Physics Book - User contributions [en]

Electric Force

2015-11-30T00:14:07Z

Asaxon7: /* History */

--[[User:Asaxon7|Asaxon7]] ([[User talk:Asaxon7|talk]]) 00:48, 18 November 2015 (EST) Claimed by Alayna Saxon

This page contains information on the electric force on a point charge. Electric force is created by an external [[Electric Field]].

==The Coulomb Force Law==

The formula for the magnitude of the electric force between two point charges is:

<math>|\vec F|=\frac{1}{4 \pi \epsilon_0 } \frac{|{q}_{1}{q}_{2}|}{r^2} </math>

where '''<math>{q}_{1}</math>''' and '''<math>{q}_{2}</math>''' are the magnitudes of charge of point 1 and point 2 and '''<math>r</math>''' is the distance between the two point charges. The units for electric force are in Newtons.

===Direction of Electric Force===

The electric force is along a straight line between the two point charges in the observed system. If the point charges have the same sign (i.e. both are either positively or negatively charged), then the charges repel each other. If the signs of the point charges are different (i.e. one is positively charged and one is negatively charged), then the point charges are attracted to each other.

===Derivations of Electric Force===

The electric force on a particle can also be written as:

<math>\vec F=q\vec E </math>

where '''<math>q</math>''' is the charge of the particle and '''<math>\vec E </math>''' is the external electric field.

This formula can be derived from <math>|\vec F|=\frac{1}{4 \pi \epsilon_0 } \frac{|{q}_{1}{q}_{2}|}{r^2} </math>, the electric force between two point charges. The magnitude of the electric field created by a point charge is <math>|\vec E|=\frac{1}{4 \pi \epsilon_0 } \frac{|q|}{r^2} </math>, where '''<math>q</math>''' is the magnitude of the charge of the particle and '''<math>r</math>''' is the distance between the observation location and the point charge. Therefore, the magnitude of electric force between point charge 1 and point charge 2 can be written as:

<math>|\vec F|=\frac{1}{4 \pi \epsilon_0 } \frac{|{q}_{1}{q}_{2}|}{r^2}=|{q}_{2}|\frac{1}{4 \pi \epsilon_0 } \frac{|{q}_{1}|}{r^2}=|{q}_{2}||\vec{E}_{1}| </math>

The units of charge are in Coulombs and the units for electric field are in Newton/Coulombs, so this derivation is correct in its dimensions since multiplying the two units gives just Newtons. The Newton is the unit for electric force.

==Examples==

===Example 1===

'''Problem: '''Find the magnitude of electric force on two charged particles located at <math> <0, 0, 0></math>m and <math> <0, 10, 0></math>m. The first particle has a charge of +5 nC and the second particle has a charge of -10 nC. Is the force attractive or repulsive?

'''Step 1: '''Find the distance between the two point charges.

<math>d=\sqrt{(0 m-0 m)^2+(0 m-10 m)^2+(0 m-0 m)^2}=\sqrt{100 m}=10 </math>m.

The distance between the two points is 10 m.

'''Step 2: '''Substitute values into the correct formula.

<math>|\vec F|=\frac{1}{4 \pi \epsilon_0 } \frac{|{q}_{1}{q}_{2}|}{r^2}=\frac{1}{4 \pi \epsilon_0 } \frac{|(5 nC)(-10 nC)|}{(10m)^2} </math>

<math>|\vec F|=4.5e-9 </math> N

The magnitude of electric force is <math>|\vec F|=4.5e-9 </math> N.

'''Step 3: '''Determine if force is attractive or repulsive.

Since the first particle is positively charged and the second is negatively charged, the force is attractive. The particles are attracted to each other.

===Example 2===

'''Problem: '''Find the electric force of a -3 C particle in a region with an electric field of <math><7, 5, 0></math>N/C.

'''Step 1: '''Substitute values into the correct formula.

<math>\vec F=q\vec E </math>

<math>\vec F=(-3 C)<7, 5, 0></math>N/C

<math>\vec F=<-21, -15, 0></math>N

The electric force vector for this particle is <math><-21, -15, 0></math>N.

==History==

French physicist Charles-Augustin de Coulomb discovered in 1785 that the magnitude of electric force between two charged particles is directly proportional to the product of the absolute value of the two charges and inversely proportional to the distance squared between the two particles. He experimented with a torsion balance which consisted of an insulated bar suspended in the air by a silk thread. Coulomb attached a metal ball with a known charge to one end of the insulated bar. He then brought another ball with the same charge near the first ball. This distance between the two balls was recorded. The balls repelled each other, causing the silk thread to twist. The angle of the twist was measured and by knowing how much force was required for the thread to twist through the recorded angle, Coulomb was able to calculate the force between the two balls and derive the formula for electric force.

== See also ==

===External links===

http://www.physicsclassroom.com/class/estatics/Lesson-3/Coulomb-s-Law

==References==

Matter & Interactions, Vol. II: Electric and Magnetic Interactions, 4th Edition

https://en.wikipedia.org/wiki/Coulomb's_law

[[Category:Which Category did you place this in?]]

Electric Force

2015-11-30T00:12:08Z

Asaxon7: /* History */

--[[User:Asaxon7|Asaxon7]] ([[User talk:Asaxon7|talk]]) 00:48, 18 November 2015 (EST) Claimed by Alayna Saxon

This page contains information on the electric force on a point charge. Electric force is created by an external [[Electric Field]].

==The Coulomb Force Law==

The formula for the magnitude of the electric force between two point charges is:

<math>|\vec F|=\frac{1}{4 \pi \epsilon_0 } \frac{|{q}_{1}{q}_{2}|}{r^2} </math>

where '''<math>{q}_{1}</math>''' and '''<math>{q}_{2}</math>''' are the magnitudes of charge of point 1 and point 2 and '''<math>r</math>''' is the distance between the two point charges. The units for electric force are in Newtons.

===Direction of Electric Force===

The electric force is along a straight line between the two point charges in the observed system. If the point charges have the same sign (i.e. both are either positively or negatively charged), then the charges repel each other. If the signs of the point charges are different (i.e. one is positively charged and one is negatively charged), then the point charges are attracted to each other.

===Derivations of Electric Force===

The electric force on a particle can also be written as:

<math>\vec F=q\vec E </math>

where '''<math>q</math>''' is the charge of the particle and '''<math>\vec E </math>''' is the external electric field.

This formula can be derived from <math>|\vec F|=\frac{1}{4 \pi \epsilon_0 } \frac{|{q}_{1}{q}_{2}|}{r^2} </math>, the electric force between two point charges. The magnitude of the electric field created by a point charge is <math>|\vec E|=\frac{1}{4 \pi \epsilon_0 } \frac{|q|}{r^2} </math>, where '''<math>q</math>''' is the magnitude of the charge of the particle and '''<math>r</math>''' is the distance between the observation location and the point charge. Therefore, the magnitude of electric force between point charge 1 and point charge 2 can be written as:

<math>|\vec F|=\frac{1}{4 \pi \epsilon_0 } \frac{|{q}_{1}{q}_{2}|}{r^2}=|{q}_{2}|\frac{1}{4 \pi \epsilon_0 } \frac{|{q}_{1}|}{r^2}=|{q}_{2}||\vec{E}_{1}| </math>

The units of charge are in Coulombs and the units for electric field are in Newton/Coulombs, so this derivation is correct in its dimensions since multiplying the two units gives just Newtons. The Newton is the unit for electric force.

==Examples==

===Example 1===

'''Problem: '''Find the magnitude of electric force on two charged particles located at <math> <0, 0, 0></math>m and <math> <0, 10, 0></math>m. The first particle has a charge of +5 nC and the second particle has a charge of -10 nC. Is the force attractive or repulsive?

'''Step 1: '''Find the distance between the two point charges.

<math>d=\sqrt{(0 m-0 m)^2+(0 m-10 m)^2+(0 m-0 m)^2}=\sqrt{100 m}=10 </math>m.

The distance between the two points is 10 m.

'''Step 2: '''Substitute values into the correct formula.

<math>|\vec F|=\frac{1}{4 \pi \epsilon_0 } \frac{|{q}_{1}{q}_{2}|}{r^2}=\frac{1}{4 \pi \epsilon_0 } \frac{|(5 nC)(-10 nC)|}{(10m)^2} </math>

<math>|\vec F|=4.5e-9 </math> N

The magnitude of electric force is <math>|\vec F|=4.5e-9 </math> N.

'''Step 3: '''Determine if force is attractive or repulsive.

Since the first particle is positively charged and the second is negatively charged, the force is attractive. The particles are attracted to each other.

===Example 2===

'''Problem: '''Find the electric force of a -3 C particle in a region with an electric field of <math><7, 5, 0></math>N/C.

'''Step 1: '''Substitute values into the correct formula.

<math>\vec F=q\vec E </math>

<math>\vec F=(-3 C)<7, 5, 0></math>N/C

<math>\vec F=<-21, -15, 0></math>N

The electric force vector for this particle is <math><-21, -15, 0></math>N.

==History==

French physicist Charles-Augustin de Coulomb discovered in 1785 that the magnitude of electric force between two charged particles is directly proportional to the product of the absolute value of the two charges and inversely proportional to the distance between the two particles. He experimented with a torsion balance which consisted of an insulated bar suspended in the air by a silk thread. Coulomb attached a metal ball with a known charge to one end of the insulated bar. He then brought another ball with the same charge near the first ball. This distance between the two balls was recorded. The balls repelled each other, causing the silk thread to twist. The angle of the twist was measured and by knowing how much force was required for the thread to twist through the recorded angle, Coulomb was able to calculate the force between the two balls and derive the formula for electric force.

== See also ==

===External links===

http://www.physicsclassroom.com/class/estatics/Lesson-3/Coulomb-s-Law

==References==

Matter & Interactions, Vol. II: Electric and Magnetic Interactions, 4th Edition

https://en.wikipedia.org/wiki/Coulomb's_law

[[Category:Which Category did you place this in?]]

Electric Force

2015-11-30T00:11:09Z

Asaxon7: /* History */

--[[User:Asaxon7|Asaxon7]] ([[User talk:Asaxon7|talk]]) 00:48, 18 November 2015 (EST) Claimed by Alayna Saxon

This page contains information on the electric force on a point charge. Electric force is created by an external [[Electric Field]].

==The Coulomb Force Law==

The formula for the magnitude of the electric force between two point charges is:

<math>|\vec F|=\frac{1}{4 \pi \epsilon_0 } \frac{|{q}_{1}{q}_{2}|}{r^2} </math>

where '''<math>{q}_{1}</math>''' and '''<math>{q}_{2}</math>''' are the magnitudes of charge of point 1 and point 2 and '''<math>r</math>''' is the distance between the two point charges. The units for electric force are in Newtons.

===Direction of Electric Force===

The electric force is along a straight line between the two point charges in the observed system. If the point charges have the same sign (i.e. both are either positively or negatively charged), then the charges repel each other. If the signs of the point charges are different (i.e. one is positively charged and one is negatively charged), then the point charges are attracted to each other.

===Derivations of Electric Force===

The electric force on a particle can also be written as:

<math>\vec F=q\vec E </math>

where '''<math>q</math>''' is the charge of the particle and '''<math>\vec E </math>''' is the external electric field.

This formula can be derived from <math>|\vec F|=\frac{1}{4 \pi \epsilon_0 } \frac{|{q}_{1}{q}_{2}|}{r^2} </math>, the electric force between two point charges. The magnitude of the electric field created by a point charge is <math>|\vec E|=\frac{1}{4 \pi \epsilon_0 } \frac{|q|}{r^2} </math>, where '''<math>q</math>''' is the magnitude of the charge of the particle and '''<math>r</math>''' is the distance between the observation location and the point charge. Therefore, the magnitude of electric force between point charge 1 and point charge 2 can be written as:

<math>|\vec F|=\frac{1}{4 \pi \epsilon_0 } \frac{|{q}_{1}{q}_{2}|}{r^2}=|{q}_{2}|\frac{1}{4 \pi \epsilon_0 } \frac{|{q}_{1}|}{r^2}=|{q}_{2}||\vec{E}_{1}| </math>

The units of charge are in Coulombs and the units for electric field are in Newton/Coulombs, so this derivation is correct in its dimensions since multiplying the two units gives just Newtons. The Newton is the unit for electric force.

==Examples==

===Example 1===

'''Problem: '''Find the magnitude of electric force on two charged particles located at <math> <0, 0, 0></math>m and <math> <0, 10, 0></math>m. The first particle has a charge of +5 nC and the second particle has a charge of -10 nC. Is the force attractive or repulsive?

'''Step 1: '''Find the distance between the two point charges.

<math>d=\sqrt{(0 m-0 m)^2+(0 m-10 m)^2+(0 m-0 m)^2}=\sqrt{100 m}=10 </math>m.

The distance between the two points is 10 m.

'''Step 2: '''Substitute values into the correct formula.

<math>|\vec F|=\frac{1}{4 \pi \epsilon_0 } \frac{|{q}_{1}{q}_{2}|}{r^2}=\frac{1}{4 \pi \epsilon_0 } \frac{|(5 nC)(-10 nC)|}{(10m)^2} </math>

<math>|\vec F|=4.5e-9 </math> N

The magnitude of electric force is <math>|\vec F|=4.5e-9 </math> N.

'''Step 3: '''Determine if force is attractive or repulsive.

Since the first particle is positively charged and the second is negatively charged, the force is attractive. The particles are attracted to each other.

===Example 2===

'''Problem: '''Find the electric force of a -3 C particle in a region with an electric field of <math><7, 5, 0></math>N/C.

'''Step 1: '''Substitute values into the correct formula.

<math>\vec F=q\vec E </math>

<math>\vec F=(-3 C)<7, 5, 0></math>N/C

<math>\vec F=<-21, -15, 0></math>N

The electric force vector for this particle is <math><-21, -15, 0></math>N.

==History==

French physicist Charles-Augustin de Coulomb discovered in 1785 that the magnitude of electric force between two charged particles is directly proportional to the product of the absolute value of the two charges and inversely proportional to the distance between the two particles. He experimented with a torsion balance which consisted of an insulated bar suspended in the air by a silk thread. Coulomb attached a metal ball with a known charge to one end of the insulated bar. He then brought another ball with the same charge near the first ball. The distance between the two balls was known. The balls repelled each other, causing the silk thread to twist. The angle of the twist was measured and by knowing how much force was required for the thread to twist through the recorded angle, Coulomb was able to calculate the force between the two balls and derive the formula for electric force.

== See also ==

===External links===

http://www.physicsclassroom.com/class/estatics/Lesson-3/Coulomb-s-Law

==References==

Matter & Interactions, Vol. II: Electric and Magnetic Interactions, 4th Edition

https://en.wikipedia.org/wiki/Coulomb's_law

[[Category:Which Category did you place this in?]]

Electric Force

2015-11-29T23:39:58Z

Asaxon7: /* See also */

--[[User:Asaxon7|Asaxon7]] ([[User talk:Asaxon7|talk]]) 00:48, 18 November 2015 (EST) Claimed by Alayna Saxon

This page contains information on the electric force on a point charge. Electric force is created by an external [[Electric Field]].

==The Coulomb Force Law==

The formula for the magnitude of the electric force between two point charges is:

<math>|\vec F|=\frac{1}{4 \pi \epsilon_0 } \frac{|{q}_{1}{q}_{2}|}{r^2} </math>

where '''<math>{q}_{1}</math>''' and '''<math>{q}_{2}</math>''' are the magnitudes of charge of point 1 and point 2 and '''<math>r</math>''' is the distance between the two point charges. The units for electric force are in Newtons.

===Direction of Electric Force===

The electric force is along a straight line between the two point charges in the observed system. If the point charges have the same sign (i.e. both are either positively or negatively charged), then the charges repel each other. If the signs of the point charges are different (i.e. one is positively charged and one is negatively charged), then the point charges are attracted to each other.

===Derivations of Electric Force===

The electric force on a particle can also be written as:

<math>\vec F=q\vec E </math>

where '''<math>q</math>''' is the charge of the particle and '''<math>\vec E </math>''' is the external electric field.

This formula can be derived from <math>|\vec F|=\frac{1}{4 \pi \epsilon_0 } \frac{|{q}_{1}{q}_{2}|}{r^2} </math>, the electric force between two point charges. The magnitude of the electric field created by a point charge is <math>|\vec E|=\frac{1}{4 \pi \epsilon_0 } \frac{|q|}{r^2} </math>, where '''<math>q</math>''' is the magnitude of the charge of the particle and '''<math>r</math>''' is the distance between the observation location and the point charge. Therefore, the magnitude of electric force between point charge 1 and point charge 2 can be written as:

<math>|\vec F|=\frac{1}{4 \pi \epsilon_0 } \frac{|{q}_{1}{q}_{2}|}{r^2}=|{q}_{2}|\frac{1}{4 \pi \epsilon_0 } \frac{|{q}_{1}|}{r^2}=|{q}_{2}||\vec{E}_{1}| </math>

The units of charge are in Coulombs and the units for electric field are in Newton/Coulombs, so this derivation is correct in its dimensions since multiplying the two units gives just Newtons. The Newton is the unit for electric force.

==Examples==

===Example 1===

'''Problem: '''Find the magnitude of electric force on two charged particles located at <math> <0, 0, 0></math>m and <math> <0, 10, 0></math>m. The first particle has a charge of +5 nC and the second particle has a charge of -10 nC. Is the force attractive or repulsive?

'''Step 1: '''Find the distance between the two point charges.

<math>d=\sqrt{(0 m-0 m)^2+(0 m-10 m)^2+(0 m-0 m)^2}=\sqrt{100 m}=10 </math>m.

The distance between the two points is 10 m.

'''Step 2: '''Substitute values into the correct formula.

<math>|\vec F|=\frac{1}{4 \pi \epsilon_0 } \frac{|{q}_{1}{q}_{2}|}{r^2}=\frac{1}{4 \pi \epsilon_0 } \frac{|(5 nC)(-10 nC)|}{(10m)^2} </math>

<math>|\vec F|=4.5e-9 </math> N

The magnitude of electric force is <math>|\vec F|=4.5e-9 </math> N.

'''Step 3: '''Determine if force is attractive or repulsive.

Since the first particle is positively charged and the second is negatively charged, the force is attractive. The particles are attracted to each other.

===Example 2===

'''Problem: '''Find the electric force of a -3 C particle in a region with an electric field of <math><7, 5, 0></math>N/C.

'''Step 1: '''Substitute values into the correct formula.

<math>\vec F=q\vec E </math>

<math>\vec F=(-3 C)<7, 5, 0></math>N/C

<math>\vec F=<-21, -15, 0></math>N

The electric force vector for this particle is <math><-21, -15, 0></math>N.

==History==

Put this idea in historical context. Give the reader the Who, What, When, Where, and Why.

== See also ==

===External links===

http://www.physicsclassroom.com/class/estatics/Lesson-3/Coulomb-s-Law

==References==

Matter & Interactions, Vol. II: Electric and Magnetic Interactions, 4th Edition

https://en.wikipedia.org/wiki/Coulomb's_law

[[Category:Which Category did you place this in?]]

Electric Force

2015-11-29T23:36:54Z

Asaxon7: /* References */

--[[User:Asaxon7|Asaxon7]] ([[User talk:Asaxon7|talk]]) 00:48, 18 November 2015 (EST) Claimed by Alayna Saxon

This page contains information on the electric force on a point charge. Electric force is created by an external [[Electric Field]].

==The Coulomb Force Law==

The formula for the magnitude of the electric force between two point charges is:

<math>|\vec F|=\frac{1}{4 \pi \epsilon_0 } \frac{|{q}_{1}{q}_{2}|}{r^2} </math>

where '''<math>{q}_{1}</math>''' and '''<math>{q}_{2}</math>''' are the magnitudes of charge of point 1 and point 2 and '''<math>r</math>''' is the distance between the two point charges. The units for electric force are in Newtons.

===Direction of Electric Force===

The electric force is along a straight line between the two point charges in the observed system. If the point charges have the same sign (i.e. both are either positively or negatively charged), then the charges repel each other. If the signs of the point charges are different (i.e. one is positively charged and one is negatively charged), then the point charges are attracted to each other.

===Derivations of Electric Force===

The electric force on a particle can also be written as:

<math>\vec F=q\vec E </math>

where '''<math>q</math>''' is the charge of the particle and '''<math>\vec E </math>''' is the external electric field.

This formula can be derived from <math>|\vec F|=\frac{1}{4 \pi \epsilon_0 } \frac{|{q}_{1}{q}_{2}|}{r^2} </math>, the electric force between two point charges. The magnitude of the electric field created by a point charge is <math>|\vec E|=\frac{1}{4 \pi \epsilon_0 } \frac{|q|}{r^2} </math>, where '''<math>q</math>''' is the magnitude of the charge of the particle and '''<math>r</math>''' is the distance between the observation location and the point charge. Therefore, the magnitude of electric force between point charge 1 and point charge 2 can be written as:

<math>|\vec F|=\frac{1}{4 \pi \epsilon_0 } \frac{|{q}_{1}{q}_{2}|}{r^2}=|{q}_{2}|\frac{1}{4 \pi \epsilon_0 } \frac{|{q}_{1}|}{r^2}=|{q}_{2}||\vec{E}_{1}| </math>

The units of charge are in Coulombs and the units for electric field are in Newton/Coulombs, so this derivation is correct in its dimensions since multiplying the two units gives just Newtons. The Newton is the unit for electric force.

==Examples==

===Example 1===

'''Problem: '''Find the magnitude of electric force on two charged particles located at <math> <0, 0, 0></math>m and <math> <0, 10, 0></math>m. The first particle has a charge of +5 nC and the second particle has a charge of -10 nC. Is the force attractive or repulsive?

'''Step 1: '''Find the distance between the two point charges.

<math>d=\sqrt{(0 m-0 m)^2+(0 m-10 m)^2+(0 m-0 m)^2}=\sqrt{100 m}=10 </math>m.

The distance between the two points is 10 m.

'''Step 2: '''Substitute values into the correct formula.

<math>|\vec F|=\frac{1}{4 \pi \epsilon_0 } \frac{|{q}_{1}{q}_{2}|}{r^2}=\frac{1}{4 \pi \epsilon_0 } \frac{|(5 nC)(-10 nC)|}{(10m)^2} </math>

<math>|\vec F|=4.5e-9 </math> N

The magnitude of electric force is <math>|\vec F|=4.5e-9 </math> N.

'''Step 3: '''Determine if force is attractive or repulsive.

Since the first particle is positively charged and the second is negatively charged, the force is attractive. The particles are attracted to each other.

===Example 2===

'''Problem: '''Find the electric force of a -3 C particle in a region with an electric field of <math><7, 5, 0></math>N/C.

'''Step 1: '''Substitute values into the correct formula.

<math>\vec F=q\vec E </math>

<math>\vec F=(-3 C)<7, 5, 0></math>N/C

<math>\vec F=<-21, -15, 0></math>N

The electric force vector for this particle is <math><-21, -15, 0></math>N.

==History==

Put this idea in historical context. Give the reader the Who, What, When, Where, and Why.

== See also ==

===Further reading===

Books, Articles or other print media on this topic

===External links===

http://www.physicsclassroom.com/class/estatics/Lesson-3/Coulomb-s-Law

==References==

Matter & Interactions, Vol. II: Electric and Magnetic Interactions, 4th Edition

https://en.wikipedia.org/wiki/Coulomb's_law

[[Category:Which Category did you place this in?]]

Electric Force

2015-11-29T23:18:20Z

Asaxon7: /* See also */

--[[User:Asaxon7|Asaxon7]] ([[User talk:Asaxon7|talk]]) 00:48, 18 November 2015 (EST) Claimed by Alayna Saxon

This page contains information on the electric force on a point charge. Electric force is created by an external [[Electric Field]].

==The Coulomb Force Law==

The formula for the magnitude of the electric force between two point charges is:

<math>|\vec F|=\frac{1}{4 \pi \epsilon_0 } \frac{|{q}_{1}{q}_{2}|}{r^2} </math>

where '''<math>{q}_{1}</math>''' and '''<math>{q}_{2}</math>''' are the magnitudes of charge of point 1 and point 2 and '''<math>r</math>''' is the distance between the two point charges. The units for electric force are in Newtons.

===Direction of Electric Force===

The electric force is along a straight line between the two point charges in the observed system. If the point charges have the same sign (i.e. both are either positively or negatively charged), then the charges repel each other. If the signs of the point charges are different (i.e. one is positively charged and one is negatively charged), then the point charges are attracted to each other.

===Derivations of Electric Force===

The electric force on a particle can also be written as:

<math>\vec F=q\vec E </math>

where '''<math>q</math>''' is the charge of the particle and '''<math>\vec E </math>''' is the external electric field.

This formula can be derived from <math>|\vec F|=\frac{1}{4 \pi \epsilon_0 } \frac{|{q}_{1}{q}_{2}|}{r^2} </math>, the electric force between two point charges. The magnitude of the electric field created by a point charge is <math>|\vec E|=\frac{1}{4 \pi \epsilon_0 } \frac{|q|}{r^2} </math>, where '''<math>q</math>''' is the magnitude of the charge of the particle and '''<math>r</math>''' is the distance between the observation location and the point charge. Therefore, the magnitude of electric force between point charge 1 and point charge 2 can be written as:

<math>|\vec F|=\frac{1}{4 \pi \epsilon_0 } \frac{|{q}_{1}{q}_{2}|}{r^2}=|{q}_{2}|\frac{1}{4 \pi \epsilon_0 } \frac{|{q}_{1}|}{r^2}=|{q}_{2}||\vec{E}_{1}| </math>

The units of charge are in Coulombs and the units for electric field are in Newton/Coulombs, so this derivation is correct in its dimensions since multiplying the two units gives just Newtons. The Newton is the unit for electric force.

==Examples==

===Example 1===

'''Problem: '''Find the magnitude of electric force on two charged particles located at <math> <0, 0, 0></math>m and <math> <0, 10, 0></math>m. The first particle has a charge of +5 nC and the second particle has a charge of -10 nC. Is the force attractive or repulsive?

'''Step 1: '''Find the distance between the two point charges.

<math>d=\sqrt{(0 m-0 m)^2+(0 m-10 m)^2+(0 m-0 m)^2}=\sqrt{100 m}=10 </math>m.

The distance between the two points is 10 m.

'''Step 2: '''Substitute values into the correct formula.

<math>|\vec F|=\frac{1}{4 \pi \epsilon_0 } \frac{|{q}_{1}{q}_{2}|}{r^2}=\frac{1}{4 \pi \epsilon_0 } \frac{|(5 nC)(-10 nC)|}{(10m)^2} </math>

<math>|\vec F|=4.5e-9 </math> N

The magnitude of electric force is <math>|\vec F|=4.5e-9 </math> N.

'''Step 3: '''Determine if force is attractive or repulsive.

Since the first particle is positively charged and the second is negatively charged, the force is attractive. The particles are attracted to each other.

===Example 2===

'''Problem: '''Find the electric force of a -3 C particle in a region with an electric field of <math><7, 5, 0></math>N/C.

'''Step 1: '''Substitute values into the correct formula.

<math>\vec F=q\vec E </math>

<math>\vec F=(-3 C)<7, 5, 0></math>N/C

<math>\vec F=<-21, -15, 0></math>N

The electric force vector for this particle is <math><-21, -15, 0></math>N.

==History==

Put this idea in historical context. Give the reader the Who, What, When, Where, and Why.

== See also ==

===Further reading===

Books, Articles or other print media on this topic

===External links===

http://www.physicsclassroom.com/class/estatics/Lesson-3/Coulomb-s-Law

==References==

Matter & Interactions, Vol. II: Electric and Magnetic Interactions, 4th Edition

[[Category:Which Category did you place this in?]]

Electric Force

2015-11-29T17:40:40Z

Asaxon7:

--[[User:Asaxon7|Asaxon7]] ([[User talk:Asaxon7|talk]]) 00:48, 18 November 2015 (EST) Claimed by Alayna Saxon

This page contains information on the electric force on a point charge. Electric force is created by an external [[Electric Field]].

==The Coulomb Force Law==

The formula for the magnitude of the electric force between two point charges is:

<math>|\vec F|=\frac{1}{4 \pi \epsilon_0 } \frac{|{q}_{1}{q}_{2}|}{r^2} </math>

where '''<math>{q}_{1}</math>''' and '''<math>{q}_{2}</math>''' are the magnitudes of charge of point 1 and point 2 and '''<math>r</math>''' is the distance between the two point charges. The units for electric force are in Newtons.

===Direction of Electric Force===

The electric force is along a straight line between the two point charges in the observed system. If the point charges have the same sign (i.e. both are either positively or negatively charged), then the charges repel each other. If the signs of the point charges are different (i.e. one is positively charged and one is negatively charged), then the point charges are attracted to each other.

===Derivations of Electric Force===

The electric force on a particle can also be written as:

<math>\vec F=q\vec E </math>

where '''<math>q</math>''' is the charge of the particle and '''<math>\vec E </math>''' is the external electric field.

This formula can be derived from <math>|\vec F|=\frac{1}{4 \pi \epsilon_0 } \frac{|{q}_{1}{q}_{2}|}{r^2} </math>, the electric force between two point charges. The magnitude of the electric field created by a point charge is <math>|\vec E|=\frac{1}{4 \pi \epsilon_0 } \frac{|q|}{r^2} </math>, where '''<math>q</math>''' is the magnitude of the charge of the particle and '''<math>r</math>''' is the distance between the observation location and the point charge. Therefore, the magnitude of electric force between point charge 1 and point charge 2 can be written as:

<math>|\vec F|=\frac{1}{4 \pi \epsilon_0 } \frac{|{q}_{1}{q}_{2}|}{r^2}=|{q}_{2}|\frac{1}{4 \pi \epsilon_0 } \frac{|{q}_{1}|}{r^2}=|{q}_{2}||\vec{E}_{1}| </math>

The units of charge are in Coulombs and the units for electric field are in Newton/Coulombs, so this derivation is correct in its dimensions since multiplying the two units gives just Newtons. The Newton is the unit for electric force.

==Examples==

===Example 1===

'''Problem: '''Find the magnitude of electric force on two charged particles located at <math> <0, 0, 0></math>m and <math> <0, 10, 0></math>m. The first particle has a charge of +5 nC and the second particle has a charge of -10 nC. Is the force attractive or repulsive?

'''Step 1: '''Find the distance between the two point charges.

<math>d=\sqrt{(0 m-0 m)^2+(0 m-10 m)^2+(0 m-0 m)^2}=\sqrt{100 m}=10 </math>m.

The distance between the two points is 10 m.

'''Step 2: '''Substitute values into the correct formula.

<math>|\vec F|=\frac{1}{4 \pi \epsilon_0 } \frac{|{q}_{1}{q}_{2}|}{r^2}=\frac{1}{4 \pi \epsilon_0 } \frac{|(5 nC)(-10 nC)|}{(10m)^2} </math>

<math>|\vec F|=4.5e-9 </math> N

The magnitude of electric force is <math>|\vec F|=4.5e-9 </math> N.

'''Step 3: '''Determine if force is attractive or repulsive.

Since the first particle is positively charged and the second is negatively charged, the force is attractive. The particles are attracted to each other.

===Example 2===

'''Problem: '''Find the electric force of a -3 C particle in a region with an electric field of <math><7, 5, 0></math>N/C.

'''Step 1: '''Substitute values into the correct formula.

<math>\vec F=q\vec E </math>

<math>\vec F=(-3 C)<7, 5, 0></math>N/C

<math>\vec F=<-21, -15, 0></math>N

The electric force vector for this particle is <math><-21, -15, 0></math>N.

==History==

Put this idea in historical context. Give the reader the Who, What, When, Where, and Why.

== See also ==

Are there related topics or categories in this wiki resource for the curious reader to explore? How does this topic fit into that context?

===Further reading===

Books, Articles or other print media on this topic

===External links===

Internet resources on this topic

==References==

Matter & Interactions, Vol. II: Electric and Magnetic Interactions, 4th Edition

[[Category:Which Category did you place this in?]]

Electric Force

2015-11-29T17:40:01Z

Asaxon7: /* Example 2 */

--[[User:Asaxon7|Asaxon7]] ([[User talk:Asaxon7|talk]]) 00:48, 18 November 2015 (EST) Claimed by Alayna Saxon

This page contains information on the electric force on a point charge. Electric force is created by an external [[Electric Field]].

==The Coulomb Force Law==

The formula for the magnitude of the electric force between two point charges is:

<math>|\vec F|=\frac{1}{4 \pi \epsilon_0 } \frac{|{q}_{1}{q}_{2}|}{r^2} </math>

where '''<math>{q}_{1}</math>''' and '''<math>{q}_{2}</math>''' are the magnitudes of charge of point 1 and point 2 and '''<math>r</math>''' is the distance between the two point charges. The units for electric force are in Newtons.

===Direction of Electric Force===

The electric force is along a straight line between the two point charges in the observed system. If the point charges have the same sign (i.e. both are either positively or negatively charged), then the charges repel each other. If the signs of the point charges are different (i.e. one is positively charged and one is negatively charged), then the point charges are attracted to each other.

===Derivations of Electric Force===

The electric force on a particle can also be written as:

<math>\vec F=q\vec E </math>

where '''<math>q</math>''' is the charge of the particle and '''<math>\vec E </math>''' is the external electric field.

This formula can be derived from <math>|\vec F|=\frac{1}{4 \pi \epsilon_0 } \frac{|{q}_{1}{q}_{2}|}{r^2} </math>, the electric force between two point charges. The magnitude of the electric field created by a point charge is <math>|\vec E|=\frac{1}{4 \pi \epsilon_0 } \frac{|q|}{r^2} </math>, where '''<math>q</math>''' is the magnitude of the charge of the particle and '''<math>r</math>''' is the distance between the observation location and the point charge. Therefore, the magnitude of electric force between point charge 1 and point charge 2 can be written as:

<math>|\vec F|=\frac{1}{4 \pi \epsilon_0 } \frac{|{q}_{1}{q}_{2}|}{r^2}=|{q}_{2}|\frac{1}{4 \pi \epsilon_0 } \frac{|{q}_{1}|}{r^2}=|{q}_{2}||\vec{E}_{1}| </math>

The units of charge are in Coulombs and the units for electric field are in Newton/Coulombs, so this derivation is correct in its dimensions since multiplying the two units gives just Newtons. The Newton is the unit for electric force.

==Examples==

===Example 1===

'''Problem: '''Find the magnitude of electric force on two charged particles located at <math> <0, 0, 0></math>m and <math> <0, 10, 0></math>m. The first particle has a charge of +5 nC and the second particle has a charge of -10 nC. Is the force attractive or repulsive?

'''Step 1: '''Find the distance between the two point charges.

<math>d=\sqrt{(0 m-0 m)^2+(0 m-10 m)^2+(0 m-0 m)^2}=\sqrt{100 m}=10 </math>m.

The distance between the two points is 10 m.

'''Step 2: '''Substitute values into the correct formula.

<math>|\vec F|=\frac{1}{4 \pi \epsilon_0 } \frac{|{q}_{1}{q}_{2}|}{r^2}=\frac{1}{4 \pi \epsilon_0 } \frac{|(5 nC)(-10 nC)|}{(10m)^2} </math>

<math>|\vec F|=4.5e-9 </math> N

The magnitude of electric force is <math>|\vec F|=4.5e-9 </math> N.

'''Step 3: '''Determine if force is attractive or repulsive.

Since the first particle is positively charged and the second is negatively charged, the force is attractive. The particles are attracted to each other.

===Example 2===

'''Problem: '''Find the electric force of a -3 C particle in a region with an electric field of <math><7, 5, 0></math>N/C.

'''Step 1: '''Substitute values into the correct formula.

<math>\vec F=q\vec E </math>

<math>\vec F=(-3 C)<7, 5, 0></math>N/C

<math>\vec F=<-21, -15, 0></math>N

The electric force vector for this particle is <math><-21, -15, 0></math>N.

==Connectedness==
#How is this topic connected to something that you are interested in?
#How is it connected to your major?
#Is there an interesting industrial application?

==History==

Put this idea in historical context. Give the reader the Who, What, When, Where, and Why.

== See also ==

Are there related topics or categories in this wiki resource for the curious reader to explore? How does this topic fit into that context?

===Further reading===

Books, Articles or other print media on this topic

===External links===

Internet resources on this topic

==References==

Matter & Interactions, Vol. II: Electric and Magnetic Interactions, 4th Edition

[[Category:Which Category did you place this in?]]

Electric Force

2015-11-29T17:39:33Z

Asaxon7: /* Example 2 */

--[[User:Asaxon7|Asaxon7]] ([[User talk:Asaxon7|talk]]) 00:48, 18 November 2015 (EST) Claimed by Alayna Saxon

This page contains information on the electric force on a point charge. Electric force is created by an external [[Electric Field]].

==The Coulomb Force Law==

The formula for the magnitude of the electric force between two point charges is:

<math>|\vec F|=\frac{1}{4 \pi \epsilon_0 } \frac{|{q}_{1}{q}_{2}|}{r^2} </math>

where '''<math>{q}_{1}</math>''' and '''<math>{q}_{2}</math>''' are the magnitudes of charge of point 1 and point 2 and '''<math>r</math>''' is the distance between the two point charges. The units for electric force are in Newtons.

===Direction of Electric Force===

The electric force is along a straight line between the two point charges in the observed system. If the point charges have the same sign (i.e. both are either positively or negatively charged), then the charges repel each other. If the signs of the point charges are different (i.e. one is positively charged and one is negatively charged), then the point charges are attracted to each other.

===Derivations of Electric Force===

The electric force on a particle can also be written as:

<math>\vec F=q\vec E </math>

where '''<math>q</math>''' is the charge of the particle and '''<math>\vec E </math>''' is the external electric field.

This formula can be derived from <math>|\vec F|=\frac{1}{4 \pi \epsilon_0 } \frac{|{q}_{1}{q}_{2}|}{r^2} </math>, the electric force between two point charges. The magnitude of the electric field created by a point charge is <math>|\vec E|=\frac{1}{4 \pi \epsilon_0 } \frac{|q|}{r^2} </math>, where '''<math>q</math>''' is the magnitude of the charge of the particle and '''<math>r</math>''' is the distance between the observation location and the point charge. Therefore, the magnitude of electric force between point charge 1 and point charge 2 can be written as:

<math>|\vec F|=\frac{1}{4 \pi \epsilon_0 } \frac{|{q}_{1}{q}_{2}|}{r^2}=|{q}_{2}|\frac{1}{4 \pi \epsilon_0 } \frac{|{q}_{1}|}{r^2}=|{q}_{2}||\vec{E}_{1}| </math>

The units of charge are in Coulombs and the units for electric field are in Newton/Coulombs, so this derivation is correct in its dimensions since multiplying the two units gives just Newtons. The Newton is the unit for electric force.

==Examples==

===Example 1===

'''Problem: '''Find the magnitude of electric force on two charged particles located at <math> <0, 0, 0></math>m and <math> <0, 10, 0></math>m. The first particle has a charge of +5 nC and the second particle has a charge of -10 nC. Is the force attractive or repulsive?

'''Step 1: '''Find the distance between the two point charges.

<math>d=\sqrt{(0 m-0 m)^2+(0 m-10 m)^2+(0 m-0 m)^2}=\sqrt{100 m}=10 </math>m.

The distance between the two points is 10 m.

'''Step 2: '''Substitute values into the correct formula.

<math>|\vec F|=\frac{1}{4 \pi \epsilon_0 } \frac{|{q}_{1}{q}_{2}|}{r^2}=\frac{1}{4 \pi \epsilon_0 } \frac{|(5 nC)(-10 nC)|}{(10m)^2} </math>

<math>|\vec F|=4.5e-9 </math> N

The magnitude of electric force is <math>|\vec F|=4.5e-9 </math> N.

'''Step 3: '''Determine if force is attractive or repulsive.

Since the first particle is positively charged and the second is negatively charged, the force is attractive. The particles are attracted to each other.

===Example 2===

'''Problem: '''Find the electric force of a -3 C particle in a region with an electric field of <math><7, 5, 0></math>N/C.

'''Step 1: '''Substitute values into the correct formula.

<math>\vec F=q\vec E </math>

<math>\vec F=(-3 C)<7, 5, 0></math>N/C

<math>\vec F=<-21, -15, 0></math>N

The electric force vector for this particle is <-21, -15, 0>N.

==Connectedness==
#How is this topic connected to something that you are interested in?
#How is it connected to your major?
#Is there an interesting industrial application?

==History==

Put this idea in historical context. Give the reader the Who, What, When, Where, and Why.

== See also ==

Are there related topics or categories in this wiki resource for the curious reader to explore? How does this topic fit into that context?

===Further reading===

Books, Articles or other print media on this topic

===External links===

Internet resources on this topic

==References==

Matter & Interactions, Vol. II: Electric and Magnetic Interactions, 4th Edition

[[Category:Which Category did you place this in?]]

Electric Force

2015-11-29T17:38:07Z

Asaxon7:

--[[User:Asaxon7|Asaxon7]] ([[User talk:Asaxon7|talk]]) 00:48, 18 November 2015 (EST) Claimed by Alayna Saxon

This page contains information on the electric force on a point charge. Electric force is created by an external [[Electric Field]].

==The Coulomb Force Law==

The formula for the magnitude of the electric force between two point charges is:

<math>|\vec F|=\frac{1}{4 \pi \epsilon_0 } \frac{|{q}_{1}{q}_{2}|}{r^2} </math>

where '''<math>{q}_{1}</math>''' and '''<math>{q}_{2}</math>''' are the magnitudes of charge of point 1 and point 2 and '''<math>r</math>''' is the distance between the two point charges. The units for electric force are in Newtons.

===Direction of Electric Force===

The electric force is along a straight line between the two point charges in the observed system. If the point charges have the same sign (i.e. both are either positively or negatively charged), then the charges repel each other. If the signs of the point charges are different (i.e. one is positively charged and one is negatively charged), then the point charges are attracted to each other.

===Derivations of Electric Force===

The electric force on a particle can also be written as:

<math>\vec F=q\vec E </math>

where '''<math>q</math>''' is the charge of the particle and '''<math>\vec E </math>''' is the external electric field.

This formula can be derived from <math>|\vec F|=\frac{1}{4 \pi \epsilon_0 } \frac{|{q}_{1}{q}_{2}|}{r^2} </math>, the electric force between two point charges. The magnitude of the electric field created by a point charge is <math>|\vec E|=\frac{1}{4 \pi \epsilon_0 } \frac{|q|}{r^2} </math>, where '''<math>q</math>''' is the magnitude of the charge of the particle and '''<math>r</math>''' is the distance between the observation location and the point charge. Therefore, the magnitude of electric force between point charge 1 and point charge 2 can be written as:

<math>|\vec F|=\frac{1}{4 \pi \epsilon_0 } \frac{|{q}_{1}{q}_{2}|}{r^2}=|{q}_{2}|\frac{1}{4 \pi \epsilon_0 } \frac{|{q}_{1}|}{r^2}=|{q}_{2}||\vec{E}_{1}| </math>

The units of charge are in Coulombs and the units for electric field are in Newton/Coulombs, so this derivation is correct in its dimensions since multiplying the two units gives just Newtons. The Newton is the unit for electric force.

==Examples==

===Example 1===

'''Problem: '''Find the magnitude of electric force on two charged particles located at <math> <0, 0, 0></math>m and <math> <0, 10, 0></math>m. The first particle has a charge of +5 nC and the second particle has a charge of -10 nC. Is the force attractive or repulsive?

'''Step 1: '''Find the distance between the two point charges.

<math>d=\sqrt{(0 m-0 m)^2+(0 m-10 m)^2+(0 m-0 m)^2}=\sqrt{100 m}=10 </math>m.

The distance between the two points is 10 m.

'''Step 2: '''Substitute values into the correct formula.

<math>|\vec F|=\frac{1}{4 \pi \epsilon_0 } \frac{|{q}_{1}{q}_{2}|}{r^2}=\frac{1}{4 \pi \epsilon_0 } \frac{|(5 nC)(-10 nC)|}{(10m)^2} </math>

<math>|\vec F|=4.5e-9 </math> N

The magnitude of electric force is <math>|\vec F|=4.5e-9 </math> N.

'''Step 3: '''Determine if force is attractive or repulsive.

Since the first particle is positively charged and the second is negatively charged, the force is attractive. The particles are attracted to each other.

===Example 2===

'''Problem: '''Find the electric force of a -3 C particle in a region with an electric field of <math><7, 5, 0></math>N/C.

'''Step 1: '''Substitute values into the correct formula.

<math>\vec F=q\vec E </math>

<math>\vec F=(-3 C)<7, 5, 0></math>N/C

<math>\vec F=<-21, -15, 0></math>N

==Connectedness==
#How is this topic connected to something that you are interested in?
#How is it connected to your major?
#Is there an interesting industrial application?

==History==

Put this idea in historical context. Give the reader the Who, What, When, Where, and Why.

== See also ==

Are there related topics or categories in this wiki resource for the curious reader to explore? How does this topic fit into that context?

===Further reading===

Books, Articles or other print media on this topic

===External links===

Internet resources on this topic

==References==

Matter & Interactions, Vol. II: Electric and Magnetic Interactions, 4th Edition

[[Category:Which Category did you place this in?]]

Electric Force

2015-11-29T17:35:31Z

Asaxon7:

--[[User:Asaxon7|Asaxon7]] ([[User talk:Asaxon7|talk]]) 00:48, 18 November 2015 (EST) Claimed by Alayna Saxon

This page contains information on the electric force on a point charge. Electric force is created by an external [[Electric Field]].

==The Coulomb Force Law==

The formula for the magnitude of the electric force between two point charges is:

<math>|\vec F|=\frac{1}{4 \pi \epsilon_0 } \frac{|{q}_{1}{q}_{2}|}{r^2} </math>

where '''<math>{q}_{1}</math>''' and '''<math>{q}_{2}</math>''' are the magnitudes of charge of point 1 and point 2 and '''<math>r</math>''' is the distance between the two point charges. The units for electric force are in Newtons.

===Direction of Electric Force===

The electric force is along a straight line between the two point charges in the observed system. If the point charges have the same sign (i.e. both are either positively or negatively charged), then the charges repel each other. If the signs of the point charges are different (i.e. one is positively charged and one is negatively charged), then the point charges are attracted to each other.

===Derivations of Electric Force===

The electric force on a particle can also be written as:

<math>\vec F=q\vec E </math>

where '''<math>q</math>''' is the charge of the particle and '''<math>\vec E </math>''' is the external electric field.

This formula can be derived from <math>|\vec F|=\frac{1}{4 \pi \epsilon_0 } \frac{|{q}_{1}{q}_{2}|}{r^2} </math>, the electric force between two point charges. The magnitude of the electric field created by a point charge is <math>|\vec E|=\frac{1}{4 \pi \epsilon_0 } \frac{|q|}{r^2} </math>, where '''<math>q</math>''' is the magnitude of the charge of the particle and '''<math>r</math>''' is the distance between the observation location and the point charge. Therefore, the magnitude of electric force between point charge 1 and point charge 2 can be written as:

<math>|\vec F|=\frac{1}{4 \pi \epsilon_0 } \frac{|{q}_{1}{q}_{2}|}{r^2}=|{q}_{2}|\frac{1}{4 \pi \epsilon_0 } \frac{|{q}_{1}|}{r^2}=|{q}_{2}||\vec{E}_{1}| </math>

The units of charge are in Coulombs and the units for electric field are in Newton/Coulombs, so this derivation is correct in its dimensions since multiplying the two units gives just Newtons. The Newton is the unit for electric force.

==Examples==

===Example 1===

'''Problem: '''Find the magnitude of electric force on two charged particles located at <math> <0, 0, 0></math>m and <math> <0, 10, 0></math>m. The first particle has a charge of +5 nC and the second particle has a charge of -10 nC. Is the force attractive or repulsive?

'''Step 1: '''Find the distance between the two point charges.

<math>d=\sqrt{(0 m-0 m)^2+(0 m-10 m)^2+(0 m-0 m)^2}=\sqrt{100 m}=10 </math>m.

The distance between the two points is 10 m.

'''Step 2: '''Substitute values into the correct formula.

<math>|\vec F|=\frac{1}{4 \pi \epsilon_0 } \frac{|{q}_{1}{q}_{2}|}{r^2}=\frac{1}{4 \pi \epsilon_0 } \frac{|(5 nC)(-10 nC)|}{(10m)^2} </math>

<math>|\vec F|=4.5e-9 </math> N

The magnitude of electric force is <math>|\vec F|=4.5e-9 </math> N.

'''Step 3: '''Determine if force is attractive or repulsive.

Since the first particle is positively charged and the second is negatively charged, the force is attractive. The particles are attracted to each other.

===Example 2===

'''Problem: '''Find the electric force of a +3 C particle in a region with an electric field of <math><7, 5, 0></math>N/C.

'''Step 1: '''Substitute values into the correct formula.

<math>\vec F=q\vec E </math>

==Connectedness==
#How is this topic connected to something that you are interested in?
#How is it connected to your major?
#Is there an interesting industrial application?

==History==

Put this idea in historical context. Give the reader the Who, What, When, Where, and Why.

== See also ==

Are there related topics or categories in this wiki resource for the curious reader to explore? How does this topic fit into that context?

===Further reading===

Books, Articles or other print media on this topic

===External links===

Internet resources on this topic

==References==

Matter & Interactions, Vol. II: Electric and Magnetic Interactions, 4th Edition

[[Category:Which Category did you place this in?]]

Electric Force

2015-11-29T17:30:34Z

Asaxon7: /* Problem 1 */

--[[User:Asaxon7|Asaxon7]] ([[User talk:Asaxon7|talk]]) 00:48, 18 November 2015 (EST) Claimed by Alayna Saxon

This page contains information on the electric force on a point charge. Electric force is created by an external [[Electric Field]].

==The Coulomb Force Law==

The formula for the magnitude of the electric force between two point charges is:

<math>|\vec F|=\frac{1}{4 \pi \epsilon_0 } \frac{|{q}_{1}{q}_{2}|}{r^2} </math>

where '''<math>{q}_{1}</math>''' and '''<math>{q}_{2}</math>''' are the magnitudes of charge of point 1 and point 2 and '''<math>r</math>''' is the distance between the two point charges. The units for electric force are in Newtons.

===Direction of Electric Force===

The electric force is along a straight line between the two point charges in the observed system. If the point charges have the same sign (i.e. both are either positively or negatively charged), then the charges repel each other. If the signs of the point charges are different (i.e. one is positively charged and one is negatively charged), then the point charges are attracted to each other.

===Derivations of Electric Force===

The electric force on a particle can also be written as:

<math>\vec F=q\vec E </math>

where '''<math>q</math>''' is the charge of the particle and '''<math>\vec E </math>''' is the external electric field.

This formula can be derived from <math>|\vec F|=\frac{1}{4 \pi \epsilon_0 } \frac{|{q}_{1}{q}_{2}|}{r^2} </math>, the electric force between two point charges. The magnitude of the electric field created by a point charge is <math>|\vec E|=\frac{1}{4 \pi \epsilon_0 } \frac{|q|}{r^2} </math>, where '''<math>q</math>''' is the magnitude of the charge of the particle and '''<math>r</math>''' is the distance between the observation location and the point charge. Therefore, the magnitude of electric force between point charge 1 and point charge 2 can be written as:

<math>|\vec F|=\frac{1}{4 \pi \epsilon_0 } \frac{|{q}_{1}{q}_{2}|}{r^2}=|{q}_{2}|\frac{1}{4 \pi \epsilon_0 } \frac{|{q}_{1}|}{r^2}=|{q}_{2}||\vec{E}_{1}| </math>

The units of charge are in Coulombs and the units for electric field are in Newton/Coulombs, so this derivation is correct in its dimensions since multiplying the two units gives just Newtons. The Newton is the unit for electric force.

==Examples==

===Problem 1===

'''Problem: '''Find the magnitude of electric force on two charged particles located at <math> <0, 0, 0></math>m and <math> <0, 10, 0></math>m. The first particle has a charge of +5 nC and the second particle has a charge of -10 nC. Is the force attractive or repulsive?

'''Step 1: '''Find the distance between the two point charges.

<math>d=\sqrt{(0 m-0 m)^2+(0 m-10 m)^2+(0 m-0 m)^2}=\sqrt{100 m}=10 </math>m.

The distance between the two points is 10 m.

'''Step 2: '''Substitute values into the correct formula.

<math>|\vec F|=\frac{1}{4 \pi \epsilon_0 } \frac{|{q}_{1}{q}_{2}|}{r^2}=\frac{1}{4 \pi \epsilon_0 } \frac{|(5 nC)(-10 nC)|}{(10m)^2} </math>

<math>|\vec F|=4.5e-9 </math> N

The magnitude of electric force is <math>|\vec F|=4.5e-9 </math> N.

'''Step 3: '''Determine if force is attractive or repulsive.

Since the first particle is positively charged and the second is negatively charged, the force is attractive. The particles are attracted to each other.

===Middling===
===Difficult===

==Connectedness==
#How is this topic connected to something that you are interested in?
#How is it connected to your major?
#Is there an interesting industrial application?

==History==

Put this idea in historical context. Give the reader the Who, What, When, Where, and Why.

== See also ==

Are there related topics or categories in this wiki resource for the curious reader to explore? How does this topic fit into that context?

===Further reading===

Books, Articles or other print media on this topic

===External links===

Internet resources on this topic

==References==

Matter & Interactions, Vol. II: Electric and Magnetic Interactions, 4th Edition

[[Category:Which Category did you place this in?]]

Electric Force

2015-11-29T16:07:34Z

Asaxon7: /* Examples */

--[[User:Asaxon7|Asaxon7]] ([[User talk:Asaxon7|talk]]) 00:48, 18 November 2015 (EST) Claimed by Alayna Saxon

This page contains information on the electric force on a point charge. Electric force is created by an external [[Electric Field]].

==The Coulomb Force Law==

The formula for the magnitude of the electric force between two point charges is:

<math>|\vec F|=\frac{1}{4 \pi \epsilon_0 } \frac{|{q}_{1}{q}_{2}|}{r^2} </math>

where '''<math>{q}_{1}</math>''' and '''<math>{q}_{2}</math>''' are the magnitudes of charge of point 1 and point 2 and '''<math>r</math>''' is the distance between the two point charges. The units for electric force are in Newtons.

===Direction of Electric Force===

The electric force is along a straight line between the two point charges in the observed system. If the point charges have the same sign (i.e. both are either positively or negatively charged), then the charges repel each other. If the signs of the point charges are different (i.e. one is positively charged and one is negatively charged), then the point charges are attracted to each other.

===Derivations of Electric Force===

The electric force on a particle can also be written as:

<math>\vec F=q\vec E </math>

where '''<math>q</math>''' is the charge of the particle and '''<math>\vec E </math>''' is the external electric field.

This formula can be derived from <math>|\vec F|=\frac{1}{4 \pi \epsilon_0 } \frac{|{q}_{1}{q}_{2}|}{r^2} </math>, the electric force between two point charges. The magnitude of the electric field created by a point charge is <math>|\vec E|=\frac{1}{4 \pi \epsilon_0 } \frac{|q|}{r^2} </math>, where '''<math>q</math>''' is the magnitude of the charge of the particle and '''<math>r</math>''' is the distance between the observation location and the point charge. Therefore, the magnitude of electric force between point charge 1 and point charge 2 can be written as:

<math>|\vec F|=\frac{1}{4 \pi \epsilon_0 } \frac{|{q}_{1}{q}_{2}|}{r^2}=|{q}_{2}|\frac{1}{4 \pi \epsilon_0 } \frac{|{q}_{1}|}{r^2}=|{q}_{2}||\vec{E}_{1}| </math>

The units of charge are in Coulombs and the units for electric field are in Newton/Coulombs, so this derivation is correct in its dimensions since multiplying the two units gives just Newtons. The Newton is the unit for electric force.

==Examples==

===Problem 1===

'''Problem: '''Find the magnitude of electric force on two charged particles located at <math> <0, 0, 0></math>m and <math> <0, 10, 0></math>m. The first particle has a charge of +5 nC and the second particle has a charge of -10 nC. Is the force attractive or repulsive?

'''Step 1: '''Find the distance between the two point charges.

<math>d=\sqrt{(0 m-0 m)^2+(0 m-10 m)^2+(0 m-0 m)^2}=\sqrt{100 m}=10 </math>m.

The distance between the two points is 10 m.

'''Step 2: '''Substitute values into the correct formula.

<math>|\vec F|=\frac{1}{4 \pi \epsilon_0 } \frac{|{q}_{1}{q}_{2}|}{r^2}=\frac{1}{4 \pi \epsilon_0 } \frac{|(5 nC)(-10 nC)|}{(10m)^2} </math>

<math>|\vec F|=4.5e-9 </math> N

===Middling===
===Difficult===

==Connectedness==
#How is this topic connected to something that you are interested in?
#How is it connected to your major?
#Is there an interesting industrial application?

==History==

Put this idea in historical context. Give the reader the Who, What, When, Where, and Why.

== See also ==

Are there related topics or categories in this wiki resource for the curious reader to explore? How does this topic fit into that context?

===Further reading===

Books, Articles or other print media on this topic

===External links===

Internet resources on this topic

==References==

Matter & Interactions, Vol. II: Electric and Magnetic Interactions, 4th Edition

[[Category:Which Category did you place this in?]]

Electric Force

2015-11-29T16:07:22Z

Asaxon7: /* Examples */

--[[User:Asaxon7|Asaxon7]] ([[User talk:Asaxon7|talk]]) 00:48, 18 November 2015 (EST) Claimed by Alayna Saxon

This page contains information on the electric force on a point charge. Electric force is created by an external [[Electric Field]].

==The Coulomb Force Law==

The formula for the magnitude of the electric force between two point charges is:

<math>|\vec F|=\frac{1}{4 \pi \epsilon_0 } \frac{|{q}_{1}{q}_{2}|}{r^2} </math>

where '''<math>{q}_{1}</math>''' and '''<math>{q}_{2}</math>''' are the magnitudes of charge of point 1 and point 2 and '''<math>r</math>''' is the distance between the two point charges. The units for electric force are in Newtons.

===Direction of Electric Force===

The electric force is along a straight line between the two point charges in the observed system. If the point charges have the same sign (i.e. both are either positively or negatively charged), then the charges repel each other. If the signs of the point charges are different (i.e. one is positively charged and one is negatively charged), then the point charges are attracted to each other.

===Derivations of Electric Force===

The electric force on a particle can also be written as:

<math>\vec F=q\vec E </math>

where '''<math>q</math>''' is the charge of the particle and '''<math>\vec E </math>''' is the external electric field.

This formula can be derived from <math>|\vec F|=\frac{1}{4 \pi \epsilon_0 } \frac{|{q}_{1}{q}_{2}|}{r^2} </math>, the electric force between two point charges. The magnitude of the electric field created by a point charge is <math>|\vec E|=\frac{1}{4 \pi \epsilon_0 } \frac{|q|}{r^2} </math>, where '''<math>q</math>''' is the magnitude of the charge of the particle and '''<math>r</math>''' is the distance between the observation location and the point charge. Therefore, the magnitude of electric force between point charge 1 and point charge 2 can be written as:

<math>|\vec F|=\frac{1}{4 \pi \epsilon_0 } \frac{|{q}_{1}{q}_{2}|}{r^2}=|{q}_{2}|\frac{1}{4 \pi \epsilon_0 } \frac{|{q}_{1}|}{r^2}=|{q}_{2}||\vec{E}_{1}| </math>

The units of charge are in Coulombs and the units for electric field are in Newton/Coulombs, so this derivation is correct in its dimensions since multiplying the two units gives just Newtons. The Newton is the unit for electric force.

==Examples==

===Problem 1===

'''Problem: '''Find the magnitude of electric force on two charged particles located at <math> <0, 0, 0></math>m and <math> <0, 10, 0></math>m. The first particle has a charge of +5 nC and the second particle has a charge of -10 nC. Is the force attractive or repulsive?

'''Step 1: '''Find the distance between the two point charges.

<math>d=\sqrt{(0 m-0 m)^2+(0 m-10 m)^2+(0 m-0 m)^2}=\sqrt{100 m}=10 </math>m.

The distance between the two points is 10 m.

'''Step 2: '''Substitute values into the correct formula.

<math>|\vec F|=\frac{1}{4 \pi \epsilon_0 } \frac{|{q}_{1}{q}_{2}|}{r^2}=\frac{1}{4 \pi \epsilon_0 } \frac{|(5 nC)(-10 nC)|}{(10m)^2} </math>

<math>|\vec F|=4.5e-9 </math>N

===Middling===
===Difficult===

==Connectedness==
#How is this topic connected to something that you are interested in?
#How is it connected to your major?
#Is there an interesting industrial application?

==History==

Put this idea in historical context. Give the reader the Who, What, When, Where, and Why.

== See also ==

Are there related topics or categories in this wiki resource for the curious reader to explore? How does this topic fit into that context?

===Further reading===

Books, Articles or other print media on this topic

===External links===

Internet resources on this topic

==References==

Matter & Interactions, Vol. II: Electric and Magnetic Interactions, 4th Edition

[[Category:Which Category did you place this in?]]

Electric Force

2015-11-29T16:06:49Z

Asaxon7: /* Examples */

--[[User:Asaxon7|Asaxon7]] ([[User talk:Asaxon7|talk]]) 00:48, 18 November 2015 (EST) Claimed by Alayna Saxon

This page contains information on the electric force on a point charge. Electric force is created by an external [[Electric Field]].

==The Coulomb Force Law==

The formula for the magnitude of the electric force between two point charges is:

<math>|\vec F|=\frac{1}{4 \pi \epsilon_0 } \frac{|{q}_{1}{q}_{2}|}{r^2} </math>

where '''<math>{q}_{1}</math>''' and '''<math>{q}_{2}</math>''' are the magnitudes of charge of point 1 and point 2 and '''<math>r</math>''' is the distance between the two point charges. The units for electric force are in Newtons.

===Direction of Electric Force===

The electric force is along a straight line between the two point charges in the observed system. If the point charges have the same sign (i.e. both are either positively or negatively charged), then the charges repel each other. If the signs of the point charges are different (i.e. one is positively charged and one is negatively charged), then the point charges are attracted to each other.

===Derivations of Electric Force===

The electric force on a particle can also be written as:

<math>\vec F=q\vec E </math>

where '''<math>q</math>''' is the charge of the particle and '''<math>\vec E </math>''' is the external electric field.

This formula can be derived from <math>|\vec F|=\frac{1}{4 \pi \epsilon_0 } \frac{|{q}_{1}{q}_{2}|}{r^2} </math>, the electric force between two point charges. The magnitude of the electric field created by a point charge is <math>|\vec E|=\frac{1}{4 \pi \epsilon_0 } \frac{|q|}{r^2} </math>, where '''<math>q</math>''' is the magnitude of the charge of the particle and '''<math>r</math>''' is the distance between the observation location and the point charge. Therefore, the magnitude of electric force between point charge 1 and point charge 2 can be written as:

<math>|\vec F|=\frac{1}{4 \pi \epsilon_0 } \frac{|{q}_{1}{q}_{2}|}{r^2}=|{q}_{2}|\frac{1}{4 \pi \epsilon_0 } \frac{|{q}_{1}|}{r^2}=|{q}_{2}||\vec{E}_{1}| </math>

The units of charge are in Coulombs and the units for electric field are in Newton/Coulombs, so this derivation is correct in its dimensions since multiplying the two units gives just Newtons. The Newton is the unit for electric force.

==Examples==

===Problem 1===

'''Problem: '''Find the magnitude of electric force on two charged particles located at <math> <0, 0, 0></math>m and <math> <0, 10, 0></math>m. The first particle has a charge of +5 nC and the second particle has a charge of -10 nC. Is the force attractive or repulsive?

'''Step 1: '''Find the distance between the two point charges.

<math>d=\sqrt{(0 m-0 m)^2+(0 m-10 m)^2+(0 m-0 m)^2}=\sqrt{100 m}=10 </math>m.

The distance between the two points is 10 m.

'''Step 2: '''Substitute values into the correct formula.

<math>|\vec F|=\frac{1}{4 \pi \epsilon_0 } \frac{|{q}_{1}{q}_{2}|}{r^2}=\frac{1}{4 \pi \epsilon_0 } \frac{|(5 nC)(-10 nC)|}{(10m)^2} </math>

<math>|\vec F|=4.5(10)^(-9) </math>N

===Middling===
===Difficult===

==Connectedness==
#How is this topic connected to something that you are interested in?
#How is it connected to your major?
#Is there an interesting industrial application?

==History==

Put this idea in historical context. Give the reader the Who, What, When, Where, and Why.

== See also ==

Are there related topics or categories in this wiki resource for the curious reader to explore? How does this topic fit into that context?

===Further reading===

Books, Articles or other print media on this topic

===External links===

Internet resources on this topic

==References==

Matter & Interactions, Vol. II: Electric and Magnetic Interactions, 4th Edition

[[Category:Which Category did you place this in?]]

Electric Force

2015-11-29T16:06:24Z

Asaxon7: /* Examples */

--[[User:Asaxon7|Asaxon7]] ([[User talk:Asaxon7|talk]]) 00:48, 18 November 2015 (EST) Claimed by Alayna Saxon

This page contains information on the electric force on a point charge. Electric force is created by an external [[Electric Field]].

==The Coulomb Force Law==

The formula for the magnitude of the electric force between two point charges is:

<math>|\vec F|=\frac{1}{4 \pi \epsilon_0 } \frac{|{q}_{1}{q}_{2}|}{r^2} </math>

where '''<math>{q}_{1}</math>''' and '''<math>{q}_{2}</math>''' are the magnitudes of charge of point 1 and point 2 and '''<math>r</math>''' is the distance between the two point charges. The units for electric force are in Newtons.

===Direction of Electric Force===

The electric force is along a straight line between the two point charges in the observed system. If the point charges have the same sign (i.e. both are either positively or negatively charged), then the charges repel each other. If the signs of the point charges are different (i.e. one is positively charged and one is negatively charged), then the point charges are attracted to each other.

===Derivations of Electric Force===

The electric force on a particle can also be written as:

<math>\vec F=q\vec E </math>

where '''<math>q</math>''' is the charge of the particle and '''<math>\vec E </math>''' is the external electric field.

This formula can be derived from <math>|\vec F|=\frac{1}{4 \pi \epsilon_0 } \frac{|{q}_{1}{q}_{2}|}{r^2} </math>, the electric force between two point charges. The magnitude of the electric field created by a point charge is <math>|\vec E|=\frac{1}{4 \pi \epsilon_0 } \frac{|q|}{r^2} </math>, where '''<math>q</math>''' is the magnitude of the charge of the particle and '''<math>r</math>''' is the distance between the observation location and the point charge. Therefore, the magnitude of electric force between point charge 1 and point charge 2 can be written as:

<math>|\vec F|=\frac{1}{4 \pi \epsilon_0 } \frac{|{q}_{1}{q}_{2}|}{r^2}=|{q}_{2}|\frac{1}{4 \pi \epsilon_0 } \frac{|{q}_{1}|}{r^2}=|{q}_{2}||\vec{E}_{1}| </math>

The units of charge are in Coulombs and the units for electric field are in Newton/Coulombs, so this derivation is correct in its dimensions since multiplying the two units gives just Newtons. The Newton is the unit for electric force.

==Examples==

===Problem 1===

'''Problem: '''Find the magnitude of electric force on two charged particles located at <math> <0, 0, 0></math>m and <math> <0, 10, 0></math>m. The first particle has a charge of +5 nC and the second particle has a charge of -10 nC. Is the force attractive or repulsive?

'''Step 1: '''Find the distance between the two point charges.

<math>d=\sqrt{(0 m-0 m)^2+(0 m-10 m)^2+(0 m-0 m)^2}=\sqrt{100 m}=10 </math>m.

The distance between the two points is 10 m.

'''Step 2: '''Substitute values into the correct formula.

<math>|\vec F|=\frac{1}{4 \pi \epsilon_0 } \frac{|{q}_{1}{q}_{2}|}{r^2}=\frac{1}{4 \pi \epsilon_0 } \frac{|(5 nC)(-10 nC)|}{(10m)^2} </math>

<math>|\vec F|=4.5(10)^-9 </math>N

===Middling===
===Difficult===

==Connectedness==
#How is this topic connected to something that you are interested in?
#How is it connected to your major?
#Is there an interesting industrial application?

==History==

Put this idea in historical context. Give the reader the Who, What, When, Where, and Why.

== See also ==

Are there related topics or categories in this wiki resource for the curious reader to explore? How does this topic fit into that context?

===Further reading===

Books, Articles or other print media on this topic

===External links===

Internet resources on this topic

==References==

Matter & Interactions, Vol. II: Electric and Magnetic Interactions, 4th Edition

[[Category:Which Category did you place this in?]]

Electric Force

2015-11-29T16:05:18Z

Asaxon7: /* Examples */

--[[User:Asaxon7|Asaxon7]] ([[User talk:Asaxon7|talk]]) 00:48, 18 November 2015 (EST) Claimed by Alayna Saxon

This page contains information on the electric force on a point charge. Electric force is created by an external [[Electric Field]].

==The Coulomb Force Law==

The formula for the magnitude of the electric force between two point charges is:

<math>|\vec F|=\frac{1}{4 \pi \epsilon_0 } \frac{|{q}_{1}{q}_{2}|}{r^2} </math>

where '''<math>{q}_{1}</math>''' and '''<math>{q}_{2}</math>''' are the magnitudes of charge of point 1 and point 2 and '''<math>r</math>''' is the distance between the two point charges. The units for electric force are in Newtons.

===Direction of Electric Force===

The electric force is along a straight line between the two point charges in the observed system. If the point charges have the same sign (i.e. both are either positively or negatively charged), then the charges repel each other. If the signs of the point charges are different (i.e. one is positively charged and one is negatively charged), then the point charges are attracted to each other.

===Derivations of Electric Force===

The electric force on a particle can also be written as:

<math>\vec F=q\vec E </math>

where '''<math>q</math>''' is the charge of the particle and '''<math>\vec E </math>''' is the external electric field.

This formula can be derived from <math>|\vec F|=\frac{1}{4 \pi \epsilon_0 } \frac{|{q}_{1}{q}_{2}|}{r^2} </math>, the electric force between two point charges. The magnitude of the electric field created by a point charge is <math>|\vec E|=\frac{1}{4 \pi \epsilon_0 } \frac{|q|}{r^2} </math>, where '''<math>q</math>''' is the magnitude of the charge of the particle and '''<math>r</math>''' is the distance between the observation location and the point charge. Therefore, the magnitude of electric force between point charge 1 and point charge 2 can be written as:

<math>|\vec F|=\frac{1}{4 \pi \epsilon_0 } \frac{|{q}_{1}{q}_{2}|}{r^2}=|{q}_{2}|\frac{1}{4 \pi \epsilon_0 } \frac{|{q}_{1}|}{r^2}=|{q}_{2}||\vec{E}_{1}| </math>

The units of charge are in Coulombs and the units for electric field are in Newton/Coulombs, so this derivation is correct in its dimensions since multiplying the two units gives just Newtons. The Newton is the unit for electric force.

==Examples==

===Problem 1===

'''Problem: '''Find the magnitude of electric force on two charged particles located at <math> <0, 0, 0></math>m and <math> <0, 10, 0></math>m. The first particle has a charge of +5 nC and the second particle has a charge of -10 nC. Is the force attractive or repulsive?

'''Step 1: '''Find the distance between the two point charges.

<math>d=\sqrt{(0 m-0 m)^2+(0 m-10 m)^2+(0 m-0 m)^2}=\sqrt{100 m}=10 </math>m.

The distance between the two points is 10 m.

'''Step 2: '''Substitute values into the correct formula.

<math>|\vec F|=\frac{1}{4 \pi \epsilon_0 } \frac{|{q}_{1}{q}_{2}|}{r^2}=\frac{1}{4 \pi \epsilon_0 } \frac{|(5 nC)(-10 nC)|}{(10m)^2} </math>

<math>|\vec F|=4.5x(10)^(-9) </math>N

===Middling===
===Difficult===

==Connectedness==
#How is this topic connected to something that you are interested in?
#How is it connected to your major?
#Is there an interesting industrial application?

==History==

Put this idea in historical context. Give the reader the Who, What, When, Where, and Why.

== See also ==

Are there related topics or categories in this wiki resource for the curious reader to explore? How does this topic fit into that context?

===Further reading===

Books, Articles or other print media on this topic

===External links===

Internet resources on this topic

==References==

Matter & Interactions, Vol. II: Electric and Magnetic Interactions, 4th Edition

[[Category:Which Category did you place this in?]]

Electric Force

2015-11-29T16:04:24Z

Asaxon7:

--[[User:Asaxon7|Asaxon7]] ([[User talk:Asaxon7|talk]]) 00:48, 18 November 2015 (EST) Claimed by Alayna Saxon

This page contains information on the electric force on a point charge. Electric force is created by an external [[Electric Field]].

==The Coulomb Force Law==

The formula for the magnitude of the electric force between two point charges is:

<math>|\vec F|=\frac{1}{4 \pi \epsilon_0 } \frac{|{q}_{1}{q}_{2}|}{r^2} </math>

where '''<math>{q}_{1}</math>''' and '''<math>{q}_{2}</math>''' are the magnitudes of charge of point 1 and point 2 and '''<math>r</math>''' is the distance between the two point charges. The units for electric force are in Newtons.

===Direction of Electric Force===

The electric force is along a straight line between the two point charges in the observed system. If the point charges have the same sign (i.e. both are either positively or negatively charged), then the charges repel each other. If the signs of the point charges are different (i.e. one is positively charged and one is negatively charged), then the point charges are attracted to each other.

===Derivations of Electric Force===

The electric force on a particle can also be written as:

<math>\vec F=q\vec E </math>

where '''<math>q</math>''' is the charge of the particle and '''<math>\vec E </math>''' is the external electric field.

This formula can be derived from <math>|\vec F|=\frac{1}{4 \pi \epsilon_0 } \frac{|{q}_{1}{q}_{2}|}{r^2} </math>, the electric force between two point charges. The magnitude of the electric field created by a point charge is <math>|\vec E|=\frac{1}{4 \pi \epsilon_0 } \frac{|q|}{r^2} </math>, where '''<math>q</math>''' is the magnitude of the charge of the particle and '''<math>r</math>''' is the distance between the observation location and the point charge. Therefore, the magnitude of electric force between point charge 1 and point charge 2 can be written as:

<math>|\vec F|=\frac{1}{4 \pi \epsilon_0 } \frac{|{q}_{1}{q}_{2}|}{r^2}=|{q}_{2}|\frac{1}{4 \pi \epsilon_0 } \frac{|{q}_{1}|}{r^2}=|{q}_{2}||\vec{E}_{1}| </math>

The units of charge are in Coulombs and the units for electric field are in Newton/Coulombs, so this derivation is correct in its dimensions since multiplying the two units gives just Newtons. The Newton is the unit for electric force.

==Examples==

===Problem 1===

'''Problem: '''Find the magnitude of electric force on two charged particles located at <math> <0, 0, 0></math>m and <math> <0, 10, 0></math>m. The first particle has a charge of +5 nC and the second particle has a charge of -10 nC. Is the force attractive or repulsive?

'''Step 1: '''Find the distance between the two point charges.

<math>d=\sqrt{(0 m-0 m)^2+(0 m-10 m)^2+(0 m-0 m)^2}=\sqrt{100 m}=10 </math>m.

The distance between the two points is 10 m.

'''Step 2: '''Substitute values into the correct formula.

<math>|\vec F|=\frac{1}{4 \pi \epsilon_0 } \frac{|{q}_{1}{q}_{2}|}{r^2}=\frac{1}{4 \pi \epsilon_0 } \frac{|(5 nC)(-10 nC)|}{(10m)^2} </math>

===Middling===
===Difficult===

==Connectedness==
#How is this topic connected to something that you are interested in?
#How is it connected to your major?
#Is there an interesting industrial application?

==History==

Put this idea in historical context. Give the reader the Who, What, When, Where, and Why.

== See also ==

Are there related topics or categories in this wiki resource for the curious reader to explore? How does this topic fit into that context?

===Further reading===

Books, Articles or other print media on this topic

===External links===

Internet resources on this topic

==References==

Matter & Interactions, Vol. II: Electric and Magnetic Interactions, 4th Edition

[[Category:Which Category did you place this in?]]

Electric Force

2015-11-29T15:59:36Z

Asaxon7:

--[[User:Asaxon7|Asaxon7]] ([[User talk:Asaxon7|talk]]) 00:48, 18 November 2015 (EST) Claimed by Alayna Saxon

This page contains information on the electric force on a point charge. Electric force is created by an external [[Electric Field]].

==The Coulomb Force Law==

The formula for the magnitude of the electric force between two point charges is:

<math>|\vec F|=\frac{1}{4 \pi \epsilon_0 } \frac{|{q}_{1}{q}_{2}|}{r^2} </math>

where '''<math>{q}_{1}</math>''' and '''<math>{q}_{2}</math>''' are the magnitudes of charge of point 1 and point 2 and '''<math>r</math>''' is the distance between the two point charges. The units for electric force are in Newtons.

===Direction of Electric Force===

The electric force is along a straight line between the two point charges in the observed system. If the point charges have the same sign (i.e. both are either positively or negatively charged), then the charges repel each other. If the signs of the point charges are different (i.e. one is positively charged and one is negatively charged), then the point charges are attracted to each other.

===Derivations of Electric Force===

The electric force on a particle can also be written as:

<math>\vec F=q\vec E </math>

where '''<math>q</math>''' is the charge of the particle and '''<math>\vec E </math>''' is the external electric field.

This formula can be derived from <math>|\vec F|=\frac{1}{4 \pi \epsilon_0 } \frac{|{q}_{1}{q}_{2}|}{r^2} </math>, the electric force between two point charges. The magnitude of the electric field created by a point charge is <math>|\vec E|=\frac{1}{4 \pi \epsilon_0 } \frac{|q|}{r^2} </math>, where '''<math>q</math>''' is the magnitude of the charge of the particle and '''<math>r</math>''' is the distance between the observation location and the point charge. Therefore, the magnitude of electric force between point charge 1 and point charge 2 can be written as:

<math>|\vec F|=\frac{1}{4 \pi \epsilon_0 } \frac{|{q}_{1}{q}_{2}|}{r^2}=|{q}_{2}|\frac{1}{4 \pi \epsilon_0 } \frac{|{q}_{1}|}{r^2}=|{q}_{2}||\vec{E}_{1}| </math>

The units of charge are in Coulombs and the units for electric field are in Newton/Coulombs, so this derivation is correct in its dimensions since multiplying the two units gives just Newtons. The Newton is the unit for electric force.

==Examples==

Be sure to show all steps in your solution and include diagrams whenever possible

===Problem 1===

'''Problem: '''Find the magnitude of electric force on two charged particles located at <math> <0, 0, 0></math>m and <math> <0, 10, 0></math>m. The first particle has a charge of +5 nC and the second particle has a charge of -10 nC. Is the force attractive or repulsive?

'''Step 1: '''Find the distance between the two point charges.

<math>d=\sqrt{(0 m-0 m)^2+(0 m-10 m)^2+(0 m-0 m)^2}=\sqrt{100 m}=10 </math>m.

The distance between the two points is 10 m.

'''Step 2: '''Substitute values into the correct formula.

<math>|\vec F|=\frac{1}{4 \pi \epsilon_0 } \frac{|{q}_{1}{q}_{2}|}{r^2}=\frac{1}{4 \pi \epsilon_0 } \frac{|(5 nC)(-10 nC)|}{(10m)^2} </math>

===Middling===
===Difficult===

==Connectedness==
#How is this topic connected to something that you are interested in?
#How is it connected to your major?
#Is there an interesting industrial application?

==History==

Put this idea in historical context. Give the reader the Who, What, When, Where, and Why.

== See also ==

Are there related topics or categories in this wiki resource for the curious reader to explore? How does this topic fit into that context?

===Further reading===

Books, Articles or other print media on this topic

===External links===

Internet resources on this topic

==References==

Matter & Interactions, Vol. II: Electric and Magnetic Interactions, 4th Edition

[[Category:Which Category did you place this in?]]

Electric Force

2015-11-29T15:35:36Z

Asaxon7:

--[[User:Asaxon7|Asaxon7]] ([[User talk:Asaxon7|talk]]) 00:48, 18 November 2015 (EST) Claimed by Alayna Saxon

This page contains information on the electric force on a point charge. Electric force is created by an external [[Electric Field]].

==The Coulomb Force Law==

The formula for the magnitude of the electric force between two point charges is:

<math>|\vec F|=\frac{1}{4 \pi \epsilon_0 } \frac{|{q}_{1}{q}_{2}|}{r^2} </math>

where '''<math>{q}_{1}</math>''' and '''<math>{q}_{2}</math>''' are the magnitudes of charge of point 1 and point 2 and '''<math>r</math>''' is the distance between the two point charges. The units for electric force are in Newtons.

===Direction of Electric Force===

The electric force is along a straight line between the two point charges in the observed system. If the point charges have the same sign (i.e. both are either positively or negatively charged), then the charges repel each other. If the signs of the point charges are different (i.e. one is positively charged and one is negatively charged), then the point charges are attracted to each other.

===Derivations of Electric Force===

The electric force on a particle can also be written as:

<math>\vec F=q\vec E </math>

where '''<math>q</math>''' is the charge of the particle and '''<math>\vec E </math>''' is the external electric field.

This formula can be derived from <math>|\vec F|=\frac{1}{4 \pi \epsilon_0 } \frac{|{q}_{1}{q}_{2}|}{r^2} </math>, the electric force between two point charges. The magnitude of the electric field created by a point charge is <math>|\vec E|=\frac{1}{4 \pi \epsilon_0 } \frac{|q|}{r^2} </math>, where '''<math>q</math>''' is the magnitude of the charge of the particle and '''<math>r</math>''' is the distance between the observation location and the point charge. Therefore, the magnitude of electric force between point charge 1 and point charge 2 can be written as:

<math>|\vec F|=\frac{1}{4 \pi \epsilon_0 } \frac{|{q}_{1}{q}_{2}|}{r^2}=|{q}_{2}|\frac{1}{4 \pi \epsilon_0 } \frac{|{q}_{1}|}{r^2}=|{q}_{2}||\vec{E}_{1}| </math>

The units of charge are in Coulombs and the units for electric field are in Newton/Coulombs, so this derivation is correct in its dimensions since multiplying the two units gives just Newtons. The Newton is the unit for electric force.

==Examples==

Be sure to show all steps in your solution and include diagrams whenever possible

===Problem 1===

'''Problem: '''Find the magnitude of electric force on two charged particles located at <math> <0, 0, 0></math>m and <math> <0, 10, 0></math>m. The first particle has a charge of +5 C and the second particle has a charge of -10 C. Is the force attractive or repulsive?

'''Step 1: '''Find the distance between the two point charges.

<math>d=\sqrt{(0 m-0 m)^2+(0 m-10 m)^2+(0 m-0 m)^2}=\sqrt{100 m}</math>

===Middling===
===Difficult===

==Connectedness==
#How is this topic connected to something that you are interested in?
#How is it connected to your major?
#Is there an interesting industrial application?

==History==

Put this idea in historical context. Give the reader the Who, What, When, Where, and Why.

== See also ==

Are there related topics or categories in this wiki resource for the curious reader to explore? How does this topic fit into that context?

===Further reading===

Books, Articles or other print media on this topic

===External links===

Internet resources on this topic

==References==

Matter & Interactions, Vol. II: Electric and Magnetic Interactions, 4th Edition

[[Category:Which Category did you place this in?]]

Electric Force

2015-11-29T15:32:26Z

Asaxon7:

--[[User:Asaxon7|Asaxon7]] ([[User talk:Asaxon7|talk]]) 00:48, 18 November 2015 (EST) Claimed by Alayna Saxon

This page contains information on the electric force on a point charge. Electric force is created by an external [[Electric Field]].

==The Coulomb Force Law==

The formula for the magnitude of the electric force between two point charges is:

<math>|\vec F|=\frac{1}{4 \pi \epsilon_0 } \frac{|{q}_{1}{q}_{2}|}{r^2} </math>

where '''<math>{q}_{1}</math>''' and '''<math>{q}_{2}</math>''' are the magnitudes of charge of point 1 and point 2 and '''<math>r</math>''' is the distance between the two point charges. The units for electric force are in Newtons.

===Direction of Electric Force===

The electric force is along a straight line between the two point charges in the observed system. If the point charges have the same sign (i.e. both are either positively or negatively charged), then the charges repel each other. If the signs of the point charges are different (i.e. one is positively charged and one is negatively charged), then the point charges are attracted to each other.

===Derivations of Electric Force===

The electric force on a particle can also be written as:

<math>\vec F=q\vec E </math>

where '''<math>q</math>''' is the charge of the particle and '''<math>\vec E </math>''' is the external electric field.

This formula can be derived from <math>|\vec F|=\frac{1}{4 \pi \epsilon_0 } \frac{|{q}_{1}{q}_{2}|}{r^2} </math>, the electric force between two point charges. The magnitude of the electric field created by a point charge is <math>|\vec E|=\frac{1}{4 \pi \epsilon_0 } \frac{|q|}{r^2} </math>, where '''<math>q</math>''' is the magnitude of the charge of the particle and '''<math>r</math>''' is the distance between the observation location and the point charge. Therefore, the magnitude of electric force between point charge 1 and point charge 2 can be written as:

<math>|\vec F|=\frac{1}{4 \pi \epsilon_0 } \frac{|{q}_{1}{q}_{2}|}{r^2}=|{q}_{2}|\frac{1}{4 \pi \epsilon_0 } \frac{|{q}_{1}|}{r^2}=|{q}_{2}||\vec{E}_{1}| </math>

The units of charge are in Coulombs and the units for electric field are in Newton/Coulombs, so this derivation is correct in its dimensions since multiplying the two units gives just Newtons. The Newton is the unit for electric force.

==Examples==

Be sure to show all steps in your solution and include diagrams whenever possible

===Problem 1===

'''Problem: '''Find the magnitude of electric force on two charged particles located at <math> <0, 0, 0> </math> and <math> <0, 10, 0> </math>. The first particle has a charge of +5 C and the second particle has a charge of -10 C. Is the force attractive or repulsive?

'''Step 1: '''Find the distance between the two point charges.

<math>d=\sqrt{(0-0)^2+(0-10)^2+(0-0)^2}=\sqrt{100}</math>

===Middling===
===Difficult===

==Connectedness==
#How is this topic connected to something that you are interested in?
#How is it connected to your major?
#Is there an interesting industrial application?

==History==

Put this idea in historical context. Give the reader the Who, What, When, Where, and Why.

== See also ==

Are there related topics or categories in this wiki resource for the curious reader to explore? How does this topic fit into that context?

===Further reading===

Books, Articles or other print media on this topic

===External links===

Internet resources on this topic

==References==

Matter & Interactions, Vol. II: Electric and Magnetic Interactions, 4th Edition

[[Category:Which Category did you place this in?]]

Electric Force

2015-11-29T15:28:46Z

Asaxon7: /* Examples */

Electric Force

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Asaxon7:

Electric Force

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Electric Force

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Electric Force

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Asaxon7: /* References */

Electric Force

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Asaxon7: /* Derivations of Electric Force */

Electric Force

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Asaxon7: /* The Coulomb Force Law */

Electric Force

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Asaxon7: /* Derivations of Electric Force */

Electric Force

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Asaxon7: /* The Coulomb Force Law */

Electric Force

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Asaxon7: /* The Coulomb Force Law */

Electric Force

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Asaxon7: /* The Coulomb Force Law */

Electric Force

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Asaxon7: /* The Coulomb Force Law */

Electric Force

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Asaxon7: /* Derivations of Electric Force */

Electric Force

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Asaxon7: /* Derivations of Electric Force */

Electric Force

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Asaxon7: /* Derivations of Electric Force */

Electric Force

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Asaxon7: /* The Coulomb Force Law */

Electric Force

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Asaxon7: /* The Coulomb Force Law */

Electric Force

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Asaxon7: /* The Coulomb Force Law */

Electric Force

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Asaxon7: /* The Coulomb Force Law */

Electric Force

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Asaxon7: /* The Coulomb Force Law */

Electric Force

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Asaxon7: /* The Coulomb Force Law */

Electric Force

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Asaxon7: /* The Coulomb Force Law */

Electric Force

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Asaxon7: /* The Coulomb Force Law */

Electric Force

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Asaxon7: /* The Coulomb Force Law */

Electric Force

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Asaxon7: /* The Coulomb Force Law */

Electric Force

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Asaxon7: /* The Coulomb Force Law */

Electric Force

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Asaxon7: /* The Coulomb Force Law */

Electric Force

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Asaxon7: /* The Coulomb Force Law */

Electric Force

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Asaxon7: /* The Coulomb Force Law */