospace engineering.&lt;br /&gt;
&lt;br /&gt;
== See also ==&lt;br /&gt;
&lt;br /&gt;
To learn more about Rotation in a more complete context, please refer to Torque or Rigid-Body Objects or Angular Momentum.&lt;br /&gt;
&lt;br /&gt;
===Further reading===&lt;br /&gt;
&lt;br /&gt;
Books, Articles or other print media on this topic&lt;br /&gt;
&lt;br /&gt;
===External links===&lt;br /&gt;
&lt;br /&gt;
Some other resources to further understand rotation are the following:&lt;br /&gt;
&lt;br /&gt;
http://www.mathwarehouse.com/transformations/rotations-in-math.php&lt;br /&gt;
&lt;br /&gt;
http://demonstrations.wolfram.com/Understanding3DRotation/&lt;br /&gt;
&lt;br /&gt;
==References==&lt;br /&gt;
&lt;br /&gt;
[1] Biomechanics, Basic. &amp;lt;i&amp;gt;“It Is Important When Learning about&amp;lt;/i&amp;gt; (n.d.): n. pag. Web.&lt;br /&gt;
&lt;br /&gt;
[2] &amp;quot;Angular Velocity and Angular Acceleration.&amp;quot; Van Nostrand&#039;s Scientific Encyclopedia (2005): n. pag. Web&lt;/div&gt;</summary>
		<author><name>Drao31</name></author>
	</entry>
	<entry>
		<id>http://www.physicsbook.gatech.edu/index.php?title=Rotational_Kinematics&amp;diff=23461</id>
		<title>Rotational Kinematics</title>
		<link rel="alternate" type="text/html" href="http://www.physicsbook.gatech.edu/index.php?title=Rotational_Kinematics&amp;diff=23461"/>
		<updated>2016-10-31T20:14:39Z</updated>

		<summary type="html">&lt;p&gt;Drao31: &lt;/p&gt;
&lt;hr /&gt;
&lt;div&gt;Claimed by drao31 10/2016&lt;br /&gt;
&lt;br /&gt;
This page is all about rotation and it&#039;s relation to torque. This page is very much a work still in progress by sthevuthasan3.&lt;br /&gt;
&lt;br /&gt;
==The Main Idea==&lt;br /&gt;
&lt;br /&gt;
Rotational motion is defined as when an object moves about an axis in a circle versus translational motion which involves the object moving in a straight trajectory.  &lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
===A Mathematical Model===&lt;br /&gt;
&lt;br /&gt;
Rotation can be characterized by its angular velocity and angular acceleration. The equations are listed below.&lt;br /&gt;
&lt;br /&gt;
Angular velocity:&lt;br /&gt;
&lt;br /&gt;
:&amp;lt;math&amp;gt;\boldsymbol{{w}} = \frac{\boldsymbol{v}}{\boldsymbol{r}}&amp;lt;/math&amp;gt; , &lt;br /&gt;
where &amp;lt;math&amp;gt;{\boldsymbol{v}}&amp;lt;/math&amp;gt; is the velocity of the object and &amp;lt;math&amp;gt;{\boldsymbol{r}}&amp;lt;/math&amp;gt; is the radius of the circle of motion. It can also be represented as the change in angle over the distance traveled in the formula shown below:&lt;br /&gt;
&lt;br /&gt;
:&amp;lt;math&amp;gt;\boldsymbol{{w}} = \frac{\boldsymbol{d\theta}}{\boldsymbol{dt}}&amp;lt;/math&amp;gt; , where &amp;lt;math&amp;gt;{\boldsymbol{d\theta}}&amp;lt;/math&amp;gt; is the change in angle and &amp;lt;math&amp;gt;{\boldsymbol{dt}}&amp;lt;/math&amp;gt; is the change in time. &lt;br /&gt;
&lt;br /&gt;
[[File:angularvelocity.png]]&lt;br /&gt;
&lt;br /&gt;
 Angular velocity always has a unit of radians (radians/sec or radians/hr). &lt;br /&gt;
&lt;br /&gt;
Angular acceleration is equal to alpha:&lt;br /&gt;
&lt;br /&gt;
:&amp;lt;math&amp;gt;\boldsymbol{{\alpha}} = \frac{\boldsymbol{a_t}}{\boldsymbol{r}}&amp;lt;/math&amp;gt; , &lt;br /&gt;
where &amp;lt;math&amp;gt;{\boldsymbol{a_t}}&amp;lt;/math&amp;gt; is the tangential acceleration of the object and &amp;lt;math&amp;gt;{\boldsymbol{r}}&amp;lt;/math&amp;gt; is the radius of the circle of motion.&lt;br /&gt;
&lt;br /&gt;
==Examples==&lt;br /&gt;
&lt;br /&gt;
Be sure to show all steps in your solution and include diagrams whenever possible&lt;br /&gt;
&lt;br /&gt;
===Simple===&lt;br /&gt;
&lt;br /&gt;
A simple example and application of the concept of rotation is the earth&#039;s rotation on it&#039;s axis. It rotates once every 24 hours. What is the angular velocity?&lt;br /&gt;
&lt;br /&gt;
:&amp;lt;math&amp;gt;\boldsymbol{{w}} = \frac{\boldsymbol{d\theta}}{\boldsymbol{dt}}&amp;lt;/math&amp;gt;&lt;br /&gt;
:&amp;lt;math&amp;gt;\boldsymbol{{w}} = \frac{\boldsymbol{2\pi}}{\boldsymbol{24}}&amp;lt;/math&amp;gt;&lt;br /&gt;
:&amp;lt;math&amp;gt;\boldsymbol{{w}} = \frac{\boldsymbol{\pi}}{\boldsymbol{12}}&amp;lt;/math&amp;gt;&lt;br /&gt;
:&amp;lt;math&amp;gt;\boldsymbol{{w}} = \frac{\boldsymbol{\pi}}{\boldsymbol{12}}*\frac{\boldsymbol{180}}{\boldsymbol{\pi}}&amp;lt;/math&amp;gt;&lt;br /&gt;
:&amp;lt;math&amp;gt;\boldsymbol{{w}} = {\boldsymbol{15 degrees}}&amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
Angular velocity can also be represented as change in angle (theta) over change in time. In this case, the earth rotates 2pi radians in 24 hours which reduces to pi/12 radians and that becomes 15 degrees.&lt;br /&gt;
&lt;br /&gt;
===Middling===&lt;br /&gt;
&lt;br /&gt;
A cylinder with a 2.5 ft radius is rotating at 120 rpm. Find the angular velocity in rad/sec and in degrees/sec. Find the linear velocity of a point on its rim in mph.&lt;br /&gt;
&lt;br /&gt;
To find the solution of this problem, rpm (revolutions per minute) should be converted to radians/second. Following this, the linear velocity can be calculated by using the v=wr formula shown above. The angular velocity is 720 degrees per sec and the linear velocity is 21.42 mph.&lt;br /&gt;
&lt;br /&gt;
Details of Explanation:&lt;br /&gt;
&lt;br /&gt;
[[File:MiddlePrb.jpg]]&lt;br /&gt;
&lt;br /&gt;
===Difficult===&lt;br /&gt;
&lt;br /&gt;
A tire with a 9 inch radius is rotating at 30 mph. Find the angular velocity at a point on its rim. Also express the result in revolutions per minute.&lt;br /&gt;
&lt;br /&gt;
[[File:Difficultprb.jpg]]&lt;br /&gt;
&lt;br /&gt;
==Connectedness==&lt;br /&gt;
Rotation is an extremely important aspect of dynamics (the study of moving objects) which plays a big role in biomechanics. Rotation relates to several important body parts such as the shoulder where there are two axis of rotation, the medial-lateral axis and the anterior-posterior axis. A study of the movement of the shoulder helps to treat medical conditions that may affect this area. Dynamics is also very important in many other disciples, including mechanical engineering and aerospace engineering.&lt;br /&gt;
&lt;br /&gt;
== See also ==&lt;br /&gt;
&lt;br /&gt;
To learn more about Rotation in a more complete context, please refer to Torque or Rigid-Body Objects or Angular Momentum.&lt;br /&gt;
&lt;br /&gt;
===Further reading===&lt;br /&gt;
&lt;br /&gt;
Books, Articles or other print media on this topic&lt;br /&gt;
&lt;br /&gt;
===External links===&lt;br /&gt;
&lt;br /&gt;
Some other resources to further understand rotation are the following:&lt;br /&gt;
&lt;br /&gt;
http://www.mathwarehouse.com/transformations/rotations-in-math.php&lt;br /&gt;
&lt;br /&gt;
http://demonstrations.wolfram.com/Understanding3DRotation/&lt;br /&gt;
&lt;br /&gt;
==References==&lt;br /&gt;
&lt;br /&gt;
[1] Biomechanics, Basic. &amp;lt;i&amp;gt;“It Is Important When Learning about&amp;lt;/i&amp;gt; (n.d.): n. pag. Web.&lt;br /&gt;
&lt;br /&gt;
[2] &amp;quot;Angular Velocity and Angular Acceleration.&amp;quot; Van Nostrand&#039;s Scientific Encyclopedia (2005): n. pag. Web&lt;/div&gt;</summary>
		<author><name>Drao31</name></author>
	</entry>
</feed>