Terminal Speed: Difference between revisions

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==Acceleration of Falling Objects==


When you drop an object from a certain height off the ground, you can observe that the speed of the object does not remain constant throughout that object's free fall.  The object's speed changes as it falls and we know from the momentum principle that this is due to a net force acting on the object( Fnet = dp/dt ).  If you drop an object from a tall enough starting height, you can also observe that the acceleration of the object is not constant either, so one can conclude that the net force on the object is not constant.  An object falling towards the Earth's surface will not accelerate indefinitely, but will reach what is called ' ' terminal velocity ' '.  Odds are you are familiar with the force of gravity, the force that holds you to Earth's surface and causes an object to accelerate initially downward.  Gravity is defined as F=mg, where g is the acceleration constant of 9.8 m/s^2 (on Earth), and is a constant force.  Another force, friction, is also acting on a falling object, however. This friction is due to the contact between molecules of the falling object and air molecules and is non-constant through the objects free-fall.  In the following sections we will look into greater detail the effects of friction due to air.


===Falling Objects in a Vacuum===


As stated above, the force due to gravity on an object is constant. This can be proven by an object that is in free fall and is also in a vacuum. When an object is falling within a vacuum, it can be observed to have constant acceleration of 9.8 m/s^2 regardless of its mass or size.  In the following video, a feather and a ball bearing are dropped inside a vacuum. See how both objects fall at the same rate. (Click on the picture)
 
==Main Idea==
 
===Mathematical Model===
In [[Projectile Motion]], we considered the motion of an object under the influence of a constant gravitational force <math> g = 9.8 m/s^2 </math>, an approximation which is essentially accurate on the Earth's surface (the more accurate understanding, provided by Newton, may be found in [[Gravitational Force]]). However, we did not take into account a very important factor, because in everyday life, objects in motion '' do not '' stay in motion:  this is because they are feeling the effects of air resistance (and, if they are in contact with other objects, friction). If, on the other hand, and object falls in a vacuum, it can be observed to have the same acceleration regardless of its mass or size.  In the following video, a feather and a ball bearing are dropped inside a vacuum, and one may observe that they fall at exactly the same rate. (Click on the picture)


[[File:Ballfeather.jpg |link=https://www.youtube.com/watch?v=_XJcZ-KoL9o ]]
[[File:Ballfeather.jpg |link=https://www.youtube.com/watch?v=_XJcZ-KoL9o ]]


===Friction Due to Air===
The friction due to air is a non-constant force on a falling object, and is determined by a number of factors.  The force of air on a falling object is defined as follows:
The friction due to air is a non-constant force on a falling object, and is related to multiple factors, such as cross-sectional area, the objects velocity, and the density of air.  The force of air on a falling object is defined by the following equation in the opposite direction of the objects motion:
 
[[File:Airforce.gif]]


C is the numerical drag coeffecient which is dependent on the shape of the object.
<math> \vec{F}_{drag} = -\frac{1}{2} C \rho A v^2 \hat{v} </math>


So, when the force of air comes into play, we see the the feather and ball bearing will not fall at the same rate because they have different cross sectional areas. The following video shows a feather and ball bearing being dropped in both scenarios.
Where <math>C</math> is the numerical drag coefficient which is dependent on the shape of the object, <math> \rho </math> is the density of air, <math> A </math> is the cross sectional area of the object, and <math> v </math> is its velocity. The vectors and sign enforce the correct direction of the force. Naturally, these coefficients vary greatly between a feather and a ball, and this is why in normal experience they fall at a substantially different rate:


[[File:ballfeather2.jpg |link:https://www.youtube.com/watch?v=4z8g8OSOMzY ]]
[[File:ballfeather2.jpg |link:https://www.youtube.com/watch?v=4z8g8OSOMzY ]]


As stated above, the force of air on a falling object is also dependent on the speed of a falling object.  In that respect, we come to discuss terminal velocity.  The force of air increases quadraticly with the speed of a falling object, so while the force of gravity remains constant, the force of air resistance will increase until the two forces perfectly cancel each other out and the net force is zero.  At this point, the acceleration of an object is zero and the object has reached terminal velocity. You may ask "Why will the force of air not exceed the force of gravity?".  This is because the force of air only continues to increase as the speed of the falling object increases and as the magnitude of the net force decreases, the speed of the object will approach being constant.  Therefor, the magnitude of the force of air will also approach being constant.  An object's terminal velocity can be defined by the following equation:
One of the important features of this equation is the dependence upon the velocity of the object: since the force of air depends on the square of the velocity, while the force of gravity remains constant, the force of air resistance will increase until the two forces cancel each other out and the net force is zero.  At this point, the acceleration of an object is zero and the object has reached terminal velocity. An object's terminal velocity is defined by:


[[File:terminalvelocity.gif]]
<math> v_t = \sqrt{\frac{2mg}{C\rho A}} </math>


==Where does that energy go?==
==Where does that energy go?==

Revision as of 15:08, 25 June 2019

claimed by cshimkus3



Main Idea

Mathematical Model

In Projectile Motion, we considered the motion of an object under the influence of a constant gravitational force [math]\displaystyle{ g = 9.8 m/s^2 }[/math], an approximation which is essentially accurate on the Earth's surface (the more accurate understanding, provided by Newton, may be found in Gravitational Force). However, we did not take into account a very important factor, because in everyday life, objects in motion do not stay in motion: this is because they are feeling the effects of air resistance (and, if they are in contact with other objects, friction). If, on the other hand, and object falls in a vacuum, it can be observed to have the same acceleration regardless of its mass or size. In the following video, a feather and a ball bearing are dropped inside a vacuum, and one may observe that they fall at exactly the same rate. (Click on the picture)

The friction due to air is a non-constant force on a falling object, and is determined by a number of factors. The force of air on a falling object is defined as follows:

[math]\displaystyle{ \vec{F}_{drag} = -\frac{1}{2} C \rho A v^2 \hat{v} }[/math]

Where [math]\displaystyle{ C }[/math] is the numerical drag coefficient which is dependent on the shape of the object, [math]\displaystyle{ \rho }[/math] is the density of air, [math]\displaystyle{ A }[/math] is the cross sectional area of the object, and [math]\displaystyle{ v }[/math] is its velocity. The vectors and sign enforce the correct direction of the force. Naturally, these coefficients vary greatly between a feather and a ball, and this is why in normal experience they fall at a substantially different rate:

link:https://www.youtube.com/watch?v=4z8g8OSOMzY

One of the important features of this equation is the dependence upon the velocity of the object: since the force of air depends on the square of the velocity, while the force of gravity remains constant, the force of air resistance will increase until the two forces cancel each other out and the net force is zero. At this point, the acceleration of an object is zero and the object has reached terminal velocity. An object's terminal velocity is defined by:

[math]\displaystyle{ v_t = \sqrt{\frac{2mg}{C\rho A}} }[/math]

Where does that energy go?

When we think of the energy of a falling object from the stance of a point-particle system, it will seem that some of the energy will disappear. When a falling object reaches terminal velocity, its kinetic energy remains constant while its potential energy due to gravity decreases. So, where does this energy go? We can now think of the falling object as an extended system and see that this energy get converted to internal energy as heat. The friction between the air and the falling object creates heat that takes the form of the lost energy. In a vacuum, this would not happen. The gravitational and kinetic energy of an object in a vacuum would vary inversely with one another.

A Graphical Interpretation

The following graphs will help you better understand the motion and energy relationships of a falling object.

A) 5 kg Ball Falling in Vacuum: Velocity vs Height

B) 5 kg Ball Falling in Air

C) .5 kg Feather Falling in Vacuum

D) .5 kg Feather Falling in Air

E) Energy of Ball Falling in Vacuum: Energy vs Time (yellow=total, red=kinetic, blue=thermal, cyan=potential)

F) Energy of Ball Falling in Air

Examples

Skydiver: Think of a free-falling skydiver. When he/she is falling with their arms and legs stretched out like a star, they will accelerate until he or she reaches their terminal velocity. Now, what would happen if the free-faller pulled in his/her arms and legs and leans forward so that their body is more parallel with their free-fall? From our definition of terminal velocity defined above, we know that this speed is inversely dependent on the surface area of the falling object. So, we can infer that the skydiver would speed up, because when he/she bring their arms and legs in, they decrease their surface area perpendicular to the fall and therefor increase their terminal velocity.

Heat of Spacecraft: Think of a spacecraft re-entering the Earth's atmosphere. How would the engineers designing that spacecraft need to determine the temperature that the space craft material needs to withstand. Well, these engineers could use the energy principle and the specific heat of the building material to do so. By calculating the terminal velocity, the initial potential and kinetic energy of the space craft when it enters the Earth's gravitational pull, and then graphing all the energy as at the space ship plummets to Earth's surface, these engineers can determine the heat this building material must be able to withstand.

Connectedness

  1. How is this topic connected to something that you are interested in?

I have always been interested in skydiving and this topic is a vital concept for the spot. Just as in the example above, the way a skydiver positions their body determines how fast they will fall. Although it may seem easy to reposition your body mid-air, at such high velocities it takes very slow calculated movements so that you do not start plummeting out of control.

  1. How is it connected to your major?

As a chemical engineer, I may encounter having to develop materials that will be used in free fall. If I am helping develop the metal coating for a spacecraft or vessel that will free fall to Earth's surface at high velocities, I will need to ensure that this material has an appropriate heat capacity to withstand the friction from the air.

  1. Is there an interesting industrial application?

Although this is not quite an industrial application, the concept of terminal velocity is very important for the military when they perform air drops. In a war zone, supplies may need to be delivered to civilians and military forces behind enemy lines. To do so, very careful calculations must be made based on the speed of the aircraft making the delivery, the sturdiness of the material the containers are made of, and when the parachutes should be deployed. If anything with the calculations is off, the packages may end up miles away from the target zone, or may be shot down if the parachute is deployed too early.

History

The study of free fall began many centuries ago by the experiments of Aristotle and Galileo. They both monitored the motion of falling objects and Aristotle noted that if a feather and a hammer are dropped from the same height, the hammer will reach the ground first. Galileo, however, noted that if the hammer and feather had similar shapes, they would reach the ground at approximately the same time. He hypothesized that in the absence of air resistance, all objects falling from the same height will reach the ground at the same time. Many centuries later, when it became possible for his theory to be tested in a vacuum, he was proved to be correct. At this point, physicists knew that it was air resistance and not mass that was the factor affecting the speed of a free fall. Further experiments were performed to determined the relationship between an objects shape and size and its terminal velocity. It was found that objects with a larger surface area perpendicular to free fall will be exposed to more air force than an object with a smaller surface areas. From these experiments and relationships, the equation for force due to air and terminal velocity were developed.

See also

Are there related topics or categories in this wiki resource for the curious reader to explore? How does this topic fit into that context?

Further reading

Galileo's Leaning Tower Experiment Materials under Extreme Loadings: Application to Penetration and Impact

Books, Articles or other print media on this topic

External links

The Physics Zone Britanica Online NASA

Internet resources on this topic

References

http://hyperphysics.phy-astr.gsu.edu/hbase/airfri2.html http://hypertextbook.com/facts/JianHuang.shtml http://www.space-propulsion.com/spacecraft-propulsion/showcase/atmospheric-re-entry-demonstrator.html https://perseshow.wordpress.com/2014/12/09/16-galileo-and-motion/